A package of nuts contains 3 servings, and each serving contains 150 calories. If you eat the entire package, how many calories did you consume?.

Government often makes laws that aim for the betterment of its people. Cesar Chavez worked with government in the 1960s to get laws passed to help noncitizens and farm workers.

Cesar was known to be a man who use nonviolent means as used by Mahatma Gandhi and Martin Luther King Jr. in all his works.

He was known to be the founder of the National Farm Workers Association (later the United Farm Workers of America)

He won a lot of significant victories so as the pay and improve working conditions for farm workers is improve in the late 1960s and 1970s

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Which of the following people worked with government in the 1960s to get laws passed to help noncitizens and farm workers?

Huey Newton

Bobby Seale

Cesar Chavez

Dolores Huerta

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Answer:

Explanation:

Dolores huerta

The expression that represents the difference of squares for this situation is [tex]x^2-c^2[/tex]

Given the generic x by x grid has c blocks moved to create an (x-c) by (x+c) grid, to get the difference of two squares, we will take the product of the expressions as shown:

[tex]=(x-c)(x+c)\\=x^2+xc-xc-c^2\\=x^2 -0-c^2\\=x^2-c^2[/tex]

Hence the expression that represents the difference of squares for this situation is [tex]x^2-c^2[/tex]

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Stokes' theorem says that the surface integral of the curl of the vector field F across the surface S is equal to the line integral of F along the boundary of S.

In this case, the boundary is a circle in the x,y-plane with radius 2. (To see this, set z = 0 and rearrange the equation for the paraboloid as x² + y² = 4.)

Then

[tex]\displaystyle \iint_S (\nabla\times\vec F)\cdot d\vec s = \int_{\partial S} \vec F \cdot d\vec r[/tex]

where

[tex]\vec r = 2\cos(t) \,\vec\imath + 2\sin(t) \,\vec\jmath[/tex]

parameterizes the circular boundary of S with 0 ≤ t ≤ 2π. Then

[tex]d\vec r = \dfrac{d\vec r}{dt}\,\dt = (-2\sin(t)\,\vec\imath + 2\cos(t)\,\vec\jmath)\,dt[/tex]

and the integral becomes

[tex]\displaystyle \iint_S (\nabla\times\vec F)\cdot d\vec s = \int_{\partial S} \vec F \cdot d\vec r[/tex]

[tex]\displaystyle \iint_S (\nabla\times\vec F)\cdot d\vec s = \int_0^{2\pi} \vec F(\vec r(t)) \cdot \frac{d\vec r}{dt}\,dt[/tex]

[tex]\displaystyle \iint_S (\nabla\times\vec F)\cdot d\vec s \\= \int_0^{2\pi} ((2\cos(t))^2 \sin(0)\,\vec\imath + (2\sin(t))^2\,\vec\jmath + (2\cos(t))(2\sin(t))\,\vec k) \cdot(-2\sin(t)\,\vec\imath + 2\cos(t)\,\vec\jmath)\,dt[/tex]

[tex]\displaystyle \iint_S (\nabla\times\vec F)\cdot d\vec s = \int_0^{2\pi} 8\sin^2(t)\cos(t) \, dt[/tex]

[tex]\displaystyle \iint_S (\nabla\times\vec F)\cdot d\vec s = \int_0^{2\pi} 8\sin^2(t) \, d(\sin(t))[/tex]

[tex]\displaystyle \iint_S (\nabla\times\vec F)\cdot d\vec s = \frac83 (\sin^3(2\pi)-\sin^3(0)) = \boxed{0}[/tex]

Por definición de probabilidad, la probabilidad de que tanto el caballo, como la vaca vivan 20 años es [tex]\frac{2}{5}[/tex].

En primer lugar, debes saber que la Probabilidad es la mayor o menor posibilidad de que ocurra un determinado suceso.

En otras palabras, la probabilidad establece una relación entre el número de sucesos favorables y el número total de sucesos posibles.

En este caso, se llama suceso A al evento de que un caballo viva 20 años, mientras que el suceso B será el evento de que una vaca viva 20 años.

La intersección de sucesos es una operación cuyo resultado está compuesto por los sucesos no repetidos y comunes de dos o más conjuntos.

Esto es, la intersección de sucesos {A∩B} es el suceso formado por todos los elementos que son, a la vez, de {A} y {B}.  De esta manera, el suceso {A∩B} se verifica cuando ocurren simultáneamente {A} y {B}.

Entonces, se debe calcular la probabilidad de que ocurra A y B al mismo tiempo, considerando que la probabilidad de la intersección de sucesos independientes (la probabilidad de cada uno de ellos no está influida porque el otro suceso ocurra o no, es decir, cuando ambos sucesos no están relacionados):

P(A∩B)= P(A)×P(B)

En este caso, la probabilidad de que ocurra A es [tex]\frac{2}{3}[/tex] y la probabilidad de que ocurra B es [tex]\frac{3}{5}[/tex]. Entonces:

P(A∩B)= [tex]\frac{2}{3}[/tex]×[tex]\frac{3}{5}[/tex]

P(A∩B)=[tex]\frac{2}{5}[/tex]

Finalmente, la probabilidad de que tanto el caballo, como la vaca vivan 20 años es [tex]\frac{2}{5}[/tex].

Aprende más:

Explanation:

density = mass / volume

96.4 g of aluminum / volume = 2.7

therefore,

96.4 = 2.7 × volume

volume = 96.4 / 2.7 = 35.7037037... ml

back to iron :

7.87 = mass / 35.7037037...

mass = 7.87 × 35.7037037... = 280.9881481... g

it would be 280.9881481... g of iron in the same volume.

Answer:

It lets people practice their faith in their own way and

It prevents the government from establishing a national religion.

Explanation:

Answer:

The three consecutive integers are 12, 13 & 14

Explanation:

Let the three consecutive integers be x, x + 1, x + 2

According to the question,

If sum of the first and third integers is increased by 8, the result is 5 less than triple the second integer.

[tex] \therefore [/tex] x + x + 2 + 8 = (x + 1) × 3 - 5

2x + 10 = 3x + 3 - 5

2x + 10 = 3x - 2

10 + 2 = 3x - 2x

x = 12

So, The three consecutive integers are 12, 13 & 14

Answer:

Fossils helped teach scientist by giving information of the species that lived back then.

Explanation:

The fossils have clues on them help identify what they are.

Answer: old major is based on Karl Marx and partially Vladimir Lenin

Explanation:

The historical figure that old major most likely to represent is Vladimir Lenin. The correct option is C.

The pig Snowball represents the intellectual revolutionary Leon Trotsky, while Old Major represents either Karl Marx or Vladimir Lenin.

Old Major represents Karl Marx and Vladimir Lenin, who promoted the Communist Party but died before their vision could be realized.

As a result, those who did not fully comprehend the dream were able to twist it to their advantage.

Old Major describes a dream he had the night before in which animals are free, happy, well fed, and treated with dignity in a world free of human tyranny.

He exhorts the animals to do everything possible to make this dream a reality, including overthrowing the humans who claim to be their owners.

Thus, the correct option is C.

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Answer:

It will be found on the inside of the protein structure

Considering the situation described in the question, the type of sample Inspector used is called Simple Random Sampling

Simple Random Sampling is a random sampling technique in which participants are taken randomly from a given population.

Here, the given population is the hospital chain with multiple locations; since the inspector only randomly selects some of their locations, this is a simple random sampling.

Hence, in this case, it is concluded that the correct answer is Simple Random Sampling

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The area of the rectangle formed by the intersection of the plane and cube is [tex]4\sqrt{2}cm^2[/tex]

The diagram of the cube and the cutting plane is shown in the figure.

Since the cube has a volume of [tex]8cm^3[/tex], the sides are [tex]2cm[/tex] each.

From the diagram, the red rectangle is the rectangle formed from the intersection of the plane and the cube. It has an area given by

[tex]A_R=\text{side of cube}\times \text{diagonal}=2d[/tex]

and, using Pythagoras' theorem,

[tex]d=\sqrt{2^2+2^2}\\d=\sqrt{8}=2\sqrt{2}\text{ cm}[/tex]

Substituting the value of [tex]d[/tex] into the formula for [tex]A_R[/tex]

[tex]A_R=2\times d\\=2\times 2\sqrt{2}\\=4\sqrt{2}[/tex]

The area of the rectangle formed by the intersection of the plane and cube is [tex]4\sqrt{2}cm^2[/tex]

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Answer:

4 square root of 2cm

Explanation:

cool stuff

Answer:

-4

Explanation:

Edge.

Answer:

A: -4

Hope this helps.

Answer:

A is the correct answer

Explanation:

EDGE

A centroid in a triangle, is the point where all the medians meet.

now a peculiar thing about the centroid is that, it cuts all medians in a 2:1 ratio. So, if that's true, then the median AE, is being cut in two segments AD and DE and AD : DE are on a 2 : 1 ratio.

In a triangle, the centroid is the point of intersection of the three medians, which are line segments joining each vertex to the midpoint of the opposite side.

The centroid divides each median into two segments, with the distance from the centroid to the vertex being twice the distance from the centroid to the midpoint of the opposite side.

Let M be the midpoint of side AB, N be the midpoint of side AC, and P be the midpoint of side BC. Then, we have:

CD = 2DP

CE = 2DN

We are also given that DE = 15. Since D is the centroid, we have:

AD = BD = CD/3

AE = CE/3

DC + DP = PC

CE + DN = NE

AD + AE = DE

Using these relationships, we can find CD and CE:

CD = 2DP = 2(PC - DC) = 2((AD + DP) - (AD/3)) = 2(2AD/3) = 4AD/3

CE = 2DN = 2(NE - CE) = 2((AE + DN) - (AE/3)) = 2(2AE/3) = 4AE/3

To find AD and AE, we can use the fact that AD + AE = DE and AD = BD:

AD + BD = DE

AD + (2AD/3) = 15

5AD/3 = 15

AD = 9

AE = DE - AD = 15 - 9 = 6

Substituting these values into the equations for CD and CE, we get:

CD = 4AD/3 = 4(9)/3 = 12

CE = 4AE/3 = 4(6)/3 = 8

Therefore, CD = 12 and CE = 8.

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We have

x = t³   ===>   dx/dt = 3t²

y = t⁴   ===>   dy/dt = 4t³

Then with the given parameteriztion, the line integral along C of x/y is

[tex]\displaystyle \int_C \frac xy \, ds = \int_1^4 \frac{t^3}{t^4} \sqrt{(3t^2)^2 + (4t^3)^2} \, dt[/tex]

[tex]\displaystyle \int_C \frac xy \, ds = \int_1^4 \frac1t \sqrt{9t^4 + 16t^6} \, dt[/tex]

[tex]\displaystyle \int_C \frac xy \, ds = \int_1^4 \frac{\sqrt{t^4}}t \sqrt{9 + 16t^2} \, dt[/tex]

[tex]\displaystyle \int_C \frac xy \, ds = \int_1^4 \frac{t^2}t \sqrt{9 + 16t^2} \, dt[/tex]

[tex]\displaystyle \int_C \frac xy \, ds = \int_1^4 t \sqrt{9 + 16t^2} \, dt[/tex]

[tex]\displaystyle \int_C \frac xy \, ds = \frac1{32} \int_1^4 32t \sqrt{9 + 16t^2} \, dt[/tex]

[tex]\displaystyle \int_C \frac xy \, ds = \frac1{32} \int_1^4 \sqrt{9 + 16t^2} \, d\left(9+16t^2\right)[/tex]

[tex]\displaystyle \int_C \frac xy \, ds = \frac1{32} \cdot \frac23 \left(9+16t^2\right)^{\frac32}\bigg|_1^4[/tex]

[tex]\displaystyle \int_C \frac xy \, ds = \frac1{48} \left(265^{\frac32} - 25^{\frac32}\right) = \boxed{\frac{265\sqrt{265}-125}{48}}[/tex]

The line integral will be "[tex]\frac{265\sqrt{265} - 125 }{48}[/tex]". To understand the calculation, check below.

According to the question,

Curves, x = t³ or,

            [tex]\frac{dx}{dt}[/tex] = 3t²

             y = t⁴ or,

            [tex]\frac{dx}{dt}[/tex] = 4t³  

Now, the line integral along C will be:

→ [tex]\int\limits_C {\frac{x}{y} } \, ds[/tex] = [tex]\int\limits^4_1 {\frac{t^3}{t^4} }[/tex] √(3t²)² + (4t³)² dt

             = [tex]\int\limits^4_1 {\frac{1}{t} }[/tex] √9t⁴ + 16t⁶ dt

             = [tex]\int\limits^4_1 {\frac{t^4}{t} }[/tex] √9 + 16t² dt

             = [tex]\int\limits^4_1 {\frac{t^2}{t} }[/tex] √9 + 16t² dt

             = [tex]\int\limits^4_1[/tex] t√9 + 16t² dt

             = [tex]\frac{1}{32}[/tex] [tex]\int\limits^4_1[/tex] √9 + 16t² d (9 + 16t²)

             = [tex]\frac{1}{32}\times \frac{2}{3}[/tex] [tex](9+16t^2)^{\frac{3}{2} } |_1^4[/tex]

             = [tex]\frac{1}{48}[/tex] ([tex]265^{\frac{3}{2}} - 25^{\frac{3}{2}[/tex])

             = [tex]\frac{265 \sqrt{265 } -125 }{48}[/tex]

Thus the above approach is correct.

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Thats really nice

Based on a scientific study, the difference between prophase 1 of meiosis from prophase of mitosis is "homologous chromosomes pair up."

Prophase 1 of meiosis is the first stage of meiosis which involves recombination and alleles crossing over genetic material to form non-identical haploid chromatids.

In Contrast, the prophase of mitosis is also the first stage of mitosis which splits the duplicated genetic fabric present in the nucleus of a parent cell to form new identical daughter cells.

However, one of the significant differences between prophase 1 of meiosis and prophase of mitosis in appearance is " homologous chromosomes pair up."

Hence, in this case, it is concluded that the correct answer is "homologous chromosomes pair up."

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It looks like the integral is

[tex]\displaystyle \int_C xy \, dx + x^2y^3 \, dy[/tex]

Let's close the loop by adding a line integral over the line segment joining (1, 4) to (0, 0). Then the closed loop is the triangular region

T = {(x, y) : 0 ≤ x ≤ 1 and 0 ≤ y ≤ 4x}

Since the integrand has no singularities over or on the boundary of T, we have by Green's theorem

[tex]\displaystyle \int_C xy \, dx + x^2y^3 \, dy = \iint_T \left(\frac{\partial(x^2y^3)}{\partial x} - \frac{\partial(xy)}{\partial y}\right) \, dx \, dy = \int_0^1 \int_0^{4x} (2xy^3 - x) \, dy \, dx[/tex]

Compute the double integral:

[tex]\displaystyle \int_0^1 \int_0^{4x} (2xy^3 - x) \, dy \, dx = \int_0^1 \int_0^{4x} \left(128x^5 - 4x^2\right) \, dx = \frac{60}3[/tex]

From this result, we subtract the line integral over the extra line segment we added. Parameterize this path by

C' : {(1 - t, 4 - 4t) : 0 ≤ t ≤ 1}

The line integral over C' is

[tex]\displaystyle \int_{C'} xy \, dx + x^2y^3 \, dy = \int_0^1 (1-t)(4-4t)(-dt) + (1-t)^2(4-4t)^3(-4\,dt)[/tex]

[tex]\displaystyle \int_{C'} xy \, dx + x^2y^3 \, dy = \int_0^1 \left(256 t^5-1280 t^4+2560 t^3-2564 t^2+1288 t-260 \right) \, dt = -44[/tex]

so that the line integral over C alone is 60/3 - (-44) = 64.

Answer:

12

Explanation:

speed=distance÷time

It has been known that some FDIC policy statements often answer to the freedom of auditor. The correct statement is that the FDIC has issued policy statements that address auditor independence in various contexts.

Auditor independence is simply known as the freedom of the internal auditor or of the external auditor from parties that do  have a financial interest in the business that is been audited.

The Independence or freedom often needs integrity and an objective means to the audit process.

The SEC do have some rules that addresses the audit independence. They are classified into:

The full question is below

Which statement best describes an element of the Federal Deposit Insurance Corporation's (FDIC) requirements for auditor independence?

o FDIC independence requirements incorporate requirements for attorneys and actuaries.

o FDIC independence requirements mirror the AICPA and DOL independence rules.

The FDIC has issued policy statements that address auditor independence in various contexts.

O The FDIC has adopted regulations that incorporate IESBA independence rules.

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Recall the double angle identity for cosine,

cos(2x) = 2 cos²(x) - 1

Then

cos(2x) = 2 (3/4)² - 1 = 1/8

Answer:C

Explanation:

did it on edge

Enzymes

Explanation:

are the catalyst that require substrate for their function. Almost all the metabolic process in the body for synthesis of any substance requires enzymes. 

I hope this is correct :)

Answer:

10385877.377477km

Explanation:

kasi po i plas lang po

Considering the whole question, the perimeter of the porch is 30 feet.

This is because the whole question is, "Bill's new porch is rectangular, with an area of 50 square feet. if the length of the porch is two times the width, what is the perimeter of the porch?"

Therefore to find the perimeter of the porch, here is the step by step:

Given that the length of the porch is two times the width.

Hence, assume that the width = X

Also, assume that the length = 2X

The general formula here:

50 = X × 2X

X × 2X50 = 2x²

2x²X² = 50 ÷2

50 ÷2X² = 25

25X = √25

√25X = 5

Hence, width = 5 feet.

Given that length of the porch is two times the width = 5 × 2 => 10 feet

Therefore Perimeter of a rectangle = 2 (Length + Breadth)

Put all the values in the formula

Perimeter of the porch = 2 × (5 + 10)

= 2 × (15)

= 30 feet.

Hence, in this case, it is concluded that the correct answer is 30 feet.

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Answer:

the value of change in entropy for freezing process of 1 mole of liquid methanol is -18.07 J/mol.k

Explanation:

Entropy is defined as the measure of possible arrangement of the atoms or molecules. Entropy change for the the freezing process mole of 1 liquid methanol at -97.6 degree celcius and 1 atm will be -18.07 J/mol.

The entropy change can be calculated by the given formula:

Thus, the value of change in entropy for freezing process of 1 mole of liquid methanol is -18.07 J/mol.k

(Hope this helps can I pls have brainlist (crown)☺️)

For the freezing of 1 mole of liquid methanol, the change in entropy value is -18.07 J/mol.

The measure of atoms' or molecules' potential arrangements is known as entropy. Entropy change for one mole of liquid methanol frozen at -97.6 degrees Celsius and one atmosphere is -18.07 J/mol.

The range of entropy is 0 to 1. Depending on the number of classes in your dataset, entropy can be greater than 1, but it still indicates a very high level of chaos. For the sake of convenience, the examples in this blog will have entropy values between 0 and 1.

The "information" a variable contains is measured by its entropy. Now, based on the surprise that this value of the bholds and the number of distinct values that are present in the variable, this amount is approximated.

Thus, it is -18.07 J/mol.

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Answer:

ion know

Explanation:

Answer:     Distance to close end of island is 3000/tan(75.8); distance to far end is 3000/tan(15.6). The difference is 9985.676 feet or about 1.9 miles.

Explanation:  2 explanation Balloon, flying or levitating, has no front to recon with, so two possible answers.

tan(90–15.6)+or-tan(90–75.08) * 3000= length of island

WWW is an abbreviation for World Wide Web ...

Corporation, Customer, Competitors (3C's) Model is a business model that focuses on the three key factors needed for success. This model was conceived by the famous business strategist, Kenichi Ohmae.

Answer:

Explanation:

The answer to your question is:

Answer:

The three main beliefs at the center of Judaism are Monotheism, Identity, and covenant (an agreement between God and his people). The most important teachings of Judaism is that there is one God, who wants people to do what is just and compassionate.

Explanation: