Answer:
His speed, in metres per second, is approximately 10m/s. The correct option is B.
Explanation:
Speed is defined as the rate in which an object cover a distance in a given time. It is measured in meters per second ( m/s). From the question, the jogger covered a distance of 3Km which when converted to meter is 3000meters in a given time 5 minutes which is 300seconds. The calculation of his speed in meter per second is shown below:
Distance= 3Km to meters ( as 1000meters = 1Km). Therefore 3× 1000 = 3000m
Time= 5 minutes to seconds ( as 1 minute = 60 Seconds). Therefore 5× 60= 300.
Speed= distance/ time
= 3000/300
= 10m/s
Therefore his speed, in metres per second, is approximately 10.
help me plsss, this is worth 30 points!! can someone pls help even if u can only give a few answers it would be helpful.
Length of table is 1.0m,1.00m and 1.000m.Which one is more accurate?
Answer:
1.00 m is a more accurate measured length.
Explanation:
Denote length of the table by L.
For L=1.0 m, there is one significant digit after the decimal.
Care 1: When one more significant digit after decimal considered, the exact number can be from 0.95 to 1.05.
So, the possible span of error [tex]\Delta E_1= 1.05-0.95= 0.1m[/tex]
For L=1.00 m, there is two significant digits after the decimal.
Case 2: When one more significant digit after decimal considered, the exact number can be from 0.095 to 1.005.
So, the possible span of error [tex]\Delta E_2= 1.005-0.095= 0.01m[/tex]
Case 3: For L=1.000 m, there is three significant digits after the decimal.
When one more significant digit after decimal considered, the exact number can be from 0.0095 to 1.0005.
So, the possible span of error [tex]\Delta E_3= 1.0005-0.0095= 0.001m[/tex]
As [tex]\Delta E_1 >\Delta E_2>\Delta E_3[/tex]
So, the least error is in the third case when L=1.00m, hence, L= 1.00m is more accurate.
Please help I need this right now
Answer:
The basket ball
Explanation:
The heavier an object is the more kinetic energy it will have even if it is thrown at the same speed; therefore, since the basketball is the heaviest, it is the logical answer.
While a marble is heavy for its size, it would not have the same kinetic energy as the basket ball.
Beach balls weigh the least out of the options given so this cannot be the answer.
Golf balls, while they are dense, they do not weigh nearly as much as a basketball would!
Hope this helps <3
Answer:
The answer is B the basketball
Explanation:
the gravitational field strength on mars is 3.7n/kg
Answer:
True
Explanation:
What would happen to the number of home runs a player could hit if the air was removed from above the field? Use your understanding of Newton's laws to explain.
Answer:
number of home runs a player would hit would drastically increase
Explanation:
In a hypothetical scenario, if this were to happen the number of home runs a player would hit would drastically increase. When a player hits the ball force is applied to the ball which sends it flying, then the ball meets an opposing force of air resistance and a downward force of gravity which ultimately causes the ball to fall to the ground. This is explained in Newton's first law which states that "objects in motion remain in uniform motion and in a straight line unless they are met by an opposing unbalanced force." Without the force of air resistance, the ball will only be met with a downward force of gravity which would allow it to travel at a much greater distance before hitting the ground, thus resulting in a drastic increase of home runs.
Answer:
number of home runs a player would hit would drastically increase
Explanation:
Do larger bodies orbit smaller bodies or do smaller bodies orbit larger bodies? Provide some examples to support your answer.
Explanation:
the small bodies in the solar system include comets, asteroids, the objects in the Kuiper Belt and the Oort cloud, small planetary satellites, Triton, Pluto, Charon, and interplanetary dust. As some of these objects are believed to be minimally altered from their state in the young solar nebula from which the planets formed, they may provide insight into planet Earth and the formation and evolution of the solar system.
What quantities belong in cells X and Y?
X: centripetal acceleration
Y: period
X: tangential speed
Y: radius
X: radius
Y: centripetal acceleration
X: period
Y: tangential speed
Answer:
X: period
Y: tangential speed
Explanation:
100% on quiz your welcome(:
The quantities belonging in cells X and Y is to be considered as the
X: period
Y: tangential speed
Quantities belong in cells X and Y:The equation for centripetal acceleration is
= v² / r
here, v should be the tangential velocity of the body
And the radius of curvature.
So based on this, we can say that
Column X. Tangential Speed
Column Y. radius
Learn more about cell here: https://brainly.com/question/15182235
A bar magnet is a permanent magnet, While an electromagnetic temperary?
yes an electromagnetic is temporary
Calculate the p.e. of a 5 kg mass when it is (i) 3 m, (ii) 6 m, above the ground. (g = 10 N/kg)
Explanation:
P.E=MGH
(1) P.E=5×10(G)×3
= 150 kg m^/s^ ( ^ =sqaure)
(2) P.E=5×10×6
= 300 kg m^/s^
Hope it helps, just remember the formula u can solve any question regarding gravition of earth (P.E=Mgh)
1. Day and Night are caused by
10 points
A. The Tilt of the Earth’s Axis.
B. Earth’s Revolution around the sun
C. Earth's ellipical orbit
D. Earth's rotation on its axis.
An object is lifted upward at a constant speed. The gain in potential energy of the object is due to the
(A) work done on the object
(B) total force applied to the object
(C) weight of the object
(D)change in kinetic energy of the object
PLEASE HELP ME
Answer:
b
Explanation:
A car accelerates uniformly from rest to a final speed of 19 m/s in 10. seconds. How far does it travel during this period of acceleration?
Answer:
x = 95 [m]
Explanation:
To solve this problem we must use the following equation of kinematics.
[tex]v_{f} =v_{o} +a*t[/tex]
where:
Vf = final velocity = 19 [m/s]
Vo = initial velocity = 0 (starts from the rest)
a = acceleration [m/s²]
t = time = 10 [s]
Now we can find the acceleration
19 = 0 *a*(10)
a = 1.9 [m/s]
With the second equation we can find the distance:
[tex]v_{f} ^{2} =v_{o} ^{2} +(2*a*x)[/tex]
where:
x = distance [m]
(19)² = (0)² + (2*1.9*x)
3.8*x = 361
x = 95 [m]
Using a force of 10 N, you
push a shopping cart 10 m.
How much work did
you
do?
Answer:
100 JExplanation:
The work done by an object can be found by using the formula
workdone = force × distance
From the question we have
workdone = 10 × 10
We have the final answer as
100 JHope this helps you
Answer if you know
If you give me a good explanation on how quantum mechanics work, you get 20 points and possibly a brainliest.
Answer:
spectra.
Atomic spectra is series of colored lines which occures when atoms emit light of certain wavelengths. Element produces a particular set of spectral lines.
Electrons exist in shells and each shell has a specific energy. Electrons absorb photons and jump to higher energy levels.
Explanation:
What happens to the kinetic energy of a hot drink when an ice cube is put into the drink?
Answer:
Heat is kinetic energy -- the higher the temperature of a substance, the faster and farther its molecules move.
Explanation:
... Conversely, when heat transfers from your beverage to the ice and the temperature of the liquid drops, the molecules in the beverage slow down. When those molecules slow down, their kinetic energy decreases.
What is the root of all electrical systems?
1 batteries
2 electrons
3 atoms
4 non of the above
Answer:
I believe it's 2. I am not sure though.
How far will you travel in 3.5 hrs if you have an average velocity of 90 km/hr
Answer:
The answer is 315 km
Which of the following statements is correct.
A. A direct relationship exists between frequency and wavelength, as the frequency increase from Radio waves to Gamma rays so does the wavelength.
B. A direct relationship exists between frequency and wavelength, as the frequency decrease
from Radio waves to Gamma rays so does the wavelength.
C. An indirect relationship exists between frequency and wavelength, as the frequency increase
from Radio waves to Gamma rays the wavelength decrease.
D. An indirect relationship exists between frequency and wavelength, as the frequency decrease
from Radio waves to Gamma rays Wie wavelength increase
Two forces act on a 6.00-kg object. One of the forces is 10.0 N. If the object accelerates at 2.00 m/s2
,
what is the greatest possible magnitude of the other force?
Given :
Two forces act on a 6.00-kg object. One of the forces is 10.0 N.
Acceleration of object 2 m/s².
To Find :
The greatest possible magnitude of the other force.\
Solution :
Let, other force is f.
So, net force, F = 10 + f.
Now, acceleration is given by :
[tex]a=\dfrac{F}{mass}\\\\a= \dfrac{10+f}{6}\\\\\dfrac{10+f}{6}=2\\\\f = 12 - 10\\\\f = 2 \ N[/tex]
Therefore, the greatest possible magnitude of the other force is 2 N.
Hence, this is the required solution.
Why did scientist's gather at Los Alamos in 1945.
A constant force acting on a body of mass 2 kg changes its
velocity from 1 m/s to 2 m/s in 20 s. If the direction of motion of
the body remains unchanged, the magnitude of the force that acted
on the body was 0.1 N.
True or False
Answer:
the correct answer is b
Answer:
true
Explanation:
just did it on ck12 lol
A box weighing 12,000 N is parked on a 36° slope. What will be the component of the weight parallel to the plane that balances friction *
Fg sin 36 degrees
Fg cos 36 degrees
Fg tan 36 degrees
Fg x N
Given :
A box weighing 12,000 N is parked on a 36° slope.
To Find :
What will be the component of the weight parallel to the plane that balances friction.
Solution :
The component of that will be parallel to the plane to balance friction is :
[tex]F \ cos ( 90 - 36)^o\\\\F\ ( sin\ 36^o)[/tex]
Therefore, component of force to balance friction is F sin 36° .
Hence, this is the required solution.
When the car was stopped by the tree, its change in velocity during the collision was -6 meters/second. This change in velocity occurred in 2 seconds. What was the acceleration of the car?
In a physics lab, students take a long piece of string and cut it into two unequal pieces. One piece is used to suspend a large weight. The second piece is tied to the bottom of the weight as seen in the diagram below. Student 1 predicts that the upper string will always break first since it has to support the weight and the applied force, while Student 2 disagrees and predicts that the shorter piece of string will always break first if you pull slowly but with enough force to exceed the strength of the string.
(a) Which aspect(s) of Student 1’s reasoning, if any, are correct? Explain your answer.
(b) Which aspect(s) of Student 2’s reasoning, if any, are correct? Explain your answer.
(c) Which aspect(s) of both Student 1’s and 2’s reasoning, if any, are incorrect? Explain your answer.
(d) The experiment is performed and both students are surprised to learn that whether
the upper or lower string breaks first depends on whether you pull slowly or with a
sudden pull. Resolve the two lines of reasoning of Student 1 and Student 2 by
explaining the results of the experiment in a clear, concise paragraph.
Answer:
(a) The aspect of the upper string supporting the weight and the applied force
Student 1 is correct because the upper string is the source of support of the large weight and the force applied to the short string reacts at the support of the long string
(b) The aspect of Student's (2) reasoning that is correct is that the shorter piece of string will always break first, however, the statement is only true for sudden pull due to the increased force experienced by the shorter string from a more rapid change in momentum
(c) The aspect of Student 1's statement that is incorrect is the that the upper string will always break first
The aspect of Student 2's statement that is incorrect is the that the shorter piece of string will always break first
(d) A string will break when subject to a force equivalent to its breaking force. The force experienced by the string increases as the rate of pull (suddenness) increases and the suddenness increases inversely with the length of the string, as such the shorter lower string will break first from a sudden pull before the force of the pull is completely transmitted to the upper string. Whereby the lower string is slowly pulled, the force is evenly transmitted to the upper string which is then taking up the load of the weight and the applied force together and is likely to break first
Explanation:
From Smallest to Largest
Moon
asteroid
meteorite
meteoroid
how is an object's motion related to speed, velocity, and acceleration?
Answer:
Speed describes only how fast an object is moving, whereas velocity gives both the speed and direction of the object’s motion being a vector quantity. The standard unit to measure velocity is meter per second (m/s or ms-1). For example, “10 meters per second” is scalar and “10 meters per second West” is vector. Acceleration
If Chris throws the baseball 60 meters forward in 4.2 sec, what is the velocity of the ball? I need answer immediately
Answer:
14.3 m/s
Explanation:
velocity equation
v= d/t
v= 60/4.2
v=14.28
round it to 1 decimal place
v= 14.3m/s
A box sitting still on the ground by itself has a Normal Force of 700N, what is the mass? (gravity’s acceleration is 9.80 m/s²)
1. Calculate the pressure of an object with an area of 10m2 force of 5N exerted
on it
Answer:
2
Explanation:
pressure(p)=force(f)\area(a)
If the weight of an object on the moon is 1/6 of the weight of an object on earth. What
would be the weight of an object on the moon who has the weight of 4800 N on earth?
Answer:
1200 N
Explanation:
Answer:
1200N
Explanation:
Suppose a body of mass "m" and its weight on the moon is Wm (where W is the weight and "m" is the moon ;which means weight on the moon).Mass of the moon is "M"
and its radius is "R"
Weight of an object on the moon = "F"(Force)with which the moon pulls.
Wm = GM*m/r2
Weight of the same object on the earth is We(where W is the weight and "e" is the earth; which means weight on the earth).
Mass of the earth is 100 times of that of the moon.
Radius of the moon = R
Radius of the Earth = 4R
Weight of the object on the moon =
We = G100M*m/(4R)2(Pronounced 4 R square)
We = G100M*m/(16R)2(Pronounced 16 R square)
Wm/We = G * M * m * 16R2/R2 * g * 100M * m
=16/100
Therefore, 4800N on earth= 1200N on moon