a quickly moving house cat has 10 j of kinetic energy at speed v. at what speed will the cat have 20 j of kinetic energy

yes an electromagnetic is temporary

Answer:

I believe it's 2. I am not sure though.

Given :

Two forces act on a 6.00-kg object. One of the forces is 10.0 N.

Acceleration of object 2 m/s².

To Find :

The greatest possible magnitude of the other force.\

Solution :

Let, other force is f.

So, net force, F = 10 + f.

Now, acceleration is given by :

[tex]a=\dfrac{F}{mass}\\\\a= \dfrac{10+f}{6}\\\\\dfrac{10+f}{6}=2\\\\f = 12 - 10\\\\f = 2 \ N[/tex]

Therefore, the greatest possible magnitude of the other force is 2 N.

Hence, this is the required solution.

Answer:

Heat is kinetic energy -- the higher the temperature of a substance, the faster and farther its molecules move.

Explanation:

... Conversely, when heat transfers from your beverage to the ice and the temperature of the liquid drops, the molecules in the beverage slow down. When those molecules slow down, their kinetic energy decreases.

Answer:

True

Explanation:

Answer:

the correct answer is b

Answer:

true

Explanation:

just did it on ck12 lol

Answer:

Explanation:

The work done by an object can be found by using the formula

workdone = force × distance

From the question we have

workdone = 10 × 10

We have the final answer as

Hope this helps you

Answer:

x = 95 [m]

Explanation:

To solve this problem we must use the following equation of kinematics.

[tex]v_{f} =v_{o} +a*t[/tex]

where:

Vf = final velocity = 19 [m/s]

Vo = initial velocity = 0 (starts from the rest)

a = acceleration [m/s²]

t = time = 10 [s]

Now we can find the acceleration

19 = 0 *a*(10)

a = 1.9 [m/s]

With the second equation we can find the distance:

[tex]v_{f} ^{2} =v_{o} ^{2} +(2*a*x)[/tex]

where:

x = distance [m]

(19)² = (0)² + (2*1.9*x)

3.8*x = 361

x = 95 [m]

Answer:

1200 N

Explanation:

Answer:

1200N

Explanation:

Suppose a body of mass "m" and its weight on the moon is Wm (where W is the weight and "m" is the moon ;which means weight on the moon).Mass of the moon is "M"

and its radius is "R"

Weight of an object on the moon = "F"(Force)with which the moon pulls.

Wm = GM*m/r2

Weight of the same object on the earth is We(where W is the weight and "e" is the earth; which means weight on the earth).

Mass of the earth is 100 times of that of the moon.

Radius of the moon = R

Radius of the Earth = 4R

Weight of the object on the moon =

We = G100M*m/(4R)2(Pronounced 4 R square)

We = G100M*m/(16R)2(Pronounced 16 R square)

Wm/We = G * M * m * 16R2/R2 * g * 100M * m

=16/100

Therefore, 4800N on earth= 1200N on moon

Explanation:

P.E=MGH

(1) P.E=5×10(G)×3

= 150 kg m^/s^ ( ^ =sqaure)

(2) P.E=5×10×6

= 300 kg m^/s^

Hope it helps, just remember the formula u can solve any question regarding gravition of earth (P.E=Mgh)

Answer:

number of home runs a player would hit would drastically increase

Explanation:

In a hypothetical scenario, if this were to happen the number of home runs a player would hit would drastically increase. When a player hits the ball force is applied to the ball which sends it flying, then the ball meets an opposing force of air resistance and a downward force of gravity which ultimately causes the ball to fall to the ground. This is explained in Newton's first law which states that "objects in motion remain in uniform motion and in a straight line unless they are met by an opposing unbalanced force." Without the force of air resistance, the ball will only be met with a downward force of gravity which would allow it to travel at a much greater distance before hitting the ground, thus resulting in a drastic increase of home runs.

Answer:

number of home runs a player would hit would drastically increase

Explanation:

Answer:

The kilometer is unit of length in the metric system equivalent to one thousand meters. 1Km is equivalent to 0.6214 miles.

Explanation:

Length is the measurement of the distance from the initial point to the final point.

________________________________________________________

The Si unit of length is meter, that means length is measured in meter units.

The Relation between meter and kilometer is that they both are the units of the length, also the Kilometer(Km) is equals to the 1000 meters(m).

1Km = 1000 meter

1m = 0.001 Km

Answer:

spectra.

Atomic spectra is series of colored lines which occures when atoms emit light of certain wavelengths. Element produces a particular set of spectral lines.

Electrons exist in shells and each shell has a specific energy. Electrons absorb photons and jump to higher energy levels.

Explanation:

Answer:

Speed describes only how fast an object is moving, whereas velocity gives both the speed and direction of the object’s motion being a vector quantity. The standard unit to measure velocity is meter per second (m/s or ms-1). For example, “10 meters per second” is scalar and “10 meters per second West” is vector. Acceleration

Explanation:

the small bodies in the solar system include comets, asteroids, the objects in the Kuiper Belt and the Oort cloud, small planetary satellites, Triton, Pluto, Charon, and interplanetary dust. As some of these objects are believed to be minimally altered from their state in the young solar nebula from which the planets formed, they may provide insight into planet Earth and the formation and evolution of the solar system.

Answer:

b

Explanation:

Answer:

The basket ball

Explanation:

The heavier an object is the more kinetic energy it will have even if it is thrown at the same speed; therefore, since the basketball is the heaviest, it is the logical answer.

While a marble is heavy for its size, it would not have the same kinetic energy as the basket ball.

Beach balls weigh the least out of the options given so this cannot be the answer.

Golf balls, while they are dense, they do not weigh nearly as much as a basketball would!

Hope this helps <3

Answer:

The answer is B the basketball

Explanation:

Answer:

1.00 m is a more accurate measured length.

Explanation:

Denote length of the table by L.

For L=1.0 m, there is one significant digit after the decimal.

Care 1: When one more significant digit after decimal considered, the exact number can be from 0.95 to 1.05.

So, the possible span of error [tex]\Delta E_1= 1.05-0.95= 0.1m[/tex]

For L=1.00 m, there is two significant digits after the decimal.

Case 2: When one more significant digit after decimal considered, the exact number can be from 0.095 to 1.005.

So, the possible span of error [tex]\Delta E_2= 1.005-0.095= 0.01m[/tex]

Case 3: For L=1.000 m, there is three significant digits after the decimal.

When one more significant digit after decimal considered, the exact number can be from 0.0095 to 1.0005.

So, the possible span of error [tex]\Delta E_3= 1.0005-0.0095= 0.001m[/tex]

As [tex]\Delta E_1 >\Delta E_2>\Delta E_3[/tex]

So, the least error is in the third case when L=1.00m, hence, L= 1.00m is more accurate.

Answer:

7.69km/hr due east

Explanation:

Given parameters:

Displacement due west  = 3km

Displacement due east = 2km

Time taken  = 8 minutes

Unknown:

Average velocity  = ?

Solution:

Average velocity is the rate of change of displacement with time.

  Velocity  = [tex]\frac{displacement}{time }[/tex]

 Displacement is deals with the start and the end;

  Here, displacement  = 3km - 2km  = 1km due east

Time  = 8min

     60min  = 1hr

       8min = [tex]\frac{8}{60}[/tex]   = 0.13hr

 Average velocity = [tex]\frac{1km}{0.13hr}[/tex]   = 7.69km/hr due east

Answer:

Other than gravity, the most commonly encountered force is what or the force that resists motion.

friction

the ratio of the force necessary to move an object (or keep it moving) and the normal force

coefficient of friction

friction between a solid and a liquid or gas

drag

a force that resists motion

friction

the force that presses two surfaces together and is directed perpendicular to the contact surface; on a level surface, its magnitude is equal to the force of the object's weight but in the opposite direction

normal force

force that opposes a rolling object

rolling friction

force that opposes a sliding object

sliding or kinetic friction

force that opposes the start of motion

starting or static friction

a force that develops when a mass is accelerated by gravity; stated as Fw = mg

weight

Friction is a force that resists what

motion

It occurs when a surface in motion rubs against another what

surface

What acts parallel to the surfaces that are moving against one another and in the direction opposite to the direction of the motion (represented by F).

Friction

riction is caused by the interaction of the what or what of each object sliding over each other.

atom or molecules

he more contact the atoms are able to make, the greater the what

frictional effect

A what surface will produce more friction (resistance) than a smooth surface

rough surface

The high points on one surface interact with the high points on the other surface allowing atoms and molecules to form temporary what

intermolecular bonds

The more bonds that are allowed to form, the greater the what

friction

he force that opposes the start of motion is referred to as what

starting or static friction

This force is caused by the what that form between two surfaces

tiny bonds

The pull required to keep the block moving at a constant speed in the example above is due to what

sliding or kinetic friction

What occurs as tiny intermolecular bonds are constantly being formed and broken.

Sliding friction

Sliding friction is also affected by the weight of the object and another force called the what

normal force

What is the force of the contact surface pressing opposite the weight of the object, as seen in the diagram below.

normal force

The normal force is always perpendicular to the what

contact surface

The ratio between the sliding friction and the perpendicular normal force is called the what of sliding friction

coefficient

What is represented by the Greek letter mu, μ,

coefficient

he third type of friction that can exist between solid surfaces is what or the force that opposes a rolling object

rolling friction

Friction can also exist between what

solids liquids and gases

Gases and liquids, such as air and water, offer what

resistance to motion

the opposing force between a solid and a liquid or gas

drag

Given :

A box weighing 12,000 N is parked on a 36° slope.

To Find :

What will be the component of the weight parallel to the plane that balances friction.

Solution :

The component of that will be parallel to the plane to balance friction is :

[tex]F \ cos ( 90 - 36)^o\\\\F\ ( sin\ 36^o)[/tex]

Therefore, component of force to balance friction is F sin 36° .

Hence, this is the required solution.

Answer:

(a) The aspect of the upper string supporting the weight and the applied force

Student 1 is correct because the upper string is the source of support of the large weight and the force applied to the short string reacts at the support of the long string

(b) The aspect of Student's (2) reasoning that is correct is that the shorter piece of string will always break first, however, the statement is only true for sudden pull due to the increased force experienced by the shorter string from a more rapid change in momentum

(c) The aspect of Student 1's statement that is incorrect is the that the upper string will always break first

The aspect of Student 2's statement that is incorrect is the that the shorter piece of string will always break first

(d) A string will break when subject to a force equivalent to its breaking force. The force experienced by the string increases as the rate of pull (suddenness) increases and the suddenness increases inversely with the length of the string, as such the shorter lower string will break first from a sudden pull before the force of the pull is completely transmitted to the upper string. Whereby the lower string is slowly pulled, the force is evenly transmitted to the upper string which is then taking up the load of the weight and the applied force together and is likely to break first

Explanation:

Answer:

2

Explanation:

pressure(p)=force(f)\area(a)