A rocket is launched from the ground at an initial velocity of 39.2 meters per second. Which equation can be used to model the height of the rocket after t seconds?

s(t) = –4.9t2 + 39.2
s(t) = –4.9t2 + 39.2t
s(t) = –4.9t2 + 39.2t + 39.2
s(t) = –4.9t2 + 39.2t – 39.2

Answer:

16

Step-by-step explanation:

12 divided by 3 = 4 and 6*2 = 12

12+4=16

The value of this answer is 16

To solve this expression, we will apply the properties of mathematical operations.

- First, we multiply or divide

- Second, we subtract or add

12/3 + 6 x 2

4 + 6 x 2

4 + 12

16

So, the correct value is 16

The amount that he needs to contribute to his employer's 401(k) in order to fall in a tax bracket will be $9750.

From the information given, Steve is a single man whose salary is $92,000 per year. Based on the tax table below, the amount that he needs to contribute to his employer's 401(k) in order to

fall in a tax bracket will be:

= $92000 - $82250

= $9750

Therefore, the amount is $9750

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The meaning of (e−l)(4) in this situation is that there are 92 people in the amusement park 4 hours after the gates open.

e(x) =  0.03x³ + 2

l (x) =  0.5x + 1

Therefore, ( e - l) =   [ .03x^3 + 2 ]  -  [ .5x + 1 ] will be:

=  0.03x³  - 0.5x + 1

Therefore, (e - l ) (4)  =  0.03(4)³  - 0.5(4) +  1  = 92  

Therefore, it means that  4 hours after the park opens, the rate that the number of people is changing is 92 people per hour

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Answer:

third grid

Step-by-step explanation:

.3×3=.9, as that is just .3 + .3 + .3

The third grid has 9/10 boxes colored, which is the same as .9

Hope this helps! :)

Replace z with the number inside the parenthesis:

f(z) = 3z-8

a. 3(-4) - 8 = -12-8 = -20

b. 3(1/2)-8 = 1 1/2 - 8 = -6 1/2

c. 3(z-7) - 8 = 3z-21-8 = 3z-29

AB= 24cm

BC = 7cm

<B = 90°

AC = ?

AC^2 = AB^2 + BC ^ 2

AC^2 = 24^2 + 7^2

AC^2 = 576 + 49

AC^2 = √625

AC = 25

sin A = 3/4

CosA = ?

TanA = ?

(Construct a triangle right angled at B with one side BC of 3cm and hypotenuse AC of 4cm.)

AC^2 = AB^2 + BC ^ 2

4² = AB² + 3²

16 = AB + 9

AB = √7cm

= AB/AC

= √7/4

=BC/AB

= 3/√7

let x = horses

5x = cows

x + 5x = 132

6x = 132

Divide both sides by 6

X = 22

he has 22 horses and 110 cows

There are 22 horses and 110 cows.

"It is a mathematical statement which consists of equal symbol between two mathematical expressions."

For given question,

Let 'c' represents the number of cows and 'h' represents the number of horses.

A rancher raises 5 times as many cows as horses.

So, we get an equation,

⇒ c = 5 × h                        .................(i)

There are 132 animals.

So, we get an equation,

⇒ c + h = 132                    ..................(ii)

Substitute the value of c = 5h in equation (ii)

⇒ c + h = 132

⇒ 5h + h = 132

⇒ 6h = 132

⇒ h = 22

This means, there are 22 horses.

Substitute the vale of h in equation (i),

⇒ c = 5 × h  

⇒ c = 5 × 22

⇒ c = 110

This means, there are 110 cows.

Therefore, there are 22 horses and 110 cows.

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Answer: B

Step-by-step explanation:

The domain is the set of x values, and the range is the set of y values.

Answer:

a=2

Step-by-step explanation:

-13 + 5a = 3a -9 Distribute 3 through the parentheses

-13 + 5a - 3a = -9 Move the variable to the left hand side and change the sign

2a= -9 + 13 collect like terms

2a=4 Divide both sides by 2

a=2

Answer:

(a)12

(b)28

(c)1

Step-by-step explanation:

the dots on the plot for a and b and for c It's almost exactly a whole hour decrease of HW a student is likely to do for every extra hour a student watches TV

Answer:

es esta 1/5 y 6/8 o 15 y 68?

The computation of the index shows that the value of 9 × 10² will be 900.

From the information given, we are told to calculate the value of 9 × 10². This will be calculated thus:

= 9 × 10²

Note that 10² simply means that you've to multiply 10 twice. This will be:

= 10 × 10 = 100

Therefore, 9 × 10² will be:

= 9 × 100

= 900

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Answer:

A

Step-by-step explanation:

[tex](g\circ f)(x)\\\\=g(f(x))\\\\=g(x-4)\\\\=e^{x-4}[/tex]

Answer:

10x^2+2x+13

Step-by-step explanation:

10x^2+3 - (-2x-10)

10x^2+3 +2x+10

10x^2+2x+13

Answer:

[tex]x=\dfrac{42}{13}[/tex]

Step-by-step explanation:

Given equation:

[tex]\dfrac{6}{(x^2-3x)}=\dfrac{12}{x}+\dfrac{1}{(x-3)}[/tex]

Factor the denominator on the left side:

[tex]\implies \dfrac{6}{x(x-3)}=\dfrac{12}{x}+\dfrac{1}{(x-3)}[/tex]

Combine the fractions on the right side by multiplying by the LCM:

[tex]\begin{aligned}\implies \dfrac{6}{x(x-3)} & =\dfrac{12}{x} \cdot \dfrac{(x-3)}{(x-3)}+\dfrac{1}{(x-3)} \cdot \dfrac{x}{x}\\\\& =\dfrac{12(x-3)}{x(x-3)}+\dfrac{x}{x(x-3)}\\\\& =\dfrac{12(x-3)+x}{x(x-3)} \end{aligned}[/tex]

As the denominators are now the same on both sides:

[tex]\begin{aligned}\implies \dfrac{6}{x(x-3)} & =\dfrac{12(x-3)+x}{x(x-3)}\\\\ \implies 6 & = 12(x-3)+x\end{aligned}[/tex]

Simplify and solve for x:

[tex]\begin{aligned}\implies 6 & = 12(x-3)+x\\\\6 & =12x-36+x\\\\6 & =13x-36\\\\13x & =42\\\\\implies x & =\dfrac{42}{13}\end{aligned}[/tex]

Answer:

Constant term of an algebraic expression: A term of an algebraic expression which has a fixed numerical value in all situations and does not have any variable is called the constant term of an algebraic expression.

For examples, in the algebraic expression 5x + 2y + xy + 10, 10 is the constant term of the expression. therefore from the above algebraic expression 2x²+x-1, -1 will be the constant term

Answer:

that is cuban that answer is easy (200)=1902

Answer:

The bottom one ....see below

Step-by-step explanation:

Using reference angle of pi/8   and half angle trig identity:

cos ( angle/2) = -sqrt  (1 + cos (angle) /2)

cos ( pi/4  / 2) = - sqrt (1+ cos ( pi/4)/2)

  cos (pi/8)      = -    sqrt (1 + sqrt (2) / 2)

                 = - sqrt (1 + sqrt 2) / sqrt 2     rationalize the denominator

                    = - sqrt ( sqrt 2 + 2) / 2

re arrange to

          - sqrt ( 2 + sqrt2)  / 2        the fourth answer  

The attached graph represents the graph of the equation y1 = 17,105 + 1.31x

The equation is given as:

y1 = 17,105 + 1.31x

To plot and graph the equation, we set some values for x and calculate the corresponding y values.

Let x = 0, 1, 2 and 3.

So, we have:

y1 = 17,105 + 1.31 * 0 = 17105

y1 = 17,105 + 1.31 * 1 = 17106.31

y1 = 17,105 + 1.31 * 2 = 17107.62

y1 = 17,105 + 1.31 * 3 = 17108.93

The graph can then be plotted using the above points

See attachment

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Answer:

x = 23.0

Step-by-step explanation:

To solve, you have to make the equation:

[tex]cos(64)=\frac{9}{x}[/tex]

Now multiply x to both sides:

[tex]cos(64)*x=9[/tex]

Next divide both sides by cos(64):

[tex]x=\frac{9}{cos(64)}[/tex]

x = 22.9675486404

Round to the tenth:

x = 23.0

Hope it helps and have a nice day!

Answer: Both plans cost the same when 50 texts are sent.

Step-by-step explanation:

When x=50 (meaning 50 texts are sent), the y coordinate (which represents the cost) is the same.

Answer: -0.8

Step-by-step explanation:

3.2 - 4  = -0.8

Answer:

If it is a hamburger, it can be held in your hands.

Step-by-step explanation:

Answer:

It's all real numbers except whatever makes the expression undefined

Step-by-step explanation:

(−∞,∞)

Answer:

All real numbers

Step-by-step explanation: (−∞,∞)

Step-by-step explanation:

Given the following question:

[tex](x-2)^2+(y-2)^2=9[/tex]

First thing we need to keep in mind is the fact that this graph is indeed a circle. We know this because we are adding two cubic roots to each other which makes the graph a circle. We know the two separate functions are cubic roots because they each have an exponent of two. Not only is this function whose graph is a circle, but the midpoint of this circle is (2,2).

Hope this helps.

Answer:

45.98

Step-by-step explanation:

there ya go I did this before so I know the correct answer

The value of WACC is 6.72%

WACC is calculated by multiplying the cost of each capital source (debt and equity) by its relevant weight by market value, and then adding the products together to determine the total.

WACC=[(Market value of Equity*cost of equity+ Market value of Debt* post tax cost of debt)/(Market value of Equity+ Market value of Debt)]

Market value of Equity= 40,000*$85=$3,400,000

Cost of equity=Risk free return+ Beta equity*market retrun

=4 +0.67*15

=7.35

Market value of Debt

=2000*1105.38

=2,210,760

Post tax rate of debt

=9*80(1-20)

=0.0576= 5.76%

WACC= [$3,400,000* 7.35+ 2,210,760 *  5.76%]\ $3,400,000+2,210,760

=6.72%

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