Long ramp would be the net static friction acting on her if the ramp has a total weight of 40 kg is F = 6.77 N.
What is the force's overall net force?The effects (the sum) of any and all pulling and pushing forces that are actually acting on an object is known as the net force. An item will speed up in the net force if the pushing and pulling forces acting on it are not equal (a net force acts).
Calculation -:E(f) - E(i) = -F(k)d
E(f) = mgy(f) = 1/2×mv²(f)
E(i) = mgy(i) + 1/2×mv²(i)
F(k) = [E(f)- E(i)]/-d
= {mgy(s) + 1/2mv²(f) - (mgy(i) + 1/2mv²(i))}/-d
F(k) = {(40)(9.8)(14.2)(sin[tex]20^{o}[/tex]) +0-(0+1/2(40)([tex]10^{2}[/tex])}/-14.2
F(k) = 6.77 N
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How do you find the velocity of an object rolling down a ramp?
The object accelerates at a constant rate as it moves down the slope because of the constant gravitational force acting on it in a major portion and the rolling tangential force on the object is acting in the smaller form.
Rolling motion of any object occurs when the object starts sliding in a different methods from the other objects such as when the objects starts to roll from the ramp or any other sloppy surface and it rolls down due to the gravitational force and with many other forces such as the rolling tangential force. many forces are acting on the object at the same moment and we are just seeing the gravitational force which is playing a major portion. Hence by this information we can consider that the ball accelerates at a constant rate as it moves down the slope because of the constant gravitational force acting on it in a major portion and the rolling tangential force on the object is acting in the smaller form.
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You are on an airplane traveling with a constant velocity at an altitude of 20,000 m. What is the acceleration of gravity at that altitude
Correct option is C) the acceleration of gravity at that altitude is 9.75m/s².
What is the gravity's acceleration?
The unit g stands for gravitational acceleration. At sea level, the standard value of g on earth's surface is 9.8 m/s2.
The following formula is used to determine the acceleration of gravity:
g= GM/r2
What G The general gravitational constant is what it is.
G is equal to 6.674x10⁻¹¹ Nm2/kg2, and M is the earth's mass:
M = 5.972x10²⁴kg
The radius of the earth plus the airplane's altitude, or r, is the distance from the earth's center in this case:
r = 6.37x10⁶ m + 20000 m equals 6.39x10⁶ m
Consequently, the acceleration in g is equal to:
(6.674x10⁻¹¹ Nm²/kg²)(5.972x10²⁴ kg) / (6.39x100m)₂
g = 9.75m/s²
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Complete Question -
You are on an airplane traveling with a constant velocity at an altitude of 20,000m. What is the acceleration of gravity at that altitude? The earth's radius is 6.37 x 10^6m.. . A) 9.81 m/s^2. B) 9.78 m/s^2. C) 9.75 m/s^2. D) 9.72 m/s^2. E) 9.69 m/s^2.
a large platform is initially at rest on a smooth surface. A dog on the platform starts running toward the east. The mass of the dog is one-half the mass of the platform. When the dog moves toward the east with a speed of v0, the platform moves toward the ____ with a speed _____.
Platform moves towards to west with a speed of v0/2 when the dog moves towards to east at a speed of v0, in accordance with the rule of conservation of momentum.
What is the straightforward meaning of speed?The speed at which an object's location changes in any direction. The distance travelled to the time needed to travel that distance is known as speed. Since speed only has a magnitude and no direction, it is a scalar quantity.
Is speed affected by acceleration?Acceleration is the method of changing a speed with which an object moves. If a substance's velocity does not change, it is not accelerating. Acceleration is a vector quantity.
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Three point charges are arranged at the corners of a square of side L as shown in (Figure 1) What is the potential at the fourth corner (point A)? Express your answer in terms of the variables Q, L, and the Coulomb’s constant k.
The potential at the fourth point will be [tex]\frac{k^3Q}{\sqrt{L}}[/tex]
Let q1= -2Q and q2 = 6Q. ( k.)
What does charge number three's value, q3, equal?
To remedy the issue, the charges' orientation is also necessary.
You might try using the formula (kQ/r) to get the potential at the fourth corner.
Electric potential is a scalor, therefore adding the values from the three sites is as simple as adding them all together.
The effort required to transfer a unit charge against an electric field from a reference point to a specified spot. Earth is typically chosen as the reference point, however, any location beyond the range of the electric field charge can be utilized. potential electricity.
for instance, q1=-Q, L from the 4th point
q2=3Q and the fourth point's root is L.
The solution to q3= Q L from the fourth point is just [tex]-\frac{kQ}{L} + \frac{k^3Q}{\sqrt{L}} +\frac{kQ}{L} = \frac{k^3Q}{\sqrt{L}}[/tex] (at the fourth point)
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The missing diagram is attached below:
Suppose a molecule has neutrons, a Coulomb total electric charge, and electrons. About how many protons must it have
molecule possesses neutrons and a total electric charge of one Coulomb. e is the electronic value, 1.60 x 10-19 Coulombs, and the proton has a cost of +e while the electron has a fee of -e.
How much is one coulomb?The quantity of charge carried by a present of one amp for one second is measured in coulombs, which is the unit of measurement used in the SI for electric charge. It may also be a quality of a substance that causes magnetic and electric effects to occur. The symbol for it is C. According to math, 1 Coulomb equals 1 Ampere x 1/sec.
A coulomb quizlet: what is it?A coulomb is an unit of power charge that represents the charge that is transmitted over one ampere of current in one second. Colomb's rule. depending on the charged items, electric force.
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A 2.6-mm-diameter sphere is charged to -4.4 nC. An electron fired directly at the sphere from far away comes to within 0.32 mm of the surface of the target before being reflected.
a. What was the electron's initial speed?
b. At what distance from the surface of the sphere is the electron's speed half of its initial value?
c. What is the acceleration of the electron at its turning point?
The correct answer to the given question is -6.944 * 10^-28 Joules
a. To find the electron's initial speed, we can use the conservation of energy. The initial kinetic energy of the electron must equal the final potential energy of the electron at its closest approach to the sphere.
Ki = 1/2 * me * v^2
v = sqrt(2Ki/me)
Ki = qe * V = (1.6 x 10^-19 C) * (-4.4 x 10^-9 C) = -6.944 x 10^-28 J
b. At the point where the speed of the electron is half of its initial value, the kinetic energy of the electron is half of its initial value. Therefore,
Ki/2 = 1/2 * me * (v/2)^2
we can solve for the distance from the surface of the sphere using the same equation as in part a, and substituting Ki/2 and v/2 for Ki and v respectively
c. The acceleration of the electron at its turning point can be found using the equation for centripetal acceleration:
a = v^2/r
where a is the acceleration, v is the speed of the electron, and r is the distance of the electron from the center of the sphere at its closest approach. We can use the value of v from part a and the distance from part b to find the acceleration.
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Suppose that the railcar passes by a horn that is emitting a sound with frequency f. Which of the following describes the frequency f PS-10-1-prime.gif that the person on the railcar hears?
A. f PS-10-1-prime.gif > f before passing the horn, f PS-10-1-prime.gif < f after passing it
B. f PS-10-1-prime.gif < f before passing the horn, f PS-10-1-prime.gif > f after passing it
C. f PS-10-1-prime.gif = f before passing the horn, f PS-10-1-prime.gif = f after passing it
D. f PS-10-1-prime.gif > f before passing the horn, f PS-10-1-prime.gif > f after passing it
F PS-10-1-prime.gif > f before passing the horn, f PS-10-1-prime.gif < f after passing it describes the frequency f PS-10-1-prime.
Hence, Option A is correct.
The Doppler effect causes the frequency heard by the railcar passenger prior to passing the horn to be higher than the real frequency of the sound released, whilst the frequency heard after passing the horn is lower than the actual frequency. This is why the answer to this question is A. A railcar is a self-propelled passenger-carrying railroad vehicle. A train with a single coach and a driver's cab at one or both ends is typically referred to as a "railcar." Such vehicles are referred to as "railmotors" by several railway companies, including the Great Western.To know more about railcars here
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what is the equation linking current, potential difference and voltage
Put your finger over P to compute power; this leaves I and V; hence, P = I x V.
What connection exists between voltage and potential difference?The quantity of current multiplied by the resistance equals the potential difference, which is the same as voltage. One Coulomb of charge uses one Joule of energy to move between two locations in a circuit, which is equal to a potential difference of one Volt.
What is a potential difference?Difference that might exist at all between the two points The amount of work required to move a unit positive charge along any path through one point to another without accelerating is referred to as the electric field.
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Part A
Determine the electric field strength in the region r ≤a. Give your answer as a multiple of Q/E0. Express your answer in terms of some or all of the variables a, b, c, r, and the constant π.
The electric field in the region r ≤a is E [tex]= - \frac{r}{4\pi a^3} . \frac{Q}{e_0} r[/tex]
The total charge is enclosed within the Gaussian surface.
Q[tex]_{enc}[/tex] = 2Q - Q = Q
Therefore, applying Gauss's law over the Gaussian surface
∫[tex]_{s}[/tex]E.dS = Q[tex]_{enc}[/tex]/ε₀ ⇒ E.4πr² = Q/ε₀ ⇒ E = Q/4πε₀r²(r)
In question solution:
A[tex]_{sphere}[/tex] = 4πr²
ΦE = ∫E⋅dA
ΦE = q/ε₀
E = q/(A⋅ε₀)
E = q/(4πr²ε₀)
for r≤a, qin = -Q
E [tex]= - \frac{r}{4\pi a^3} . \frac{Q}{e_0} r[/tex]
So, the electric field in the region is E [tex]= - \frac{r}{4\pi a^3} . \frac{Q}{e_0} r[/tex]
Your question is incomplete but most probably your full question was:
A uniformly charged ball of radius a and charge −Q is at the center of a hollow metal shell with inner radius b and outer radius c. The hollow sphere has a net charge of +2Q.
Part A: Determine the electric field strength in the region r ≤a. Give your answer as a multiple of Q/E0. Express your answer in terms of some or all of the variables a, b, c, r, and the constant π.
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A 2kg block is initially at rest on a horizontal frictionless table. A force of 15N is then exerted on the block at an angle of 37° below the horizontal. The change in kinetic energy after moving 3m is?
Answer:
Approximately [tex]36\; {\rm J}[/tex].
Explanation:
Under the assumption, there is no friction to hinder the motion of the block. As a result, the increase in the kinetic energy of the block would be equal to the external work done on the block.
Let [tex]F[/tex] denote this magnitude of this force, let [tex]s[/tex] denote the magnitude displacement, and let [tex]\theta[/tex] denote the angle between this force and displacement. To find the work that this force has done on the block, use the formula:
[tex]\begin{aligned}(\text{work}) &= F\, s\, \cos(\theta)\end{aligned}[/tex].
For example, since the block in this question is moving along a horizontal table, displacement of the block would be in the horizontal direction. It is given that the angle between this force and the horizontal direction is [tex]37^{\circ}[/tex]. Thus, the angle between the force and the displacement would be [tex]\theta = 37^{\circ}[/tex].
Magnitude of this force is [tex]F = 15\; {\rm N}[/tex], while magnitude of displacement is [tex]s = 3\; {\rm m}[/tex]. The work done on this block would be:
[tex]\begin{aligned}(\text{work}) &= F\, s\, \cos(\theta) \\ &= (15\; {\rm N})\, (3\; {\rm m})\, \cos(37^{\circ}) \\ &\approx 36\; {\rm N\cdot m} = 36\; {\rm J}\end{aligned}[/tex].
Hence, the kinetic energy of this block would increase by [tex]36\; {\rm J}[/tex].
Explain why a fish under water appears to be at a diffrent depth below the surface than it actually is does it appear deeper or shallower
A fish under water appears to be at a different depth than it actually is due to the refraction of light as it passes through the water.
When light travels through a medium with a different index of refraction, such as air to water, it bends, or refracts. This causes objects to appear displaced, or closer or farther away than they actually are. Because water has a higher refractive index than air, light bends more when it enters the water, causing objects, like fish, to appear closer to the surface than they actually are.
The result is that the fish will appear to be deeper in the water than it actually is.
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A classroom has a volume of
165 m^3. How many moles of gas
are in the room if the temperature
is 20. 0°C and the pressure is
1. 00 atm?
(Make sure to put P, V, and I
in the right units. )
(Unit = mol)
The number of moles in the room which has a volume of 165 m³ is 0.0686 moles
The volume of the classroom = 165 m³
The temperature of the room = 20°C
= 293 K
The pressure = 1 atm
The number of moles in the room can be found using the formula,
PV = nRT
where P is the pressure
V is the volume
n is the number of moles
R is the gas constant
T is the temperature
Let us rearrange the above equation, we get
n = PV/RT
Let us substitute the known values in the above equation, we get
n = 1 x 165 / 8.21 x 293
= 165 / 2405.53
= 0.0686 moles
Therefore, the number of moles in the room is 0.0686 moles
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An object is dropped from a height of 8 m. At what height will its kinetic energy and its potential energy be equal
At the peak it has the same potential and kinetic energy.
How is kinetic energy calculated?Kinetic energy (K.E.) is inversely proportional to the square of an object's velocity and its mass: K.E. = 1/2 m v2. When a mass is measured in kilograms and a speed is measured in meters per second, the kinetic energy is measured in kilogram-meters squared per second squared.
Kinetic energy and potential energy are equivalent at what height?The velocity will be zero and the ball's displacement will be at its maximum at the highest point of the trajectory. We might state that the energy present is equivalent to the sum of the potential energy.
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What is the KE of a 0.5 kg puffin flying at 22 m/s?
Important Formulas:
[tex]KE=.5mv^2[/tex]
Kinetic energy(measured in joules) = .5 * mass(measured in kg) * velocity(measured in m/s)^2
__________________________________________________________
Given:
[tex]m=0.5kg[/tex]
[tex]v=22m/s[/tex]
[tex]KE=?[/tex]
__________________________________________________________
Finding kinetic energy:
[tex]KE=.5mv^2[/tex]
[tex]KE=.5(0.5)(22)^2[/tex]
__________________________________________________________
[tex]\fbox{KE = 121 Joules}[/tex]
The kinetic energy of Flying pluff is 121 KJ.
What is Kinetic energy?The energy that an object has as a result of motion is known as kinetic energy. It is described as the effort required to move a mass-determined body from rest to the indicated velocity.
The body holds onto the kinetic energy it acquired during its acceleration until its speed changes. The body exerts the same amount of effort when slowing down from its current pace to a condition of rest.
Formally, a kinetic energy is any term that includes a derivative with respect to time in the Lagrangian of a system. According to classical physics, an object with mass m moving at a speed of v has kinetic energy equal to mv2.
Therefore, The kinetic energy of Flying pluff is 121 KJ.
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Suppose the particles in the preceding problem have masses The velocities of the particles are (a) Calculate the angular momentum of each particle about the origin. (b) What is the total angular momentum of the four-particle system about the origin?
Part A: The angular momentum of each particle about the origin
The angular momentum of the first particle is -0.4 kg.m²/s.The angular momentum of the second particle is 0.The angular momentum of the third particle is 1.3 kg.m²/s.The fourth particle's angular momentum is 0.Part B: The total angular momentum of the four-particle system is 0.95 kg.m²/s.
The expression used to calculate angular momentum L is:
L = r x mv
Here, r is the position vector of the object m is the mass and v is the velocity vector.
According to the superposition principle, the resultant angular momentum due to many particles is the vector sum of the individual angular momentum.
L = L₁ + L₂ + L₃ + ...
Here, L₁ is the angular momentum of a particle, L₂ is the angular momentum of the particle, and so on.
In the question
Mass of a particle = 5.0 kg
vector r = (2.0i - 3.0j) m
vector v = (3.0i) m/s
Part A (seen in the picture for instruction)
For particle 1
The position vector is 2.0j m
Substitute 0.10 kg from m₁, 2.0j from r, and 2.0i m/s for v₁ in the expression of angular momentum
L = r x mv
L₁ = (2.0jm) x [(0.10 kg)( 2.0i m/s)]
L₁ = -4.0 kg.m²/s
The angular momentum for the first particle is -4.0 kg.m²/s.
For particle 2
Position vector is (2.0i - 2.0j) m
Substitute 0.20 kg from m₂, (2.0i - 2.0j) m from r, and (3.0i - 3.0j)m/s for v₂ in the expression of angular momentum
L₂ = (2.0i - 2.0j) m x [ (0.20 kg) (3.0i - 3.0j) m/s]
L₂ = 0
The angular momentum for the second particle is 0
For particle 3
The position vector is (-3.0i + 1.0j) m.
Substitute 0.30 kg from m₃, (-3.0i + 1.0j) m from r, and -5.0j m/s for v₃ in the expression of angular momentum
L₃ = (-3.0i + 1.0j) m x [((-3.0i + 1.0j) m) ( -5.0j m/s)]
L₃ = 1.35 kg.m²/s
The angular momentum for three particles is 1.35 kg.m²/s.
For particle 4
The position vector is 4.01i m.
Substitute 0.40 kg from m₄, 4.0i m from r, and -4.0i m/s for v₄ in the expression of angular momentum
L₄ = (4.0i m) x [(0.40 kg) (-4.0i m/s)
L₄ = 0
The angular momentum for four particles is 0.
Part B
Formula used: L = L₁ + L₂ + L₃ + L₄
The total angular momentum of the four-particle system is calculated as follows:
By superposition principle
L = L₁ + L₂ + L₃ + L₄
L = -4.0 kg.m²/s + 0 + 1.35 kg.m²/s + 0
L = 0.95 kg.m²/s
Hence, the total angular momentum of the four-particle system is 0.95 kg.m²/s.
Your question is incomplete but most probably your full question was:
Suppose the particles in the preceding problem have masses m₁ =0.10 kg, m₂=0.20 kg, m₃ = 0.30 kg, m₄ = 0.40 kg. The velocities of the particel are v₁= 2.0i m/s,v₂= (3.0i - 3.0j) m/s, v₃= - 1.5j m/s, v₄= -4i m/s.
(a) Calculate the angular momentum of each particle about the origin.
(b) What is the total angular momentum of the four-particle system about the origin?
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an object that falls twice as far will be moving twice as fast when it hits the ground. true or false
An object that falls twice as far will be moving twice as fast when it hits the ground is true.
Whath is object?
Objects are entities that have properties and state. They are the fundamental building blocks of a programming language. They are physical or abstract items that have a set of characteristics, such as a name, a type, and a value.Objects are items that can be seen and touched, such as a toy, a computer, a chair or a book. They are physical items that can be owned or interacted with. Objects can also exist in a virtual or abstract form, such as a software program or a mathematical concept. They can also be a combination of both, such as a website or a mobile app. Objects are made up of properties and behavior, which can be seen in the way they interact with other objects in the environment.
Objects can also contain other objects, known as properties. Objects can also have methods which are functions that can be performed on the object. Examples of objects in programming include variables, classes, functions, and arrays.
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With the Sun and Moon in this position, what does the side of the earth facing the moon experience? ft Select one O A a normal high tide B. a neap high tide C. a spring high tide D. a spring low tide a neap low tide F a normal low tide age
With the Sun and Moon in this position, the side of the earth facing the moon experiences a spring high tide. Thus Option C is the answer.
A spring tide is a tide that occurs when the gravitational pull of the Moon and the Sun are in alignment. During a new moon or full moon phase, the gravitational pull of the Moon and the Sun combine to produce stronger than normal high tides and stronger than normal low tides. The term "spring tide" does not refer to the season of spring, but rather the tide's "springing forth" of water.
During a spring tide, the difference between high tide and low tide is at its greatest, and the water level rises higher and falls lower than during a neap tide. This is because the gravitational pull of the Moon and Sun are working together to produce the tide, rather than against each other. This results in a high tide that is higher than a normal high tide, referred to as a spring high tide.
It is important to note that spring tides occur twice a month, around the time of the new and full moon, when the Moon and Sun are in alignment.
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Why is solar energy called renewable?
Solar energy is called renewable because it is abundant in nature and can be filled repeatedly.
Energy is power or strength that can be used for various activities. Energy cannot be created but can be changed from one form to another and can be transferred.
Solar energy is energy produced from the radiant heat of sunlight that can be utilized by all living things on earth, both humans, animals and plants. Solar energy can also be used as an alternative energy because it is environmentally friendly. This energy is included in renewable energy because the amount is abundant and endless even though it is used in large quantities.
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A very powerful vacuum cleaner has a hose 2.27 cm in diameter. With no nozzle on the hose (no change to hose area), what is the weight of the heaviest brick it can lift
A very powerful vacuum cleaner has a hose 2.27 cm in diameter. The atmospheric pressure is 1.00 atm=101,300 Pa. then vacuume cleaner generate the force F = 65.1 N
What does diameter mean?A line that is straight and cuts through the middle of a body or figure. Particularly: the length of a diameter; a line segment passing through the center of a circle with its ends on the circumference.
Calculation -:Given,
diameter of the nose is d= 2.86 cm
radius of the nose r= 1.43 cm = 1.43× [tex]10^{-2}[/tex] m
We know F=P.A
where P is the atmospheric pressure and A is the surface area of the circulsr nose F is the force exerted by vacuume cleaner on the air
∴ F=P ( [tex]\pi r^{2}[/tex])
we know atmospheric pressure, p=1.013×[tex]10^{5}[/tex] pa
F = 1.013 × [tex]10^{5}[/tex] × 3.14 (1.43 × [tex]10^{-2}[/tex]) ^2
⇒ 65.1 N
⇒ F = 65.1 N
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A imple pendulum ha a period of 3 econd. If the value of ‘g’ i taken a 9. 98 m-2 calculate the length of the pendulum
Answer:
T (Period) = 2 π (L / g)^1/2 for a simple pendulum
L = g * T^2 / (4 π^2)
L = 9.98 m/s^2 * 9 s^2 / 39.5 = 2.27 m
Deviance has an effect on social power. How is this BEST demonstrated?
A. Powerful people in society keep their power by defining the laws of deviant behavior.
B. People with little power perform more questionable acts with fewer consequences than the more powerful people.
C. All groups that follow cultural norms tend to have a large amount of social power in society.
D. Someone who doesn't follow norms in a society always gains power because other people will rebel with them.
Deviance has an effect on social power. Then, Powerful people in society keep their power by defining the laws of deviant .
Forms of Deviant Behavior Deviant Behavior Based on NatureBased on the nature is divided into two kinds, namely negative behavior and positive behavior.
a. Positive deviant behavior
Positive behavior is deviant behavior that gives or has a positive impact on social life, because it has innovative elements and ideas that emerge are also creative, so as to enrich people's insights.
Positive behavior is also directed primarily at the values to be achieved together as well as social interests and is often considered as something ideal in society. Positive behavior will usually be accepted by society, because it is a form of development and adjustment to the times.
b. Negative deviant behavior
Negative behavior is the opposite of positive behavior.
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Answer:
a
Explanation:
Mercury thermometer is not suitable to measure the temperature of very cold place. Why?
The use of a mercury thermometer is not suitable for the purpose of determining the temperature of extremely cold ice because at such low temperatures, mercury transforms into a translucent state, making it impossible to read.
Another reasons why mercury thermometer is not suitable to measure the temperature of the very cold place are:
Since mercury freezes at a temperature of -38.83 degrees Celsius, a mercury thermometer will not work in extremely cold temperatures. We are unable to use a thermometer that contains mercury at low temperatures because the glass could shatter at those temperatures.The body whose temperature we are measuring with the thermometer does not radiate heat in the opposite direction.When exposed to low temperatures, mercury takes on a transparent appearance, making it more challenging to obtain accurate readings.To learn more about mercury thermometer, click here:
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What pressure, in pascals, can you create by exerting a force of 480 N with your tooth on an area of 0.95 mm2
According to the given statement The pressure exerted by the tooth is 506,315.78 Pa.
What is pressure?Pressure is a measure of the force exerted on a surface per unit area. It is a scalar quantity and is measured in units of force per unit area, such as pascals (Pa), pounds per square inch (psi), or atmospheres (atm).
It can be calculated using the formula:
Pressure (Pa) = Force (N) / Area (m²)
Given that the force exerted is 480 N and the area of contact with the tooth is 0.95 mm^2, we can use the formula to find the pressure exerted:
Pressure (Pa) = 480 N / (0.95 x 10⁻³ m²)
To convert mm² to m², we divide by 10⁶
Pressure (Pa) = 480 N / (0.95 x 10⁻³ m²) = 506,315.78 Pa
Hence, the pressure exerted by the tooth is approximately 506,315.78 Pa.
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A picture frame hung against a wall is suspended by two wires attached to its upper corners. If the two wires make the same angle with vertical, what must this angle be if the tension in each wire is equal to 0.75 of the weight of the frame?
(Neglect any friction betweem the wall and the picture fame)
The angle must be formed if the tension in each cable is equal to 0.75 of the frame weight is 83.6⁰.
By using the parallelogram law of vector addition, it is possible to calculate the angle between the two wires.
a² + b² - 2abcosθ = R²
Where;
R = is the outcome vector = the frame's weight ⇒ W
Angle between the two wires equals 0.75W for the first wire's tension and 0.75W for the second wire's tension.
(0.75W)² + (0.75W)² - 2(0.75W x 0.75W) cosθ = W²
1.125W² - 1.125W² cosθ = W²
= 1.125W²(1 - cosθ)
W²/1.125W² = 1 - cosθ
0.8889 = 1 - cosθ
cosθ = 1 - 0.8889
cos θ = 0.1111
θ = arc cos(0.1111)
θ = 83.6⁰
So, the angle must be formed if the tension in each cable is equal to 0.75 of the frame weight is 83.6⁰
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Written problem: I find that I can blow 1000 cm3 of air through a drinking straw in 1.3 s. The diameter of the straw is 5 mm. Find the velocity of the air through the straw.
Answer:
Below
Explanation:
Diameter of straw = .5 cm then the radius = .25 cm
AREA of the straw = pi r^2 = pi ( .25 cm)^2 = .19635 cm^2
Now we need to find the LENGTH necessary to have a volume of 1000 cm^3
1000 cm^3 = L * . 19635 cm^2
L = 5.092.958 cm <=== your blowing covers this distance in 1.3 s
5092.958 cm / 1.3 s = 3917.7 cm / s = 39.2 m/s
jordan wants to see if earthworms prefer rough or smooth terrain to crawl through. What will be his independent variable
The independent variable in this investigation is the type of surface which is changing whereas, the dependent variable is the mobility of earth worm.
What is independent variable?In a experiment or investigation, there are two types of variables which are dependent and independent variable. Dependent variable are those which are dependent on other variables and are changing with respect to other variables.
Independent variables are those not dependent on any other variables and we can change the independent variable to study the change in dependent variable.
Here, the one we studying is the mobility of earth worm which is the dependent variable and the type of surface rough or smooth is the independent variable.
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A person weighing 500 N and a girl weighing 350 N are sitting on a board. The 50N- board is uniform and is supported at the center. The 500-N person is 1.5 m from the center, how far from the center should the girl sit so that the board is in equilibrium
The girl should sit 2.14 m from the center to keep the board in equilibrium.
What is equilibrium?
Equilibrium is a state in which the net force and net torque acting on an object are both equal to zero. This means that the object is either at rest or moving at a constant velocity. In other words, the object is not accelerating or rotating.
In order for the board to be in equilibrium, the sum of the forces acting on it must be equal to zero. Since the board is uniform and supported at the center, the only forces acting on it are the weights of the person and the girl.
To find the distance from the center that the girl should sit, we can set up the following equation:
F_net = 0 = (500 N)(1.5 m) - (350 N)(x)
where F_net is the net force acting on the board, x is the distance from the center where the girl is sitting, and the 1.5 m is the distance from the center where the person is sitting.
Solving this equation for x:
x = (500 N)(1.5 m) / 350 N = 2.14 m
Hence, the girl should sit 2.14 m from the center to keep the board in equilibrium.
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A certain satellite orbiting Earth has a speed of about 17,000 miles/hour. What is its approximate speed expressed to the correct number of significant figures in kilometers/second
The speed of the satellite in terms of kilometers per second is 455.89 km/sec
The speed of the satellite = 17,000 miles/hour
The speed of the satellite can be converted into kilometers/second by converting the miles into kilometers and then the hour into seconds
1 miles = 1.609 km
Thus, the speed of the satellite,
= 17,000 x 1.609 km/hour
= 27,353 km/hr
Then, the speed of the satellite in one second is
1 hour = 60 seconds
Thus, the speed of the satellite,
= 27,353 x 1/60 km/sec
= 455.89 km/sec
Thus, the speed of the satellite is 455.89 km/sec
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the electrical potential due to a dipole on its axis at a point p at a large distance x from the dipole is given by v
The electrical potential due to a dipole at a point P on its axis at a large distance x from the dipole is given by the formula: V = (p * x) / (4 * pi * epsilon_0 * x^2)
Where:
p is the dipole moment, a vector quantity that represents the magnitude and direction of the dipole. It is defined as the product of the magnitude of one of the charges (q) and the distance between the charges (d), p = q*d.x is the distance from the dipole to point P, it is a scalar quantity.epsilon_0 is the electric constant or vacuum permittivity, it is a scalar quantity that relates the electric flux density to the electric field strength. Its value is approximately 8.85 x 10^-12 C^2/Nm^2.The equation assumes that point P is located on the axis of the dipole (the line connecting the two charges) and that the distance x is much larger than the size of the dipole. This means that the dipole can be considered as a point source of electric potential and the field at point P is well approximated by the field of a point charge.It's important to note that the formula gives the potential at point P due to the dipole, however, the dipole itself also has an electric field which can be found by taking the gradient of the potential.Learn more about the electrical potential here:
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A theme park is planning out a new free-fall ride. The drop is almost perfectly frictionless, with a distance of 190 meters. Assuming that the initial velocity was zero, what would be the speed at the bottom of the drop?
a-53 m/s
b-61 m/s
c-67 m/s
d-72 m/s
Answer:
Approximately [tex](-61)\; {\rm m\cdot s^{-2}}[/tex], assuming that [tex]g = 9.81\; {\rm m\cdot s^{-2}}[/tex].
Explanation:
Under the assumptions, the vehicle would be in a free fall. Acceleration would be constant: [tex]a = (-g) = (-9.81)\; {\rm m\cdot s^{-2}}[/tex].
Let [tex]u[/tex] denote the initial velocity of the vehicle. Let [tex]v[/tex] denote the velocity of the vehicle at the bottom of the drop. Let [tex]x[/tex] denote the displacement of the vehicle during the drop.
It is given that the initial velocity is [tex]u = 0\; {\rm m\cdot s^{-1}}[/tex]. During the drop, displacement would be [tex]x = (-190)\; {\rm m}[/tex] (negative since the vehicle is below where it started.) The value of final velocity [tex]v[/tex] needs to be found.
It is known that the vehicle is moving downwards at the end of the fall. Therefore, the value of [tex]v\![/tex] would be negative. Apply the SUVAT equation [tex]v^{2} - u^{2} = 2\, a\, x[/tex] to find [tex]v[/tex] from [tex]u[/tex], [tex]a[/tex], and [tex]x[/tex].
[tex]\begin{aligned}v^{2} &= u^{2} + 2\, a\, x\end{aligned}[/tex].
[tex]\begin{aligned}v &= -\sqrt{u^{2} + 2\, a\, x} \\ &= -\sqrt{(0\; {\rm m\cdot s^{-1}})^{2} + 2\, (-9.81\; {\rm m\cdot s^{-2}})\, (-190\; {\rm m})} \\ &\approx (-61)\; {\rm m\cdot s^{-1}}\end{aligned}[/tex].
(Note that [tex]v[/tex] is negative.)
In other words, the velocity of the vehicle would be approximately [tex](-61)\; {\rm m\cdot s^{-1}}[/tex] at the end of the drop.