A lump of lead with mass 0.50 kg is dropped from a height of 20 m onto a hard surface. It does not rebound but remains there at rest for a long period of time.
what are:
a)∆Q,(b)∆W and (c)∆U for the lead during this process?
d) What is the temperature change in the lead immediately aer the impact? [specific heat capacity of lead = 128 kJ/kg K]

Answer:

the mouse will overshoot and will not land in the nest.

The initial velocity of the student as he leaves the ground is 3.57 m/s.

The velocity of the student as he leaves the ground can be calculated using the following kinematic equation for upward motion.

v² = u² - 2gh

where;

At the maximum height, the final velocity of the student = 0

0 = u² - 2gh

u²  =  2gh

u = √2gh

u = √(2 x 9.8 x 0.65)

u = 3.57 m/s

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The final velocity of the plane at 250 m distance is 50 m/s.

To calculate the final velocity of plane we need to use the formula from equation of motion,

In equation of motion we will use the formula,

v² = u² + 2as

where,

v is final velocity

u is initial velocity

a is the acceleration of plane

s is the distance

In this given data are,

s = 250 m

a = 5 m/s²

u = 0 m/s ( as the initial of plane is resting )

v = ?

Now, since we know the values, putting them into the formula,

v² = ( 0 )² m/s + 2 x (5 m/s²) x 250 m

v² = 2 x (5 m/s²) x 250 m

v² = 2,500 m/s

v = √2,500 m/s

v = 50 m/s

Hence, the final velocity of the plane at 250 m is 50 m/s.

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a.)  the ball rises to a height of 31.88m

b.) It takes the ball 2.55 seconds to reach its highest point

c.) It takes the ball 2.55 seconds to hit the ground

d.) The ball's velocity is -24.99 m/s in the negative direction which is downwards.

Velocity is the directional speed of a object in motion as an indication of its rate of change in position as observed from a particular frame of reference and as measured by a particular standard of time.

From the given question, we have that

b.) At highest point velocity of the ball will become zero so v=0m/s.

So using equation

v = u + gt

0 = 25 - 9.8t

t = 25/9.8 s =2.551 s

Time taken by the ball to reach its highest point will be 2.551 seconds .

a.)  The height the ball rises is given by

v²-u²=2gh

=> 0-(25.0)²=-2*9.8*h

=> 19.6h= (25.0)²

=> h= 31.88m.

c.)  It will take the ball 2.55 seconds to hit the ground

after it reaches its highest point because it will take the ball same time for the ball to reach its highest point or fall to the ground.

d.) velocity = u - gt

V = 0 - 9.8 * 2.55

V= -24.99 m/s in the negative direction which is downwards.

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Given that the time taken to reach the ground is t = 6 s

The final velocity is v = 0m/s

We have to find the height of the monument, h.

The initial velocity can be calculated by the formula

Here, g is the acceleration is due to gravity whose value is 9.81 m/s^2

Substituting the values, the initial velocity will be

The formula to find height is

Substituting the values, the height will be

Thus, the correct option is 177 m.

The weight of the rider will remain the same that is 65 kg after the ride is finished because the weight does not depend on speed.

It gauges how much gravity is pulling on a body.

Weight being a force, the SI unit of weight is the Newton, which is also the same as the SI unit of force (N). When we look at how weight is expressed, we can see that it depends on both mass and the acceleration caused by gravity; while the mass may not change from one location to another, the acceleration caused by gravity does.

According to the question, the weight will remain same because weight depends on mass and gravity but not the speed. As per the definition of weight it is the product of mass and gravity, it means for different plants the weight will be different but for the same planet the weight will be the same everywhere.

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The formula for determining the gravitational potential energy of the balloon is expressed as

Energy = mgh

where

m is the mass of the ballon

g is the accelaration due to gravity and the value is 9.8m/s^2

h is the height of the balloon above the ground

From the information given,

m = 371

h = 615

Thus,

= 371 x 89.8 x615 = 22316017 NKJoulesJoules8298.651

Answer:

That is human_scale thinking and understanding

Explanation..

If you are going to consider stars(sun's), then you have to thik on a more cosmological scale stars are prodigiously immense which means they can burn 4 million tons of their fuel per second and not even realize it.

Consider this_if the life of our sun is of the order of 8 billion years, then it takes two billion years to bum only a quit of its fuel.

The universe is a very large place and if you are going to understand it, you have to think large.

Answer:

HOW TO DO IT…

Use the correct cutting oil on the tap when cutting threads.

Turn the tap clockwise one-quarter to one-half turn, then turn back three-quarters of a turn to break the chip.

When tapping a blind hole, use the taps. in the order starting, plug, and then bottoming.

The development of complex societies depends of the Northwest Coast tribes on;

The term society just has to do with people that are found to live around a give geographical area. This is the way the people tend to live along with the civilization that they may tend to have actually created over a long period of time as we can see.

Having said thus, the people of the are the people that there originally found around the west of which the original native Americans also formed a huge part of. These were the people that tend to be found around the Americas before the onset of modern civilization as we can se.

The factors that  helped Northwest Coast tribes develop complex societies are found in the section above. These factors saw to the development of the region.

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The potential energy of an object of mass m at a height h from the ground on the Earth, where the gravitational acceleration is g, is:

As we can see, the velocity of the object is not a variable that needs to be taken into account to find the potential energy,

Then, the answer is:

Based on the given figure, you have that the components of the forces on the direction of the incline are:

applied force:

Fa = 500N*cos(-30°) = 433.01N

friction force:

Fr = µk*N = µk*m*g*cos(30°) = (0.42)(40kg)(9.8 m/s^2)cos(30°) = 142.58N

gravitational force:

Fg = m*g*sin(30°) = (40kg)(9.8)sin(30°) = 196.0N

Next, consider that the work done by a force is equal to the product of the force and the distance at which the force is applied. In this case, such distance is 8m.

Then, you have:

Work done by the applied force:

WFa = (433.01N)(8.0m) = 3464.08 J

Work done by the friction force:

WFr = (142.58N)(8.0m) = 1140.64 J

Work done by the gravitational force:

WFg = (196.0N)(8.0m) = 1568.0 J

Finally, the net work, based on the direction of the forces, is:

Net work = WFa - WFr - WFg = 3464.08J - 1140.64J - 1568.0J = 755.44J

Hence, the net work is 755.44 J

Answer: Wfr = -1883.25 J

Explanation:

1) In the x direction (direction of motion of the crate):

Fcos(30^o) - f_fr - mgsin(30^o ) = 0 (because a_x = 0)

f_fr = Fcos(30^o ) - mgsin(30^o)

f_fr = (498)(√3/2) - (40)(9.81) (1/2) = 235.28 N

⇒ W_fr = f_fr.s.cos(180^o) = -(235.28)(8.0) = -1882.25 J (1)

2) In the y direction (perpendicular to the motion of the crate):

n - Fsin(30^o) - mgcos(30^o) = 0 (because a_y = 0)

⇒ n = Fsin(30^o) + mgcos(30^o) = (498)(1/2) + (40)(9.81)(√3/2) = 588.83 N

⇒ f_fr = μ_k.n = (0.40)(588.83) = 235.53 N

⇒ W_fr = f_fr.s.cos(180^o ) = -(235.53)(8.0) = -1884.24 J (2)

Average of calculations (1) & (2): W_fr = -1883.25 J

Answer: i usually use the calendar on my phone to set my day or i make plans with other people.

The y-component of the constant net force applied to the car to bring it to a stop is mathematically given as

F_y =666.38N

This is further explained below.

Generally, In the field of physics, an influence that may alter the motion of an object is referred to as a force.

An object having mass may experience a change in its velocity, often known as acceleration, when subjected to a force.

Intuitively, force may also be conceptualized as either a push or a pull. Because it may be measured in both magnitude and direction, a force is considered a vector quantity.

When considering coplanar force of a point or a body we tend to consider the x components and the y components of force as they come together to give the Net Force or the resultant for and directions of force.

But for this case we shall strictly consider the y company of force as it pertains to this body and its force independent of the x components force as regards to Resultant force

In conclusion,

v^2 =2 a s

[tex]a &=\frac{v^2}{25}=\frac{(18.4)^2}{2 \times 268} \\\\[/tex]

a =0.631ms^2

F_y =m a

F_y=1055* 0.631

F_y =666.38N

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THE MASS OF AN OBJECT IS 1100

The mass of the Sun is 1.98 * 10³⁰ kg.

The mass of the Sun is calculated from the data given about Venus as follows:

radius of Venus from the Sun = 1.08 x 10¹¹ meters

Period of rotation of Venus around the Sun, T = 224.7 days.

T in seconds = 224.7 * 24 * 3600 = 1.94 * 10⁷ s

Force of gravity = Centripetal force

GMm/r₂ = mv²/r

M = mass of Sun

m = mss of Venus

M = rv²/G

G = 6.67 * 10⁻¹¹ m³kg⁻¹s⁻²

But v = 2πr/T

v = 2 * 3.14 * 1.08 x 10¹¹ / 1.94 * 10⁷

v = 3.496 * 10⁴ m/s

Hence;

M =  1.08 x 10¹¹ * (3.496 * 10⁴)² / 6.67 * 10⁻¹¹

M = 1.98 * 10³⁰ kg

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The linear velocity of a point p(5,1,3) on the body relative to a point Q(3,4,2) on the axis of rotation​ is 17.13 m/s.

Linear velocity is defined as the rate of change of displacement with respect to time when the object moves along a straight path.

The relationship between linear velocity and angular velocity is given as;

v = ωr

where;

The magnitude of the radius is calculated as follows;

r = √[(5-3)² + (1-4)² + (3-2)²]

r = 3.74 m

The magnitude of the angular speed is calculated as;

ω = √[(-4)² + (1)² + (-2)²]

ω = 4.58 rad/s

The linear speed of the object is calculated as follows;

v = ωr

v = (4.58 rad/s) x (3.74 m)

v = 17.13 m/s

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Answer:

U = 41.65 J

Explanation:

We have just to calculate it with the following expression of gravitational potential energy:

U = m*g*h

Where:

m: mass

g: gravity acceleration;

h: height.

So:

U = m * 9.8 * 0.85

U = 8.33 * m

Then, it is just putting the mass value of the dog in that equation to obtain the value of potential energy acquired by the dog when jumping.

The mass of this kind of dog is between 3.6kg - 5kg, so, the maximum value of the potential energy can be like this:

U = 5 * 9.8 * 0.85

U = 41.65 J

Take into accouint that the regions that suffer deforestation tend to generate soil erosion to eventually become non-productive land.

Then, from the given choices you have that deforestation impacts in the following way:

The elimination of a protective covering causes the sun to dry out the ground.

According to the given statement the heat absorbed is 43676.78 J .

The water's specific heat and the formula Q= mcΔT are used to compute the amount of heat absorbed. At 100°C, water vaporizes into steam. Calculating the amount of heat absorbed requires multiplying the number of moles of water by the molar heat of vaporization.

Mass, m = 227.1grams

To find how much heat is absorbed when 227.1 grams of steam is heated from  115.6°C to 12.2°C.

Heat absorbed is given by :

Q= mcΔT

c is specific heat of water

Put all the values, we get :

Q = 227.1 * 1.86 * (115.6 - 12.2)

Q = 43676.78 J

43676.78 J heat is absorbed.

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The difference in the acceleration due to gravity on the moon and the Earth are different due to the difference in their masses and radius.

Yes, can shield a gravitational field in a vacuum by coming in between the mass and gravitational source.

Newton's law of universal gravitation states that every two objects in the universe attracts each other with a force directly proportional to the product of the masses and inversely proportional to the distance between the two objects.

F = GmM/R²

where;

From Newton's second law of motion,

F = mg

where;

mg  = GmM/R²

g = GM/R²

Thus, the acceleration due to gravity on the moon and the Earth are different because of difference in their masses and radius.

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The conservation of momentum states that the total intiial momentum is equal to the total final momentum. In this cae this will mean that:

Given:

Let's determine the preferred units used when measuring the velocity of the center of mass.

The center of mass can be said to be the mean position of matter in a given system.

This is the point in a body where the whole mass of the body is concentrated upon.

The SI unit for center of mass is meters (m).

When measuring the center of mass, the preferred unit is meters per second.

herefiore, when measuring the velocity of the center of mass, the preferred unit is meters/second.

• NSWER:

A. meters/second

According to the give statement:

a)Work done on the gas is 567 J.

b)The change in its internal energy is 167J.

The temperature and condition of a substance are examples of internal energy. For instance, the internal energy of water is influenced by its temperature as well as whether it is in a solid, liquid, or gas state. Due to its condition, liquid water has greater stored energy than copper metal at the same temperatures.

The work done on the gas is evaluated using formulas:

W = -p * ΔV

Only the large volumes which is signified by large data Substituting the known values we obtain

W= 0.8 * 1.01325 * 10⁵ Pa * -1 (-7) * 10⁻³ m³

W = 567 J

Change in Internal energy is given by

ΔU=W - Q

=567−400)

=167J

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a ) The tension in a vertical strand = 68.6 * [tex]10^{-5}[/tex] N

b ) The tension in a horizontal strand = 149.13 * [tex]10^{-5}[/tex] N

c ) Tension in horizontal strand / Tension in vertical strand = 2.17

a ) The tension in a vertical strand,

m = 7 * [tex]10^{-5}[/tex] kg

g = 9.8 m / s²

Since the strand is vertical and the spider is motionless,

∑ [tex]F_{y}[/tex] = 0

T - mg = 0

T = 7 * [tex]10^{-5}[/tex] * 9.8

T = 68.6 * [tex]10^{-5}[/tex] N

b ) The tension in a horizontal strand,

θ = 13.0°

The strands left and right have same magnitude and makes the same angle with the horizontal. Resolving,

sin θ = [tex]T_{y}[/tex] / T

[tex]T_{y}[/tex] = T sin 13.0°

∑ [tex]F_{y}[/tex] = 0

[tex]T_{y}[/tex] + [tex]T_{y}[/tex] - mg = 0

T sin 13.0° + T sin 13.0° = 7 * [tex]10^{-5}[/tex] * 9.8

2 T sin 13.0° = 68.6 * [tex]10^{-5}[/tex]

T = 68.6 * [tex]10^{-5}[/tex] / 0.46

T = 149.13 * [tex]10^{-5}[/tex] N

c ) Ratio of strands,

Tension in horizontal strand / Tension in vertical strand = 149.13 * [tex]10^{-5}[/tex] / 68.6 * [tex]10^{-5}[/tex]

Tension in horizontal strand / Tension in vertical strand = 2.17

Therefore,

a ) The tension in a vertical strand = 68.6 * [tex]10^{-5}[/tex] N

b ) The tension in a horizontal strand = 149.13 * [tex]10^{-5}[/tex] N

c ) Tension in horizontal strand / Tension in vertical strand = 2.17

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Answer:

mrs.casts

Explanation:

she's married

A parallel plate capacitor is connected to a battery that maintains a constant potential difference.

As we know,

Here, Q is the charge which is inversely proportional to the separation between the plates.

That means if the separation between the plates increases the magnitude of the charge on the plates decreases.

Thus, if the separation between the plates is doubled the magnitude of the charge will be cut in half.

The answer is true, that the hydraulic press utilizes Bernoulli's principle.

It can be derived from the Principle of conservation of energy.

According to Bernoulli's principle, which governs fluid dynamics, a fluid's speed increases concurrently with a reduction in pressure or potential energy. The mathematical concept is named after Swiss mathematician Daniel Bernoulli, who first published it in his book Hydrodynamics in 1738.

The venturi tube is a real-world example of Bernoulli's Principle in action. The venturi tube has an air intake that constricts to a throat and an exit segment that widens as it moves backward. The entrance and outflow both have the same diameter.

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In astronomy, luminosity is the power (amount of energy per unit of time) emitted in all directions by a celestial body. It is directly related to the absolute magnitude of the star. The luminosity of the Sun, L☉ is the classical unit used in astronomy to compare the luminosity of other stars. Its approximate value is:

From the options, the correct one is:

A. Sun