A rotating wheel requires 8.00 s to rotate 27.0 revolutions. Its angular velocity at the end of the 8.00-s interval is 99.0 rad/s. What is the constant angular acceleration (in rad/s) of the wheel?

Answer:

First one,

Its because

Downward force must greater to uplift its weight.

From 3rd law of motion

Answer:

The downward force of the rocket exhaust is greater than the upward force on the rocket.

Explanation:

Your Welcome (;

Answer:

A

Explanation:

heat transfer occurs between two objects that are not in thermal equilibrium (do not have the same temperature)(heat flows from hot to cold objects)

temp= measure of how hot/cold something is

internal E= total E of a closed system

The transfer of thermal energy between objects of different temperatures is called Heat.

Heat is the energy transferred from one object to another as a result of a temperature differential. When two bodies of different temperatures come into contact, energy is transferred—that is, heat flows— towards the colder body from the hotter.

As we know that when two bodies are not in thermal equillibrium then the heat starts to flow, from the higher temperature body towards the lower temperature body. Thus, The transfer of thermal energy between objects of different temperatures is called Heat.

Learn more about Heat:

https://brainly.com/question/1429452

It would be

O A) It is a eukaryotic cell.

Answer:

The gravitational potential energy between two particles, if the distance between them is halved, is multiplied by 4 (option c).

Explanation:

The gravitational force is the force of mutual attraction that two objects with mass experience.

The Law of Universal Gravitation enunciated by Newton says that every material particle attracts any other material particle with a force directly proportional to the product of their masses and inversely proportional to the square of the distance that separates them. Mathematically this is expressed as:

[tex]F=G*\frac{m1*m2}{r^{2} }[/tex]

where m1 and m2 are the masses of the objects, r the distance between them and G a universal constant that receives  the name of constant of gravitation.

If the distance between two particles is reduced by half, then, where F' is the new value of the gravitational force:

[tex]F'=G*\frac{m1*m2}{(\frac{r}{2} )^{2} }[/tex]

[tex]F'=G*\frac{m1*m2}{\frac{(r )^{2} }{2^{2} } }[/tex]

[tex]F'=G*\frac{m1*m2}{\frac{(r )^{2} }{4} }[/tex]

[tex]F'=4*G*\frac{m1*m2}{r^{2} }[/tex]

F'=4*F

The gravitational potential energy between two particles, if the distance between them is halved, is multiplied by 4 (option c).

Answer:

B. During condensation, the heavier elements tended to sink nearer the Sun and, being rare, only provided enough material to build the relatively small terrestrial planets.

D. During the collapse of the gaseous nebula, most of the material tended to collect far from the Sun because of the large centrifugal forces, which provided the necessary material to build the large Jovian planets.

Explanation:

The solar nebular hypothesis is the theory of how the earth came to be as proposed and believed by most scientists. It states that the solar system was formed from a nebular which is a large collection of dust. As the condensation of the nebular progressed, the heavier materials which could withstand higher temperatures formed closer to the sun. Because these materials were not so much the planets formed by them were not large in size.

However, the Jovian planets formed beyond the frost line which could sustain icy compounds. The ices that formed these planets were much thus accounting for their larger sizes. Solar winds blew off the lighter hydrogen and helium elements leading to their accumulation far away from the sun.

Answer: The height of its fourth bounce = 0.43m

Explanation:

The coefficient of restitution denoted by (e), is the ratio that shows the  final velocity to initial relative velocity between two objects after collision

IT is given by the formula in terms of height as

Coefficient of Restitution, e  = √(2gh))/√(2gH) = √(h/H)

Where

Coefficient of Restitution, e= 0.821

H = 2.07 m

At fourth bounce ,   we have that

Coefficient of Restitution, e⁴  =√(h₄/H)  

Putting the given values and solving , we have,

e⁴  =√(h₄/H)  

= 0.821⁴ = √(h₄/2.07)

 (0.821⁴ )² =h₄/2.07

0.2064 x 2.07 = 0.427 = 0.43

At  fourth bounce,  h₄ height = 0.43m

Answer:

It is Newton's first law of motion also referred  to as the law of inertia.

Explanation:

Answer:

1) f= 8.6 GHz

2) t= 0.2 ms

Explanation:

1)

        [tex]v = \lambda * f (1)[/tex]

       [tex]f =\frac{c}{\lambda} =\frac{3e8m/s}{0.035m} = 8.57e9 Hz (2)[/tex]

⇒     f = 8.6 Ghz (with two significative figures)

2)

       [tex]v =\frac{d}{t} (3)[/tex]

       where v= c= speed of light in vacuum = 3*10⁸ m/s

       d= distance between mountaintops = 52 km = 52*10³ m

       [tex]t = \frac{d}{c} = \frac{52e3m}{3e8m/s} = 17.3e-5 sec = 0.173e-3 sec = 0.173 ms (4)[/tex]

       ⇒  t = 0.2 ms (with two significative figures)

Answer: 0.6cm

Explanation:

Strain is defined as  how much an object can be stretched or deformed  when force is applied to it .  it measures the  fractional change of the object’s length when the object faces  tensional stress. It is calculated  by using the formulae

Strain =  ΔL/ L

where strain = 6%

L= Original length

ΔL= change in length

 6% = ΔL/ 10 cm

ΔL= 10cm X 0.06

ΔL=0.6cm

Answer:

When elements bond together or when bonds of compounds are broken and form a new substance

Explanation:

Answer:

wave is in the y-direction, the wave is traveling in the

Explanation:

Answer:

wazzam blood

Explanation:

Answer:

16.67m/s

Explanation:

Given parameters:

Distance Pete drove  = 300m

Time taken  = 18s

Unknown:

Speed  = ?

Solution:

Speed is the distance traveled per unit of time.

It is mathematically expressed as;

   Speed  = [tex]\frac{distance}{time}[/tex]

Insert the parameters and solve;

  Speed  = [tex]\frac{300}{18}[/tex]  = 16.67m/s

Answer:

no

Explanation:

This downward force and acceleration results in a downward displacement from the position that the object would be if there were no gravity. The force of gravity does not affect the horizontal component of motion; a projectile maintains a constant horizontal velocity since there are no horizontal forces acting upon it.

Answer:

when u learn something new it goes to ur short term memory

Answer:

velocity = 44.98 m/s

Explanation:

given data

velocity = 45.0 m/s

angle = 30.0 degrees

solution

first we get here time that is

time = 2u × sin θ ÷ g   .............1

time = 2×45 × sin 30 ÷ 9.8

time = 4.59 sec

and

velocity = [tex]\sqrt{vx^2+vy^2}[/tex]   .....................2

here

vx = 45 cos30 = 38.97 m/s

vy = uy - gt

vy = 45 sin30 - 9.8 ×  4.59  = -22.48 m/s

so velocity will be

velocity = [tex]\sqrt{38.97^2+22.48^2}[/tex]

velocity = 44.98 m/s

Answer:

i think its 2.5 as well

Explanation:

Answer:

D) 763 nm

Explanation:

Calculation for the wavelength of light

Using this formula

Wavelength of light=Delta Y*Distance / Length

Where,

Delta Y represent the 2nd order bright fringe

Length represent the distance between both the slits and the screen

Distance represent the Distance between the slits

Let note that cm to m = (4.2) x 10^-2 and mm to m= ( 0.0400x 10^-3)

Now Let plug in the formula

Wavelength of light=[(4.2 x 10^-2m)(0.0400 x 10^-3m) / 2(1.1m)]*10^-7 meters

Wavelength of light=[(0.042m) (0.0004m)/2.2m]*10^-7 meters

Wavelength of light =(0.0000168m/2.2m)*10^-7 meters

Wavelength of light =7.63 *10^-7 meters

Wavelength of light =763 nm

Therefore the Wavelength of light will be 763 nm

Answer:

S = 40.8m

Explanation:

Given the following data;

Initial velocity, u = 2m/s

Acceleration, a = 1.6m/s²

Time, t = 6secs

Required to find the displacement

Displacement, S = ?

The displacement of an object is given by the second equation of motion;

[tex] S = ut + \frac {1}{2}at^{2}[/tex]

Where;

Substituting into the equation, we have;

[tex] S = 2*6 + \frac {1}{2}*(1.6)*6^{2}[/tex]

[tex] S = 12 + 0.8*36[/tex]

[tex] S = 12 + 28.8 [/tex]

S = 40.8m

Therefore, the displacement of the skateboarder during this game is 40.8 meters.

Answer:

a = 2m/s^2

Explanation:

Force (F) = 100 N

Mass (m) = 50 kg

Here,

F = m×a

100 = 50 × a

a = 100÷50

a = 2m/s^2

Thus, the acceleration on the cart is a = 2m/s^2

-TheUnknownScientist

Given :

Object A is 71 degrees and object B is 75 degrees .

To Find :

How will thermal energy flow.

Solution :

We know, by law of thermodynamics thermal energy will flow from higher temperature to lower temperature.

So, in the given question energy will flow from object B from object A.

Hence, this is the required solution.

Answer:

A. heat is released from the ocean and land causing wind.

Assuming both forces act horizontally, the net force is in Kathryn's direction with a magnitude of 5 N.

If "towards Kathryn" is taken the be the positive direction, then the net force is

∑ F = 20 N - 15 N = 5 N

Answer:

ac = 204 [m/s²]

Explanation:

To solve this problem we must use the following equation that relates the tangential velocity to the radius of rotation.

ac = v²/r

where:

v = tangential velocity = 15 [m/s]

r = radius = 1.1 [m]

Now replacing we have:

ac = (15)²/1.1

ac = 204 [m/s²]

Answer:240 meters

Explanation:60×4

Answer:

Earth would suddenly warm up because more heat from the Sun would be allowed to enter the atmosphere.

Explanation:

The greenhouse gasses would make the ozone layer thinner letting in more harmful rays on the sun.

Hope this helps!! :)

Also I need one more brainliest if you dont mind giving it to me :)

Answer:

Earth would cool down because it would reflect more solar radiation.     it would be A.

Explanation:

Answer:

A. 5.03 solar mass.

B. the masses of Star A and B are 1.01 solar mass and 4.02 solar mass respectively.

Explanation:

A. The sum of their two masses can be found using Kepler's third law:

[tex]\frac{P^{2}}{a^{3}} = \frac{4\pi^{2}}{G(m_{A} + m_{B})}[/tex]

Where:

P: is the period = 5 y = 1.58x10⁸ s

a: is the separation between the stars = 5 AU = 7.5x10¹¹ m

G: is the gravitational constant = 6.67x10⁻¹¹ m³kg⁻¹s⁻²

[tex]m_{A}[/tex] and [tex]m_{B}[/tex] are the masses of Star A and Star B respectively.    

[tex]m_{A} + m_{B} = \frac{4\pi^{2}a^{3}}{P^{2}G} = \frac{4\pi^{2}(5 AU*\frac{1.5\cdot 10^{11} m}{1 AU})^{3}}{(1.58 \cdot 10^{8} s)^{2}6.67 \cdot 10^{-11} m^{3}*kg^{-1}*s^{-2}} = 1.00 \cdot 10^{31} kg*\frac{1 M_{\bigodot}}{1.989\cdot 10^{30} kg} = 5.03 M_{\bigodot}[/tex]    

Hence, the sum of their two masses is 5.03 solar mass.  

B. Their individual masses can be found using the center of the mass equation:

[tex] a_{B} = (\frac{m_{A}}{m_{A} + m_{B}})a [/tex]

Where:

[tex]a_{B}[/tex] is the distance of Star B from the center of the mass

Since, [tex]a_{A}[/tex] is four times [tex]a_{B}[/tex] and a = 5 AU we have:

[tex] a_{A} = 4a_{B} [/tex]

[tex] a = a_{A} + a_{B} [/tex]

[tex] a_{B} = a - a_{A} = a - 4a_{B} \rightarrow a_{B} = \frac{a}{5} [/tex]      

Then, their individual masses are:

[tex]\frac{a}{5} = (\frac{m_{A}}{5.03 M_{\bigodot}})a[/tex]  

[tex]m_{A} = \frac{5.03 M_{\bigodot}}{5} = 1.01 M_{\bigodot}[/tex]

Now, the mass of Star B is:

[tex]m_{B} = m_{T} - m_{A} = 5.03 M_{\bigodot} - 1.01 M_{\bigodot} = 4.02 M_{\bigodot}[/tex]

Therefore, the masses of Star A and B are [tex]1.01 M_{\bigodot}[/tex] and [tex]4.02 M_{\bigodot}[/tex] respectively.

I hope it helps you!