a helicopter flies over a city the helicopter changes it's altitude by -42.9m. then it changes it's altitude by another -15.4m what is the total change in the helicopters altitude

Answer:

one

Step-by-step explanation:

y = (x + 3)^2

Start with the parent function y = x^2.

y = x^2 touches the x-axis at only 1 point, (0, 0).

The difference between y = (x + 3)^2 and its parent function y = x^2, is that in y = (x + 3)^2, x was replaced by x + 3. That is a translation of 3 units left. The function y = (x + 3)^2 still only touches the x-axis once, but at x = -3.

Answer: one

Answer:

Step-by-step explanation:

To answer this, set the function y = (x + 3)^2 touch the x-axis (where y = 0) and find the actual value(s) of x:

y = (x + 3)^2 = 0

Taking the square root of both sides, we get x + 3 = ±0, or x = -3.  As this equation is a quadratic, there MUST be two roots; the roots are {-3, -3}.  Thus in theory, the graph touches the x-axis in two places, but these two places are identical:   (-3, 0)

Answer:

he  spent $75.80

Step-by-step explanation:

hope this helps:D

Answer:

A

Step-by-step explanation:

1ft times 1ft is only 1 ft

Answer:

1ft

Step-by-step explanation:

Answer:

x=8. Explanation: Factor of 6561 are. 6561=3×3×3×3×3×3×3×3=38. As such, 3x=6561 can be written as 3x=38. Hence, x=8.  Step-by-step explanation:

Answer:

The value of b is 3

then B - (n4 – 3)(n4 + 3)

Step-by-step explanation:

Answer:

28.1 units

Step-by-step explanation:

Area of circle= πr², where r is the radius.

Given that the area is 20π,

20π= πr²

Divide both sides by π:

20= r²

Square root both sides:

[tex]r = \sqrt{20} [/tex]

[tex]r = \sqrt{4(5)} [/tex]

[tex]r = ( \sqrt{4} )( \sqrt{5} )[/tex]

[tex]r = 2 \sqrt{5} [/tex]

Circumference of circle= 2πr

Substitute the value of r:

Circumference of the circle

[tex] = 2(\pi)( 2\sqrt{5} )[/tex]

[tex] = 4\pi \sqrt{5} [/tex]

= 28.1 units (3 s.f.)

Answer:

11th term is 0

Step-by-step explanation:

30, 27 , 24 ,......0

a = first term = 30

Common difference = second term - first term = 27 - 30 = -3

nth term = a+(n-1)*d

a + (n-1)d = 0

30 + (n - 1) *(-3) = 0

30 + n*(-3) -1*(-3) = 0

30 - 3n + 3 = 0

      -3n + 33 = 0

               -3n = -33

                   n = -33/-3

n = 11

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Answer:

I think it's about 15 to 22.

Step-by-step explanation: So first I checked the length for the unknown number and I added the 12 and 10 together but that didn't work and so i'm just estimating the number for x yo.

Sorry if I didn't helped you yo.

Answer:

42 = 2*3*7

Step-by-step explanation:

42 can be rewritten as 2*21, for example.  

2 is prime.  21 = 3*7.

Then 42 = 2 * 21 is also equal to:

         42 = 2*3*7. where these factors are ordered from least to greatest.  The prime factors of 42 are {2, 3, 7}.

Answer:

the slope is -2

Step-by-step explanation:

Answer:

1/1 = 1

Step-by-step explanation:

Use rise/run.

The x value increases by 1 in the same amount of time that the y value increases by 1. This gives you the slope 1/1 (y increase/x increase).

1/1 can then be converted to 1.

Answer:

A) Akash (1.5m), Meera (1.52), Rahul (1.54m), Lakshmi (1.56m)

B) Lakshmi is the tallest, 1.56m tall

Step-by-step explanation:

Rahul- 1.54m

Akash- 1500mm

Meera- 152cm

Lakshmi- 1560mm

Let's start by converting all the measurements to meters.

Rahul is already in meters, so he can just stay the same.

1500mm = 1.5m

152cm = 1.52m

1560mm = 1.56m

So our new measurements are:

Rahul- 1.54m

Akash- 1.5m

Meera= 1.52m

Lakshmi= 1.56m

We can now make our conclusions.

A) Akash (1.5m), Meera (1.52), Rahul (1.54m), Lakshmi (1.56m)

B) Lakshmi is the tallest, 1.56m tall

Answer:

Step-by-step explanation:

Let's convert all the heights to meters:

Rahul 1.54m

Akash 1.50 m

Meera 1.52 m

Lakshmi 1.56m

Now, let's arrange their heights in ascending order (shortest to tallest):

Akash 1.50 m

Meera 1.52 m

Rahul 1.54m

Lakshmi 1.56m

a) 1500 mm, 152 cm, 1.54 m, 1560 mm

b) therefore Lakshmi is the tallest.

Answer:

[tex]p(t) = - 3t + 75 \\ p(t) = 0 \\ - 3t + 75 = 0 \\ 3t = 75 \\ t = \frac{75}{3} \rightarrow \boxed{t = 25 \: mins} \\ 3 \: papers \: per \: mins \\ domain \: \boxed{t \geqslant 0} \: \\ because \: time \: cant \: be \: negative \: on \\ \: this \: perticular \: occasion \\ \therefore \: range \: \boxed {p(t) \geqslant 0 }[/tex]

Answer:

35

Step-by-step explanation:

Numbers that add up to 8 and number combinations

0 and 8: 80, 08

1 and 7: 17, 71

2 and 6: 26, 62

3 and 5: 35, 53

4 and 4: 44

Since the number must be between 25 and 40, the only possible numbers are 26 and 35

Since 26 is not the answer, the number is 35

Answer:

A

Step-by-step explanation:

not sure if it is correct

Answer:

10

8+40÷20=8+2=10

,.,.......

Answer:

It is c

Step-by-step explanation:

Answer:

25x + 75 ≥ 30

Hope this helps!

Answer:

B) 5/8

Step-by-step explanation:

Because we are working with fractions that have different denominators, we need to find the lowest common denominator, which would be 8, because 1/8 cannot be divided anymore in 2 or 4, but 1/2 can be multiplied in eighths.

So, to make 1/2 into eighths, we have to multiply both the numerator and denominator by 4 in order for 2 to become 8:

1/2 * 4 = 4/8

Now, we can add the amounts of the total granola bar that he consumed:

4/8 + 1/8 = 5/8

Because 5/8 cannot be simplified any further, that is our final answer.

Hope this helps :)

Answer:

Perpendicular

neither

[tex]y=\frac{4}{5}x-2[/tex]

Step-by-step explanation:

Answer:

10/21

Step-by-step explanation:

Number of minutes required for printing 21 pages: 10

So, number of minutes required for printing 1 page

= 10/21

(= 0.47 = 0.5 [approximately])

Notice that

4/9 = 2²/3² = (2/3)²

so that

(2/3)³ (4/9)⁴ = (2/3)³ ((2/3)²)⁴

… = (2/3)³ (2/3)⁸

… = (2/3)¹¹

Answer:

6

Step-by-step explanation: You subtract 12-6

Transformation involves changing the position of a shape.

The complete statement is:

There are _3_ more ways with the order of the triangles reversed. There is a total of _9_ ways to write a congruence statement.

From the question, we understand that:

[tex]\mathbf{\triangle DVW \cong \triangle LCY}[/tex]

This mean that, the following 6 statements can be used as the congruent statements

[tex]\mathbf{\triangle DVW \cong \triangle LCY}[/tex]

[tex]\mathbf{\triangle DWV \cong \triangle LYC}[/tex]

[tex]\mathbf{\triangle VDW \cong \triangle CLY}[/tex]

[tex]\mathbf{\triangle VWD \cong \triangle CYL}[/tex]

[tex]\mathbf{\triangle WDV \cong \triangle YLC}[/tex]

[tex]\mathbf{\triangle WVD \cong \triangle YCL}[/tex]

A triangle has 3 sides, and there are 2 triangles in the question.

The number (n) of congruence statements is:

[tex]\mathbf{n = 3^2 = 9}[/tex]

The remaining (r) number of congruent statement is:

[tex]\mathbf{r = 9 - 6 = 3}[/tex]

So, the blanks should be completed with 3 and 9

Read more about congruent triangles at:

https://brainly.com/question/12413243

Answer:

the answer is c :)

Step-by-step explanation:

Answer: 14 cm

Step-by-step explanation:

Answer:

R=14 cm

total area= πr²

=22/7*196=616 cm²

r2= 3.5 cm

area of the small circles= 2*πr²=2*12.25*22/7=77 cm²

length of rectangle=3

breadth=1

area =lb=3 cm²

area of the small circles+area of rectangle=77+3=80 cm²

remaining area=616-80=536 cm²

Answer:

Sequence 1: Translate 5 units to the right, and 5 units down

Sequence 2: Reflect across the origin, translate 1 unit down, 1 unit to the right

Step-by-step explanation:

Chose 1 point to focus in, such as (-1, 1)

Move that point 5 units to the right, and 5 units down. See how it matches up with the same corner of the red square?

Now, use that same point, and change the signs of both the x and y, this is to reflect across the origin. (In reality, you are just reflecting across the x and y axis)

So you originally have: (-1,1) -> (1, -1)

Now move this point one unit to the right, and 1 unit to the left.

It may seem that you made it touch the wring corner, but do the same thing with another corner's points. They all flipped!

Answer:

you need 8 bins because 150/20 is 7.5 but you can't have half a bin and you need somewhere to put the other books