A liquid has a volume of 4 mL and a mass of 24 g, 6gm/mol is the density of the liquid.
What is density?Density is the mass of a material substance per unit volume. d = M/V, where d is density, M is mass, and V is volume, is the formula for density. The unit of density that is most frequently used is grams per cubic centimeter, or gm/mol.
One of an object's most significant and practicable physical characteristics is density. Densities are often used to identify pure substances, classify mixtures, and estimate their composition.
To calculate volume of a substance, we use the equation:
Density = Mass/volume
We are given:
Mass of liquid = 24 g
Volume of liquid = 4 ml
Putting values in above equation, we get:
density = 24 gm /4 ml
or, density = 6 gm/mol.
Hence, the density of liquid is 6 g/ml
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When pentane(C5H12) reacts with oxygen, carbon dixoide and water is produced.
If 18.7 grams of pentane is burned, what mass of carbon dioxide is produced?
Pentane, which has the chemical formula C5H12, reacts with oxygen to produce carbon dioxide and water according to the following balanced chemical equation:
2 C5H12 + 25 O2 -> 10 CO2 + 12 H2O
To determine the mass of carbon dioxide produced when 18.7 grams of pentane is burned, we can use the stoichiometry of the chemical reaction. Stoichiometry is the study of the quantities of reactants and products in a chemical reaction, and it allows us to predict the amount of a product that will be produced based on the amount of reactant consumed.
Since the chemical equation is balanced, we know that for every 2 molecules of pentane that react, 10 molecules of carbon dioxide are produced. This means that for every 2 grams of pentane that react, 10 grams of carbon dioxide will be produced.
Since 18.7 grams of pentane is equivalent to 18.7 / 2 = 9.35 moles of pentane, we can use this value to calculate the number of moles of carbon dioxide produced:
9.35 moles of pentane * (10 moles of CO2 / 2 moles of C5H12) = 9.35 * 5 = 46.75 moles of CO2
To convert the number of moles of carbon dioxide to mass, we can use the molar mass of carbon dioxide, which is 44.01 grams per mole:
46.75 moles of CO2 * 44.01 grams/mole = 2068.7 grams of CO2
Therefore, if 18.7 grams of pentane is burned, approximately 2068.7 grams of carbon dioxide is produced.
For the chemical reaction
3KOH+H3PO4⟶K3PO4+3H2O
how many moles of potassium phosphate (K3PO4) are produced from 6.0 mol of potassium hydroxide (KOH)?
Answer:
2 moles
Explanation:
if 3 moles are used to produce one mole of K3PO4what about six do the maths if 3 is equal to one what about 6answer is twoGiven the approximate pH of the following items, calculate the pOH, the [H+], and the [OH-]: oranges 3.5, rainwater 6.2, milk of magnesia 10.5.
pH plus pOH equals 14. POH equals -log[OH-]. The pOH is a measure of a solution's basicity, whereas the pH is a measure of a solution's acidity.
The pOH equation is what How can pH be used to calculate pOH?The concentration of hydrogen ions in a solution is gauged by its pH value. The concentration of hydroxide ions in a solution is determined by its pOH value. The formula pH + pOH = 14 relates the pH and pOH.
What is the pOH formula?You must know the hydroxide ion concentration in moles per liter to calculate the pOH of a solution. The following expression is used to calculate the pOH: pOH equals -log [OH-].
Calculation:pH of oranges 3.5
pH of rainwater 6.2
pH of milk of magnesia 10.5
pH + pOH = 14
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A mixture of 14.2 g of H2 and 36.7 g of Ar is placed in a 100.0 L container at
STP.
a. What is the total pressure in atmospheres inside the container?
b. What is the mole fraction and partial pressure of H2 in atmospheres?
c. What is the mole fraction and partial pressure of Ar in atmospheres?
a) The total pressure of the system is 1.79 atm
b) The mole fraction and partial pressure of hydrogen is 0.89 and 1.59 atm respectively
c) The mole fraction and the partial pressure of argon is 0.11 and 0.19 atm.
What is the total pressure?We know tat we can be able to obtain the total pressure in the system by the use of the ideal gas equation. We would have from the equation;
PV = nRT
P = pressure
V = volume
n = Number of moles
R = gas constant
T = temperature
Number of moles of hydrogen = 14.2 g/2g = 7.1 moles
Number of moles of Argon = 36.7 g/40 g/mol
= 0.92 moles
Total number of moles = 7.1 moles + 0.92 moles = 8.02 moles
Then;
P = nRT/V
P = 8.02 * 0.082 * 273/100
P = 1.79 atm
Mole fraction of hydrogen = 7.1/8.02 = 0.89
Partial pressure of hydrogen = 0.89 * 1.79 atm
= 1.59 atm
Mole fraction of argon = 0.92 / 8.02
= 0.11
Partial pressure of argon = 0.11 * 1.79 atm
= 0.19 atm
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Question 32 of 43
Indicate the electron pair geometry and the molecular geometry for each of the six compounds
1) Electron pair geometry - tetrahedral
Molecular geometry - bent
2) Electron pair geometry - tetrahedral
Molecular geometry - bent
3) Electron pair geometry - tetrahedral
Molecular geometry - linear
4) Electron pair geometry - tetrahedral
Molecular geometry - trigonal bipyramidal
5) Electron pair geometry - trigonal planar
Molecular geometry - trigonal planar
What is the electron pair geometry?We know that a compound would have its structure based on the number of electrons pairs that can be found on the valence shell of the atom. According to the valence shell electron pair repulsion theory, the electron pairs that surround the valence shell would be the major determinant of the structure of the compound.
We also have to recall that the number of the lone pairs and the bond pairs in the compound are also a key as we want to determine the structure. This is because, while all the electron pairs count towards the electron pair geometry, the bond pairs count towards the molecular geometry of the compound.
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The electron configuration of a Ti atom is A) [Ne]3s23d2. B) [Ne] 3s24d2 C) [Ar]4s 3d2 D) [Ar]4s24d2 E) [Ar]3d 2. The electron configuration of an Fe2ion is A) [Arj4s24d. B) [Ar]4s23d6. C) Ar]3d. D) [Ar]3d5. E) Ar]3d 3. The total number of electrons in the 3d orbitals of a copper atom is A) 6 B) 7 C)8 D) 9 E) 10 4. How would you expect the molecule 1,10-phenanthroline (shown below) to functi a ligand? C-C ?-? H-C C-C C-H CEN A) It would be expected to be a monodentate ligand. B) It would be expected to be a bidentate ligand. C) It would be expected to be a tridentate ligand. D) It would be expected to be a tetradentate ligand E) It would not be expected to function as a ligand. 5. In the complex ion (Co(en)2Bralt, the oxidation number of Co is 6. Give the coordination number (C.N.) and oxidation number (O.N.) of the meta in the coordination compound ICr(NHs)len )Cla]. C) CN. = 5; O.N. = +2.
The electronic configuration of Ti is d)[Ne]3d²4s². The electronic configuration of Fe2+ is b)[Ar]4s²3d⁶. The total number of electrons in the 3d orbitals of Copper is E)10. The molecule 1-10phenanthroline is b)bidentate ligand and coordination number and oxidation number of (Cr(NH₃)₂(en)Cl₂ is E) CN = 6; ON = +2
A) The electron configuration of a Ti atom is d) [Ne]3d²4s².
This is the correct answer because Titanium (Ti) is a transition metal with atomic number 22. Therefore, it has 22 electrons with the following configuration: 1s² 2s² 2p⁶ 3s² 3p⁶ 3d² 4s².
B) The electron configuration of a Fe2+ ion is b) [Ar]4s²3d⁶.
This is the correct answer because Iron (Fe) is a transition metal with atomic number 26. Therefore, it has 26 electrons with the following configuration: 1s² 2s² 2p⁶ 3s² 3p⁶ 3d⁶ 4s². When it forms a Fe²⁺ ion, it loses two electrons from the 4s orbital, leaving [Ar]4s²3d⁶ as the electron configuration.
C) The total number of electrons in the 3d orbitals of a copper atom is E) 10.
This is the correct answer because Copper (Cu) is a transition metal with atomic number 29. Therefore, it has 29 electrons with the following configuration: 1s² 2s² 2p⁶ 3s² 3p⁶ 3d¹⁰ 4s¹. Therefore, the total number of electrons in the 3d orbitals is 10.
D) b) It would be expected to be a bidentate ligand. This is the correct answer because 1,10-phenanthroline is a bidentate ligand, meaning it can bind to two electron-rich sites at the same time. It binds to the metal center through its nitrogen atom and an oxygen atom. Therefore, it is expected to be a bidentate ligand.
E) In the complex ion (Cr(NH₃)₂(en)Cl₂, the oxidation number of Co is +2 and the coordination number is 6. Hence the correct option is E).
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Answer: B. [Ar] 4s23d2
Explanation:
A.[Ar]4s23p2
B.[Ar]4s23d2
C.[Ar]4s24d2
D.[Ar]4s24p2
Would an action potential be possible without the presence of proteins? Explain your
response.
A. Yes, the action potential would be possible since the Na+ being hydrophobic can enter the neuron through the phospholipid bilayer.
B. No, the action potential would not be possible since Na+ being hydrophilic would not be able to move across the plasma membrane.
C. No, the action potential would not be possible since Na+ being hydrophilic would not be able to move across the plasma membrane unless ATP was available
Action potential would not be possible because ions would not be able to move across the plasma membrane without the channels provided by proteins.
What is action potential ?When the membrane potential of a particular cell site rapidly increases and decreases, an action potential happens. Following this depolarization, nearby areas also experience depolarization. Excitable cells, which include neurons, muscle cells, and some plant cells, are a class of animal cells that exhibit action potentials.
Larger protein molecules are integrated within a lipid bilayer that makes up a cell membrane. The lipid bilayer serves as an insulator because it impedes the flow of electrically charged ions very effectively.
Action potentials are produced by channel proteins, which change their state from closed to open depending on the voltage differential between the cell's interior and exterior.
Therefore, action potential is not possible without proteins.
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which of the following should be compared when deciding whether a given nucleophilic acyl substitution reaction will occur as written? select all that apply.
The following should be compared when deciding whether a given nucleophilic acyl substitution reaction will occur as written :
the relative basicity of the nucleophile and leaving group.The nucleophilic acyl substitution reaction will occur as written there are the following that we should compare is given as follows :
we should compare the relative basicity of the nucleophile and the basicity of the leaving group.the abilities of the relative abilities of the leaving group to nucleophile and the leaving group.The nucleophilic acyl substitution is the reaction in which the carbonyl and the nucleophile will forms a new bond of the acyl group.
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Calculate the amount of heat needed to melt 99.9 g of solid acetic acid (HCH,CO2) and bring it to a temperature of 85.1 °C. Round your answer to 3 significant digits. Also, be sure your answer contains a unit symbol
Q = 1.161 J/kg of heat is required to melt 99.9 g of solid acetic acid (HCH,CO2). Q = mL(Latent heat is the energy emitted or absorbed by a body while changing it state ). (Latent heat is the energy released or absorbed by a body while changing it state ).
How to fix?Apply the equation Q = mL where:
Energy is Q. (J)
m = Mass (g)
L = Acetic acid's latent heat of fusion 192(J/g) = J/g
Q is equal to 0.099 kg times 11.73 kj/mol.
Q = 1.161J/kg.
What is latent heat, and what varieties are there?Latent heat is the amount of energy that a substance experiencing a change in state, such as ice turning into water or water turning into steam, can absorb or release while maintaining a constant temperature and pressure. Types: The material exists in three states: solid, liquid, and gaseous.
What does "sensible heat" mean?Heat that can actually be felt is considered to be sensible heat. Instead of the phase shifting, energy is what causes the temperature to vary as it moves from one system to another. For instance, it warms the water instead of melting the ice.
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Compare the viscosity of neopentane, (CH3)4C, and n-pentane.Match the words in the left column to the appropriate blanks in the sentences on the right. Make certain each sentence is complete before submitting your answer. You would expect the viscosity of _____ to be larger mainly because _____ when compared to the other hydrocarbon. the spherical shape results in weaker dispersion forces the cylindrical shape results in stronger dispersion forces the linear shape means the molecule is more polar the symmetrical shape means tire molecule is less polar neopentane n-pentane
You would expect the viscosity of n-pentane to be larger mainly because the cylindrical shape results in stronger dispersion forces when compared to the other hydrocarbon.
It can be seen that the surface area of pentane increases because all carbon atoms are densely packed in neopentane. Therefore, the van der Waals forces are stronger in pentane and the intermolecular forces are stronger. Pentane is therefore the most vicious of the pair.
n-pentane has a higher boiling point than neopentane. The linear form of n-pentane mixes well with other n-pentane molecules, forming well-compacted layers of solids that are more difficult to separate. Viscosity is determined by the strength of the intermolecular forces, especially the shape of the molecules in the liquid.
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how to balance equation
Answer:
Count each type of atom in reactants and products. ...
Place coefficients, as needed, in front of the symbols or formulas to increase the number of atoms or molecules of the substances. ...
Repeat steps 1 and 2 until the equation is balanced.
Explanation:
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Question 30 of 43
The balanced equation for the neutralization reaction of aqueous H2SO4 with aqueous KOH is shown.
H2SO4 (aq) +2KOH (aq) → 2H2O+K2SO4 {aq}.
What volume of 0.240M KOH is needed to react completely with 11.4mL of 0.110M H2SO4 ?
The volume of 0.240 M KOH to react completely with 11.4 ml of 0.110 M sulphuric acid is 5.225 ml.
What is molarity?Molarity of a solution is the ratio of the number moles of solutes to the volume of solution in liters. Molarity is most common term used to express the concentration of a solution.
Let the volume and molarity of the titrant be V1 and M1 respectively and the volume of molarity of the analyte be V2 and M2 then,
M1 V1 = M2 V2.
Given volume of H₂SO₄ = 11.4 ml
Molarity = 0.11 M
Molarity of KOH = 0.24 M
volume of KOH = (11.4 ml × 0.11 M) / 0.24 M
= 5.225 ml.
Hence, the volume of KOH needed for the titration with sulphuric acid is 5.2 ml.
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Determine the equilibrium constant at 255 K for the following reaction under acidic conditions.
4H+ (aq) + MnO₂ (s) + 2Fe²+ (aq) ———› Mn²+ (aq) + 2Fe³+ (aq) + 2H₂O(1)
The two half-reactions are:
MnO₂ (s) + 4H+ (aq) + 2e¯¯ ———› Mn²+ (aq) + 2H₂O(1) E* = 1.23 V
Fe³+ (aq) + e, Fe²+ (aq) E³ = .0.770 V
Temperature is supplied to us as 225 K. The reduction potential potentials will be used to get it equilibrium constant for the this reaction.
What does equilibrium mean in its simplest form?Definition of EQUILIBRIUM as a noun in the Britannica Dictionary. [noncount] 1. a condition when conflicting forces or acts are matched so that neither is stronger or more significant than the other.
What does the term "equilibrium" signify in biology?The forces that affect the body must balance out with an equivalent and opposing force for there to be a condition of equilibrium. The physiological state of equilibrium, wherein forces internal and external are all in balance, in an active moving animal. The system is hence stable.
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1. What is the use of the following reagents in the various organic reactions?
a. Carbon tetra chloride in the preparation of alkynes (5 marks)
b. Hydrogen bromide in the preparation of alkynes (5 marks)
a. Carbon tetra chloride is used as a solvent in the preparation of alkynes through the process of dehydrohalogenation. It acts as a reactant in the reaction, where it is converted into a chloride ion and a molecule of acetylene.
b. Hydrogen bromide is used in the preparation of alkynes through the process of bromination. It acts as a reactant in the reaction, where it is converted into a bromide ion and a molecule of acetylene. It is typically used in the presence of a Lewis acid catalyst, such as aluminum chloride, to facilitate the reaction.
Answer: A. Carbon tetrachloride (CCl4) is used as a solvent and a reactant in the preparation of alkynes through a reaction known as the chloroformic esterification or the Wurtz reaction. In this reaction, an alkyne is treated with CCl4 and sodium metal to produce a chloroformate ester, which can then be hydrolyzed to the corresponding carboxylic acid.
b. Hydrogen bromide (HBr) is used in the preparation of alkynes through a reaction known as the bromination of alkynes. In this reaction, an alkyne is treated with HBr and a Lewis acid catalyst to produce a geminal dibromide, which can then be hydrolyzed to the corresponding alkyne. This reaction is useful for the synthesis of alkyne compounds that are not readily available from other sources.
Both CCl4 and HBr are commonly used reagents in organic chemistry due to their reactivity and versatility. They can be used to synthesize a wide range of compounds, including alkynes, by reacting with various organic compounds under appropriate conditions.