a gas with a volume of 20.0l at a pressure of 275 kpa is allowed to expand to a volume of 35.0l. what is the pressure in the container if the temperature remains constant?

1. 2.54 kPa

2. 157 kPa

3. 481 kPa

pls help ;(

Answers

Answer 1

Answer:

[tex]\boxed {\boxed {\sf 2. \ 157 \ kPa}}[/tex]

Explanation:

Since temperature remains constant, the only variables that change are volume and pressure. Therefore, we are using Boyle's Law. This states that the pressure is inversely proportional to the volume. The formula is:

[tex]P_1V_1=P_2V_2[/tex]

We know the gas starts with a volume of 20.0 liters at a pressure of 275 kPa. We can substitute these values into the left side of the formula.

[tex]275 \ kPa *20.0 \ L=P_2V_2[/tex]

We know the gas expands to a volume of 35.0 Liters, but we do not know the pressure.

[tex]275 \ kPa *20.0 \ L=P_2* 35.0 \ L[/tex]

Since we are solving for the new pressure, we must isolate the variable P₂. It is being multiplied by 35.0 Liters and the inverse of multiplication is division. Divide both sides by 35.0 L.

[tex]\frac {275 \ kPa * 20.0 \ L}{ 35.0 \ L}= \frac{P_2*35.0 \ L}{35.0 \ L}[/tex]

[tex]\frac {275 \ kPa * 20.0 \ L}{ 35.0 \ L}=P_2[/tex]

The units of liters cancel.

[tex]\frac {275 \ kPa * 20.0 }{ 35.0 }=P_2[/tex]

[tex]\frac {5500}{35.0} \ kPa= P_2[/tex]

[tex]157.142857 \ kPa=P_2[/tex]

The original measurements of pressure and volume have 3 significant figures, so our answer must have the same. For the number we calculated, that is the ones place.

The 1 in the tenths place (157.142857) tells us to leave the 7 in the ones place.

[tex]157 \ kPa= P_2[/tex]

If the gas expanded to a volume of 35.0 liters while the temperature remained constant, the pressure in container was approximately 157 kilopascals.


Related Questions

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Explain How you know.

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Both weigh in the same but the feathers has more pieces in it

Answer:

They equal the same

Explanation:

Because A ton of feathers and A ton of bricks. They both equal A ton.

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ig The right answer is -Give the reaction more time.

I'll give brainless! no l!nks!!!

1. Imagine a very warm 60 degree day in January with a steady rain. What type of air mass would you expect to be bringing in this weather pattern?

2. Imagine a very cold 20 degree day in January with lots of blue sunny skies. What type of air mass would you expect to be bringing in this weather pattern?

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Answer:

Maritime tropical air mass

Continental polar air mass

Which of the following best describes asexual reproduction?

it produces offspring with a large amount of genetic variation

it occurs in simple organisms, such as bacteria, but not in multicellular organism such as plants and animals

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it can be an advantage to organisms that live in a stable unchanging environment

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Answer:

First Choice

it produces offspring with a large amount of genetic variation

Answer: i think this is correct.

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Why might metamorphic rocks show signs of blending and distortion?

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Answer:

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Which emission causes the atomic number of a nuclide to decrease by 2 and its mass number to
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2.
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3.
gamma radiation
4.
a positron

Answers

An alpha particle emission causes the atomic number of a nuclide to decrease by 2 and its mass number to decrease by 4.

What is nuclear emission?

Nuclear Emission explains the release of energy stored in the nucleus of an atom in the form of particles like alpha particles, beta particles, gamma ray etc.

When a nucleus emits an alpha particle, it loses 2 protons and 2 neutrons, so its atomic number decreases by 2 and its mass number decreases by 4.

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How many grams of magnesium are in sample containing 9.12+ 10 ^23atoms

Answers

Answer: There are 1.51 moles present in [tex]9.12 \times 10^{23}[/tex] atoms.

Explanation:

According to the mole concept, there are [tex]6.022 \times 10^{23}[/tex] atoms present in one mole of every substance.

Hence, moles present in [tex]9.12 \times 10^{23}[/tex] atoms are calculated as follows.

[tex]Moles = \frac{9.12 \times 10^{23}}{6.022 \times 10^{23}}\\= 1.51 mol[/tex]

Thus, we can conclude that there are 1.51 moles present in [tex]9.12 \times 10^{23}[/tex] atoms.

significant figures to 2.3 x 4.50

Answers

Answer:

10.35= 4 sig figs but change it to 2 since it's 2.3 is the lowest number

10.

hope this helps

have a good day :)

Explanation:

I am one percent away from failing. I just need help. No false answers
How many grams of Al(OH)3 are produced from 3.00 g of AlCl3 with excess of NaOH?

Answers

Answer:

I did it in steps in the picture I just hope it helps you to understand:)

Which pair of formulas represents the empirical formula and the molecular formula of a compound?

Answers

Answer:

CH2O and C6H12O6

Explanation:

To find an empirical formula, take a molecular formula and divide the subscript of each element by the greatest common factor of all the subscripts. In this case, the only pair that works is CH2O,C6H12O6, which can be verified by dividing the coefficients of the molecular formula by 6.

Which oxide is covalent?
A. AsO2 B. K2O
C. CuO D. ZnO

Answers

Answer:

A.

Cu Zn K is are metals which form ionic bond with oxygen

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Answers

Answer:

2H2 in products

Explanation:

she should have added another 2 in H2

The edited equation does not balance the number of hydrogens. The correct balanced equation for the given reaction is written as follows:

[tex]\rm 2H_{2}O \rightarrow 2H_{2} +O_{2}[/tex].

What is balanced chemical equation?

The balanced chemical equation of a reaction represents the perfect stochiometric coefficients of all the reactants and products. Thus, each elements in the reaction have to be equal in both side.

According the mass conservation law, the total mass of the reactants is equal to the total mass of the products. Thus, all elements have to balanced on each side.

When water dissociates into hydrogen and oxygen molecules, 2moles of water undergoes dissociation to give two moles of H2 and one mole of O2. Thus the balanced equation is:

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Anthony needs to make a solution with a concentration of 2.5m. He begins with 2.0 iters and a 8.0M solution. What final volume does he need. Tally and solve.

Answers

Answer:

The final volume is 6.4 L.

Explanation:

Dilution is reducing the concentration of a chemical and is achieved by adding more solvent to the same amount of solute. In other words, dilution is the procedure that is followed to prepare a less concentrated solution from a more concentrated one, and it simply consists of adding more solvent.

In a dilution the amount of solute does not vary, and as only more volume (and mass) of solvent is being added, the concentration of the solute decreases.

In a dilution the expression is used:

Ci*Vi = Cf*Vf

where:

Ci: initial concentration Vi: initial volume Cf: final concentration Vf: final volume

In this case:

Ci: 8 M Vi: 2 L Cf: 2.5 M Vf: ?

Replacing:

8 M* 2 L= 2.5 M* Vf

Solving:

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The final volume is 6.4 L.

ANSWER THIS QUESTION FOR 29 POINTS
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I NEED HELP HELP ASAP

Answers

Answer:

Explanation:

cells process rna and trna

converting food into energy

the regrowth of cells that have died through out the day

the transcription of dna to rna

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Help? s/o to itsdevilsj754

Answers

Explanation:

A geological process where materials of Earth are transported from one place to another by natural forces like wind or water is called erosion.

When materials of Earth are deposited over a certain landmark due to transportation by natural forces then this process is called deposition.

The four major causes of erosion and deposition are as follows.

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Answers

Complete question:

ΔU for a van der Waals gas increases by 475 J in an expansion process, and the magnitude of w is 93.0 J. calculate the magnitude of q for the process.

Answer:

The magnitude of q for the process 568 J.

Explanation:

Given;

change in internal energy of the gas, ΔU = 475 J

work done by the gas, w = 93 J

heat added to the system, = q

During gas expansion process, heat is added to the gas.

Apply the first law of thermodynamic to determine the magnitude of heat added to the gas.

ΔU = q - w

q = ΔU +  w

q = 475 J  +  93 J

q = 568 J

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Is all the biomass consumed by a primary consumer, such as a brine shrimp, transferred to the secondary consumer, such as a gull, when the brine shrimp is eaten? For instance, if a brine shrimp eats 10 g of algae in its life before the gull eats it, does the gull get 10 g of biomass when it eats the brine shrimp? Why or why not?​

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Okkkkkkjjjjkdnhehdydyegevevevbenrjrjrjduueuegeveveve

Calculate the amount, in mol, of sodium atoms represented by 1.0x10(to the power of 20) sodium atoms

Answers

Explanation:

moles= number of particle or atom / 6.02×10^23

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Answer:

1.7 * 10^-4 moles

Explanation:

According to Avogadro, one mole of a substance contains 6.02 * 10^23 number of atoms, molecules, ions etc.

Hence;

1 mole of Na contains 6.02 * 10^23 atoms

x moles of Na contains  1.0x10^20 atoms

x = 1.0x10^20 * 1/6.02 * 10^23

x = 1.7 * 10^-4 moles

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Answers

Answer: Electrolysis

Explanation: ‍♀️

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Answers

Answer:

molar mass (molar weight)

Explanation:

How can the coefficients in a balanced chemical reaction be used to convert from moles of a reactant to moles of a product?

Answers

The coefficients in a balanced equation can be used as molar ratios, which can act as conversion factors to relate the reactants to the products. These conversion factors state the ratio of reactants that react but do not tell exactly how much of each substance is actually involved in the reaction.

please help asap i will mark you as brainly and give u 10 points ( don’t mind the answer i accidentally clicked )

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Answers

Answer:

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Explanation:

If I have 1.9 moles of gas held at a pressure of 5 atm and in a container with a volume of 100 liters, what is the temperature of the gas? 3205K

Answers

Answer:

T = 3206.89 K

Explanation:

Given that,

Number of moles, n = 1.9 moles

Pressure, P = 5 atm

Volume, V = 100 L

We need to find the temperature of the gas. Let the temperature is T. We know that,

PV = nRT

Where

R is gas constant, R = 0.08206 L-atm/mol-K

Put all the values,

[tex]T=\dfrac{PV}{nR}\\\\T=\dfrac{5\times 100}{1.9\times 0.08206 }\\\\T=3206.89\ K[/tex]

So, the temperature of the gas is 3206.89 K.

All of the following elements are metals EXCEPT?
A. Br B. Co C. Cu D. Zn

Answers

Answer:

Br

Explanation:

08.04 MC) An unknown solution has a pH of 7.2. Which of these chemicals is likely to cause the greatest decrease in the pH of the solution when added to the solution? (5 points) a HF b KOH c NH3 d HNO3

Answers

Answer:

HNO3

Explanation:

i have the test

The correct answer that will decrease the PH is ( HNO3)

Since the unknown solution is containing a pH of 7.2, it means it is more basic not acidic, then to make it have  decrease in PH, then acidic substance needs to be added to it so as to reduce the PH from 7.2

KOH : potassium hydroxide is a base, if it is added to the substance, it will increase in PH value

NH3 : Ammonia is a base, if it is added to the substance, it will increase in PH value

HNO3 : Trioxonitrate (v) acid is an acid , adding it to the substance will make the PH to be acidic hence decrease in PH

When a substance  is neither acidic nor basic it can be regarded as   neutral.

The pH scale gives the measurements of  how acidic or basic a particular substance is.

The pH scale can be given in the  ranges starting from 0 to 14.

A pH of 7 is  considered neutral.

Therefore, decrease in PH can be achieved by adding acidic substance.

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which statement is an example of diffusion
Answer
(A) A kitchen towel soaks up some split milk
(B) ice cream melts in a warm room
(C) pollen from flowers is blown by the wind
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Answers

D is the answer I think

Answer:

(C) pollen from flowers is blown by the wind.

I think this is the correct answer friend

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Answers

Answer:

It is a halogen element

Explanation:

hope this helps

have a great day/night

How many liters are 1.20 g of oxygen?

Answers

Answer:

The required volume is 0.84 L

Explanation:

Given,

Mass of O2 gas = 1.20 g

We know,

At STP, molar volume of all gases is 22.4 L

and Molar mass of O2 gas is 32 g

Now,

Number of moles = mass/molar mass

                              = 1.20/32

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Again,

At STP,

Number of moles = Volume/Molar volume

or, Volume = Number of moles X Molar Volume

or Volume = 0.0375 X 22.4

∴ Volume = 0.84 L

So, the required volume is 0.84 L

pls help me guys please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please​

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5) B

6) C

7) B newland, law of octaves

8) A)

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