A recreational vehicle in the amusement park is traveling on a frictionless track that can make a circular loop as shown in the figure below. The vehicle is released from a point A at a height h from the base of the circular section of the track. (a) What must be the minimum height h required for the vehicle to complete the circular section of the track at point B without falling? If h= 3.50 R and R=20 m, calculate the speed, centripetal acceleration and tangential acceleration of the occupants while the vehicle is at point C (point C is in the horizontal diameter direction).

Answers

Answer 1

The minimum height that the block must start to make it around the loop without falling off is h = 5R/2

What is present inside the circular loop?

The block slides are around the inside of a circular loop. This shows that or it means that we are dealing with critical velocity in vertical circular motion.

In the critical velocity in the vertical circular motion, the formula for the minimum velocity just at the lowest Point of the vertical circle required to get the critical velocity at the highest point is given as;

v = √(5gR)

Therefore, m will cancel out to give;

½v² = gh

Plugging in the relevant values gives;

½ × [√(5gR)]² = gh

Simplify to get;

5gR = 2gh

g will cancel out to get;

5R = 2h

h = 5R/2

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Related Questions

It is almost as if each outer planet is a solar system in its own right.

True or False

Answers

False there are many planets in our solar system
False.... planets like venus / mars is in our solar system

Which of the following is true of the
thermocline layer of the ocean?
A. rapidly decreases in temperature
B. warmest and least dense of the ocean layers
C. is the bottom layer of the ocean
D. is the top layer of the ocean

Answers

Answer:

d is trueeeeeeeeeeeeeeeee

A turntable, with a mass of 1.5 kg and diameter of 20 cm, rotates at 70 rpm on frictionless bearings. Two 540 g blocks fall from above, hit the turntable simultaneously at opposite ends of a diameter, and stick to it.

Required:
What is the turntable's angular speed, in rpm, just after this event?

Answers

Answer:

The turntable's angular speed after the event is 28.687 revolutions per minute.

Explanation:

The system formed by the turntable and the two block are not under the effect of any external force, so we can apply the Principle of Conservation of Angular Momentum, which states that:

[tex]I_{T}\cdot \omega_{o} = (2\cdot r^{2}\cdot m +I_{T})\cdot \omega_{f}[/tex] (1)

Where:

[tex]I_{T}[/tex] - Moment of inertia of the turntable, in kilogram-square meters.

[tex]r[/tex] - Distance of the block regarding the center of the turntable, in meters.

[tex]m[/tex] - Mass of the object, in kilograms.

[tex]\omega_{o}[/tex] - Initial angular speed of the turntable, in radians per second.

[tex]\omega_{f}[/tex] - Final angular speed of the turntable-objects system, in radians per second.

In addition, the momentum of inertia of the turntable is determined by following formula:

[tex]I_{T} = \frac{1}{2}\cdot M\cdot r^{2}[/tex] (2)

Where [tex]M[/tex] is the mass of the turntable, in kilograms.

If we know that [tex]\omega_{o} \approx 7.330\,\frac{rad}{s}[/tex], [tex]M = 1.5\,kg[/tex], [tex]m = 0.54\,kg[/tex] and [tex]r = 0.1\,m[/tex], then the angular speed of the turntable after the event is:

[tex]I_{T} = \frac{1}{2}\cdot M\cdot r^{2}[/tex]

[tex]I_{T} = 7.5\times 10^{-3}\,kg\cdot m^{2}[/tex]

[tex]I_{T}\cdot \omega_{o} = (2\cdot r^{2}\cdot m +I_{T})\cdot \omega_{f}[/tex]

[tex]\omega_{f} = \frac{I_{T}\cdot \omega_{o}}{2\cdot r^{2}\cdot m +I_{T}}[/tex]

[tex]\omega_{T} = 3.004\,\frac{rad}{s}[/tex] ([tex]28.687\,\frac{rev}{min}[/tex])

The turntable's angular speed after the event is 28.687 revolutions per minute.

1.
is the rate that velocity changes
O Acceleration
O
Time
O
Distance
O
Mass

Answers

Answer:

a) acceleration

Explanation:

Acceleration is, by definition, the change of an object's velocity.

what happens during subduction

Answers

Answer:

Subduction , Latin for "carried under," is a term used for a specific type of plate interaction. It happens when one lithospheric plate meets another—that is, in convergent zones —and the denser plate sinks down into the mantle.

Two points on a progressive wave are out of phase by 0.41 rad.
What is this phase difference?
[1 mark]
A 23° [e]
B 47° [e]
C 74° [e]
D 148° [e]

Answers

The phase difference between two points on a progressive wave are out of phase by 0.41 rad is 23°.

What is an equation?

An equation is an expression that shows the relationship between two or more numbers and variables.

The two points on a progressive wave are out of phase by 0.41 rad.

Hence, Phase difference = 0.41 rad

But:

Rad to degree = (rad * 180/π)°

Hence:

0.41 rad = (0.41 rad * 180/π) = 23°

The phase difference between two points on a progressive wave are out of phase by 0.41 rad is 23°.

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Select all the correct answers.
Which statements about our solar system are false?
Our solar system is made up of the Sun and other objects that orbit the Sun.
The Sun is the only star in our solar system.
Dwarf planets have several other bodies in their path orbiting the Sun just as they do.
The Kuiper Belt is between Uranus and Neptune.
A large number of irregularly shaped comets are located in a vast ring between the orbits of Mars and Jupiter.

Answers

D and E are false.

A, B, and C are true.

Answer:

- Our solar system is made up of the Sun and other objects that orbit the Sun.

- The Sun is the only star in our solar system.

- Dwarf planets have several other bodies in their path orbiting the Sun just as they do.

Explanation:

plato

Can anybody help in number 6? <3​

Answers

Answer:

5.4 will be the weight in illustrate form

Describe the formation of the land, the atmosphere, and the oceans of earth

Answers

Land: Tectonic plate movement under the Earth can create landforms by pushing up mountains and hills. Erosion by water and wind can wear down land and create landforms like valleys and canyons. ... Landforms can exist under water in the form of mountain ranges and basins under the sea.

Atmosphere: (4.6 billion years ago)
As Earth cooled, an atmosphere formed mainly from gases spewed from volcanoes. It included hydrogen sulfide, methane, and ten to 200 times as much carbon dioxide as today's atmosphere. After about half a billion years, Earth's surface cooled and solidified enough for water to collect on it.

Ocean: After the Earth's surface had cooled to a temperature below the boiling point of water, rain began to fall—and continued to fall for centuries. As the water drained into the great hollows in the Earth's surface, the primeval ocean came into existence. The forces of gravity prevented the water from leaving the planet.

A charged particle (charge 1.6x10-19 C and mass 1.67x10-27 kg) is initially moving with a velocity of 2x105 m/s and then moves into a region having a magnetic field and an electric field (6x104 V/m). The direction of initial velocity is perpendicular to the electric field and magnetic field. If the charged particle keep moving in the original direction without being deflected, what is the magnitude of the magnetic field

Answers

Answer:

[tex]0.3\ \text{T}[/tex]

Explanation:

q = Charge = [tex]1.6\times 10^{-19}\ \text{C}[/tex]

m = Mass of particle = [tex]1.67\times 10^{-27}\ \text{kg}[/tex]

v = Velocity = [tex]2\times 10^5\ \text{m/s}[/tex]

E = Electric field = [tex]6\times 10^4\ \text{V/m}[/tex]

B = Magnetic field

Magnetic field is given by

[tex]B=\dfrac{E}{v}\\\Rightarrow B=\dfrac{6\times 10^4}{2\times 10^5}\\\Rightarrow B=0.3\ \text{T}[/tex]

The magnitude of magnetic field is [tex]0.3\ \text{T}[/tex]

A student hangs a block from a light string that is attached to a massive pulley of unknown radius R, as shown in the figure. The student allows the block to fall from rest to the floor. Which two of the following sets of data that could be measured or determined should the student use together to determine the final angular velocity of the pulley just before the block hits the floor? Select two answers. Justify your selections.

Answers

Answer:

The mass of the block, the distance of the block above the floor, and the time it takes the block to reach the floor, because these quantities can be used to determine the acceleration of the block.

The radius and the mass of the pulley, because these quantities can be used together to determine the rotational inertia of the pulley.

Explanation:

If the motion starts from rest, the initial angular velocity will be zero and the final angular velocity can be determined with the product of angular acceleration and time of motion of the pulley.

Angular velocity is defined as the change in the angular displacement per change in time of motion. This can be expressed mathematically as follows;

[tex]\omega = \frac{\Delta \theta}{\Delta t} = vr[/tex]

where;

Ф is the angular displacementt is the time of the motionv is the linear velocityr is the radius of the circular path.

In a circular motion that starts from rest and ends with final velocity, the equation is given as;

[tex]\omega_f =\omega_i + \alpha t[/tex]

Where;

[tex]\omega_f[/tex] is the final angular velocity[tex]\omega_i[/tex] is the initial angular velocity[tex]\alpha[/tex] is the angular acceleration

Thus, if the motion starts from rest, the initial angular velocity will be zero and the final angular velocity can be determined with the product of angular acceleration and time of motion of the pulley.

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TIME REMAINING
15:56:15
A plant root is an example of
Type here to search

Answers

Answer:

h

Explanation:

Which of the following is NOT true about
newspaper weather maps?
A. They report the temperature of the area in degrees
Fahrenheit.
B. They let you know how much precipitation to expect.
C. They provide more detail than weather service maps.
D. They tell you about the warm and cold air fronts.

Answers

It’s obviously C since all the rest of the answers make sense except for C.

A wave has a frequency of 2 Hz. Find its period

Answers

It’s period would be 0.5 seconds or 1/2. I think
T=1/f where f=2Hz => T=1/2 or 0,5 seconds.

g A velocity selector consists of crossed electric and magnetic fields. The electric field has a magnitude of 480 N/C and is in the negative z direction. What should the magnetic field (magnitude and direction) be to select a proton moving in the negative x direction with a velocity of 3.50 cross times 10 to the power of 5 m/s to go un-deflected

Answers

Answer:

B = 1.37 mT

Explanation:

Given that,

The magnitude of the electric field, E = 480 N/C

The speed of the proton, [tex]v=3.50 \times 10^5\ m/s[/tex]

We need to find the magnitude of the magnetic field. In a velocity selector, the electric field is balanced by the magnetic field. So,

[tex]qE=qvB[/tex]

Where

B is the magnetic field

[tex]B=\dfrac{E}{v}\\\\B=\dfrac{480}{3.5\times 10^5}\\\\B=1.37\times 10^{-3}\ T\\\\or\\\\B =1.37\ mT[/tex]

So, the magnetic field is equal to 1.37 mT.

Coherent monochromatic light of wavelength l passes through a narrow slit of width a, and a diffraction pattern is observed on a screen that is a distance x from the slit. On the screen, the width w of the central diffraction maximum is twice the distance x. What is the ratio a>l of the width of the slit to the wavelength of the light

Answers

Answer:

λ = a

Explanation:

This is a diffraction exercise that is described by the expression

          a sin θ = m λ

         sin θ  = m λ/ a

the first zero of the diffraction occurs for m = 1

        sin θ  = λ / a

 

angles are generally very small and are measured in radians

         sin θ  = θ  = y / x

we substitute

         [tex]\frac{y}{x} = \frac{\lambda}{a}[/tex]

the width of the central maximum is twice the distance to zero

         w = 2y

in the exercise indicate that this width is equal to twice the distance to the screen (2x)

          W = 2x

           2y = 2x

we substitute

          1 = λ/ a

          λ = a

we see that the width of the slit is equal to the wavelength used.

Jovian planets have rings because:__________.
a. their thick gaseous atmospheres would disintegrate any small rock that enter them
b. there is too much material to have fit into the ball of each planet
c. tidal forces prevent the material in rings from forming into moons
d. Jovian planets rotate very rapidly, and some material near the equator of these planets was flung outward, forming the rings
e. tidal forces cause volcanic eruptions on some moons, and part of this material subsequently escaped the gravity of the moons, forming the rings.

Answers

Answer:

E

Explanation:

Planets after Mars in our solar system are called Jovian planets. Therefore, Jupiter, Saturn, Uranus and Neptune are Jovian planets. The specialty of these planets is that they mostly made of gases and have ring around them.

They have rings around them because tidal forces cause volcanic eruptions on some moons, and part of this material subsequently escaped the gravity of the moons, forming the rings.

A 101 kg basketball player crouches down 0.380 m while waiting to jump. After exerting a force on the floor through this 0.380 m, his feet leave the floor and his center of gravity rises 0.920 m above its normal standing erect position. (a) Using energy considerations, calculate his velocity (in m/s) when he leaves the floor. m/s (b) What average force (in N) did he exert on the floor

Answers

Answer:

[tex]4.25\ \text{m/s}[/tex]

[tex]3391.22\ \text{N}[/tex]

Explanation:

y = Height of compression = 0.38 m

m = Mass of basketball player = 101 kg

h = Height of center of gravity after jump = 0.92 m

g = Acceleration due to gravity = [tex]9.81\ \text{m/s}^2[/tex]

Energy balance of the system is given by

[tex]mgh=\dfrac{1}{2}mv^2\\\Rightarrow v=\sqrt{2gh}\\\Rightarrow v=\sqrt{2\times 9.81\times 0.92}\\\Rightarrow v=4.25\ \text{m/s}[/tex]

The velocity of the player when he leaves the floor is [tex]4.25\ \text{m/s}[/tex]

[tex]Fy=mgy+\dfrac{1}{2}mv^2\\\Rightarrow F=\dfrac{mgy+\dfrac{1}{2}mv^2}{y}\\\Rightarrow F=\dfrac{101\times 9.81\times 0.38+\dfrac{1}{2}\times 101\times 4.25^2}{0.38}\\\Rightarrow F=3391.22\ \text{N}[/tex]

The force exerted on the floor is [tex]3391.22\ \text{N}[/tex].

It takes 20 seconds to fill a two-liter bottle with water from your kitchen faucet. What is the mass flow rate from the faucet if water has a density of 1000 fraction numerator k g over denominator m cubed end fraction?
a. 0.1kg/sec.
b. 0.01kg/sec.
c. 1g/sec.
d. 1kg/sec.

Answers

Answer:

0.1 kg/s.

Explanation:

The density of water, d = 1000 kg/m³

Volume, V = 2 L

Time, t = 20 s

We need to find the mass flow rate from the faucet. We know that the density of an object is given by :

[tex]d=\dfrac{m}{V}\\\\m=d\times V\\\\\dfrac{m}{t}=\dfrac{dV}{t}\\\\\dfrac{m}{t}=\dfrac{1000\times 0.002}{20}\\\\=0.1\ kg/s[/tex]

So, the mass flow rate is equal to 0.1 kg/s.

The steering wheel of a car has a radius of 0.19 m, and the steering wheel of a truck has a radius of 0.25 m. The same force is applied in the same direction to each steering wheel. What is the ratio of the torque produced by this force in the truck to the torque produced in the car

Answers

Answer:

[tex]\frac{T_t}{T_c} = 1.32[/tex]

Explanation:

The torque applied on an object can be calculated by the following formula:

[tex]T = Fr[/tex]

where,

T = Torque

F = Applied Force

r = radius of the wheel

For car wheel:

[tex]T_c = Fr_c\\[/tex]

For truck wheel:

[tex]T_t = Fr_t[/tex]

Dividing both:

[tex]\frac{T_t}{T_c} = \frac{Fr_t}{Fr_c}[/tex]

for the same force applied on both wheels:

[tex]\frac{T_t}{T_c} = \frac{r_t}{r_c} \\[/tex]

where,

rt = radius of the truck steering wheel = 0.25 m

rc = radius of the car steering wheel = 0.19 m

Therefore,

[tex]\frac{T_t}{T_c} = \frac{0.25\ m}{0.19\ m} \\[/tex]

[tex]\frac{T_t}{T_c} = 1.32[/tex]

question is included in the picture!!! PUT REAL ANSWERS OR I WILL REPORT YOU​

Answers

Answer:

Explanation:

this is like rubbing a balloon on your head to make your hair stand up.  Do that to the can.    The balloon is filled , ofc,  and then just rub the balloon on the can.  This will charge the can with static electricity.   :P

A 1.8 kg book has been dropped from the top of the football stadium. Its speed is 4.8 m/s when it is 2.9 m above the ground. How high is the stadium?

Answers

Answer:

the height of the stadium is 4 m

Explanation:

The computation of the height of the stadium is shown below:

but before that total mechanic energy should be determined

E = PE + KE

where

PE = mgh

and, KE = 1 ÷2 mv^2

Now

E = mgh + 1 ÷2 mv^2

= (1.8) (9.8) (2.9) + 1 ÷ 2 (1.8) (4.8)^2

= 71.9J

= 72J

Now the height of the stadium is

TE = mgh

72 = (1.8) × (9.8) × h

So, h = 4 m

Hence, the height of the stadium is 4 m

I WILL REPORT YOU IF YOU DON'T ANSWER QUESTION OR POST OTHER LINKS
Rank these objects in order of their resistance to change in motion (from greatest to least).
A. pyramid, cone, sphere, cube
B. cube, pyramid, cone, sphere
C. sphere, cone, pyramid, cube
D. None of the above

Answers

Answer:

pyramid, cone, sphere, cube

What happens when a neutral atom gains an electrons?

Answers

it will become a ion , if it gains a negative electron it becomes a negative ion

Answer:

The neutral atom becomes an anion.

Explanation:

When a neutral atom gains an electron (e−), the number of protons (p+) in the nucleus remains the same, resulting in the atom becoming an anion (an ion with a net negative charge).

Object A is moving due east, while object B is moving due north. They collide and stick together in a completely inelastic collision. Momentum is conserved. Object A has a mass of mA = 16.7 kg and an initial velocity of = 7.26 m/s, due east. Object B, however, has a mass of mB = 29.3 kg and an initial velocity of = 4.39 m/s, due north. Find the (a) magnitude and (b) direction of the total momentum of the two-object system after the collision.

Answers

Answer:

a)  v = 3,843 m / s, b)  46.7º  North- East

Explanation:

Moment is a vector quantity, so one of the best ways to solve this problem is to solve each component separately.

The system is formed by the two vehicles so that the moment is preserved during the crash

Direction to the East    

initial instant. Before the crash

          p₀ = mₐ vₐ₀

final insttne. After the crash

          p_f = (mₐ + m_b) vₓ

         p₀ = p_f

         mₐ vₐ₀ = (mₐ + m_b) vₓ

         vₓ = [tex]\frac{m_a}{m_a + m_b} \ v_{ao}[/tex]

let's calculate

          vₓ = [tex]\frac{16.7}{16.7 + 29.3} \ 7.26[/tex]

          vₓ = 2,636 m / s

direction north

initial   p₀ = m_b v_{bo}

final     p_f = (mₐ + m_b) v_y

          p₀ = p_f

          m_b v_{bo} = (mₐ + m_b) v_y

          v_y = [tex]\frac{m_b}{m_a+m_b} \ v_{bo}[/tex]

let's calculate

          v_y = [tex]\frac{29.3}{16.7 + 29.3} \ 4.39[/tex]

          v_y = 2.796 m / s

the final speed of the two two vehicles is

          v = (2,636 i ^ + 2,796 j ^) m / s

a) the magnitude of the velocity

let's use the Pythagorean theorem

       v = [tex]\sqrt{v_x^2 + v_y^2}[/tex]

      v = [tex]\sqrt{2.636^2 + 2.796^2}[/tex]

      v = 3,843 m / s

b) let's use trigonometry to find the direction

      tan θ = v_y / vₓ

      θ = tan⁻¹ v_y / vₓ

      θ = tan⁻¹ (2,796 / 2,636)

      θ = 46.7º

This direction is 46.7º  North East

The rollercoaster is near the
bottom of the hill after the first big
drop. Which best describes the
potential and kinetic energy?
A. It has mostly kinetic energy.
B. It has mostly potential energy.
C. The kinetic energy is decreasing.
D. The potential energy is about 50%
and increasing.

Answers

Answer:

A. It has mostly kinetic energy

Explanation:

Kinetic energy refers to movement. Potential energy refers to height. In this case, the big drop just got over. So, when the coaster is at the bottom, it has more kinetic than potential energy . Potential energy is still present but kinetic is more at the bottom.

Which of the following is an example of heat transfer by conduction?
A. Heat is transferred to the air above a candle flame.
B. Heat is transferred to the soil on a sunny day.
c. Heat is transferred to your hand from a warm cup.
D. Heat is transferred to the air from a warm lightbulb.

Answers

Answer:

option c

Heat is transferred to your hand from a warm cup

conduction is the process of transferring of heat from one material to another when they are in contact

hope it helps

It’s option c.
Conducting need contact

What is the index of refraction of a refractive medium if the angle of incidence in air is 40 degrees and the angle of refraction is 29 degrees?

Answers

N= 1.33
Explanation: (1) sin 40 degrees = n(sin 20 degrees)

The index of refraction is 1.33.

To find the answer, we need to know about index of refraction.

What is index of refraction?

The indication of the light bending ability of a medium is the refractive index of that medium.It determines how much the path of light is bent or refracted.It's a dimensionless number.

What is the mathematical expression of refractive index?

Mathematically, the refractive index(n) is

n= sin∅₁ / sin∅₂

where, ∅₁= angle of incident

             ∅₂= angle of refraction

What is the refractive index,  if the angle of incidence in air is 40 degrees and the angle of refraction is 29 degrees?

n= sin(40) /sin(24) = 1.33

Thus, we can conclude that the index of refraction is 1.33.

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Fluid mechanics questions and answers​

Answers

Answer:

Fluid mechanics is considered one of the toughest subdisciplines within mechanical and aerospace engineering. It is unique from almost any other field an undergraduate engineer will encounter. It requires viewing physics in a new light, and that's not always an easy jump to make.

an object is acted by force of 22 newtons to the right and a force of 13 newtons to left ​

Answers

Answer:

Explanation:

I'm going to guess that you want the net force.

These two forces are acting in opposite directions. Therefore the forces are subtracted in effect.

F = F1 - F2

F1 = 22N to the right

F2 = 13N to the left

F = 22 - 13 = 9 N to the right.

Specifying the direction is very important. Forces do have directions and you must specify what that is. Otherwise, the question should be marked incorrect.

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