Answer:
Reaction force = Weight
the force exerted by A on B is equal.
M1a = M2a
Explanation: I think the answer is right if wrong message me.
19) Suppose a ball is thrown straight up and experiences no appreciable air resistance. What is its acceleration just before it reaches its highest point? A) zero B) slightly less than g C) exactly g D) slightly greater than g
Answer:
C)
Explanation: In freefall motion object always has gravity as its acceleration.
During which time does Jamal have the greatest momentum?
Answer:
Momentum Packet Answer KEY - Science Online
YOU WILL SEE THE PDF
Student 1 lifts a box with a force of 500 N and sets it on a tabletop 1.2 m high. Student 2 pushes an identical box up a 5 m ramp from the floor to the top of the same table. Which student did the MOST work?
The student who did the most work is student 2 with 2500 Joules.
Given the following data:
Force 1 = 500 NewtonDistance 1 = 1.2 meterForce 2 = 500 NewtonDistance 2 = 5 meterTo determine which of the students did the most work:
Mathematically, the work done by an object is given by the formula;
[tex]Work\;done = Force \times distance[/tex]
For student 1:
[tex]Work\;done = 500 \times 1.2[/tex]
Work done = 600 Joules
For student 2:
[tex]Work\;done = 500 \times 5[/tex]
Work done = 2500 Joules.
Therefore, the student who did the most work is student 2 with 2500 Joules.
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Answer:student 2 did the most work
Explanation:student 2 did more work because he pushed it up 5 m instead of 1.2.
what color will a yellow banana appear when illuminated by yellow light
Answer:
A yellow banana reflects only yellow light,
Explanation:
*
as the mass of an object increases, the force of attraction...
Answer:
Since the gravitational force is directly proportional to the mass of both interacting objects, more massive objects will attract each other with a greater gravitational force. So as the mass of either object increases, the force of gravitational attraction between them also increases.
Answer:
thanks
Explanation:
for answer byebye
Assuming a current is flowing, what increases the strength of the magnetic field of a coiled electrical wire? Select all that apply. Straightening the wire changing the direction of the current flow adding more coils to the wire placing a metal bar within the coils stopping the current.
The strength of the magnetic field is increased by adding more coils to the wire and placing a metal bar within the coils.
The given problem is based on the concept and fundamentals of the magnetic strength in a current-carrying coil of wire. The current-carrying wire in a coiled form is known as Solenoid.
And the mathematical expression for the magnetic field in a solenoid is,[[tex]B = \dfrac{\mu_{0} \times N \times i}{L}[/tex]
Here,
B is the strength of the magnetic field.
[tex]\mu_{0}[/tex] is the magnetic permeability of free space.
N is the number of coils.
The strength of the magnetic field will increase by increasing the number of coils and placing the metallic slab (it will increase magnetic permeability) within the coils.
Thus, we can conclude that the strength of the magnetic field is increased by adding more coils to the wire and placing a metal bar within the coils.
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Answer:
C
Explanation:
Two hockey players are skating toward each other on a frictionless ice. One is moving at 1 m/s while the other is traveling at 2 m/s. The players collide and stick together. Find their combined speed.
Their combined speed will be 1m/s
Given the following parameters;
The velocity of the first hockey player is 1m/s.The velocity of the second hockey player is 2m/s.If the player collides and stick together, the combined speed is expressed as;
Combined speed = differences in velocityCombined speed = 2m/s - 1m/sCombined speed = 1m/s.Hence their combined speed will be 1m/s
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describe the working principle of a hydraulic press using pascals principle
Answer:
A hydraulic press works on the principle of Pascal's law, which states that when pressure is applied to a confined fluid, the pressure change occurs throughout the entire fluid. Within the hydraulic press, there is a piston that works as a pump, that provides a modest mechanical force to a small area of the sample.
Explanation:
A 50 kg driver of a car is traveling at 35 m/s when she hits a large deer. She strikes the air bag/seatbelt combination that brings her body to a stop in 1.1s. What is the impulse imparted to the driver of the car?
Answer:1590 N
Explanation:
Impulse = change in momentum/time
change in momentum = 0 - 50 x 35 = -1750
-1750/1.1 = 1590 (3s.f.) N
Physical data is often used in the court system. In fact, police officers use radar to determine your speed when you are driving and admit that record in court if you are ever given a ticket. In one such instance, the police officer submitted data that goes against the claim of the driver, who is contesting his ticket in court. The police officer (who was stationary when he made the measure) claims that the driver was speeding at 44.7 m/s, but the driver claims he was only going 26.8 m/s (according to his speedometer). The speed limit was 60 mph. The driver argues that the radar gun must have been set incorrectly to record relative velocity. Is it possible that they are both telling the truth?
The driver is telling the truth, the radar gun must have been set incorrectly to record relative velocity.
The given parameters:
Speed of the driver observed by the stationary police officer, Vo = 44.7 m/sSpeed of the driver, V = 26.8 m/s.Speed limit = 60 mphThe speed limit of the driver in meter per second is calculated as follows;
[tex]= 60 \ \times \frac{miles}{hour} \times \frac{1609.34 \ m}{1 \ mile} \times \frac{1 \ hr}{3600 \ s}\\\\= 26.82 \ m/s[/tex]
From the speed limit, it is obvious that the driver's speed is within the limit. Thus, we can conclude that the driver is telling the truth, the radar gun must have been set incorrectly to record relative velocity.
Learn more about relative velocity here: https://brainly.com/question/17228388
The engine of a 2400 kg car applies a force of 740 N to make the car accelerate. Calculate the
acceleration of the car.
Answer:
0.31 m/s²Explanation:
The acceleration of an object given only it's mass and the force acting on it can be found by using the formula
[tex]a = \frac{f}{m} \\ [/tex]
f is the force
m is the mass in kg
From the question
m = 2400 kg
f = 740 N
We have
[tex]a = \frac{740}{2400} = \frac{74}{240} \\ = 0.308333...[/tex]
We have the final answer as
0.31 m/s²Hope this helps you
What event will produce the greatest increase in the gravitational force between the two masses?
Question 5 options:
Doubling the distance between the masses
Reducing the small mass by half
Doubling the large mass
Reducing the distance between the masses by half
Answer:
Doubling the large mass
Explanation:
Doubling the destance bewteen the masses will simply make the gravitational force weaker
same with every answer exce
Event will produce the greatest increase in the gravitational force between the two masses is Doubling the large mass.
What is force?
A force is an effect that can alter an object's motion according to physics. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.
Gravitational force is directly proportional to product of mass and inversely proportional to product of distance between them. So, on increasing heaver mass greatest increase in the gravitational force.
Event will produce the greatest increase in the gravitational force between the two masses is Doubling the large mass.
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The velocity of an ocean wave is 5m/s. The distance between crests is 3m. What is the frequency of the wave
I need the Formula,Known,Substitute & Solve Answer with Units
Answer:
1.67m
5m/s
Explanation:
Wavelength of the wave = 3m
Speed of the wave = 5m/s
The distance between crest and the adjacent trough of water waves is known as the wavelength of a wave.
To find the frequency ;
V = f∧
V is the speed of the wave
f is the frequency
∧ is the wavelength
Insert the parameters and find the frequency;
f = V/ ∧ = 5 / 3 = 1.67Hz
The rate at which the wave passed a given point is the speed of the wave and it is 5m/s
A 0.5 kg rock is thrown straight downward off a cliff. If the rock only experience a gravitation force for 4.3 seconds, and ends with a downward velocity of 46.1 m/s, what was rock initial velocity? What is the gravitational force?
Answer:Answer:
See diagram for answers. The force and acceleration vectors are directed inwards towards the center of the circle and the velocity vector is directed tangent to the circle.
Explanation:
what is the most likely reason for the difference between how the compass works on earth and on the moon?
Answer: A compass taken to Earth's moon does not point in a specific direction on the moon. The moon does not have a strong magnetic field.
Record your observations. Include the data table you created for the lab and a graph based on the data table. Type your answer here:
To create a graph of the data you collected during the lab, first, organize the data, then select the best type of graph, and finally create the graph.
One of the steps you need to complete after an experiment is to graph your results. This implies organizing the data and creating a diagram to visually represent your findings.
These are the steps you can follow to complete this task:
Organize the data: The first thing you need to do is to understand what were the main factors for example if your experiment measured temperature changes this is the main factor you need to consider. Then try to organize this data in a chart so you can visualize it.Select the type of graph: There are different types of graphs such as:Bar graph.Pie chart.Scatter plot.Among others.Each of these graphs focuses on specific types of data, and therefore you need to select the one that best fits the data you collected.
Create the graph: Finally, you can create the graph to do this, there are programs like excel that help you create the graph only by entering the data.Learn more about graphs in: https://brainly.com/question/16192791
why efficiency of energy converters is less than 100%
The output work is always less than the input work because some of the input work is used to overcome friction.
The following data were collected during a short race between two friends. Velocity (m/s) 0 0.5 1 1.5 2 2 4 6 2 0 Time (s) 0 2 4 6 8 10 12 14 16 18 a) Describe the different sections of the graph. b) Determine the acceleration over the first eight seconds. c) Determine the maximum acceleration. d) Using the graph calculate the displacement: i) over the first eight seconds ii) the total race. e) Find the maximum velocity reached by the runner.
The characteristics of the kinematics allow to find the results for the questions about the movement of the body are:
a) we have four sections;
0 to 8 s The body is accelerating. 8 to 10 s The body goes at a constant speed, the acceleration is zero. 10 to 14 Body accelerating. 14 to 18 Body slowing down.b) The acceleration is the first 8 s is: a = 0.25 m / s²
c) The maximum acceleration is: a = 1 m / s²
d) The displacement is: i) d₁ = 8m, ii) [tex]d_{total}[/tex]= 16 m
e) maximum speed is: v = 6 m / s
Kinematics studies the movement of bodies by finding relationships between the position, speed and acceleration of bodies.
v = v₀ + a t
y = v₀ t + ½ a t²
where v and v₀ is the current and initial velocity, respectively, a is the acceleration and t is time.
In many circumstances graphs are made for their analysis, in a graph of speed versus time when we have a horizontal line the speed is constant, the acceleration is zero and in the case of a slope there is an acceleration, we have two cases:
Positive slope the body is accelerating and the speed is increasing. Negative slope the body is stopping, the speed decreases.
Let's answer the different questions about the system.
a) in the attached we have a graph of the velocity versus time, each section corresponds to a change in the slope of the graph, we have four sections;
0 to 8 s The body is accelerating. 8 to 10 s The body goes at a constant speed, the acceleration is zero. 10 to 14 Body accelerating. 14 to 18 Body slowing down.
b) The acceleration is the first 8 s
v = v₀ + a t
[tex]a = \frac{v-v_o}{\Delta t}[/tex]
[tex]a = \frac{2-0}{8-0}[/tex]
a = 0.25 m / s²
c) The maximum acceleration is when the slope is maximum.
[tex]a = \frac{6-2}{ 14-10}[/tex]
a = 1 m / s²
Therefore the acceleration is maximum in the section between 10 and 14 s
d) The total displacement is the sum of the displacements of each section.
[tex]d_{total } = d_1 +d_2 + d_3 +d_4[/tex]
We look for every displacement.
d₁ = v₀ + ½ a₁ Δt²
d₁ = 0 + ½ 0.25 8²
d₁ = 8 m
In the second section the velocity is constant
d₂ = v₂ Δt₂
d₂ = 2 (10-8)
d₂ = 4 m
The third section.
d₃ = v₀ + ½ a t²
d₃ = 2 + ½ 1 (14-10) ²
d₃ = 10 m
The distance of the fourth section.
we look for acceleration
a₄ = [tex]\frac{v-v_o}{\Delta t}[/tex]
a₄ = [tex]\frac{0-6}{18-14}[/tex]
a₄ = -1.5 m / s²
d₄ = 6 + ½ (-1.5) (1814) ²
d₄ = -6 m
The total displacement is;
[tex]d_{total}[/tex] = 8 + 4 + 10 -6
[tex]d_{total}[/tex] = 16 m
e) The maximum speed is the highest point in the graph of speed versus time that in the attachment we can see corresponds to
v = 6 m / s
In conclusion using the characteristics of kinematics we can find the results for the questions about the motion of bodies are:
a) we have four sections;
0 to 8 s The body is accelerating. 8 to 10 s The body goes at a constant speed, the acceleration is zero. 10 to 14 Body accelerating. 14 to 18 Body slowing down.b) The acceleration is the first 8 s is: a = 0.25 m / s²
c) The maximum acceleration is: a = 1 m / s²
d) The displacement is: i) d₁ = 8m, ii) [tex]d_{total}[/tex]= 16 m
e) maximum speed is: v = 6 m / s
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At which point does a substance have the greatest amount of kinetic energy
why is acceleration not constant near the speed of light
Answer:
because when an object approaches the speed of light, it's mass starts to increase exponentially, and would be infinite at the speed of light. It would therefore require MORE than an infinite amount of energy to accelerate even a single electron to the speed of light
2. A nutty professor leaves a history classroom and walks 10. meters north to a drinking fountain. Then, in a daze, she turns and walks 30. meters south to an art classroom. (draw vectors to scale to show your work)
(a) What is the professor’s total displacement from the classroom to the art classroom?
(b) What was the total distance she traveled?
Total displacement:-
[tex]\\ \sf\Rrightarrow 10-30=20m[/tex]
Total distance
[tex]\\ \sf\Rrightarrow 10+30=40m[/tex]
Chapter name :- Physical Optics
Question :-
When two waves of magnitude I and 4I overlap, the maximum and minimum light intensity will be-
a) 9I, 3I
b) 3I,I
c) 9I, I
d) 5I, 3I
Guys I need the correct answer in details!
✖️❌Please No links, No rubbish answer! Otherwise, I'll report your answer!
Answer:
Hey There!
Refer to the attachment...
or in this way also you can solve shown in second attachment
I hope it is helpful to you...Cheers!_________anyone to help with this question
Answer:
i can
Explanation:
i know what's the answer
a body of mass 10 kg is moving with velocity of 10ms-1.a force acts for 5 seconds to reduce its velocity to 2ms-1.find the momentum of the body before and after application of the force on it
Answer:
momentum before: 100kgm/s
momentum after: 20kgm/s
Explanation:
initial velocity: 10
final velocity: 2
p=mv
before: 10kg×10m/s
after:10kg×2m/s
I'm not 100% sure btw
An automobile with a mass of 1250 kg accelerates at a rate of 4 m/sec2 in the forward direction. What is the net force acting on the automobile?
[tex]\large{\underline{\underline{\maltese{\pink{\pmb{\sf{ \; Question \; :- }}}}}}}[/tex]
An automobile with a mass of 1250 kg accelerates at a rate of 4 m/sec² in the forward direction. What is the net force acting on the automobile?
_________________________________________
[tex]\large{\underline{\underline{\maltese{\green{\pmb{\sf{ \; Given\; :- }}}}}}}[/tex]
➢ Mass of the automobile = 1250 kg➢ Acceleration of the body = 4m/sec²_________________________________________
[tex]\large{\underline{\underline{\maltese{\orange{\pmb{\sf{ \; To \: Find \; :- }}}}}}}[/tex]
Net force acting on the automobile = ?_________________________________________
[tex]\large{\underline{\underline{ \bigstar{{\pmb{\sf{ \; Concept \: and \: Formula \: Used \; :- }}}}}}}[/tex]
➯ Force is defined as the product of the mass of the body and its acceleration.
[tex] \bigstar \: \small{ \fbox {\textsf {\textbf{F = ma}}}}[/tex]
Where :
F = Force m = Mass of the bodya = acceleration due to gravity[tex]\large{\underline{\underline{ \bigstar{{\pmb{\sf{ \; Substituting \: the\: Given\: Values :- }}}}}}}[/tex]
[tex]⇝ \: \: \small \textsf {\textbf{ F = (1250 × 4) N }}[/tex]
[tex]⇝ \: \: \small \textsf {\textbf{ F = 5000 N }}[/tex]
[tex]\large{\underline{\underline{ \bigstar{{\pmb{\sf{ \; Therefore \; :- }}}}}}}[/tex]
❝ The net force acting on the automobile is 5000 N. ❞
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Help it multiple-choice 16 and 17 only
Answer:
16. c
17. d
Explanation:
16. Newton’s third law states that a force will always have an opposite but equal force as a reaction, so every force comes as a pair of action-reaction forces. For example, if you push on a book, the book also pushes on you.
17. If 1cm represents 15N, then 5cm must represent 15N*5=75N.
4. In not less than 150 words, write your substantial insights on what you have learned in the past modules in relevance to what is happening now.
Answer:
“I think it’s about putting yourself in the students’ shoes and seeing how a first-time student, maybe someone who hasn’t even taken chemistry before, is looking at it.”
—Valerie Taraborelli, undergraduate chemistry student, University of Arizona1
“In some ways, I think the people who are the most successful as teachers are the ones who are able to remember what it was like being uncertain and not knowing. When you become an expert, things are easy. So the idea is to try and see where [students] are coming from and why they’ve developed this misconception and what you can do to specifically address it.”
—Dee Silverthorn, biology professor, University of Texas2
Hope this helps !!The average distance between the Earth and the Moon is 384,000,000 meters. What is the distance in kilometers?
Answer:
384000
Explanation:
it would be 384000 in km
the maximum displacement of a particle by a wave is called
what does the geocentric model of the solar system look like