The distance is 34m , magnitude of the displacement is 6m and direction of displacement is towards west.
As per question, a dog walks 14 meters to the east and then 20 meters back to the west.
The distance moved for this motion is given below,
Distance = 14 + 20 m = 34m
The magnitude of the displacement and its direction are given below:
Displacement = 14 - 20 m = - 6m
negative sign indicates that the direction of displacement is towards west.
Magnitude of the displacement = 6m
Thus, the distance is 34m ,direction of displacement is towards west and magnitude of the displacement is 6m.
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which mass is the lightest between 5m/s,0m/s and 3m/s?
Diane is writing a summary statement of her experiment. This statement is
written.
A after data is collected and analyzed
B before writing the scientific question
C before writing the hypothesis
D at the same time data is collected.
.
a 10 kg block of ice slide down the ramp 20 m long. inclined at 10 degrees to the horizontal.
if the ramp is frictionless what is the acceleration of the block of ice
if the coefficient of friction is 0.10 how long will it take the block to slide down the ramp if it starts from rest
At the given coefficient of friction of the ramp, the acceleration is 0.97 m/s².
The time taken for the block to travel down the ramp is 6.42 s.
What is the acceleration of the block?The acceleration of the block is calculated as follows;
Apply Newton's second law of motion to determine the acceleration of the block.
μmgcos(θ) = ma
μgcos(θ) = a
where;
μ is coefficient of frictiong is acceleration due to gravityθ is the angle of inclination of the planea = (0.1)(9.8) cos(10)
a = 0.97 m/s²
The time taken for the block to travel down the inclined plane is calculated as follows;
s = vt + ¹/₂at²
where;
v is the initial velocity = 0s is the length of the ramp20 = 0 + ¹/₂(0.97)t²
40 = 0.97t²
t² = 40/0.97
t² = 41.24
t = √41.24
t = 6.42 seconds
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If the distance between the Earth and Sun were decreased by a factor of 4, how much would the gravitational force on the Earth change?
The gravitational force between the sun and the earth will become 16 times of the original force if distance between the Earth and Sun were decreased by a factor of 4.
What is universal law of gravitation?The universal law of gravitational states that the force of attraction between two masses is directly proportional to product of their masses and inversely proportional to the square of the distance between them.
Given are the Earth and Sun and the distance between them is decreased by a factor of 4.
Assume that the mass of sun is m[S] and that of earth is m[E] and the distance between them be R. Then the gravitational force of attraction would be -
F [1] = Gm[S]m[E]/R²
If the distance is decreased by the factor of 4, then we can write -
F [2] = Gm[S]m[E]/(R/4)²
Now,
F[1]/F[2] = {Gm[S]m[E]/R²}/{Gm[S]m[E]/(R/4)²}
F[1]/F[2] = (R/4)²/R²
F[1]/F[2] = (R²/16)/R²
F[1] /F[2] = 1/16
F[2] = 16 F[1]
Therefore, the gravitational force between the sun and the earth will become 16 times of the original force if distance between the Earth and Sun were decreased by a factor of 4.
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module 2 question 2
Find the components of vtot along the x and y axes in Figure 3.25, where = 25.0° and vtot = 6.00 m/s.
vtot, x =
what is x? I've seen others put 4.41 but it is wrong.
m/s
vtot, y = 5.07
The x and y component of [tex]V_{tot}[/tex] where θ = 25° and [tex]V_{tot}[/tex] = 6 m / s are 4.68 m / s and 3.72 m / s respectively.
Resolving [tex]V_{tot}[/tex] into its x and y components,
sin θ = [tex]V_{tot,y}[/tex] / [tex]V_{tot}[/tex]
sin 51.5° = [tex]V_{tot,y}[/tex] / 6
[tex]V_{tot,y}[/tex] = 4.68 m / s
cos θ = [tex]V_{tot,x}[/tex] / [tex]V_{tot}[/tex]
cos 51.5° = [tex]V_{tot,x}[/tex] / 6
[tex]V_{tot,x}[/tex] = 3.72 m / s
These are called as trigonometric ratios. Some of the basic formulae are:
sin θ = Opposite side / Hypotenusecos θ = Adjacent side / Hypotenusetan θ = Opposite side/ Adjacent sideTherefore, the x and y component of [tex]V_{tot}[/tex] are 4.68 m / s and 3.72 m / s respectively.
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A projectile is fired from the edge of a cliff 200.0 m high with an initial speed of 30.0 m/s at an angle of 45° above the horizontal.
Determine the maximum horizontal range.
The maximum horizontal range of the projectile is 91.8 m.
What is maximum horizontal range of a projectile?
The maximum horizontal range of a projectile is the maximum horizontal distance travelled by the projectile.
Mathematically, the horizontal range of a projectile is given as;
R = u² sin(2θ) / g
where;
u is the initial velocity of the projectileθ is the angle of projection of the projectileg is acceleration due to gravityR is the range of the projectileR = (30² x sin(2 x 45))/9.8
R = 91.8 m
Thus, we can conclude that the maximum horizontal distance travelled by the projectile occurs when the angle of projection is 45 degrees.
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discuss the types and operation of active and passive filters in measurements and instrumentation
Resistors, capacitors, and inductors are the only passive elements used in passive filters. In contrast, active filters don't employ inductors and instead use resistors, capacitors, and active components like op-amps.
What makes it a passive filter?A common type is called a passive filter because it uses solely passive inductive (L), capacitive (C), and resistive (R) components rather than active ones like transistors. Passive filters do not require a power source.
As they separate and only permit certain sinusoidal input signals to pass, passive RC filters "filter-out" undesirable signals.
What are various types of passive filters?Low Pass Filters.High Pass Filters.Band Pass Filters.Band Stop/Reject Filters.Power Line Filters.SAW Filters.Signal Filters.Sinusoidal Filters.To know more about Passive filter visit:
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PLEASE HELP ME I NEED THIS ASAP
Investigating Energy Systems
Harnessing Human Energy Chapter 1 Lesson 1.2
Reasoning Tool
Possible subclaims:
The Battery System does have energy.
or
The Battery System does not have energy.
The Hand-Crank Generator System does have energy.
or
The Hand-Crank Generator System does not have energy.
The Solar Cell System does have energy.
or
The Solar Cell System does not have energy.
Evidence
(observations about whether the system does or does not have energy)
This matters because . . .
(How does this evidence support the subclaim?)
Therefore, . . .
(subclaim)
The Battery System does have energy, the Hand-Crank Generator System does not have energy and the Solar Cell System does have energy.
The Battery System does have energy.
Because the battery can be charged again and again by using the source of energy like windmill or dam. The battery can convert chemical energy to electrical energy. If initiated the whole chemical energy will be converted only
The Hand-Crank Generator System does not have energy.
Because, it will only produced energy only as long the hand is moving the generator. It will not produced any energy if it is not moved.
The Solar Cell System does have energy. Because it contains energy of sun converted directly in to the electrical form and it will release energy spontaneously.
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You have a parallel‑plate 5.13×10−6 F capacitor that is charged to 0.00967 C. While the capacitor is isolated, you change the plate separation so that the capacitance becomes 1.27×10−6 F. How much work do you perform in this process?
The work done to separate the plates of the parallel plate capacitor that's charged to a 0.00967 C is 2864.5 J
U = 1 / 2 C V²
U = Initial energy
C = Capacitance
V = Electric Potential
Q = Charge
C[tex]_{i}[/tex] = 5.13 μ F
Q[tex]_{i}[/tex] = 9.67 m C
C[tex]_{f}[/tex] = 1.27 μ F
As the capacitor is isolated, there'll be no further current flow and charge will remain constant.
Q[tex]_{f}[/tex] = Q[tex]_{i}[/tex] = 9.67 m C
Q = C V
Q² = ( C V )²
U[tex]_{i}[/tex] = 1 / 2 * C[tex]_{i}[/tex] * V[tex]_{i}[/tex]²
U[tex]_{i}[/tex] = 0.5 * ( C[tex]_{i}[/tex] * [tex]V_{i}[/tex] )² / C[tex]_{i}[/tex]
U[tex]_{i}[/tex] = 0.5 * Q[tex]_{i}[/tex]² / C[tex]_{i}[/tex]
U[tex]_{i}[/tex] = 0.5 * ( 9.67 * [tex]10^{-3}[/tex] / 5.13 * [tex]10^{-6}[/tex] )
U[tex]_{i}[/tex] = 942.5 J
U[tex]_{f}[/tex] = 1 / 2 * C[tex]_{f}[/tex] * [tex]V_{f}[/tex]²
U[tex]_{f}[/tex] = 0.5 * ( C[tex]_{f}[/tex] * [tex]V_{f}[/tex] )² / C[tex]_{f}[/tex]
U[tex]_{f}[/tex] = 0.5 * Q[tex]_{f}[/tex]² / C[tex]_{f}[/tex]
U[tex]_{f}[/tex] = 0.5 * ( 9.67 * [tex]10^{-3}[/tex] / 1.27 * [tex]10^{-6}[/tex] )
U[tex]_{f}[/tex] = 3807 J
W = U[tex]_{f}[/tex] - U[tex]_{i}[/tex]
W = 3807 - 942.5
W = 2864.5 J
Therefore, the work done to separate the plates of the parallel plate capacitor is 2864.5 J
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A sled and rider with a combined weight of 70.0 kg are at rest on the top of a hill 11.0 m high. (Enter your answers in J.)(a)What is their total energy at the top of the hill? answer in______J(b)Assuming there is no friction, what would the total energy be on sliding halfway down the hill? answer in_______J(c)What would the total energy be at the bottom of the hill? answer in_________J
We will ahve the following:
a)
[tex]\begin{gathered} E=mgh \\ \\ \Rightarrow E=(70.0kg)(9.8m/s^2)(11.0m)\Rightarrow E=7546J \end{gathered}[/tex]So, the total energy will be 7546 J.
b) The total energy halfway must also be the same, but half of it will be kinetic energy and half potential energy.
c) The total energy at the bottom must be the same, but this time it will be all kinetic energy.
what does a closed circuit need to work?
Answer:
Explanation what does a closed circuit need to work?
Closed Circuit: In a closed circuit, the connected source and load form a closed-loop path. We need a switch to make (ON) and break (OFF) the circuit for the electrical and electronic circuits to work (open circuit and closed circuit).
Angle of incidence is 70 degrees what is the relection and refraction ray
The angle of incidence = 35°.
The normal divides the angle between the incident and reflected rays into two equal angles. The angle between the incident ray and the normal is called the angle of incidence. The angle between the reflected ray and the normal is called the reflection angle. When a ray of light approaches a smooth and polished surface and bounces off it, it is called a light reflection.
An incident ray striking a surface is reflected by the surface. A reflected ray is called a reflected ray. The difference between light reflection and refraction is simple. In reflection, a ray hitting a plane returns to its original source/medium as the wave bounces off the surface. However, when refracted, the wave passes through the surface, changing its speed and direction.
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A girl is moving in a straight line at a velocity of 3 m/s and starts to slow down at a constant rate. If she stops 6 seconds later, what is her acceleration?
The acceleration of the girl moving in a straight line at a velocity of 3 m/s is - 0.5 m / s²
a = v - u / t
a = Acceleration
v = Final velocity
u = Initial velocity
t = Time
v = 0
u = 3 m / s
t = 6 s
a = ( 0 - 3 ) / 6
a = - 0.5 m / s²
The negative symbol signifies that she is decelerating.
Deceleration is the acceleration in opposite direction. As a result, the body will lose velocity at a constant pace. Hence, if the acceleration has a negative value it is called as Deceleration.
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What is momentum?.
.
.
.
The quantity of motion of a moving body, measured as a product of its mass and velocity.
What is velocity?The primary indicator of an object's position and speed is its velocity. It is the distance that an object travels in one unit of time. The displacement of the item in one unit of time is the definition of velocity.velocity is a term that describes the speed and direction of a point's motion.Velocity is the pace and direction of an object's movement, whereas speed is the time rate at which an object is travelling along a path.To learn more about : Velocity
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I need help with my work
xplanation:
A swinging edndulum bob performs a simple harmonic motion under the influence of the gravity of the earth. In simple harmonic motion, the restoring force acts on the displaced mass which continuously tries to bring the mass to the equilibrium position.
The object of mass m falls due to the gravity of the earth.
Thus for the motion of the pendulum, a gravitational force acts as a restoring force and the object of mass will fall due to the gravity of the earth. The motion of the pendulum and the falling mass is due to the gravity of the earth and the acceleration due to the gravity of the earth is independent of the mass that is accelerating towards the earth.
inal answrer:
The correct option is (B) although they both accelerate due to gravity at the same rate, a restoring force acts on the bob.
A ball is rolled at a speed of 12 m/seconds after 36 seconds it comes to stop what is the acceleration of the ball
Answer:
Approximately [tex](-0.33)\; {\rm m\cdot s^{-2}}[/tex] ([tex](-1/3)\; {\rm m\cdot s^{-2}}[/tex]) on average.
Explanation:
Acceleration is the rate of change in velocity.
For the ball in this question:
Initial velocity: [tex]u = 12\; {\rm m\cdot s^{-1}}[/tex].Final velocity: [tex]v = 0\; {\rm m\cdot s^{-1}}[/tex] since the ball has stopped.Time required: [tex]\Delta t = 36\; {\rm s}[/tex].Subtract the initial velocity [tex]u[/tex] from the final velocity [tex]v[/tex] to find the change in velocity:
[tex]\begin{aligned}(\text{change in velocity}) &= (\text{final velocity}) - (\text{initial velocity}) \end{aligned}[/tex].
[tex]\begin{aligned}\Delta v &= v - u \\ &= 0\; {\rm m\cdot s^{-1}} - 12\; {\rm m\cdot s^{-1}} \\ &= (-12)\; {\rm m\cdot s^{-1}} \end{aligned}[/tex].
(Note that the change in velocity is negative because the final velocity [tex]v = 0\; {\rm m \cdot s^{-1}}[/tex] is more negative than the initial velocity [tex]u = 12\; {\rm m\cdot s^{-1}}[/tex].)
To find the average acceleration [tex]a[/tex] (average rate of change in velocity,) divide the change in velocity [tex]\Delta v[/tex] by the time [tex]\Delta t[/tex] required to achieve such change:
[tex]\begin{aligned}(\text{average acceleration}) &= \frac{(\text{velocity change})}{(\text{time required for change})}\end{aligned}[/tex].
[tex]\begin{aligned} a &= \frac{\Delta v}{\Delta t} \\ &= \frac{(-12)\; {\rm m\cdot s^{-1}}}{36\; {\rm m\cdot s^{-1}}} \\ &\approx (-0.33) \; {\rm m\cdot s^{-2}}\end{aligned}[/tex].
(Average acceleration is negative since velocity is becoming less positive.)
What would the mechanical advantage of a ramp be if the length is 20 feet and the height is 5 feet?
100
8
1000
4
please use a multiple choice answer for branliest (how ever you spell it)
Assume that when we go to Mars, we discover that there is a previously unknown planet between Mars and Jupiter. The newly found planet is 2.5 Astronomic Units (A.U.) from the Sun.
What is the period around the Sun of the new Planet?
The period of the revolution as obtained from the question is 3.95 years.
What is the solar system?We know that the solar system is composed of the sun and the planets. The sun is at the center of the solar system and the sun is surrounded by the planets which tend to form concentric circles.
From the Kepler's laws, we can see that the square of the period is directly proportional to the cube of the radius of the planet;
Hence;
T^2 α r^3
T = period
r = distance
T = r^3/3
T = (2.5)^3/2
T = 3.95 years
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A soccer ball (k = 2/3) with a radius of 0.101 meters and a mass of 0.400 kilograms rolls on a field with an angular speed of 93 radians per second. a. What is the translational kinetic energy of the ball? Include units in your answer.b. What is the rotational kinetic energy of the ball? Include units in your answer.c. The ball then rolls up a hill. What height will the ball reach before coming to rest? Include units in your answer. All answers must be in 3 significant digits.
Given,
The radius of the ball, r=0.101 m
The mass of the ball, m=0.400 kg
The angular speed of the ball, ω=93 rad/s
a.
The linear velocity of the ball is given by,
[tex]v=\omega r_{}[/tex]The translational kinetic energy is given by,
[tex]\begin{gathered} K_t=\frac{1}{2}mv^2 \\ =\frac{1}{2}m\omega^2r^2 \end{gathered}[/tex]On substituting the known values,
[tex]\begin{gathered} K_t=\frac{1}{2}\times0.400\times93^2\times0.101^2 \\ =17.6\text{ J} \end{gathered}[/tex]hus the translational kinetic energy of the ball is 17.6 J
b.
The moment of inertia of the ball is given by,
[tex]I=\frac{2}{3}mr^2[/tex]The rotational kinetic energy of the ball is given by.
[tex]\begin{gathered} K_r=\frac{1}{2}I\omega^2 \\ =\frac{1}{2}\times(\frac{2}{3}\times mr^2)\times\omega^2 \\ =\frac{1}{3}mr^2\omega^2 \end{gathered}[/tex]On substituting the known values,
[tex]\begin{gathered} K_r=\frac{1}{3}\times0.400\times0.101^2\times93^2 \\ =11.8\text{ J} \end{gathered}[/tex]hus the trotational kinetic energy of the ball is 11.8 J
.
From the law of conservation of energy, the energy can neither be created nor be destroyed but can be converted from one form to another.
When ball rolls up the hill the ball will lose its translational and rotational kinetic energy. But the lost kinetic energy will be converted into its gravitational potential energy.
Therefore, the gravitational potential energy of the ball when it is up the hill is equal to the sum of its translational and rotational kinetic energy.
Thus,
[tex]\begin{gathered} K_t+K_r=P \\ =\text{mgh} \end{gathered}[/tex]Where g is the acceleration due to gravity and h is the height that the ball will reach before coming to rest.
On rearranging the above equation,
[tex]h=\frac{K_t+K_r}{mg}[/tex]On substituting the known values,
[tex]\begin{gathered} h=\frac{17.6+11.8}{0.400\times9.8} \\ =7.5\text{ m} \end{gathered}[/tex]herefore the ball will treach a height of 7.5 m before coming to rest.
EXPERIMENT: COMPARING HARDNESS AND DENSITY OF SOLIDS 100 POINTS I NEED THIS DONE
In this activity, you will identify several minerals, then you will compare the minerals to determine if there is a relationship between the hardness of a sample and its density. You should consider the factors that determine the density and the hardness of a material and then form a hypothesis as to whether you believe these two properties will show a correlation. If they show a correlation, it may indicate that one property depends on or is in some way related to the other property. You should consider this in making your hypothesis. If two properties have a positive correlation, then the graph of their values will be a straight line. You will use this fact to test the accuracy of your hypothesis.
OBJECTIVES
Use several tests, including hardness to identify 6 minerals.
Using hardness and density data, creating a graph.
Explain how to interpret a positive or negative correlation between graphed values.
Answer:
sbdjhdjrjrjrjrjrbdhhrhejejejejejejejejdndndjsj
Answer: My hypothesis was that the future results of the experiment would show a correlation. According to my data, my hypothesis was correct. The file uploaded to this assignment shows that the graph is a correlation but not a 100% positive correlation because if you imagined there was a straight line there, the points would be completely aligned. The correlation is simply a “positive correlation”. Some of the difficulties I had when performing the experiment was distinguishing which type of luster was for each mineral because the light almost looked the same with other minerals. You might change the procedure to avoid this problem in the way of getting all the rest of the results for that specific mineral and then look at which of the graph with the answers was most alike and then you can see why the luster is that certain result in that data which is the correct one. A graphical analysis can be used to explore the relationship between any two scientific variables by changing the numerical data of the experiment into a graph, which is a much more effective and easier way of interpreting the gathered results. It's easier to visualize a graph data than read all the tables with numbers.
The graph is in the attachment below and the 6 minerals also with their names, their density, and their hardness
8.Sara took her solid gold ring to the jeweler for cleaning. While the jeweler was
cleaning, he mixed up the ring with another that is only gold-plated. How can the
jeweler determine which ring is Sara's? Hurry pls
The jeweler can determine which ring is Sara's by scratch test, acid test or magnet test.
Sara's solid gold ring is mixed with gold plated ring and now she has to identify which one is her real ring.
There are many method to identify if the ring is solid gold or not,
1. A scratch test. A scratch deep enough to penetrate till the metal of the gold-plated ring can tell if the ring is solid gold or not. The solid gold ring will be all uniformly distributed gold through the structure.
2. By acid test. By putting both the rings in the acid solution is can be found out which one is the real gold ring. The gold plated ring in the acid solution which eventually changes the color of the ring.
3. Magnet test. A very strong magnet will attract the gold plated ring but not solid gold ring because the solid gold rings are non-magnetic in nature.
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1. Which of the following statement(s) are true about the atoms of any element?
A. The number of protons in an atom of an element is unique to each element.
B. The number of protons and neutrons in an atom of an element is unique to each element.
C. A proton is an atom of one element that is identical to a proton in an atom of another element.
D. The number of protons in an atom of an element is the same for all elements.
2. Which of the following statements explains why atoms are always neutral in charge
A. They have the same number of protons as the atoms of all other elements.
B. They have protons that are identical to the protons of all other elements.
C. They have the same size as the atoms of all other elements.
D. They have the same number of protons as electrons.
3. What is the atomic number of an atom? Why is this number important?
4. Where are the electrons in an atom located?
5. Where are the neutrons in an atom located?
6. Where are the protons in an atom located?
7. What is the relationship between protons and elements?
8. Compare and contrast electrons, neutrons, and protons.
The answers include the following:
The number of protons in an atom of an element is the same for all elements is the true statement about atoms of other elements and is denoted as option B.They have the same number of protons as electrons explains why atoms are always neutral in charge and is denoted as option D.Atomic number is the charge number on an atomic nucleus and it is important because it helps in identifying elements.The electrons in an atom is located in the outermost shell.The neutrons in an atom is located inside the nucleus.The protons in an atom is located inside the nucleus.The relationship between protons and elements is that they are equal and the same.Electrons, protons and neutrons are subatomic particles in which electron is negatively charged, protons is positively charged and neutrons is neutral.What is an Atom?This is referred to as the smallest unit of a chemical element and has subatomic particles such as proton, neutron etc.
The electron is negatively charged, protons is positively charged and neutrons is neutral.
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1.) Describe the process you would use to find the magnitude (length) of the resultant of two perpendicular vectors, one in the x-direction, and another in the y-direction.
Pythagorean theorem is the process use to find the magnitude of the resultant of two perpendicular vectors.
The Pythagorean Theorem is used to calculate the steepness of slopes of hills or mountains. A surveyor appears via a telescope in the direction of a measuring stick a fixed distance away, so that the telescope's line of sight and the measuring stick form a right angle.
It allows to explain the space round us and is important no longer only in construction however suitably tailored in equations of thermodynamics and preferred relativity.
The Pythagorean Theorem is useful for two-dimensional navigation. you may use it and two lengths to discover the shortest distance. The distances north and west will be the two legs of the triangle, and the shortest line connecting them might be the diagonal. The same ideas may be used for air navigation.
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WHAT FAMILY DOES THIS BELOND TO?
PLEASE ANSWER WILL MARK BRAINIEST
Answer:
See below
Explanation:
2 - 8 - 2 is the configuration for Mg Magnesium is an alkaline earth metal
Q: Compare and contrast the different parts of the Electromagnetic Spectrum. Evaluate the usefulness of each part and decide which part is most useful, or most important, to you and society as a whole. You must provide two reliable sources to back up your opinion. Recall that reliable sources include scientific sites or publications, education sites or publications, and government sites or publications.
The purpose of this assignment is to debate and consider different opinions on this topic. There is no right or wrong answer. However, this discussion should represent varying opinions. You will need to do some research and back up your opinions with facts. Remember to cite your sources!
A: The different parts of the electromagnetic spectrum are ultraviolet lights, infrared lights, x-rays, gamma rays, and radio waves. All of these colors are called the electromagnetic spectrum. Each of these parts have different energy levels, wavelengths, and frequencies. According to scied.ucar,edu, Gamma rays have the highest energies and radio waves have the lowest. As imagine.gsfc.nasa.gov states, a comparison of all of the parts is that their radiations are defined by the amount of energy found in the photons. They will still have different energies but they all use photons. Usefulness for Radio: It captures radio waves emitted by radio station which makes our favorite tunes. Microwave: cooks popcorn in a few mins. Infrared: night vision goggles use this light. Helps us map dust between stars. Visible: Our eyes detect visible light. Fireflies, light bulbs, and stars all emit visible light. Ultraviolet:Emitted by sun and reason why skin tans and burns. X-ray:Dentist uses to view teeth, airport security to see through your bag, used to see inside things. Gamma ray: Doctors use it to image inside your body. I think the most important would be the visible ones because those are the ones everyone uses no matter what. If there was no light we wouldn't see. We can see light with our vision.
The infrared and ultraviolet parts of the electromagnetic spectrum can be used in the field of chemical analysis.
The sections of the EM spectrum are named in order of increasing energy gamma rays X-rays ultraviolet-visible light infrared, and radio waves. Microwaves used in microwave ovens are a subsection of the radio segment of the EM spectrum.
Electromagnetic energy travels in waves and covers a wide spectrum from very long radio waves to very short gamma rays. The human eye can only see a small portion of this spectrum known as visible light. The electromagnetic spectrum includes all frequencies of electromagnetic radiation that carry energy and travel through space in the form of waves. Low frequencies and long wavelengths make up the radio spectrum.
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velocity of a body of mass 20kg decreases from 20m/s to 5m/s in a distance of 100m . force on the body is
The force on the body of 20 kg mass is F = 11.2 N
Equation :To calculate the force of the body use the formula
F = ma
Where,
F is force
m is mass
a is acceleration
Given data are :
m = 20 kg
a = ?
v = 20 m/s
u = 5 m/s
s = 100 m
So, as we have the values of initial velocity, (u), final velocity, v and distance s. First we need to calculate acceleration
Use formula for equation of motion,
v² = u² + 2as
(20 m/s)² = (5 m/s)² + 2 x a x 100 m
400 m/s = 25 m/s + 200 m a
a = 225 m/s / 400 m/s
a = 0.56 m/s²
Now, we have the acceleration.
Calculating force by formula given above;
F = ma
F = 20kg x 0.56 m/s²
F = 11.2 N
Hence, the force on the body of 20 kg mass is F = 11.2 N
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3.-A projectile has an initial horizontal velocity of
5 m/s and an initial vertical velocity of 3 m/s second upward. At what angle was the projectile
fired?
Answer:
Explanation:
tg α = V₂ / V₁ = 3 / 5 = 0.6
α ≈ 31°
The radius of a wheel is 0.680 m. A rope is wound around the outer rim of the wheel. The rope is pulled with a force of magnitude 5.00 N, unwinding the rope and making the wheel spin CCW about its central axis. Ignore the mass of the rope.What is the angular displacement Δθ, in radians, of the wheel during 1.20 revolution?
Givens.
• The radius of the wheel is 0.680 m.
,• The applied force is 5.00 N, and it's a tangential force.
,• The number of revolutions is 1.20.
We need to find the circumference of the wheel, use the circumference formula.
[tex]C=2\pi r[/tex]Where r = 0.680 m and pi = 3.14.
[tex]C=2\cdot3.14\cdot0.680=4.27m[/tex]The circumference of the wheel is 4.27 meters.
It's important to notice that the circumference represents 1 revolution, so for 1.20 revolutions we have
[tex]1.20\text{rev}\cdot\frac{4.27m}{1\text{rev}}=5.12m[/tex]This means the total distance covered is 5.12 m. However, the displacement is different because it takes into account only the change of position, so basically, the displacement would be 0.20 revolutions because at 1 revolution we are at the same starting point.
[tex]0.20\text{rev}\cdot\frac{4.27m}{1\text{rev}}=0.854m[/tex]Therefore, the total displacement is 0.854 meters.
However, we need to find the angular displacement, so
[tex]\theta=\frac{d}{r}=\frac{0.854m}{0.680m}=1.26\text{rad}[/tex]Hence, the angular displacement is 1.26 radians.
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How is Sonar method different from Radar method
Sonar systems function using sound waves mostly in water, whereas radar systems operate primarily using radio frequencies in the air. Despite the medium difference, radar and sonar's identical underlying concepts frequently lead to technical convergence.
Why do we use sonar instead of radar?Sonar, which stands for Sound Navigation and Ranging, is beneficial for exploring and charting the ocean since sound waves travel farther in water than radar and light waves do.
RADAR transmits electromagnetic waves, whereas active SONAR transmits acoustic (sound) waves. Both systems rely on these waves returning echoes from particular features or targets to determine the most important properties and qualities of the target (i.e., shape, size, speed, distance, etc.).
Both of these sensor systems depend on the sending and receiving of return signals to operate. While sonar systems function largely with sound waves in water, radar systems primarily use radio waves in the air.
Active SONAR transmits acoustic (sound) waves, whereas RADAR transmits electromagnetic waves. Both systems rely on these waves returning echoes from specific features or targets to identify the target's crucial characteristics and traits (i.e., shape, size, speed, distance, etc.).
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