Answer:
Average speed 3m/sAverage velocity is 4m/s
Explanation:
In this problem, we are going to solve for the average speed and average velocity for the entrire trip made by the dolphin.
Given data
speed v= 2 m/s
time t= 24s
the distance travelled by the dolphin is
speed= distance/time
distance= speed*time
distance= 2*24
distance= 48m
now the dolpine made a reverse and covered this 48m in 8s to return to it initial position
the speed it took is
speed= distance/time
speed= 48/8
speed= 6m/s
It average speed is the total distance divided by the total time taken
average speed= (48+48)/(24+8)= 96/32= 3m/s
average speed= 3 m/s
it average velocity is the sum of the initial and final velocity is divided by 2 to find the average
(2+6)/2= 8/2= 4m/s
average velocity is 4m/s
What year will y'all graduate
Answer:
I'm in college and i'm a senior so i will graduate this year.
Explanation:
How is a scientific theory different from a scientific law?
"A student bikes to school by traveling first dN = 0.900" and "Similarly, let d⃗ W be the displacement vector corresponding to the second leg of the student's trip. Express d⃗ W in component form. Express your answer as two numbers separated by a comma. Be careful with your signs"
Complete Question
A student bikes to school by traveling first dN = 0.900 miles north, then dW = 0.300 miles west, and finally dS = 0.100 miles south.
Similarly, let d⃗ W be the displacement vector corresponding to the second leg of the student's trip. Express d⃗ W in component form.
Express your answer as two numbers separated by a comma. Be careful with your signs.
Answer:
The value is [tex]dT = ( -0.3, 0.8)[/tex]
Explanation:
From the question we are told that
The first displacement is [tex]dN = 0.900 \ due \ North[/tex] i.e positive y-axis
The second displacement is [tex]dW = 0.300 \ miles \ due \ west[/tex] i.e negative x-axis
The final displacement is [tex]dS = 0.100 \ miles \ due \ south[/tex] i.e negative y-axis
Generally dW in component for is
[tex]dW = (-0.3 , 0)[/tex]
Generally the total displacement of the student is mathematically represented as
[tex]dT = ( -0.3, (0.90 - 0.10))[/tex]
[tex]dT = ( -0.3, 0.8)[/tex]
In Einstein's special theory of relativity, mass and energy are equivalent. An expression of this equivalence can be made in terms of electron volts ( units of energy) and kilograms, with one electron volt (eV) being equal to 1.78*10^ -36 kg. Using this ratio, express the mass of the heaviest mammal on earth, the blue whale, which has an average mass of 1.90*10^ 5 kg , in mega electron volts and tera electron volts
Answer:
In MeV: 10.674 × 10^(34) MeV
In TeV: 10.674 × 10^(28) TeV
Explanation:
We are given that;
1.78 × 10^(-36) kg = 1 eV
We are now told that the blue whale has an average mass of 1.90 × 10^(5) kg
Thus, converting this mass of the blue whale to eV, we have;
(1.90 × 10^(5) × 1)/(1.78 × 10^(-36)) = 10.674 × 10^(40) eV
Now, converting to mega electron volts;
From conversions;
1 eV = 10^(-6) MeV
Thus,
10.674 × 10^(40) eV will be;
(10.674 × 10^(40) × 10^(-6))/1 = 10.674 × 10^(34) MeV
Also, converting to Tera electron Volts;
From conversion, we know that;
1 eV = 10^(-12) TeV
Thus;
10.674 × 10^(40) eV will give;
(10.674 × 10^(40) × 10^(-12))/1 = 10.674 × 10^(28) TeV
Convert the following measurements. Only type numbers and decimals into the answer boxes:
1. 34mm =
cm
2.234cm =
m
3.3km =
m
4.35 m =
mm
Answer:
2m 4m2Explanation:rteji3ujnrej
1. .134
2. 22.34
3. 330
4. 4350
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