Answer:
work
Explanation:
If a yellow ball is rolled with an average speed of 5 m/s, how far will it travel
in 5 seconds? (just type the number, no need for units).
*
A car engine burns gas at 495 K and exhausts to the air at 293 K if it ran at the highest possible efficiency and use 10,000 J of input heat how much he would it be rejected into the air? WILL GIVE BRAINLIEST
Answer:
5,920 J
Explanation:
Lowest temperature T₂ = 293 K
Highest temperature T₁ = 495 K
Highest possible efficiency e = 1 - T₂/T₁ = 1 - 293/495 = 0.408
Input heat Q₁ = 10,000 J
Find output heat Q₂
e = 1 - Q₂/Q₁
0.408 = 1 - Q₂/10,000
Q₂/10,000 = 1 - 0.408 = 0.592
so
Q₂ = 10,000 x 0.592 = 5,920 J
what is the kinetic energy of a sky diver with a mass of 60.0 kg falling at a terminal velocity of 40.0 ms?
Answer:
48,000 J
Explanation:
m = 60.0 kg
v = 40.0 m/s
kinetic energy = mv^2/2 = 60*40^2/2 = 48,000 J
I need help algebra in physics
Answer:
A: 0.26
Explanation:
how can i plot a graph?
Answer:
so you have your boxes go by tens on the x-axis okay which is the one going straight up then the second number goes by 5's is your y-axis. 30,6 so 30 is your x and 6 is your y. start at 0,0 which is the little corner piece. find 30 on x and then go over 6 and that's it!
Explanation:
What do you mean by escape speed at a place?
In celestial mechanics, escape velocity or escape speed is the minimum speed needed for a free, non-propelled object to escape from the gravitational influence of a primary body, thus reaching an infinite distance from it.
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A new company is making security cameras. These security cameras will be different than other security cameras because instead of detecting motion, they will detect body heat.
What type of electromagnetic wave will the camera detect?
A
gamma ray
B
infrared
C
microwave
D
radio wave
Answer:
b
Explanation:
At time t = 0 a car has a velocity of 16 m/s. It slows down with an acceleration given by
−0.50t, in m/s2 for t in seconds. It stops at t =
A. 64 s
B. 32 s
C. 16 s
D. 8.0s
E. 4.0s
A car is moving at 16 m/s at a time t = 0. With an acceleration of 0.50t, in m/s², for t, in seconds, it slows down. At t = 8 seconds, it stops. Option D is correct.
What is velocity?The change of displacement with respect to time is defined as the velocity. velocity is a vector quantity.
Given data;
t = 0 ,u=16 m/s
acceleration = −0.50t m/s²
v=0,t=?
The acceleration is found as;
[tex]\rm a= \frac{dv}{dt} \\\\\ dv=adt \\\\ dv=-0.50 \ t dt[/tex]
Intregating both sides we get;
[tex]\rm [v]_0^{16}=-0.50\frac{t^2}{2} \\\\ 16=0.25 t^2\\\\\ t^2=\frac{16}{0.25} \\\\\ t= 8 \ sec[/tex]
Hence, the car stops at t=8sec. Option D is correct.
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If you increase your speed from 10 mph to 30 mph, how much will your stopping distance increase?
When you double the speed of your car, your braking distance quadruples. every time you double your speed, you multiply your braking distance by four.
The stopping distance of a vehicle is the sum of breaking distance and thinking distance. The stopping distance of a vehicle when we increase the velocity from 10mph to 30 mph, increases from30 feet to 90 feet.
What is stopping distance?Stopping distance is the distance covered by a vehicle when we stops. Distance is the product of time and velocity. As the velocity increases then, the time taken to cover the distance will be lower.
Stopping distance mathematically is the sum of breaking distance and thinking distance .Thinking distance is simply the speed and it is in fact means how long it takes on average to think for a break.
Breaking distance is means how long the driver takes to break or stop in actual. In general, the breaking distance is speed multiplied by 2.
Thus, for 10 mph, the thinking distance is 10 feet and breaking distance is 10 × 2 = 20 feet and therefore, the stopping distance is 10 + 20 =30 feet.
Similarly for 30 mph, breaking distance is 60 feet and thinking distance is 30 feet thus, having 60 + 30 = 90 feet of stopping distance.
Therefore, when the speed increased from 10 mph to 30 mph, stopping distance increases from 30 feet to 90 feet.
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If a green ball is rolled from an initial position of 2m and travels to a final
position of 10m - what distance does it travel? (just type the number, no
need for units).
Answer:
10m-2m = 8m
8
Hope this helps!
Calculate change in height of a 2kg ball moving a speed of 10m/s up a frictionless ramp until it stops
The change in the height of the object is 5.1 m.
Conservation of mechanical energyThe principle of conservation of mechanical energy states that the total energy of an isolated system is always conserved.
The change in the height of the object is calculated by applying the principle of conservation of mechanical energy as follows;
P.E = K.E
[tex]mg \Delta h = \frac{1}{2} mv^2\\\\g \Delta h = \frac{1}{2}v^2\\\\\Delta h = \frac{v^2}{2g} \\\\\Delta h = \frac{(10)^2}{2(9.8)} \\\\\Delta h = 5.1 \ m[/tex]
Thus, the change in the height of the object is 5.1 m.
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If a driver brings a car traveling at 22m/s to a full stop in 2.0 s with an acceleration of -8 m/s2 then how far did the car travel while braking?
Answer:
v=u + at
0= 22 + a*2
a = -22/2 = -11 m/s^2
The car's acceleration is -11 m/s^2
V^2 = u^2 + 2as
022^2 + 2*(-11)s
s = 22^2/22 = 22m
The car will travel 22 m before stopping.
Explanation:
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#carry on learning
Calculate the speed of a 5 kg object that possesses 20 J of kinetic energy KE=1/2
mv2
2.83 m/s/s
2.83 m/s
2 m/s
4 m/s
Answer:
2.83 m/s
Explanation:
m = 5 kg,
KE = 20 J
KE = mv^2/2
20 = 5*v^2/2
5*v^2 = 40
v^2 = 8
v = [tex]\sqrt{8}[/tex] = 2.83 m/s
How much work is done on a small car if 4250 N force is exerted to move it 83.5 m to the side of the road?
Answer:
354875 J
Explanation:
The equation for Work is:
[tex]Work=Force*Distance[/tex]
We can plug in the given values into the equation:
[tex]Work=4250N*83.5m=354875J[/tex]
Physics Unit 5 CA - Conservation of
1. A student is pushing a car toward a gas station. They exert a constant force of 100 N
on the car for 40 m bring the car from rest to 5 m/s. What is the mass of the car?
Answer:
160 kg
Explanation:
f = ma
100 = m * a
a = v/t
v = distanc/time
dist = 40m
time = 8 sec
v = 40/8
a = 40/(64)= 5/8
m = 100*8/5= 160 kg
The period of a .75 m pendulum is _s
Hi there!
We can use the following equation for the period of a pendulum:
[tex]\large\boxed{T = 2\pi \sqrt{\frac{L}{g}}}[/tex]
T = Period (s)
L = length of simple pendulum (.75 m)
g = acceleration due to gravity (9.8 m/s²)
Plug in the values:
[tex]T = 2\pi \sqrt{\frac{.75}{9.8}} = \boxed{1.738 s}[/tex]
Two spheres carry a charge of 1x10^-7 C. Their centers are separated by 0.7m. Calculate the magnitude of the force between the two charged objects.
Write your answer in scientific notation using one significant figure
PLEASE HELP ME
We have that the force between the two charged objects is mathematically given as
F=2.349N
Magnitude of the force between two charged objects.Question Parameters:
Two spheres carry a charge of 1x10^-7 C.
Their centers are separated by 0.7m.
Generally the equation for the Force is mathematically given as
[tex]F=\frac{q1q2}{4*\pi e*r}[/tex]
Therefore
[tex]F=\frac{(1e-7)^2}{9e9*0.7}[/tex]
F=2.349N
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The lightbulb of a flashlight creates light and heat, both of which are forms of
energy. What is the source of the energy?
A. Elastic potential energy stored in the molecules of the flashlight
B. Chemical potential energy stored in the ions of the battery
C. Kinetic energy of the electrons flowing through the lightbulb
O D. Gravitational potential energy stored in Earth's gravitational field
Answer:
B
Explanation:
A ball with a weight of 15 N is thrown striaght up into the air with an initial speed of 14 m/s. What is the maximum height it will achieve above its starting position
Answer:
10m above initial height
Explanation:
let acceleration due to gravity = 9.8 m/s/s
v final = v initial - time • gravity
0 = 14m/s - t • 9.8m/s/s
t = 1.43 seconds to reach max height
distance = 1/2 • acceleration • time^2
distance = 1/2 • 9.8 • 1.43^2
distance = 10 meters above initial height
What is the effect of clouds on the "output" of a Solar PV module?
Answer:
What is the effect of clouds on the "output" of a Solar PV module?
Clouds do impact photovoltaic panels. The quantity of power your photovoltaic panels can produce is directly dependent on the level of light they receive. ... They will see complete direct sunlight “plus” reflected light from the clouds! They will drink in more energy than they could on a cloudless day!
Explanation:
I hope it will help you...
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this is the question on the attachment
Explanation:
a) to allow for the metal tracks to expand on hot days.
reason:- as you have seen in summer the sunlight fall on these tracks and make the metal expand and fill that gaps.
hope this helps you
have a great day :)
Light passes through a single slit of width 8.77 x 10-6 m. The second (m = 2 diffraction minimum occurs at an angle of 5.62º. What is the wavelength of the light IN NANOMETERS?
Answer:
429.424
Explanation:
Trust :)
The wavelength of the light passing through the single slit is approximately 429 nanometers.
To calculate the wavelength of the light passing through a single slit, we can use the formula for the diffraction of light:
w × sin(θ) = m ×λ
Where:
w is the width of the slit
θ is the angle of the diffraction minimum
m is the order of the diffraction minimum
λ is the wavelength of the light
Given:
Width of the slit (w) = 8.77 × 10^(-6) m
Angle of the diffraction minimum (θ) = 5.62º = 5.62° = 5.62 × π/180 radians
Order of the diffraction minimum (m) = 2
To solve for the wavelength (λ), rearrange the formula:
λ = (w × sin(θ)) / m
Substituting the given values:
λ = (8.77 × 10^(-6) m × sin(5.62° × π/180)) / 2
Calculating this expression:
λ ≈ (8.77 × [tex]10^{(-6)[/tex] m × sin(0.098)) / 2
λ ≈ (8.77 ×[tex]10^{(-6)[/tex] m × 0.098) / 2
λ ≈ 4.29 ×[tex]10^{(-7)[/tex] m
To convert the wavelength to nanometers, we multiply by[tex]10^9[/tex]:
λ = 4.29 × [tex]10^{(-7)[/tex] m × 10^9 nm/m
λ ≈ 429 nm
Therefore, the wavelength of the light passing through the single slit is approximately 429 nanometers.
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According to newton second law of motion what is force equal to
Answer:
According to Newton, "Force is equal to the change in momentum per change in time. For a constant mass, force equals mass times acceleration."
Force = mass x acceleration
Answer: According to Newton’s Second Law of physics, the force is equal to the mass of the object times the acceleration. The force acting on an object would be equal to the mass of an object times its acceleration... This means the more mass an object has, the more force you need to accelerate it. And the greater the force, the greater the object's acceleration
What is the acceleration of the object?
using my friend account again
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Explain why friction becomes desirable and undesirable
Answer:
A friction is very much desirable to stop the body from its moving condition. ... If the friction is more between the block and inclined surface then a large force is required to push the block on the plane.
Explanation:
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On the periodic table, the elements known as noble gases are found in
Answer:
The noble gases are located in the 18th group of the periodic table.
What is that force that simply pushes bodies through the planet's gravitational field
Answer:
Actually, it is not a force. It is a velocity attained by the bodies hence escaping through the gravitational field.
This velocity is called escape velocity.
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Answer:
Gravity is the force by which a planet or other body draws objects toward its center. The force of gravity keeps all of the planets in orbit around the sun. Weight is a measure of the force of gravity pulling down on an object. It depends on the object's mass and the acceleration due to gravity, which is 9.8 m/s2 on Earth. The gravitational force between two bodies is directly proportional to the product of the masses of those bodies and is inversely proportional to the square of the distance between them.
Hope this helped! Have a nice day!
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A 10 N force is applied to a 2 kg mass, how fast will it be going in 10 sec?
Answer:
v = 50 ms^1
Explanation:
We know:
F = 10N
m = 2kg
t = 10 sec
F=ma
10 = 2*a
5=a
a = 5 ms^2
Now,
a=v/t
5 = v/10
50 = v
v = 50 ms^1
Car 1 brakes to a stop on a dry road. Car 2 does the same thing, at the same speed, on a road where it has been raining. Explain how the following will be different for car 2: a) braking distance, b) thinking distance and c) stopping distance.
Answer: car 1 is going how fast
Explanation: no need to answer without speed I won't know distance.