A pool float was filled with air to capacity in the middle of a hot day. The next morning the pool float looked different yet no gas escaped or entered the float. Describe what you think the float looked like in the morning and why it occurred.

Answers

Answer 1

Answer:

The pool float looked would have looked deflated the next morning.

Explanation:

When temperature decreases the volume decreases.


Related Questions

find the empirical formula for
42.05g of nitrogen, 95.95 of oxygen

and
7.33g of lanthanum, 2.96g of oxygen

Answers

Answer:

[tex]NO_2[/tex] and [tex]La_2O_7[/tex]

Explanation:

Nitrogen:

[tex]\frac{42.05}{14}=3[/tex]

Oxygen:

[tex]\frac{95.95}{16}=6[/tex]

Ratio:

[tex]3:6=1:2[/tex]

So empirical formula becomes [tex]NO_2[/tex]

-----

Lanthanum:

[tex]\frac{7.33}{139}=0.0527[/tex]

Oxygen:

[tex]\frac{2.96}{16}=0.185[/tex]

Ratio:

[tex]0.0527:0.185=1:3.5=2:7[/tex]

So empirical formula becomes [tex]La_2O_7[/tex]

gas
LA of certain mass occupies a volume of 650 cm3 under
a pressure of 760mmHg. Calculate the pressure under which
the volume of the
gas
cent
of its original volume
will be reduced by 10 per​

Answers

Answer:

844.4cm³

Explanation:

Using Boyle's law equation;

P1V1 = P2V2

Where;

P1 = initial pressure (mmHg)

P2 = final pressure (mmHg)

V1 = initial volume (cm³)

V2 = final volume (cm³)

According to the information in this question,

V1 = 650cm³

P1 = 760mmHg

P2 = ?

V2 = 10% reduction of V1

10% of 650 = 10/100 × 650

65

V2 = 650 - 65 = 585cm³

Using P1V1 = P2V2

P2 = P1V1 ÷ V2

P2 = (760 × 650) ÷ 585

P2 = 494000 ÷ 585

P2 = 844.44

final pressure (P2) = 844.4cm³

Describe the kinds of potential energy that are stored by a car driving on a hill.

Answers

Answer:

The internal combustion engine in the car converts the potential chemical energy in gasoline and oxygen into thermal energy which is transformed into the mechanical energy that accelerates the vehicle (increasing its kinetic energy) by causing the pressure and performing the work on the pistons.

Explanation:

When a mixture of iron powder and sulphur is heated it glows more brightly than that of iron filings and sulphur.Explain this observation

Answers

Answer:

I don't know

Explanation:

mixture of iron powder and sulphur heated it glows because sulphur and iron are more reactive metals that they shine and sulphur can react with water produce fire it's write

Use this equation to calculate the specific heat capacity of each metal:
cmetal =

c water = sp. heat capacity of water (4.18 J/gC)
m water = mass of the water in the cup
T water = change in water temperature
m metal = mass of the metal
T metal = change in metal temperature

What is the specific heat for the aluminum wire?
What is the specific heat for the steel wire?
What is the specific heat for the lead pellets?

Answers

Answer:

What is the specific heat for the aluminum wire?

0.82

What is the specific heat for the steel wire?

0.47

What is the specific heat for the lead pellets?

0.25

Explanation:

Answer:

What is the specific heat for the aluminum wire?

0.82

What is the specific heat for the steel wire?

0.47

What is the specific heat for the lead pellets?

0.25

Explanation:

This is the person above me. All credits go to them.

Does anyone know the simplest way to find the rate constant in rate law chemistry?

Answers

Answer:no I don’t sorry

Explanation:

A single atom of an element has 11 protons, 11 electrons, and 12 neutrons. Which element is it?
OV
Na
Mg
Se
Save and Frit

Answers

Answer:

Na

Explanation:

Sodium

What is the empirical formula for H2SO4? Explain.

Answers

Answer: The empirical formula is H2SO4 only.

Explanation: Because it is the simplest ratio of atoms of elements in a compound.

The probability?????????????????

Answers

Answer: 4/20

Explanation:

Identify the correct coefificients to balance it
-C3H8+O2 to -CO2 +-H2O

Answers

Answer:

[tex]{\rm 1\; C_3H_8} + {\rm 5\; O_2} \to {3\; \rm CO_2} + {4\; \rm H_2O}[/tex].

Explanation:

[tex]{\rm ?\; C_3H_8} + {\rm ?\; O_2} \to {?\; \rm CO_2} + {?\; \rm H_2O}[/tex].

Among the four species in this reaction, [tex]\rm C_3H_8[/tex] is species with the largest number of atoms per molecule. Assume that the coefficient of this compound is [tex]1[/tex].

[tex]{\rm 1\; C_3H_8} + {\rm ?\; O_2} \to {?\; \rm CO_2} + {?\; \rm H_2O}[/tex].

Number of atoms on the left-hand side of the reaction:

[tex]\rm C[/tex]: [tex]1 \times 3 = 3[/tex].[tex]\rm H[/tex]: [tex]1 \times 8 = 8[/tex].[tex]\rm O[/tex]: not found yet.

By the conservation of atoms, the number of atoms on the right-hand side of the reaction should match those on the left-hand side. In this reaction, [tex]\rm CO_2[/tex] is the only product with carbon atoms, whereas [tex]\rm H_2O[/tex] is the only product with hydrogen atoms. These [tex]3[/tex] carbon atoms and [tex]8[/tex] hydrogen atoms would correspond to:

[tex]3 / 1 = 3[/tex] [tex]\rm CO_2[/tex] molecules, and[tex]8 / 2 = 4[/tex] [tex]\rm H_2O[/tex] molecules.

[tex]{\rm 1\; C_3H_8} + {\rm ?\; O_2} \to {3\; \rm CO_2} + {4\; \rm H_2O}[/tex].

Number of atoms on the right-hand side of the reaction:

[tex]\rm C[/tex]: [tex]3 \times 1 = 3[/tex].[tex]\rm H[/tex]: [tex]4 \times 2 = 8[/tex].[tex]\rm O[/tex]: [tex]3 \times 2 + 4 \times 1 = 10[/tex].

The number of [tex]\rm O[/tex] atoms on the left-hand side should match those on the right-hand side. In this reaction, [tex]\rm O_2[/tex] is the only reactant with [tex]\rm O\![/tex] atoms. These [tex]10[/tex] [tex]\rm \! O[/tex] atoms would correspond to:

[tex]5[/tex] [tex]\rm O_2[/tex] molecules.

[tex]{\rm 1\; C_3H_8} + {\rm 5\; O_2} \to {3\; \rm CO_2} + {4\; \rm H_2O}[/tex].

what is the only thing that stops gamma rays?

Answers

The Answer is LEAD ......................

How is evaporation related to molarity?

Answers

Answer:

Molarity is the amount (in mole) of solute in a solvent. If the solute is very volatile, then it will evaporated from the solution as temperature rising. So the amount of solute is decreasing, causing the molarity decreasing. If the solvent itself volatile, then the molarity will increase.

(Looked up the answer for you)

The relationship between evaporation and molarity is; the rate of evaporation of will decrease as the molarity increases

What is evaporation and molarity?

Molarity (M) is defined as the amount of a substance in a certain volume of solution. Molarity can also be defined as the number of moles of a solute per liters of a solution.

Now, the rate of evaporation of will decrease as the solute concentration increases due to the fact that for the same surface area for evaporation, as the concentration of the solute increases, less water molecules will get exposed to escape from the water surface.

Read more about Evaporation and Molarity at; https://brainly.com/question/14718840

What about 50 g of water?
I need help what this

Answers

Answer:

3.38  Tablespoons

10.14 Teaspoons

0.21 U.S. Cups

0.18 Imperial Cups

0.20 Metric Cups

50.00 Milliliters

Explanation:

Identify Acid, Base, Conjugate acid, and base pairs in the following: HPO2 + NH" -> H-PO, + NH, Conjugate Acid ,HPO 2 Acid NH, ΝΗ, Base H PO Conjugate Base​ I need answers now

Answers

Answer:

no ablo inglés porfavor amigos

An atom starts with 20 electrons and 20 protons; after a reaction, it has 18 electrons and 20 protons.

Answers

Answer:

(+20) + (-18) = +2

Explanation:

3. Two liquids are being studied to find which one
evaporates more quickly. Liquid A boils at 50°C and
Liquid B boils at 25°C. Which liquid do you think
evaporates faster?
A.Liquid A
B.Liquid B
C.Both will evaporate at the same rate
D.Neither evaporate at all

Answers

Answer: D

Explanation:

Because at temerature at 25 and 50 is

to low for a compound to evaporate as gas because the bioling point is 100.

Answer: B

Explanation: Evaporation rate is influenced by the liquid's boiling temperature. A lower boilng point means that converting the liquid to a gas takes less energy because higher temperatures mean higher energy content. Assuming that this relationship holds at room temperature and that all other factors are equal, you should expect that Liquid B will evaporate faster.

The disinfectant hydrogen peroxide (H2O2)
decomposes to form water and oxygen gas.
How much O2 will result from the decomposition of 7.6 mol of hydrogen peroxide?
Answer in units of mol.

Answers

Answer: amount of O2 is 3.8 moles

Explanation: reaction. 2 H2O2 -> 2 H2O + O2

Two moles H2O2. Produces one ole Oxygen

How many moles of oxygen are required to react with 12 moles of FeS2?

4FeS2 + 11O2 → 2Fe2O3 + 8SO2

Answers

19 moles of O2 probably

Define Evaporation.
Thanks​

Answers

Answer:

evapouration is a type of vaporization that occur on the surface of liquid as it change into the gas phase.

hope it helps.

Evaporation happens when a liquid turns into a gas. It can be easily visualized when rain puddles “disappear” on a hot day or when wet clothes dry in the sun.

(iii) Explain the following statements about drugs:
a. You can be arrested by the police for possessing heroin
b.All drugs are dangerous.​

Answers

Answer:

A

Explanation:

Heroine destroying the body system

Carlotta notices that the words of a book are blurry, but a sign across the road is not. What might correct Carlotta’s vision?


a diverging lens, to fix her farsightedness

a diverging lens, to fix her nearsightedness

a converging lens, to fix her farsightedness

a converging lens, to fix her nearsightedness


hurry plz

Answers

Answer:

C.

Explanation:

What is the total number of grams of HI in 0.500 liter of
1.00 M HI?
64.0 g
128 g
1.00 g
0.500 g

Answers

Answer:

The amount of HI is "64 grams".

Explanation:

The given values are:

Volume,

= 0.500 L

Molarity,

= 1.00 H

Molar mass of HI,

= 128

Now,

The moles of HI will be:

=  [tex]Molarity\times Volume[/tex]

On substituting the values, we get

=  [tex]1.00\times 0.500[/tex]

=  [tex]0.5 \ mol[/tex]

hence,

The amount of HI will be:

=  [tex]Moles\times Molar \ mass[/tex]

=  [tex]0.5\times 128[/tex]

=  [tex]64 \ grams[/tex]

The following diagram on the left represents the copper nitrate solution in the half‑cell before the galvanic cell starts to operate. In the following diagram on the right, draw a representation of the solution in the same half‑cell after the galvanic cell has been operating for some time and is still producing a voltage.

Before reaction : 4 Cu2+ molecules and 8NO3-

Answers

Answer:

There is too much here for me to attempt in one sitting, but I will get you started and give suggestions that may help you proceed on your own.

a)  As far as I can tell, you didn't provide the reduction potentials in the table below.  So, I looked them up and find them to be

Cu2+ +2e- ==> Cu(s)  Eº = +0.34 V

Zn2+ + 2e- ==> Zn(s)  Eº = -0.76 V

Net ionic equation:  Cu2+(aq) + Zn(s) ==> Cu(s) + Zn2+(aq)

b)  Eºcell = 0.34 V + 0.76 V = 1.10 V

c)  ∆Gº = -nFEº  where n = number of electrons transferred (2) and F = 96,485 C/mol e- and Eº = 1.1 V

d)  Again, there is no diagram

e)  same

f)  Use the Nernst equation  Ecell = Eºcell - 2.303RT/nF log Q  where R = 8.314; T = Kelvin; F = Faraday const. and Q = reaction quotient, i.e. products/reactants

g)  the cell voltage is an intensive property.  That should help you answer this part of the question

Explanation:

its not much but i hoped this helped

From the balanced reaction below, when you have 3.33 moles of (NH4)2Cr2O7, how many grams of N2 will be produced

Answers

Answer:

[tex]m_{N_2}=93.3gN_2[/tex]

Explanation:

Hello there!

In this case, for this stoichiometry-based problem, it is firstly necessary to realize that the decomposition of ammonium dichromate is given by:

[tex](NH_4)_2Cr_2O_7(s)\rightarrow N_2(g)+4H_2O(l)+Cr_2O_3(s)[/tex]

Thus, since the mole ratio between ammonium dichromate and the gaseous nitrogen (molar mass = 28.02 g/mol) is 1:1, we can compute the produced mass of the latter via stoichiometry as shown below:

[tex]m_{N_2}=3.33mol(NH_4)_2Cr_2O_7*\frac{1molN_2}{1mol(NH_4)_2Cr_2O_7}*\frac{28.01gN_2}{1molN_2}\\\\ m_{N_2}=93.3gN_2[/tex]

Best regards!

Now balance the chemical reaction by providing the correct coefficients:

carbon + fluorine gas yields
carbon tetrafluoride

[?] C+[?]F2 → [?]CF4

Answers

1C + 2F2 -> 1CF4 is the answer
So the coefficients are 1,21

Orbital structure of sodium?

Answers

Answer:

na.

sodium

11( 2,81,)

pls Mark me as brainlest

where is the magnitude of force of magnetism the greatest​

Answers

Answer:

The strength of the field varies depending on its location around the magnet. The magnetic field of a bar magnet is strongest at either pole of the magnet. It is equally strong at the north pole when compared with the south pole.

Explanation:

What is a limitation for using solar energy to meet global energy needs?

Answers

Answer:

The sun provides more than enough energy to meet the whole world's energy needs, and unlike fossil fuels, it won't run out anytime soon. As a renewable energy source, the only limitation of solar power is our ability to turn it into electricity in an efficient and cost-effective way.

A helium balloon with a volume of 5.0 L and a pressure of 105 kPa at 25°C floats up high in the sky where the pressure is 850 mm Hg and the temperature is -15°C. What is the new volume of the balloon?

Answers

Answer:

volume 2-     4.011 L

Un convertidor catalítico acelera la reacción del monóxido de carbono con oxígeno para producir dióxido de carbono. ¿De qué manera cada uno de los siguientes cambios afectaría la velocidad de reacción que se muestra aquí? Sustente 2CO (g) + O2(g) → 2CO2(g) a). Quitar el catalizador. B). Eliminar parte de O2(g)

Answers

Answer:

a. Disminuye.

b. Disminuye.

Explanation:

¡Hola!

En este caso, considerando que tenemos una reacción en la cual se podría asumir que tanto la concentración de monóxido de carbono y la de oxígeno contribuye a la velocidad de reacción, de acuerdo a la siguiente cinética elemental:

[tex]r=k[CO]^2[O_2][/tex]

Al aplicar los siguientes cambios, resultaría:

a. En este caso, bien sabemos que la velocidad de reacción es aumentada al adicionar un catalizador ya que la constante de velocidad aumenta al disminuir la energía de activación; no obstante, al retirar el catalizador, la energía de activación aumentaría y por consiguiente la velocidad de reacción disminuiría.

b. En este caso, dado que la relación entre el oxígeno y la rapidez de reacción es directamente proporcional, es possible para nosotros determinar que al eliminar parte del oxígeno, la concentración disminuye y por ende la velocidad de reacción también.

¡Saludos!

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