A population of bacteria is 8500 on day 1, 9350 on day 2, and 10,285 on day 3. What will the population be on day 30?.

Answers

Answer 1

Population are often represented using exponential functions

The population of the bacteria on day 30 is 134837

Let x represent the number of days, and y represents the population.

So, we have: (x,y) = (1,8500), (2, 9350) (3, 10285)

An exponential functions is represented as [tex]\mathbf{y = ab^x}[/tex]

So, we have:

[tex]\mathbf{8500 = ab}[/tex]

[tex]\mathbf{9350 = ab^2}[/tex]

Divide both equations

[tex]\mathbf{\frac{9350}{8500} = \frac{ab^2}{ab}}[/tex]

[tex]\mathbf{1.1 = b}[/tex]

Rewrite as:

[tex]\mathbf{b = 1.1 }[/tex]

Substitute 1.1 for b in [tex]\mathbf{8500 = ab}[/tex]

[tex]\mathbf{ 8500 = 1.1a}[/tex]

Divide both sides by 1.1

[tex]\mathbf{ 7727.3 = a}[/tex]

Rewrite as:

[tex]\mathbf{ a = 7727.3 }[/tex]

So, we have:

[tex]\mathbf{y = ab^x}[/tex]

[tex]\mathbf{y = 7727.3 \times 1.1^x}[/tex]

On day 30, we have: x = 30.

So, the equation becomes

[tex]\mathbf{y = 7727.3 \times 1.1^{30}}[/tex]

[tex]\mathbf{y = 134837}[/tex]

Hence, the population of the bacteria on day 30 is 134837

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Using the equations 2 sr(s) + o₂ (g) → 2 sro (s) ∆h° = -1184 kj/mol co₂ (g) → c (s) + o₂ (g) ∆h° = 394 kj/mol determine the molar enthalpy (in kj/mol) for the reaction c(s) + 2 sro(s) → co₂ (g) + 2 sr(s).

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Considering the Hess's Law, the enthalpy change for the reaction is 790 kJ/mol.

Hess's Law indicates that the enthalpy change in a chemical reaction is the sum of the ∆H of each stage of the reaction will give us a value equal to the ∆H of the reaction when it occurs in a single stage.

In this case you want to calculate the enthalpy change of:

C(s) + 2 SrO(s) → CO₂ (g) + 2 Sr(s)

You know the following reactions, with their corresponding enthalpies:

Equation 1: 2 Sr (s) + O₂ (g) → 2 SrO (s) ∆H° = -1184 kJ/mol

Equation 2: CO₂ (g) → C (s) + O₂ (g) ∆H° = 394 kJ/mol  

First step

In this case, first, to obtain the enthalpy of the desired chemical reaction you need 1 mole of C (s) on reactant side and it is present in second equation. But since this equation has 1 mole of C (s) on the product side, it is necessary to locate this on the reactant side (invert the reaction). And when an equation is inverted, the sign of ΔH also changes.  

Second step

Now, 2 moles of SrO (s) must be a reactant and is present in the first equation. Since this equation has 2 moles of Sr0 (s) on the product side, it is necessary to locate the O on the reactant side (invert the reaction) and the sign of ΔH changes.

Summary

In summary, you know that two equations with their corresponding enthalpies are:

Equation 1:  2 SrO (s) → 2 Sr (s) + O₂ (g)     ∆H° = 1184 kJ/mol

Equation 2: C (s) + O₂ (g) → CO₂ (g)     ∆H° = -394 kJ/mol

Adding or canceling the reactants and products as appropriate, and adding the enthalpies algebraically, you obtain:

C(s) + 2 SrO(s) → CO₂ (g) + 2 Sr(s)     ΔH= 790 kJ/mol

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edge 2022

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Answer:democracy

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Option C

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990-00

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The diagram shows the intersections of several straight roads. The avenues run parallel to each other. First Avenue and Second Avenue are parallel. Oak goes through both streets at point A and B. Main goes diagonally down through both streets and intersects with Oak Street. The distance from First to Second on Main is 280 feet. The distance from Second to the intersection of Oak is 140 feet. The distance from Point B to the intersection of Main is 113 feet. Amana walks along Oak from point A to B. To the nearest foot, how far does she walk? 75 ft 226 ft 307 ft 347 ft.

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answer is B 226 ft

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because I got it right

Answer:

The above answer is correct - option B. 226 is your answer :D

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Here's a screenshot for proof :)

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Answer:

C. 115°

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I did it

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Answer:

facilitate currency conversion

Analyze the solution set of the following system by following the given steps. 2x y = 5 3y = 9 − 6x Write each equation in slope-intercept form. Y = x y = x.

Answers

Answer:

2x + y = 5  

2x -2x+ y = 5 -2x

y=5-2x  

y=-2x+5

3y = 9 − 6x

3y/3= 9/3 - 6x/3

y = 3 - 2x  

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y= - 2x +3

Explanation: Hope this helps :)

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