A man pushes a 10-kg block 10 m, along a rough, horizontal
surface with a 40-N force directed 37° below the horizontal. If
the coefficient of kinetic friction is 0.2, calculate the total
work done on the block

Answer:

Applications of zeroth law of thermodynamics:

1. When we get very hot food, we wait to make it normal. In this case, hot food exchanges heat with surrounding and brings equilibrium.

2. We keep things in the fridge and those things come equilibrium with fridge temperature.

3. Temperature measurement with a thermometer or another device.

4. In the HVAC system, sensors or thermostats are used to indicate temperature. It always comes in a thermal equilibrium with room temperature.

5. If you and the swimming pool you’re in are at the same temperature, no heat is flowing from you to it or from it to you (although the possibility is there). You’re in thermal equilibrium.

Answer:

3m

Explanation:

Answer:

[tex]p =-1.03[/tex]

Explanation:

From the question we are told that:

Focal length of lens [tex]f=-0.304 m[/tex]

Image distance [tex]q=0.237 m[/tex]

Height of image [tex]H_i=0.343[/tex]  

Generally the lens equation is mathematically given by

[tex]\frac{1}{f} = \frac{1}{q} - \frac{1}{p}[/tex]

Where [tex]p[/tex] is Subject

[tex]p = \frac{(qf) }{(f - q)}[/tex]

[tex]p = \frac{(-0.237)(-0.304)) }{((-0.304) - (0.237))}[/tex]

[tex]p =-1.03[/tex]

Therefore the distance between  the person and the car is

[tex]p =-1.03[/tex]

Answer:

W = F * S = 300 N * 30 m = 9000 Joules

This is the work out of the system regardless of how the pulleys are arranged

Conservation of energy tells that

Work Out = Work In - Work done by friction

So Work In = 9000 J + 2000 J = 11000 J      The work input to the system

Answer:

Z

Explanation:

correct on edge

Answer: Z

good luck!

The term used to describe the block of organs that are removed during the autopsy is Thoracic organs.

The organs that are removed during autopsy include:

The thoracic cavity contains organs and tissues that function in the respirator, cardiovascular, nervous and digestive system.

These thoracic organs include the following;

Thus, we can conclude that the term used to describe the block of organs that are removed during the autopsy is Thoracic organs.

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Answer:

3.44 s

Explanation:

speed=distance/time

=>t = s/v

=> t = 275/80

= 3.437.. s

Answer:

1.04 s

Explanation:

The computation is shown below:

As we know that

t = t' × 1 ÷ (√(1 - (v/c)^2)

here

v = 0.5c

t = 1.20 -s

So,

1.20 = t' × 1 ÷ (√(1 - (0.5/c)^2)

1.20 = t' × 1 ÷ (√(1 - (0.5)^2)

1.20 = t' ÷ √0.75

1.20 = t' ÷ 0.866

t' = 0.866 × 1.20

= 1.04 s

The above formula should be applied

Answer:

Following are the solution to the given question:

Explanation:

For crashing speed, we can use energy conservation:

kinetic energy [tex]= \frac{1}{2}\times m \times v^2[/tex]  

potential energy [tex]= -\frac{GMm}{r}[/tex]

moon mass[tex]= 7.36\times 10^{22} \ kg[/tex]

Radius[tex]= 1738\ km[/tex]  

[tex]\to (K + U) \ orbit = (K + U)\ crash\\\\\to \frac{1}{2}\times m \times v_o^2 - \frac{GMm}{(1738000 + 110000)} \\\\ \to \frac{1}{2}\times m \times vc^2 - \frac{GMm}{1738000}[/tex]

Calculating the mass drop for the leave:

[tex]\to \frac{vo^2}{2} - \frac{GM}{1848000}\\\\ \to \frac{vc^2}{2} - \frac{GM}{1738000}[/tex]

Solve the value for

[tex]vc = \sqrt{(vo^2 +2\times GM \times(\frac{1}{1738000} - \frac{1}{1848000}))}\\\\vc = \sqrt{(1600^2 +2\times 6.67\times 10^{-11} \times 7.36 \times 10^{22}\times (\frac{1}{1738000} - \frac{1}{1848000}))}\\\\vc = 1701 \ \frac{m}{s}\\\\[/tex]  

The approach is correct but misrepresented in replacing 180 km instead of 110 km.

Answer: True

Explanation:

Government as an academic field of study refers to the study of political institutions, processes and theories taught in schools, colleges and higher institution of learning. It is called Political Science in higher institution.

Longitudinal waves

In a longitudinal wave the particles are displaced parallel to the direction the wave travels.

Answer:

a. The system will rotate in the clockwise direction with a constant angular speed.

Explanation:

As all the clay is identical sphere and there will be hence same mass 'm' for all three clay spheres. Now their identical speed 'v' and collision time [tex]$'t_0'$[/tex] are also same. So all the spheres will exert same force F on the rod.

[tex]$f=\frac{mv}{t_0}$[/tex]

Force exerted by the clay Z on rod is passing through pivot, so no torque will be produced.

Now clay X will collide at near distance from pivot than that of clay Y.

So clay Y will produce more torque than clay X. So clay Y will give more clockwise torque. So rod will rotate clockwise.

Now in any impact because net force and net torque are zero (because in impact torque and force occurs in equal and opposite pairs). So net angular momentum will be conserved and hence angular speed will be constant.

Therefore it is clear that option (a) is correct.

Answer:

300

Explanation:

the momentum is 300

p=mv

p=5×60

5×60 =300

Solution :

Given :

Mass of grinding wheel, m = 700 g

                                             = 0.7 kg

Diameter of the grinding wheel, d = 22 cm

                                                         = 0.22 m

Radius of the grinding wheel, r = 0.11 m

Initial angular velocity of grinding wheel, [tex]$\omega_0$[/tex] = 215 rpm

                                                                               [tex]$=215 \ rpm \times \frac{2 \pi \ rad}{1 \ rev}\times \frac{1 \ min}{60 \ s}$[/tex]

where, [tex]$\pi = \frac{22}{7}$[/tex]

Time taken to stop, t = 50 s

Final angular velocity is [tex]$\omega$[/tex] = 0

Angular acceleration of the grinding wheel is given by :

[tex]$\alpha = \frac{\omega-\omega_0}{t}$[/tex]

   [tex]$=\frac{0-215 \ rpm \times \frac{2 \pi \ rad}{1 \ rev}\times \frac{1 \ min}{60 \ s}}{50 \ s}$[/tex]

   [tex]$=-0.45 \ rad/s^2$[/tex]

Magnitude of the angular acceleration of grinding wheel [tex]$\alpha$[/tex] [tex]$=-0.45 \ rad/s^2$[/tex]

Moment of inertia of the grinding wheel (solid disk),

[tex]$I=\frac{1}{2}mR^2$[/tex]

   [tex]$=\frac{1}{2} \times 0.7 \times 0.11^2$[/tex]

  [tex]$=4.235 \times 10^{-3} \ kgm^2$[/tex]

Torque exerted by friction while the wheel is slowing down is

[tex]$\tau = I \alpha$[/tex]

  [tex]$=4.235 \times 10^{-3} \times 0.45$[/tex]

 [tex]$=1.90 \times 10^{-3} \ Nm$[/tex]

Answer:

F=ma

Explanation:

Force is equal to mass multiplied by area

Force= mass × area

In turn the formula can be twisted so

Force/mass= area

Force/area= mass

Answer:

It states that the rate of change of velocity of an object is directly proportional to the force applied and takes place in the direction of the force. It is summarized by the equation: Force (N) = mass (kg) × acceleration (m/s²). Thus, an object of constant mass accelerates in proportion to the force applied.

Explanation:

The geometry of the BF 3 molecule is called trigonal planar (see Figure 5). The fluorine atoms are positioned at the vertices of an equilateral triangle. The F-B-F angle is 120° and all four atoms lie in the same plane.

Answer:

In a way it does, but overall, there are many factors that affect your rank. In general, and talking about the average Platinum II, they are pretty decent according to casual player standards.

Explanation:

Answer:

jguewjdofe

Explanation:

Answer:

A. infrared

Explanation:

Heat lamps used to keep foods warm are infrared on the light spectrum

Answer:

Bacteria: Unicellular organisms that can cause disease in living things

Plant: A multicellular organism that makes it's own food

Animal: A multicellular organism that does not make it's own food

Answer:

D)

The mass of the reactants is greater than the mass of the products.

Answer:

R ≈ 15 ohms

Explanation:

Using ohm's law equation,

I = V/R, to solve for the resistance of the heating coil.

R = V/I

Known:

V = 220 v = 220 kgm^2s^-3A^-1

I = 15 A

Unknown:

R =?

Solution:

R = (220 kgm^2s^-3A^-1)/ 15.0 A

R = 14.6 kgm^2s^-3A^-2

R ≈ 15 kgm^2s^-3A^-2

R ≈ 15 ohms

Answer:

7.4375N

Explanation:

According to Newtons second law

F = ma

m is the mass = 140g = 0.14kg

Get the acceleration

v = u + at

8.5 = 0+0.1a

a = 8.5/0.16

a = 53.125m/s²

Get the required force

F = 0.14 * 53.125

F = 7.4375N

Hence the magnitude of the average force on the wall is 7.4375N