A force of 400N acts on a body for time 10ms impulse will be

Answer:

you cant really give any answers because i cant tell u were to drag

Answer:

f

Explanation:

f = μk.N (N = m.g)

f = 0.29 x 95 x 10

f = 275.5 N

Answer:

Refraction

Explanation:

When light passes from a rarer medium into a denser medium, it bends in the medium away from the normal. This creates the phenomenon of "apparent depth" as given in the question.

If you wanted the laser to refract less as it exits the prism, you should increase the wavelength of the light.

Refraction can be defined as a phenomenon which describes a change (bend) in the path taken by light when it's at surfaces between different transparent materials.

According to the model of light wave, the refraction of light is inversely proportional to its wave. Thus, you should increase the wavelength of light, if you want the laser to refract less as it exits the prism.

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Explanation:

Acceleration is a vector quantity which is defined as the rate at which an object changes its velocity

The distance traveled by the object in the first 1 second is determined as 0.98 m.

The distance traveled by the object is calculated as follows;

F - μkmgcosθ = ma

0 - μkmgcosθ = ma

- μkgcosθ = a

-(0.4)(9.8)cos60 = a

- 1.96 m/s² = a

s = ut + ¹/₂at²

s = 0(1) + ¹/₂(-1.96)(1)²

s = -0.98 m

|s| = 0.98 m

Thus, the distance traveled by the object in the first 1 second is determined as 0.98 m.

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Answer:

9.8 m / s^2

Explanation:

Assuming free fall====> there is no initial downward/upward velocity

  Assuming metric units   78.4  m/s

 vf = a t

 78.4 = a (8)     shows     a = 9.8 m/s^2

Answer:

I think this

One bulb burning out in a series circuit breaks the circuit. In parallel circuits, each light has its own circuit, so all but one light could be burned out, and the last one will still function.

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Answer:

The specific heat capacity is defined as the quantity of heat (J) absorbed per unit mass (kg) of the material when its temperature increases 1 K (or 1 °C), and its units are J/(kg K) or J/(kg °C).

Explanation:

identified by one of the Chi Omega survivors as the assailant, and hair and fiber evidence tied him to the Leach murder. His trial for the Florida attacks in June 1979 was the first-ever nationally televised trial in the United States.

When an object is thrown at an angle from the horizontal, the path followed by the body is called the projectile motion. The duration in seconds that the object is above the height of 14 m is 4.698 s.

Speed is the time rate at which velocity is changing.

Vertical speed component is

V₀y = 52sin 30°= 26 m/s

Given is the height h=14m

Using second equation of motion,

S=ut+ 1/2 at²

Substituting the values, we get

14 = 26t - 4.9t²

4.9t² - 26t +14 =0  

Solving the quadratic equation, we get the time as

taking the positive sign, t =4.698 s

taking the negative sign , t = 0.6082 s

Thus, the duration in seconds that the object is above the height of 14 m is 4.698s.

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Answer:

Gotta be it

Explanation:

m1*v1 = m2*v2

1200*v1 = 1600*3

1200*v1  = 4800

v1 = 4800 / 1200

v1 = 4.0 m/s

Answer:

After some time on the counter, ripe bananas will develop a brown peel. Bananas contain the enzyme polyphenol oxidase, and when the enzyme interacts with oxygen, it causes a chemical reaction. This chemical reaction, known as enzymatic browning, changes the banana's peel and fruit to brown

Explanation:

Answer:

Mag isip ka po wag Kang tanong ng tanong kac kami po Yung nahihirapan mag hanap ng answer

Answer:

i dont know

Explanation:

sorry i cant answer this question

Answer:

√ ae/ ap = √ mp/me 1/2

Explanation:

Mass of the electron = M (Given)

Mass of the proton = M (Given)

Time = t (Given)

But acceleration of electron, ae =FE/me whereas

acceleration of proton, ap = FE/mp

S = 1/2at²1 = 1/2apt²2

t2/t1= √ ae/ ap

t2/t1= √ ae/ ap = √ mp/me 1/2

Answer:

Correct option is D) …

Explanation:

For electron t1​ (small 1) = [tex]\sqrt{ \frac{2S}{ae}[/tex] (small e)

For protion, t2 (small 2) = [tex]\sqrt \frac{2S}{ap}[/tex] (small p)

or [tex]\frac{t2}{t1}[/tex] = [tex]\sqrt\frac{ae}{ap}[/tex] = [tex]\sqrt\frac{eE}{me} *\frac{mp}{eE}[/tex]

= [tex]\sqrt\frac{mp}{me}[/tex]

I’m gonna say everything that needs to go down as an exponent but down for example H20 but the 2 is small, also in order from top to bottom to fraction to fraction (small 2, 1, e, p, e, p, (after equal sign) p, e).

Hope this helped and brainliest pls

Answer:

5941m/s

Explanation:

velocity equals frequency x lamdha

Answer:

Explanation:

Focal length of diverging lens,

fd= -33.5 cm

focal length of converging lens,

fc = 20 cm

Now let s is object distance and s' is image distance.

Now using lens formula for conversing lens

\frac1{f_c}=\frac1{s}+\frac1{s'}

f

c

​

1

​

=

s

1

​

+

s

′

1

​

Putting all values(object is at s=infinity)

Then image distance

\frac1{s'}= \frac1{f_c}- \frac1{s}

s

′

1

​

=

f

c

​

1

​

−

s

1

​

=\frac1{20}- \frac1{\infin}=

20

1

​

−

∞

1

​

s'=20cms

′

=20cm

Now using lens formula for diversing lens

s''=14-20=-6cm

Using lens formula

\frac{1}{-33.5} = \frac{1}{-6 }+ \frac{1}{s''' }\\s'''=\frac{(6)\times(-33.5)}{(-33.5+6)}\\s'''=\frac{(-201) }{(-27.5) }

−33.5

1

​

=

−6

1

​

+

s

′′′

1

​

s

′′′

=

(−33.5+6)

(6)×(−33.5)

​

s

′′′

=

(−27.5)

(−201)

​

image distance for diverging lens

s''' = 7.3 cm (behind the diverging lens)

A diverging lens with f = -33.5 cm is placed 14 cm behind converging lens with f = 20cm. image distance for diverging lens, s''' = 7.3 cm (behind the diverging lens)

When a lens in the path of a beam of parallel rays causes the rays to diverge after refraction, it is referred to as a diverging lens.

It always creates a virtual image and has a thinner core than its boundaries.

Concave lenses(diverging lenses) function as diverging lenses because they cause light rays to diverge as they pass through them.

Therefore, when used with air as the operating medium, a concave lens can be thought of as a diverging lens.

The concave lens has several applications, including in telescopes, cameras, lasers, glasses, binoculars, and other optical devices.

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If the current is held constant, an increase in voltage will result in an increase in resistance.

hope it helps...!!!

8.3×10 to the power minus 7

Explanation:

lambda equals velocity over frequency.

Let's look at Newton's second law

Force is directly proportional towards mass

If mass is more force will be more.

Between baseball and bowling ball Bowling ball has higher mass

So it would expert most force

Option D

Answer:

Spring High Tide

When the moon is full or new, the gravitational pull of the moon and sun are combined. At these times, the high tides are very high and the low tides are very low.

A projectile is shot with the initial speed, it follows the motion called projectile motion. The height of the cliff is 44.91 m.

The speed at the start of the motion is the initial speed.

The horizontal distance is

x = v₀ sin θ. t

Substitute 26.5 for θ, 24 for x and 8.94 m/s for x, we get the time taken to complete the journey.

t = 24/ (8.94 cos26.5) = 3 s

Maximum height reached

H = v₀²sin²θ/2g

H = (8.94)² x sin²( 26.5) /(2 x 9.8)

H =0.8118 m

The height of the cliff is obtained by the equation of motion

0.8118 - h = -1/2 gt² +v₀sinθ.t

Substitute the values, we get

h =0.8118 +1/2x9.8x (3)²

h =44.911m

Thus, the height of the cliff is 44.91 m.

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Answer:

the speed of light in air is about 299,000,000 and 3×10⁸ m/s

Given the the current flowing in the circuit and the elapsed time, the charge that passes through the LED is 1260 Coulombs.

Current is simply the rate of flow of charged particles i.e electrons caused by EMF or voltage.

If a charge passes through the cross-section of a conductor in a given time, the current I is expressed as;

I = Q/t

Where Q is the charge and t is time elapsed.

Given the data in the question;

We substitute our given values into the expression above to determine the charge.

I = Q/t

Q = I × t

Q = 0.35A × 3600s

Q = 1260C

Therefore,  given the the current flowing in the circuit and the elapsed time, the charge that passes through the LED is 1260 Coulombs.

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The material will go as high as 91.54 km would this material go on earth if it were ejected with the same speed as on Io.

The height of the material on earth will be derived from the given values as follows:

Tue acceleration due to gravity on Io, go is given as:

[tex]g_o = \frac{GM}{r^{2}}[/tex]

Substituting the values:

[tex]g_o= \frac{6.67×10^{-11}×8.93×10^{22}}{1821000^{2}}[/tex]

[tex]g_o = 1.796 m/s^{2}[/tex]

Height on earth, He and Height on Jupiter H is given as follows:

[tex]H_e = \frac{v^{2}}{2g}[/tex]

[tex]H = \frac{v^{2}}{2g_o}[/tex]

Taking ratio of the two heights and solving for height on earth, He:

[tex]H_e = H × \frac{g_o}{g}[/tex]

Substituting the values:

[tex]H_e = 500000 × \frac{1.796}{9.81} = 91539.245 m[/tex]

Therefore, the material will go as high as 91.54 km would this material go on earth if it were ejected with the same speed as on Io.

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