a rectanguluar parking lot has a length that is 5 yards greater than the width the area of the parking lot is 300 square yards find the length and the width use formula area =length * width the -parking lot width is of yards is? the length is?

Answer:

Let

Breadth =x

length=x+5

As we know that in a rectangle

[tex]{\boxed{\sf Area=lb}}[/tex]

[tex]{:}\longrightarrow[/tex][tex]\sf x (x+5)=300[/tex]

[tex]{:}\longrightarrow[/tex][tex]\sf x^2+5x=300 [/tex]

[tex]{:}\longrightarrow[/tex][tex]\sf x^2+5x-300=0 [/tex]

[tex]{:}\longrightarrow[/tex][tex]\sf x^2+20x-15x-300=0 [/tex]

[tex]{:}\longrightarrow[/tex][tex]\sf x (x+20)-15 (x+20)=0 [/tex]

[tex]{:}\longrightarrow[/tex][tex]\sf (x+20)(x-15)=0 [/tex]

[tex]{:}\longrightarrow[/tex][tex]\sf x+20=0\:or\:x-15=0 [/tex]

[tex]{:}\longrightarrow[/tex][tex]\sf x=-20 (Impossible)\:or \;x=15 [/tex]

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If the distance from 0 to x on a number line is greater than 0, then -2 + X is positive.:

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