If the rod is in rotational equilibrium, then the net torques acting on it is zero:
∑ τ = 0
Let's give the system a counterclockwise orientation, so that forces that would cause the rod to rotate counterclockwise act in the positive direction. Compute the magnitudes of each torque:
• at the left end,
τ = + (50 N) (2.0 m) = 100 N•m
• at the right end,
τ = - (200 N) (5.0 m) = - 1000 N•m
• at a point a distance d to the right of the pivot point,
τ = + (300 N) d
Then
∑ τ = 100 N•m - 1000 N•m + (300 N) d = 0
⇒ (300 N) d = 1100 N•m
⇒ d ≈ 3.7 m
O True
False
Question 15
2 pts
Kiana rides her skateboard with a constant speed of 6 km/h. How long will she take to travel a distance
of 10 kilometers? Please SHOW YOUR WORK
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An object weighing 120 n is set on a rigid beam of negligible mass at a distance of 3 m from a pivot, as shown above. A vertical force is to be applied to the other end of the beam a distance of 4 m from the pivot to keep the beam at rest and horizontal. What is the magnitude f of the force required?.
The force required to keep the beam in equilibrium is 90 N.
Principle of moments of forcesIt states that for a system at equilibrium, the sum of the clock-wise moment is equal to the sum of anti clock wise moment.
To calculate the magnitude of the force required to keep the beam at equilibrium, we use the Formula below.
Formula:
Fd = fD............... Equation 1Where
F = Force/ weight of the objectd = Distance of the object from the pivotf = Vertical force applied on the other endD = Distance of the vertical force from the pivot.Make f the subject of the equation
f = Fd/D............... Equation 2From the question,
Given:
F = 120 Nd = 3 mD = 4 mSubstitute the given values into equation 2
f = (120×3)/4f = 90 NHence, The force required to keep the beam in equilibrium is 90 N.
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Ata football match between two college teams, the referee ordered a free kick. The ball of mass 1.5 kg was placed at rest. The kick was about to be taken by an eager footballer.
What was the potential energy of the ball just before the kick was taken?
The potential energy of the ball just before the kick was taken is zero (0).
What is Potential energy?Potential energy is the energy possessed by an object due to its position above the ground.
Potential energy of the ball
The Potential energy of the ball is calculated as follows;
P.E = mgh
where;
m is the mass = 1.5 kgh is height of the ball above the ground = 0P.E = 1.5 x 9.8 x 0
P.E = 0
Thus, the potential energy of the ball just before the kick was taken is zero (0).
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After the softball leaves your hand, it rises, slowing down.
Answer:
yes it do rises and then fall down due to gravitational
what are the things to consider in planning food for the family?
Answer:
tips to get you started
Make a menu. ...
Plan your meals around foods that are on sale. ...
Plan at least one meatless meal a week. ...
Check your pantry, refrigerator and freezer. ...
Enjoy grains more often. ...
Avoid recipes that need a special ingredient. ...
Look for seasonal recipes. ...
Plan to use leftovers.
Explanation:
sana po makatulong
Consider a gas at STP in a container of 22. 4 L. What is the approximate value of n according to the ideal gas law? 0. 5 1 2008. 31 224.
STP is defined as the standard temperature and pressure. These are some standard values given in 1982. the approximate value of n according to the ideal gas law will be 0.986.
What is the ideal gas equation?The ideal gas equation is derived from the Boyle and Charles law states that the product of pressure and volume is directly propotional to the temperature at STP.
It is mathematically given as
[tex]\rm pv=nRT[/tex]
P is the pressure =100kPa at STP.
R is universal gas constant=8.314 j/kgk
v is the volume=22.4 L=22.4×10³ m³
T is the temperature =273.15 K at STP
[tex]\rm pv=nRT\\\\\rm n=\frac{RT}{pv} \\\\\ \rm n=\frac{8.314\times273.15}{100\times10^3\times10^{-3}} \\\\\rm n=0.986[/tex]
Hence the approximate value of n according to the ideal gas law will be 0.986.
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Answer:
1
Explanation:
1 mol = 22.4 L
Four people return home from work and walk up the stairs to their own apartments
in the same building. Which person has gained the most gravitational potential
energy upon arriving at the door of their apartment?
A 50kg person who lives on the second floor
A 50kg person who lives on the third floor
A 100kg person who lives on the second floor
A 100kg person who lives on the third floor
Answer:
A 100 kg person who lives on the third floor
Explanation:
its ^ the answer above
A circular disk of moment of inertia [tex]I_t[/tex] is rotating in a horizontal plane, about its axis , with a constant angular speed [tex]\omega_i[/tex] . Another disc of moment of inertia [tex]I_b[/tex] is dropped coaxially onto the rotating disk. Initially the 2nd disc has 0 angular speed. Eventually both the disks rotate with a constant angular speed [tex]\omega_f[/tex] . The energy lost initially rotating disk to friction is ?
The kinetic energy of the circular disc in initial state is,
[tex]K^{1r} = \frac{1}{2}I^{t}ω^{ \frac{2}{i} } [/tex]
The initial kinetic energy of the other disc dropped on the first disc is,
[tex]K^{2r} = \frac{1}{2}I^{b}(0)^{2}[/tex]
[tex] = > K^{2r} = 0J[/tex]
As both the disc in the final state are moving with the same angular velocity, thus, the net kinetic energy in the final state is,
[tex]E^{f} = \frac{1}{2}(I^{t} + I^{b})ω^{ \frac{2}{f} }[/tex]
The net kinetic energy in the initial state is,
[tex]E^{i} = K^{1r} + K^{2r}[/tex]
[tex] = > E^{i} = \frac{1}{2} I^{t}ω^{ \frac{2}{i} } + 0[/tex]
[tex] = > E^{i} = \frac{1}{2} I^{t}ω^{ \frac{2}{i} }[/tex]
Thus, the change in the kinetic energy during the change of state is,
[tex]dE = E^{f} - E^{i}[/tex]
[tex] = > dE = \frac{1}{2} (I^{t} + I^{b})ω^{ \frac{2}{f} } - \frac{1}{2}I^{t}ω^{ \frac{2}{i} } [/tex]
[tex] = > dE = \frac{1}{2} I^{t}(ω^{ \frac{2}{f} } - ω^{ \frac{2}{i} }) + \frac{1}{2}I^{b}ω^{ \frac{2}{f} } [/tex]
This change in value of energy is the energy lost initially rotating the disk to friction.
Hence, the energy lost in the given case is [tex]dE = \frac{1}{2} I^{t}(ω^{ \frac{2}{f} } - ω^{ \frac{2}{i} }) + \frac{1}{2}I^{b}ω^{ \frac{2}{f} } [/tex]
The energy lost initially by the rotating disk to friction is equal to [tex]\frac{1}{2}I_t (\omega_f^2 - \omega_i^2)+\frac{1}{2} I_b\omega_f^2[/tex]
Given the following data:
Angular speed = 0How to calculate the energy lost.At the initial state, the kinetic energy of the circular disc is given by this formula:
[tex]K.E = \frac{1}{2} I_t\omega_i^2[/tex]
For the second disc, the initial kinetic energy is given by this formula:
[tex]K.E_2 = \frac{1}{2} I_b\omega_f^{2 }\\\\K.E_2 = \frac{1}{2} I_b(0)^{2 }\\\\K.E_2 = 0[/tex]
At the final state, the discs would move with the same angular velocity and the net kinetic energy is given by this formula:
[tex]E_f = \frac{1}{2} (I_t + I_b)\omega_f^2[/tex]
For the energy lost:
Also, the change in the kinetic energy is given by this formula:
[tex]\Delta E = E^f - E^i\\\\\Delta E = \frac{1}{2} (I_t + I_b)\omega_f^2 - \frac{1}{2} I_t\omega_i^2\\\\\Delta E = \frac{1}{2}I_t (\omega_f^2 - \omega_i^2)+\frac{1}{2} I_b\omega_f^2[/tex]
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Determinati rezistenta unui conductor electric daca prin el circula un curent de 0,3 a, iar tensiunea masurata la capetele lui este 0.05 v
WHAT? I DON'T UNDERSTAND WHAT ARE YOU SAYING
How does the behaviour of s-waves and p-waves indicate the properties of the earth?.
Answer:
S waves are transverse and cannot travel through liquids. P waves are longitudinal and can travel through liquids. When an earthquake happens on one side of the Earth, P and S waves can be detected all around the world. S waves cannot be detected on the opposite side of the earth but can be detected at angles less than or equal to 90 degrees or slightly more. This is because there is a liquid core in the centre of the earth preventing the S waves from travelling to the direct opposite side of the Earth. P waves can be detected all around the world
Explanation:
Jill runs for 20 seconds at 10 m/s, how far did she travel?
Answer:
200 (m) for 20 seconds
10 times 20 is 200
Answer:
200
Explanation:
Jill is running at 10 meters per second
20 * 10 = 200
BRAINLIEST OF CORRECT
Match the atom to the number of electrons it is likely to gain/lose,
Answer:
Na: lose 1
O: gain 2
Al: lose 3
Be: lose 2
N: gain 3
Cl: depends on the limit of your study im grade nine and the energy level M can hold only eight electrons so i would have answered (gain 1)
Explanation:
The atoms according to the number of electrons it will lose or gain is matched as follows;
Sodium → lose 1
Nitrogen → gain 3
Sulphur → gain 2
Fluorine → gain 1
Boron → lose 3
Beryllium → lose 2
Atoms
Atoms are the building block of matter. The outermost electron of an atom determines the number of electron an atom loose during bonding. Therefore,
Na(sodium) with an outermost electron of one will lose 1 electron to attain the octet rule.Nitrogen with an outermost electron of 5 will easily gain 3 electrons to attain the octet ruleSulphur(S) with an outermost electron of 6 will easily gain 2 electrons to attain the octet ruleFluorine with an outermost electron of 7 will easily gain 1 electrons to attain the octet rule Boron with an outermost electron of 3 will easily loose 3 electrons to attain the octet ruleBeryllium with an outermost electron of 2 will easily loose 2 electrons to attain the octet rulelearn more on electrons here:https://brainly.com/question/5141076
What is the period of a pendulum that is 1.3 m long?
Answer:
T≈2.2876585681s
Explanation:
Since you were not given the degrees of amplitude or radians of amplitude, we assume that the degrees of amplitude are less than 20∘ or 20∘ and we also assume that this is a simple pendulum
The frequency, or number of waves that pass a given point per second, of
sound is measured in:
A. hertz
B. meters
C. cycles
D. frequencies
Answer:
Hertz is the answer for this question
A neutral atom of Fluorine has seven valence electrons. How many valence electrons are present in the ion F-1?
Answer:
8 valence electrons
Explanation:
Fluoride is F^-, so it has one additional electron, which is expected to be in a valence level (completing a closed-shell inert-gas structure). Thus fluoride should be 1s^2,2s^2,2p^6 , and have 8 valence electrons.
3. What appears to be creating the magnetic field being represented here? How can moving the compass around confirm that? Why do you suppose the magnetic field surrounding the compass is not being represented by the simulation in this instance?
Movement occurs on the compass when there is magnetic field in the surrounding environment.
The movement of the needle appears which represents the presence of magnetic field. The moving compass around confirm that there magnetic field present in that region because the magnetic field is detected by the compass.
What is magnetic field?A magnetic field is invisible force which can be detected by a compass. A compass contains a small bar magnet which can rotate when it experience magnetic field around it so we can conclude that movement occurs on the compass when there is magnetic field in the surrounding environment.
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A chair is pushed backward with a force of 100 N. The gravitational force of Earth on the
chair is 120 N downward, and the floor exerts a force of 120 N upward on the chair.
Draw a free-body diagram showing the forces acting on the chair.
Explanation:
he fell down with telling any one,
What is the mass of an object traveling at 30. m/s if it has 33,750 J of energy?
Answer:
[tex]30 \div 33750 = 0.008888[/tex]
A charge is divided q1 and (q-q1)what will be the ratio of q/q1 so that force between the two parts placed at a given distance is maximum?
Answer:
[tex]q / q_{1} = 2[/tex], assuming that [tex]q_{1}[/tex] and [tex](q - q_{1})[/tex] are point charges.
Explanation:
Let [tex]k[/tex] denote the coulomb constant. Let [tex]r[/tex] denote the distance between the two point charges. In this question, neither [tex]k[/tex] and [tex]r[/tex] depend on the value of [tex]q_{1}[/tex].
By Coulomb's Law, the magnitude of electrostatic force between [tex]q_{1}[/tex] and [tex](q - q_{1})[/tex] would be:
[tex]\begin{aligned}F &= \frac{k\, q_{1}\, (q - q_{1})}{r^{2}} \\ &= \frac{k}{r^{2}}\, (q\, q_{1} - {q_{1}}^{2})\end{aligned}[/tex].
Find the first and second derivative of [tex]F[/tex] with respect to [tex]q_{1}[/tex]. (Note that [tex]0 < q_{1} < q[/tex].)
First derivative:
[tex]\begin{aligned}\frac{d}{d q_{1}}[F] &= \frac{d}{d q_{1}} \left[\frac{k}{r^{2}}\, (q\, q_{1} - {q_{1}}^{2})\right] \\ &= \frac{k}{r^{2}}\, \left[\frac{d}{d q_{1}} [q\, q_{1}] - \frac{d}{d q_{1}}[{q_{1}}^{2}]\right]\\ &= \frac{k}{r^{2}}\, (q - 2\, q_{1})\end{aligned}[/tex].
Second derivative:
[tex]\begin{aligned}\frac{d^{2}}{{d q_{1}}^{2}}[F] &= \frac{d}{d q_{1}} \left[\frac{k}{r^{2}}\, (q - 2\, q_{1})\right] \\ &= \frac{(-2)\, k}{r^{2}}\end{aligned}[/tex].
The value of the coulomb constant [tex]k[/tex] is greater than [tex]0[/tex]. Thus, the value of the second derivative of [tex]F[/tex] with respect to [tex]q_{1}[/tex] would be negative for all real [tex]r[/tex]. [tex]F\![/tex] would be convex over all [tex]q_{1}[/tex].
By the convexity of [tex]\! F[/tex] with respect to [tex]\! q_{1} \![/tex], there would be a unique [tex]q_{1}[/tex] that globally maximizes [tex]F[/tex]. The first derivative of [tex]F\![/tex] with respect to [tex]q_{1}\![/tex] should be [tex]0[/tex] for that particular [tex]\! q_{1}[/tex]. In other words:
[tex]\displaystyle \frac{k}{r^{2}}\, (q - 2\, q_{1}) = 0[/tex].
[tex]2\, q_{1} = q[/tex].
[tex]q_{1} = q / 2[/tex].
In other words, the force between the two point charges would be maximized when the charge is evenly split:
[tex]\begin{aligned} \frac{q}{q_{1}} &= \frac{q}{q / 2} = 2\end{aligned}[/tex].
A ball is dropped from the top of a building. When does the ball have the LEAST kinetic energy?
A: After it has hit the ground
B: Just before it hits the ground
C: Halfway through the fall
D: Just after it is released
Answer:
The answer is probably A
What is the momentum of a 3-kg object moving at 5 m/s?
Answer: 15 kg*m/s
Explanation:
Momentum = mass*velocity
Momentum = 3kg*5 m/s
Momentum = 15 kg*m/s
Answer:
15 kg m/s
Explanation:
Momentum = mass xvelocity
Momentum = 3kgx 5 m/s
Momentum = 15 kg m/s
A car accelerates from to at a constant rate of How far does it travel while accelerating?.
Distance is the measure of the length of ground covered by an object during its motion. Distance is a scalar quantity. The car will travel 69 m while accelerating.
What is the distance?
Distance is the measure of the length of ground covered by an object during its motion. While the displacement is defined as the shortest distance between the two paths.
Distance is a scalar quantity. While displacement is a vector quantity. Mathematically it is given as the product of speed and time.
The following data are given in the problem as
u is the initial speed=5.0 m/sec
v is the final speed=21 m/sec
s is the distance covered by the car =?
a= Acceleration of car =3.0 m/sec²
According to Newton's third equation of motion, the formula derived will be
[tex]\rm{v^2=u^2+2as \\\\[/tex]
[tex]\rm s = \frac{v^2-u^2}{2a} \\\\\rm s = \frac{(21)^2-(5)^2}{2\times3.0} \\\\ \rm s=69 m[/tex]
Hence the car will travel 69 m while accelerating.
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A person invests money, or ___, in a business.
Explanation:
A person invests money, or resources in a business .
How much power does it take to do 400 joules of work in 5 seconds?
Answer:
Explanation:
Power = work / time
P = 400 J / 5 s
P = 80 watts
The area of a room that is 10 feet wide and 12 feet long is
13.3 square feet
14 square yards
120 square feet
12 squa2 yards
Describe the magnetic field lines between like poles.(what is the direction indicated and why
Answer/Explanation:
The magnetic fields line are closer apart at other places. Hence, magnetic field is strongest at the poles. Magnetic Field has Direction The Magnetic Field lines are like closed curves They emerge from North Pole and Merge to South Pole.
Brainliest?!
Check out the Image below!
A lightening rod saves us from lightening give reason
Can you tell me by looking this book
Please fast
Answer:
Because Rod protect house from burning down and people from electrocution.
What is Socio historical context
Answer:
It is the combination of social and historical factors.
When a car of mass 1167 kg accelerates from 10.0 m/s to some final speed, 4.00 10 5J of work are done. Find this final speed.
Apply Newton's second law
[tex]\\ \tt\hookrightarrow F=ma[/tex]
[tex]\\ \tt\hookrightarrow F=1167(4)=4668N[/tex]
Now
[tex]\\ \tt\hookrightarrow W=Fd[/tex]
[tex]\\ \tt\hookrightarrow d=\dfrac{W}{F}[/tex]
[tex]\\ \tt\hookrightarrow d=\dfrac{105}{4668}[/tex]
[tex]\\ \tt\hookrightarrow d=0.022m[/tex]
Now
d be sAccording to third equation of kinematics
[tex]\\ \tt\hookrightarrow v^2=u^2+2as[/tex]
[tex]\\ \tt\hookrightarrow v^2=10^2+2(4)(0.022)[/tex]
[tex]\\ \tt\hookrightarrow v^2=100+8(0.022)[/tex]
[tex]\\ \tt\hookrightarrow v^2=100+0.176[/tex]
[tex]\\ \tt\hookrightarrow v^2=100.176[/tex]
[tex]\\ \tt\hookrightarrow v=10.001m/s[/tex]
Why is soccer a great athletic sport
Answer:
that is the answer
Explanation:
look at it