Answer:
4.5 m/s = 16.2 km/h
Explanation:
The speed is the ratio of distance to time:
speed = (180 m)/(40 s) = 4.5 m/s
Rocks in mountains can be weathered by breaking them apart. How can they be eroded?
A. Pieces of rocks are moved by the deep roots of plants.
B. Pieces of rocks are moved by water and gravity.
C. Rocks expand by the temperature changes in the mountains.
D. Rocks are smoothed by the flowing water and ice.
NO LINKS PLEASE!
Answer: If you look up its definition of eroded it'll tell you the answer should be B
Explanation:
A fully charged battery with 6 cells should indicate
Answer:
Battery Voltage
Voltage refers to the amount of electrical potential your battery holds. The standard automotive battery in today's vehicles is a 12-volt battery. Each battery has six cells, each with 2.1 volts at full charge. A car battery is considered fully charged at 12.6 volts or higher.
how many times greater is the value of the 2 of the 270413 than the valuce of the 2 in 419427?
If you had to pick a priority for future engineers, what would it be and why?
Answer:
Explanation:
Civil engineers have become experts in creating sustainable and environmentally friendly buildings and systems. Multiplied over many communities, the energy and emissions savings can make a real difference in the environment. Other life-improving functions can also make communities better places to live.Jul 19, 2017
Can anyone solve this for me?sequential circuit ,flipflop
Explanation:
We assume the T flip-flop changes state on the rising edge of the clock input.
The first stage is connected to the clock. The second stage clock is connected to the inverse of the Q output of the first stage, so that when the first stage Q makes a 1 to 0 transition, the second stage changes state.
12. How will the temperature change in a room with an open refrigerator door, once equilibrium is established
Answer:
then back into the room
Explanation:
If you leave the door open, heat is merely recycled from the room into the refrigerator, then back into the room. A net room temperature increase would result from the heat of the motor that would be constantly running to move energy around in a circle.
Thank you,Thank you udahfsdf
Answer: Um, a little feedback would help, cause I'm new but if you are thanking someone, let me know and i'll thank them for you, any other questions?
Explanation:
How can we honor what we value and care about in a world of disruptive technologies like AI?
Answer: Well, that's a good question. When we look around us, we tend to see what technology has done for us, and how far it is taking us. It might be disruptive, but without it there would be no high tech military weapons, and then how would we defend ourselves? There would be no technology entertainment and without that, life would be very dull. In answering your question, we can be thankful for what it is and how far it has been taking us in life.
Explanation: Please mark a brainliest if correct it helps and have meery holidays!
In order to write a good problem statement, you need to identify the following components of the problem.
who, what, when, how
O True
O False
Answer:
True.
Explanation:
4. What is the ampacity of 8-gage copper wire?
O A. 45 amps
OB. 30 amps
O C. 50 amps
O D. 25 amps
The feedback looping system in a three-way catalytic converter serves to adjust
I can say it oxidizes gas pollutants such as hydrocarbons and carbon monoxide. It also reduces nitrogen oxides into water, hydrogen, and carbon dioxide.
Explain the conditions under which galvanic corrosion occurs
Answer:
Explanation:
Galvanic corrosion occurs when two dissimilar metals are immersed in a conductive solution and are electrically connected. One metal (the cathode) is protected, whilst the other (the anode) is corroded. The rate of attack on the anode is accelerated, compared to the rate when the metal is uncoupled.
A tank with a volume of 40 cuft is filled with a carbon dioxide and air mixture. The pressure within the tank is 30 psia at 70oF. It is known that 2 lb of carbon dioxide was placed in the tank. Assume that air is 80% nitrogen and 20% oxygen and use the ideal gas laws. Calculate ,
The correct responses are;
(i) Weight percent of nitrogen: 58.6%
Weight percent of oxygen: 14.65%
Weight percent of carbon dioxide: 29.59%
(ii) Volume percent of nitrogen: 64.38%
Weight percent of oxygen: 14.1%
Weight percent of carbon dioxide: 21.53%
(iii) Partial pressure of nitrogen: 19.314 psia
Partial pressure of oxygen: 4.23 psia
Partial pressure of carbon dioxide: 6.459 psia
(iv) Partial pressure of nitrogen: 19.314 psia
Partial pressure of oxygen: 4.23 psia
Partial pressure of carbon dioxide: 6.459 psia
(v) The average molecular weight is approximately 32.02 g/mole
(vi) At 20 psia, 60 °F, the density is 0.11275 lb/ft.³
At 14.7 psia, 60 °F, the density is 0.0844 lb/ft.³
At 14.7 psia, 32 °F, the density is 0.0892 lb/ft.³
(vii) The specific gravity of the mixture 0.169
Reasons:
The volume of the tank = 40 ft.³ = 1.132675 m³
Content of the tank = Carbon dioxide and air
The pressure inside the tank = 30 psia = 206843 Pa
The temperature of the tank = 70 °F ≈ 294.2611 K
Mass of carbon dioxide placed in the tank = 2 lb.
Percent of nitrogen in the tank = 80%
Percent of oxygen in the tank = 20%
(i) 2 lb ≈ 907.1847 g
Molar mass of carbon dioxide = 44.01 g/mol
Number of moles of carbon dioxide = [tex]\displaystyle \mathbf{ \frac{907.1847 \, g}{44.01 \, g/mol}} \approx 20.613 \, moles[/tex]
Assuming the gas is an ideal gas, we have;
[tex]\displaystyle n = \mathbf{\frac{206843\times 1.132674}{8.314 \times 294.2611} }\approx 95.7588[/tex]
The number of moles of nitrogen and oxygen = 95.7588 - 20.613 = 75.1458
Let x represent the mass of air in the mixture, we have;
[tex]\displaystyle \mathbf{ \frac{0.8 \cdot x}{28.014} + \frac{0.2 \cdot x}{32}}= 75.1458[/tex]
Solving gives;
x ≈ 2158.92 grams
Mass of the mixture = 2158.92 g + 907.1847 g ≈ 3066.1047 g
[tex]\displaystyle Weight \ percent \ of \ nitrogen= \frac{0.8 \times 2158.92}{3066.105} \times 100 \approx \underline{58.6 \%}[/tex]
[tex]\displaystyle Weight \ percent \ of \ oxygen = \frac{0.8 \times 2158.92}{3066.105} \times 100 \approx \underline{14.65\%}[/tex]
[tex]\displaystyle Weight \ percent \ of \ carbon \ dioxide = \frac{907.184}{3066.105} \times 100 \approx \underline{29.59\%}[/tex]
ii.
[tex]\displaystyle Number \ of \ moles \ nitrogen= \frac{0.8 \times 2158.92 \, g}{28.014 \, g/mol} \approx 61.65\, moles[/tex]
[tex]\displaystyle Number \ of \ moles \ oxygen= \frac{0.2 \times 2158.92 \, g}{32 \, g/mol} \approx 13.5\, moles[/tex]
Number of moles of carbon dioxide = 20.613 moles
Sum = 61.65 moles + 13.5 moles + 20.613 moles ≈ 95.763 moles
In an ideal gas, the volume is equal to the mole fraction
[tex]\displaystyle Volume \ percent \ of \ nitrogen= \frac{61.65}{95.763} \times 100 \approx \underline{64.38 \%}[/tex]
[tex]\displaystyle Volume \ percent \ of \ oxygen = \frac{13.5}{95.763} \times 100 \approx \underline{14.1\%}[/tex]
[tex]\displaystyle Volume \ percent \ of \ carbon \ dioxide = \frac{20.613 }{95.763} \times 100 \approx \underline{21.53\%}[/tex]
(iv) The partial pressure of a gas in a mixture, [tex]P_A = \mathbf{X_A \cdot P_{total}}[/tex]
Partial pressure of nitrogen, [tex]P_{N_2}[/tex] = 0.6438 × 30 psia ≈ 19.314 psia
Partial pressure of oxygen, [tex]P_{O_2}[/tex] = 0.141 × 30 psia ≈ 4.23 psia
Partial pressure of carbon dioxide, [tex]P_{CO_2}[/tex] = 0.2153 × 30 psia ≈ 6.459 psia
(v) The average molecular weight is given as follows;
[tex]\displaystyle Average \ molecular \ weight = \frac{3066.105\, g}{95.7588 \, moles} = 32.02 \, g/mole[/tex]
(vi) At 20 psia 70 °F, we have;
Converting to SI units, we have;
[tex]\displaystyle n = \frac{137895.1456\times 1.132674}{8.314 \times 294.2611} \approx 63.84[/tex]
The number of moles, n ≈ 63.84 moles
The mass = 63.84 moles × 32.02 g/mol ≈ 2044.16 grams ≈ 4.51 lb
[tex]\displaystyle Density = \frac{4.51\ lb}{40 \ ft.^3} \approx \underline{0.11275\, lb/ft.^3}[/tex]
When the pressure is 14.7 psia = 101352.93 Pa, and 60 °F
[tex]\displaystyle n = \frac{101352.9\times 1.132674}{8.314 \times 288.7056} \approx 42.8247[/tex]
The mass = 47.8247 moles × 32.02 g/mol ≈ 1531.35 grams = 3.376 lb.
[tex]\displaystyle Density = \frac{3.376 \ lb}{40 \ ft.^3} \approx \underline{ 0.0844\, lb/ft.^3}[/tex]
When the pressure is 14.7 psia = 101352.93 and 32 °F
[tex]\displaystyle n = \frac{101352.9\times 1.132674}{8.314 \times 273.15} \approx 50.5482[/tex]
The mass = 50.5482 moles × 32.02 g/mol ≈ 1618.55 grams = 3.568 lb.
[tex]\displaystyle Density = \frac{3.568 \ lb}{40 \ ft.^3} \approx \underline{ 0.0892 \, lb/ft.^3}[/tex]
(vii) [tex]\displaystyle The \ specific \ gravity \ of \ the \ mixture \ = \frac{\frac{3066.1047\, g}{40 \, ft.^3} }{1.00} = \frac{\frac{6.7596 \, lbs}{40 \, ft.^3} }{1.00} \approx \underline{0.169}[/tex]
Learn more about partial pressure here:
https://brainly.com/question/19813237
Help! Please explain also. Thank you
Answer:
17A) 52mm
17B) 132mm
17C) 67mm
18.) 34
Explanation:
For 17)
Each distance is determined by the total distances surrounding it. For example, 17A is 73mm - 21mm, which is 52mm.
For 18)
Set up the problem as an algebraic expression:
a + b + c + d = 115
Since you know 3 of the values, you can plug them in and subtract them from 115, which turns into 34.
What is the first step in the decision-making process?
Answer: identify your decision. relize you need to make a decision.
Explanation:
What are minerals made of?
NO LINKS PLEASE
A. Different substances
B. Liquid substances
C. Two or more substances
D. The same substance throughout
Answer:
the answer I know is A. different substances. hope this helps :).
Explanation:
just always study hard and God bless.
Describe two fundamental reasons why flexural strength should depend on porosity
Answer: The elastic modulus and flexural strength are found to decrease with increased porosity. Fractography studies have been undertaken to identify the role of the pores on the fracture path. The deflection and cracking behavior of concrete structure depend on the flexural tensile strength of concrete. Many factors have been shown to influence the flexural tensile strength of concrete, particularly the level of stress, size, age and confinement to concrete flexure member, etc.
Explanation:
HELP HELPHELP HELPHELP HELPHELP HELPHELP HELPHELP HELPHELP HELPHELP HELPHELP HELPHELP HELPHELP HELPHELP HELPHELP HEL
Answer:
oh this happened with me to ,this will be alright just wait a bit
Describe the first case where the power of synthesis was used to solve design problems.
The first case where the power of synthesis was applied was in Chile when they had to put 100 families in houses around 40m².
It should be noted that the power of architecture is the fact that it can synthesize a complex entry to a problem.
Chilean architect Alejandro used this in building more than several houses for the poorest communities in Chile. His rigorous and innovative design approach used a social framework that laid a precedent within the profession.
During this period in Chile, a normal middle-class home was about 80m² but he built his in 40m² and it was a good home that managed the resources that were available.
Learn more about synthesis on:
https://brainly.com/question/884041
When framing a building, a simple way to estimate the total amount of wall studs needed is to allow
for one for every foot of wall. If you are building a garage that is 17' x 52', how many studs are needed?
Which of the following is a measurement at the nominal level?
A-personal income in a year
B-student grades
C-the color of a person's hair (blond, brunette, redhead)
D-temperature
Answer:
A-personal income in a year this is the answer
What effect did the Ice Age have on early humans
Answer:
The development of homosapiens
Explanation:
People adapted to the harsh weather by creating tools and used land bridges to spread to new regions
Font
Paragraph
Styles
Editing
(1) What are the available methods for crop establishments in the field?
(2) Give a conceptual sketch for a seeder to establish soybean seeds in an
agricultural field of dry zone in Sri Lanka (Use software where
necessary/or a hand sketch with detail).
(3) Discuss the advantages of the seed dibbling mechanism and list the
crops that can be used dibbler.
A
(4) Discuss the key points to enhance agricultural productivity using the
fertilizer applicators.
(5) Calculations: Calibration of a seed drill
Number of furrows = 5
Spacing between the furrows = 8 cm
Diameter of the ground wheel = 0.65 m
Number of rotations of the ground wheel = 300
Weight of seed collected = 20 kg
Calculate the seed rate in kg/ha
The average number of seeds dropped per one revelation =6
Calculate the
(1) seed rate and
(ii)
hole to hole spacing
Answer:
1) Therefore it was so much more than one answer my head10. Which is of the following is not used in the
testing/analysis step?
A. Engineering notebooks.
B. Multiview drawings.
C. 3-D modeling software.
D. CNC machines.
A CNC machine stands for Computer Numerically Controlled Machine, they are used to Machine objects in hence create items, machine parts from prototypes. Hence the CNC machines are not used for testing/Analysis
D. CNC machines.
In Engineering the following items are basically needed for and during test/Analysis
Engineering notebooks: This is used to write down importance observations and findingsMulti-view drawings: This is also needed to visualise prototypes from different perspective or views3-D modelling software: e.g AutoCad , Autodesk Inventor, Revit to mention a few can be used to design and analyse project even before their actual implementation or designLearn more:
https://brainly.com/question/9275741
All of the following are employment requirements for a technician EXCEPT:
Select one:
a. Being drug and alcohol free
b. Having all of your ASE certifications
c. Having a clean driving record
O d. Having honesty, integrity, reliability, and quality
Answer:
I think it would be C but im not sure sorry if its wrong
An unknown relative passes away and bequeaths upon you a small tract of land in Amherst. You decide to build a two-story storage facility to make the best of your bequest. But your self-storage dream is in jeopardy due to a 10 meter thick layer of soft clay (N<4) on the site. You put on your best geotechnical engineer hat, hire a driller to pull up some samples, and send them off to a lab for a consolidation test. The report indicates that the clay is a dark grey, slightly sweet, kaolinite blend with a cy = 1x10-7 mº/s, single-drained, and an ultimate settlement of 0.73 meters. It does not make financial sense to install deep foundations, so you are interested in how long it will take to consolidate the clay layer using a passive load.
How long will it take for settlements of 25, 50, and 65 cm to occur?
If you need to build within the next 12 months and have at least 65cm of settlement to be viable, does it make sense to proceed?
Answer: It does make sense, because I've been involved in these careers and have a long family line of them. And other questions?
Explanation:
Chemical engineers determine how to transport chemicals.
O True
False
Answer:
Chemical Engineers determine how to transport chemicals:
TRUE
Answer:
Explanation:
Trues
The section 5(a)(1) of the osh act is commonly known as
Answer:
general duty clause
Explanation:
Text wrapping in Sheets means the text will be on more than 1 line within the cell.
Answer:
True
Explanation:
Had it on my quiz
Text wrapping in spreadsheets simply means the text will be on more than one (1) line within the cell.
What is a spreadsheet?A spreadsheet can be defined as a file (document) which comprises cells arranged in a tabulated format (rows and columns) and it is typically used for formatting, arranging, analyzing, storing, calculating and sorting data on computer systems.
In Computer science, when a text in spreadsheets is formatted through text wrapping, the text will appear on more than one (1) line within the cell.
Read more on spreadsheets here: https://brainly.com/question/4965119
Question 2 Given the following gas Volume (%) Component Methane 58.7 Ethane 16.5 9.9 Propane Butanes 5.0 Pentanes 3.5 Hydrogen Suflide 6.4 100 Total I Calculate: 1. Average molecular weight 1. Density at 320F and 14.7 psia ni. Density at OoC and 760 mm mercury iv. Specific gravity and gross and net heating value
Answer
I think 51.96 I hope it's help