A pilot at an altitude of 2,000 feet and has a horizontal distance of 8,020 feet from the runway. At what angle of depression should he set the plane to touch down at the exact end of the runway?

Answer:

h (-5) = 41/4 or 10.25

h (-2) = -3

h (3) = 25/4 or 6.25

Step-by-step explanation:

h (-5) = 1/4(-5)^2 + 4

h (-5) = 1/4(25) + 4

h (-5) = 41/4 or 10.25

h (-2) = -3 (this is given to you in the function)

h (3) = 1/4 (3)^2 + 4

h (3) = 1/4(9) + 4

h (3) = 25/4 or 6.25

Answer:

The coral reef grows 266 cm in 14 weeks.

Step-by-step explanation:

Lets convert 0.19 meters to centimeters.

1m= 100cm

0.19m×100= 19 cm

It grows 19 cm every week, so:

[tex]\frac{1w}{19 cm} *14 =\frac{14w}{x= 266 cm}[/tex]

So, the coral reef grows 266 cm in 14 weeks.

Hope this helps!

Answer:

im pretty sure its -3/2

Step-by-step explanation:

since you have to do rise over run and your falling 3 so its a negative 3 and you always run right so its run 2 so then its -3/2 if its not that sorry

Explanation:

The perimeter is 48 mm. We divide that by 4 to find the side length of the square, since each side is the same length.

48/4 = 12

Each side is 12 mm long.

This means the area of this square is 12^2 = 12*12 = 144 square mm

no lol ;0 you should ask your teacher for help ;(

Answer:

x = 11

Step-by-step explanation:

Since the 2 triangles are exact replicas of each other, we see the angle for this is 54 from the first triangle, and that 4x+10 is the angle as well.

So we set up the equation:

[tex]4x+10=54\\4x=44\\x=11[/tex]

[tex]\Large{\underline{\underline{{\mathfrak{{\bigstar}\:Answer}}}}}\\\\[/tex]

[tex]\bf{1.\:\:x^{2}+4x+1=0}[/tex]

[tex]\longrightarrow\:\:\sf{x=\dfrac{-4{\underline{+}}\sqrt{4^{2}-4\times1\times1}}{2\times1}}[/tex]

[tex]\longrightarrow\:\:\sf{x=\dfrac{-4{\underline{+}}\sqrt{16-4}}{2}}[/tex]

[tex]\longrightarrow\:\:\sf{x=\dfrac{-4{\underline{+}}\sqrt{12}}{2}}[/tex]

[tex]\longrightarrow\:\:\sf{x=\dfrac{4{\underline{+}}2\sqrt{3}}{2}}[/tex]

[tex]\longrightarrow\:\:\sf{x_{1}=-2-\sqrt{3}\:,\:x_{2}= -2+\sqrt{3}}\\\\\\[/tex]

[tex]\bf{2.\:\:x^{2}-9x+14=0}[/tex]

[tex]\longrightarrow\:\:\sf{x^{2}-2x-7x+14=0}[/tex]

[tex]\longrightarrow\:\:\sf{x\times (x-2)-7(x-2)=0}[/tex]

[tex]\longrightarrow\:\:\sf{x_{1}=2\:,\:x_{2}=7}\\\\\\[/tex]

[tex]\bf{3.\:\:x^{2}+8x+2=22}[/tex]

[tex]\longrightarrow\:\:\sf{x^{2}+8x+2-22=0}[/tex]

[tex]\longrightarrow\:\:\sf{x(x+10)-2(x+10)=0}[/tex]

[tex]\longrightarrow\:\:\sf{(x+10)(x-2)=0}[/tex]

[tex]\longrightarrow\:\:\sf{x_{1}=-10\:,\:x_{2}=2}\\\\\\[/tex]

[tex]\bf{4.\:\:x^{2}+8x+7=0}[/tex]

[tex]\longrightarrow\:\:\sf{x^{2}+7x+x+7=0}[/tex]

[tex]\longrightarrow\:\:\sf{x(x+7)+x+7=0}[/tex]

[tex]\longrightarrow\:\:\sf{(x+7)(x+1)=0}[/tex]

[tex]\longrightarrow\:\:\sf{x_{1}=-7\:,\:x_{2}=1}\\\\\\[/tex]

[tex]\bf{5.\:\:x^{2}-10x+25=9}[/tex]

[tex]\longrightarrow\:\:\sf{(x-5)^{2}=9}[/tex]

[tex]\longrightarrow\:\:\sf{x-5={\underline{+}}3}[/tex]

[tex]\longrightarrow\:\:\sf{x-5=-3 \: ; \:x-5=3}[/tex]

[tex]\longrightarrow\:\:\sf{x_{1}=2\:,\:x_{2}=8}\\\\\\[/tex]

[tex]\bf{6.\:\:x^{2}-10x+16=0}[/tex]

[tex]\longrightarrow\:\:\sf{x^{2}-2x-8x+16=0}[/tex]

[tex]\longrightarrow\:\:\sf{(x-2)(x-8)=0}[/tex]

[tex]\longrightarrow\:\:\sf{x-2=0\:;\:x-8=0}[/tex]

[tex]\longrightarrow\:\:\sf{x_{1}=2\:,\:x_{2}=8}\\\\\\[/tex]

[tex]\bf{7.\:\:2x^{2}+7x-4=0}[/tex]

[tex]\longrightarrow\:\:\sf{2x(x+4)-(x-4)=0}[/tex]

[tex]\longrightarrow\:\:\sf{(x+4)((2x-1)=0}[/tex]

[tex]\longrightarrow\:\:\sf{x+4=0\:;\:2x-1=0}[/tex]

[tex]\longrightarrow\:\:\sf{x_{1}=-4\:,\:x_{2}=\dfrac{1}{2}}\\\\\\[/tex]

[tex]\bf{8.\:\:x^{2}-2x+3=0}[/tex]

[tex]\longrightarrow\:\:\sf{x=\dfrac{-(-2){\underline{+}}\sqrt{(-2)^{2}-4\times 1\times 3}}{2\times1}}[/tex]

[tex]\longrightarrow\:\:\sf{\dfrac{2{\underline{+}}\sqrt{4-12}}{2}}[/tex]

[tex]\longrightarrow\:\:\sf{\dfrac{2{\underline{+}}\sqrt{-8}}{2}}[/tex]

[tex]\longrightarrow\:\:\sf{x \notin {\mathbb{R}}}\\\\\\[/tex]

[tex]\bf{9.\:\:3x^{2}+8x+5=0}[/tex]

[tex]\longrightarrow\:\:\sf{x(3x+5)+3x+5=0}[/tex]

[tex]\longrightarrow\:\:\sf{(3x+5)(x+1)=0}[/tex]

[tex]\longrightarrow\:\:\sf{3x+5=0\:;\:x+1=0}[/tex]

[tex]\longrightarrow\:\:\sf{x_{1}=-\dfrac{5}{3}\:,\:x_{2}=-1}\\\\\\[/tex]

[tex]\bf{10.\:\:{\mathbb{\red{1}}}\:\:}[/tex]:')

The solutions are listed below:

(i) [tex]x = -2\pm \sqrt{3}[/tex], (ii) [tex]x = \frac{9}{2}\pm \frac{5}{2}[/tex], (iii) [tex]x = -4 \pm 6[/tex], (iv) [tex]x = -4\pm 3[/tex], (v) [tex]x = -5\pm 3[/tex], (vi) [tex]x = 5 \pm 3[/tex], (vii) [tex]x = -\frac{7}{4}\pm \frac{9}{4}[/tex], (viii) [tex]x = 1 \pm i\sqrt{2}[/tex], (ix) [tex]x = -\frac{4}{3}\pm \frac{1}{3}[/tex], (x) 1. I do not celebrate Valentine's day at all.

Completing the square consists in applying algebraic operations to transform part of the second order polynomial into a perfect square trinomial and simplify the resulting expression. Now we proceed to present the corresponding solutions:

(i) [tex]x^{2}+4\cdot x + 1 = 0[/tex]

[tex]x^{2}+4\cdot x +4 = 3[/tex]

[tex](x+2)^{2} = 3[/tex]

[tex]x+2 = \pm \sqrt{3}[/tex]

[tex]x = -2\pm \sqrt{3}[/tex]

(ii) [tex]x^{2}-9\cdot x + 14 = 0[/tex]

[tex]x^{2}-9\cdot x + 14+\frac{25}{4} = \frac{25}{4}[/tex]

[tex]x^{2}-9\cdot x +\frac{81}{4} = \frac{25}{4}[/tex]

[tex]\left(x-\frac{9}{2} \right)^{2} = \frac{25}{4}[/tex]

[tex]x -\frac{9}{2} = \pm \frac{5}{2}[/tex]

[tex]x = \frac{9}{2}\pm \frac{5}{2}[/tex]

(iii) [tex]x^{2}+8\cdot x + 2 = 22[/tex]

[tex]x^{2}+8\cdot x +16 = 36[/tex]

[tex](x+4)^{2} = 36[/tex]

[tex]x+4 = \pm 6[/tex]

[tex]x = -4 \pm 6[/tex]

(iv) [tex]x^{2}+8\cdot x + 7 = 0[/tex]

[tex]x^{2}+8\cdot x + 16 = 9[/tex]

[tex](x+4)^{2} = 9[/tex]

[tex]x+4 = \pm 3[/tex]

[tex]x = -4\pm 3[/tex]

(v) [tex]x^{2}+10\cdot x + 25 = 9[/tex]

[tex](x+5)^{2} = 9[/tex]

[tex]x+5 = \pm 3[/tex]

[tex]x = -5\pm 3[/tex]

(vi) [tex]x^{2}-10\cdot x + 16 = 0[/tex]

[tex]x^{2}-10\cdot x + 25 = 9[/tex]

[tex](x-5)^{2} = 9[/tex]

[tex]x-5 = \pm 3[/tex]

[tex]x = 5 \pm 3[/tex]

(vii) [tex]2\cdot x^{2} + 7\cdot x - 4 = 0[/tex]

[tex]x^{2}+\frac{7}{2}\cdot x -2 = 0[/tex]

[tex]x^{2} + \frac{7}{2}\cdot x -2 +\frac{81}{16} = \frac{81}{16}[/tex]

[tex]x^{2}+\frac{7}{2}\cdot x +\frac{49}{16} = \frac{81}{16}[/tex]

[tex]\left(x+\frac{7}{4} \right)^{2} = \frac{81}{16}[/tex]

[tex]x + \frac{7}{4} = \pm \frac{9}{4}[/tex]

[tex]x = -\frac{7}{4}\pm \frac{9}{4}[/tex]

(viii) [tex]x^{2}-2\cdot x + 3 = 0[/tex]

[tex]x^{2}-2\cdot x + 1 + 2 = 0[/tex]

[tex](x-1)^{2} = -2[/tex]

[tex]x-1 = \pm \sqrt{-2}[/tex]

[tex]x = 1 \pm i\sqrt{2}[/tex]

(ix) [tex]3\cdot x^{2} + 8\cdot x + 5 = 0[/tex]

[tex]x^{2}+\frac{8}{3}\cdot x +\frac{5}{3} = 0[/tex]

[tex]x^{2}+\frac{8}{3}\cdot x +\frac{5}{3}+\frac{1}{9} = \frac{1}{9}[/tex]

[tex]x^{2}+\frac{8}{3}\cdot x + \frac{16}{9} = \frac{1}{9}[/tex]

[tex]\left(x+\frac{4}{3} \right)^{2} = \frac{1}{9}[/tex]

[tex]x + \frac{4}{3} = \pm \frac{1}{3}[/tex]

[tex]x = -\frac{4}{3}\pm \frac{1}{3}[/tex]

(x) 1. I do not celebrate Valentine's day at all.

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Answer:

area = 6.5 square units

Step-by-step explanation:

Use the area of a triangle in coordinate geometry formula:

[tex]\triangle GHI =\frac{1}{2} |x_1(y_2- y_3) + x_2(y_3 -y_1) + x_3(y_1 -y_2)|[/tex]

where [tex](x_1,y_1)=(-8,-8) \ \ \ \ (x_2,y_2)=(-6,-7) \ \ \ \ (x_3,y_3)=(-9,-2)[/tex]

      [tex]\triangle GHI =\frac{1}{2} |x_1(y_2- y_3) + x_2(y_3 -y_1) + x_3(y_1 -y_2)|[/tex]

[tex]\implies \triangle GHI =\frac{1}{2} |-8(-7+2) -6(-2 +8) -9(-8 +7)|[/tex]

[tex]\implies \triangle GHI =\frac{1}{2} |40 -36 +9|[/tex]

[tex]\implies \triangle GHI =6.5[/tex]

Answer:

c = 13j × $0.71

Step-by-step explanation:

give me a minute

Answer:

no

Step-by-step explanation:

because 8 isnt a perfect square

Answer:

2.2      Solve  :    3x-20 = 0

Add  20  to both sides of the equation :

                     3x = 20

Divide both sides of the equation by 3:

                    x = 20/3 = 6.667

x = 20/3 = 6.667

Answer:

A, the first option, 49 square cm

Step-by-step explanation:

[] To know

-> A squares sides are all the same size

-> The area of a square can be found by finding L * W

[] Solving

-> We can use the points given to solve for one side, EF, of the square

-> Both the x coordinates are the same, so we can subtract the y values as they are on the same line.

6 - -1 = 6 + 1 = 7

-> Now for the area

7 * 7 = 49 square cm

Have a nice day!

     I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly.

- Heather

Answer: I think the answer b

Step-by-step explanation:

The cost function for Julia's clothing store per month is 14.60n +970

A function is defined as a relation between a set of inputs having one output each.

Given that, Julia is opening a clothing store. She plans to start by selling sweatshirts. It costs her $10.50 for each sweatshirt, $4 per box for the shirts, and $0.10 a bag. Julia also spends $900 on rent, $40 on electricity, and $30 on advertising each month.

There are two types of cost Julia have,

The variable cost that is not fixed and depend on how many shirts she's making, = $10.50+$4 +$0.10 = $14.60

Let she makes n shirts, so cost = $14.60n

And the second one is fixed cost that is cost she is spending on rent, electricity and advertising, = $900+$40+$30 = $970

Therefore, cost = 14.60n +970

Hence, the cost function for Julia's clothing store per month is 14.60n +970

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Answer:

768

Step-by-step explanation:

because 2 to the 3rd power is 8 then 8 times 8 is 64 times 64 times 12 is 768!

please mark brainliest i rlly need one last one

Answer:

rate 72 mph; current 16 mph

Step-by-step explanation:

to find the rate of the boat and the current we can model the equation like this

let r = rate

let c = current

8(r - c) = 464

6(r + c) = 540

8r - 8c = 464

6r + 6c = 540

r - c = 58

r + c = 90

then you could use elimination to find r

2r = 148

r = 74

the rate is 74 mph

then plug it in

the current is 16 mph

Answer:

I'm gonna head with B forgive me I'd I'm wrong

Answer:

all sides have different lengths

and the third angle measures 90⁰

[tex]volume \: = \frac{1}{3} \times base \: area \: \times \: height \\ [/tex]

Thus :

[tex]80 = \frac{1}{3} \times 24 \times h \\ [/tex]

[tex]h = \frac{80 \times 3}{24} \\ [/tex]

[tex]h = \frac{240}{24} \\ [/tex]

[tex]h = \frac{24 \times 10}{24} \\ [/tex]

[tex]h = 10 \: cm[/tex]

Thus the last option is the correct answer.

Answer:

a conjecture is a conclusion made on incomplete information

Step-by-step explanation:

so in saying that, it can be true or false because conjecture can be used with true information thats not fully been proved yet/ verified

hope I helped

The equation of a line in slope intercept form is given by:

y = mx + c

The equation 15x - 9y = -9 of a line into slope-intercept form after simplifying all fractions is y = (5/3)x + 1

The equation of a line is given by:

y = mx + c

where m is the slope of the line and c is the y-intercept.

Example:

y = 2x - 3

y = 3x + 4

We have,

15x - 9y = -9

We will rewrite in the slope-intercept form of y = mx + c.

15x - 9y = -9

Subtract 15x on both sides.

-9y = -9 - 15x

-9y = -15x - 9

Divide both sides by -9.

y = (-15x - 9) / -9

y = (15/9)x + 1

y = (5/3)x + 1

Slope = m = 5/3

y-intercept = 1

This is in the slope-intercept form of y = mx + c.

Thus,

The equation 15x - 9y = -9 of a line into slope-intercept form after simplifying all fractions is

y = (5/3)x + 1

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Answer:

a. (11) (24x) (2526xx)

11×24x=264x

264x ×2526x²

= 666864 =6.7×10⁵x²

Step-by-step explanation:

b. the product of a and b is not equal because the the numbers are the same except for 42 in question b. which makes them not to be equal

Answer: The Answer would be 61

Step-by-step explanation: You will be focusing on PEMDAS if you know the term. Parenthesis, Exponent, Multiplication, Division, Addition, and Subtraction, all in the order shown. Since there is no parenthesis or exponent, we go with multiplication as the first option in this problem. 16 x 3 and 3 x 3. 16 x 3 = 48, and 3 x 3 = 9. Since there is no Division on here, we will go the addition, where you add all the numbers up. 48 + 4 = 52 + 9 = 61

Hope this helps!

If the model remains valid, in the year 2,019 the average monthly bill will be $38.46

The linear equation that models the average monthly bill is:

B(x) = -$1.463*x + $95.514

We now want to know when the average monthly bill will be $38.46, then we need to solve:

B(x) = $38.46 = -$1.463*x + $95.514

Solving this for x, we get:

$38.46 = -$1.463*x + $95.514

$1.463*x = $95.514 - $38.46 = $57.054

x = ($57.054)/($1.463)  = 39

And x is the number of years after 1980, then this will be in the year:

1980 + 39 = 2,019

Then, if the model remains valid, in the year 2,019 the average monthly bill will be $38.46

If you want to learn more about linear functions, you can read:

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Answer:

Step-by-step explanation:

There's no image, so can't answer it.  If you upload an image, I will help :)

Answer:

Step-by-step explanation:

Need a picture or we can't solve so yes please post another one.

Answer:

23° and 157°

Step-by-step explanation:

Let n represent the smaller angle then the larger angle would be...

n+134

Supplementary angles add up to 180 degrees. We can use this information to set up an equation...

n+n+134=180

Combine like terms

2n+134=180

Subtract 134 from both sides

2n=46

Divide both sides by 2

n=23

n+134=157

23° and 157°

Answer:

The simplified version of this equation is -3x - 12.

Step-by-step explanation:

To simplify this equation, distribute -3 to both x and 4.

-3(x+4) = -3x -12

Answer:

-3x-12 as an expression

Step-by-step explanation:

To solve this problem, we need to distribute!

Multiply -3 by both the x and the 4

When we do this, we get:

-3x and -12

Note: when you multiply a positive by a negative, you get a negative so it turns into a negative number

Note 2: When you see an x without a number in front of it, it becomes 1x. In this problem, that is why it is a -3x because -3 x 1 is -3

Hope this helps! :) Please award brainliest if possible!

Answer: 240mph

Step-by-step explanation:

Answer:

C) 471

Step-by-step explanation:

Surface area for a cylinder formula:

SA = 2πrh + 2πr²

Given:

r = 5

h = 10

Work:

SA = 2πrh + 2πr²

SA = 2(3.14)(5)(10) + 2(3.14)(5²)

SA = 314 + 2(3.14)(25)

SA = 314 + 157

SA = 471

Answer:

1212=1212=

33weeks=33we2ks33weeks=33we2ks

weeks=we2ksweeks=we2ks

1616=we2ks1616=we2ks

Step-by-step explanation:

simplificar 16161616.

1212=1212=

33weeks=33we2ks33weeks=33we2ks

weeks=we2ksweeks=we2ks

1616=we2ks1616=we2ks