a.0.05 ≤ P (χ²(17) < (18 - 1)35.05/σ²M < χ²(0.95)(17))0.05 ≤ P (χ²(17) < 577.57/σ²M < χ²(0.95)(17))0.05 ≤ P (χ²(17) < 577.57/σ²M < 28.412)The above inequality represents the 90%
b. 0.05 ≤ P (χ²(7) < (8 - 1)18.40/σ²F < χ²(0.95)(7))0.05 ≤ P (χ²(7) < 122.18/σ²F < χ²(0.95)(7))0.05 ≤ P (χ²(7) < 122.18/σ²F < 14.067)
The above inequality represents the 90% confidence interval estimate for sigma2F.
a. 90% confidence interval estimate for sigma2M:We are given that the sample variance is s²M=35.05 and a sample of 18 male students was asked how much they spent on textbooks. We are also given that the amount spent on textbooks is normally distributed for both the populations of male students.
Using the Chi-Square distribution, we have: (n - 1)s²M/σ²M follows a Chi-Square distribution with n - 1 degrees of freedom.
Then, (n - 1)s²M/σ²M ~ χ²(n - 1)For a 90% confidence interval estimate, we can write: 0.05 ≤ P (χ²(17) < (n - 1)s²M/σ²M < χ²(0.95)(17))
Using the table of chi-square values with (n - 1) degrees of freedom, we have:χ²(0.05)(17) = 8.567χ²(0.95)(17) = 28.412
Substituting the values, we have:0.05 ≤ P (χ²(17) < (18 - 1)35.05/σ²M < χ²(0.95)(17))0.05 ≤ P (χ²(17) < 577.57/σ²M < χ²(0.95)(17))0.05 ≤ P (χ²(17) < 577.57/σ²M < 28.412)The above inequality represents the 90%
b. confidence interval estimate for sigma2M.b. 90% con? dence interval estimate for sigma2F:Using the same concept as above, we can write: 0.05 ≤ P (χ²(7) < (n - 1)s²F/σ²F < χ²(0.95)(7))
Using the table of chi-square values with (n - 1) degrees of freedom, we have:χ²(0.05)(7) = 3.357χ²(0.95)(7) = 14.067
Substituting the values, we have:0.05 ≤ P (χ²(7) < (8 - 1)18.40/σ²F < χ²(0.95)(7))0.05 ≤ P (χ²(7) < 122.18/σ²F < χ²(0.95)(7))0.05 ≤ P (χ²(7) < 122.18/σ²F < 14.067)
The above inequality represents the 90% confidence interval estimate for sigma2F.
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To calculate a 90% confidence interval estimate for σ2M, the population variance of the amount spent on textbooks by male students, we use the formula below:
[tex]$$\chi_{0.05,17}^2 <\frac{(n - 1)s^2}{\sigma^2} < \chi_{0.95,17}^2$$[/tex]
where n = 18, s2M = 35.05, df = n - 1 = 17, and χα2,
df is the critical value from the chi-squared distribution with df degrees of freedom.
We know that:
[tex]$$\chi_{0.05,17}^2 = 8.909$$[/tex]
and
[tex]$$\chi_{0.95,17}^2 = 31.410$$[/tex]
Substituting these values, we have:
[tex]$$8.909 < \frac{(18-1)(35.05)}{\sigma^2} < 31.410$$[/tex]
Solving for σ2, we have:
[tex]$$\frac{(18-1)(35.05)}{31.410} < \sigma^2 < \frac{(18-1)(35.05)}{8.909}$$[/tex]
Hence, a 90% confidence interval estimate for σ2M is:
[tex]$$(48.704, 194.154)$$b.[/tex]
To calculate a 90% confidence interval estimate for σ2F, the population variance of the amount spent on textbooks by female students, we use the formula below:
[tex]$$\chi_{0.05,7}^2 <\frac{(n - 1)s^2}{\sigma^2} < \chi_{0.95,7}^2$$[/tex]
where n = 8, s2F = 18.40, df = n - 1 = 7, and χα2,
df is the critical value from the chi-squared distribution with df degrees of freedom.
We know that:
[tex]$$\chi_{0.05,7}^2 = 14.067$$[/tex] and
[tex]$$\chi_{0.95,7}^2 = 2.998$$[/tex]
Substituting these values, we have:
[tex]$$14.067 < \frac{(8-1)(18.40)}{\sigma^2} < 2.998$$[/tex]
Solving for σ2, we have:
[tex]$$\frac{(8-1)(18.40)}{2.998} < \sigma^2 < \frac{(8-1)(18.40)}{14.067}$$[/tex]
Hence, a 90% confidence interval estimate for σ2F is:
[tex]$$(7.176, 23.622)$$[/tex]
Therefore, the 90% confidence interval estimate for σ2M,
the population variance of the amount spent on textbooks by male students, is (48.704, 194.154), while the 90% confidence interval estimate for σ2F,
the population variance of the amount spent on textbooks by female students, is (7.176, 23.622).
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Find the area under the standard normal distribution curve between z=0 and z=0.25. Use The Standard Normal Distribution Table and enter the answer to 4 decimal places.
The area between the two z values is ______
The area under the standard normal distribution curve between z=0 and z=0.25 is 0.0987.
First cumulative probability = z = 0 and
Second cumulative probability = z = 0.25
The Standard Normal Distribution Table, often known as the Z-table, may be used to determine the area under the standard normal distribution curve between z=0 and z=0.25. The table shows the total likelihood (area) up to a specified z-value. The cumulative probability, which can be found by looking up the z-value of 0 in the table, is 0.5000. The cumulative probability is 0.5987 when we look up the z-value of 0.25.
Calculating the area -
Area = First cumulative probability - Second cumulative probability
= 0.5987 - 0.5000
= 0.0987
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Can someone please help me with this
Answer:
Step-by-step explanation:
5- There are 2 right-angled triangles and 1 equilateral triangle or you can just say triangles
6- area for a triangle is a=bh(1/2)
so 4×3=12(1/2)=6
and 4×3=12(1/2)=6
In both triangles, they're a=6
7- 4×6=24(1/2)=12
the top flag is a=12
8-12+6+6=24
9- the rectangular flag has an area of 24 since a=bh and the added areas of the triangles are 24. I conclude that these are two ways of finding the area of this rectangular flag.
hope this helps : )
PLEASE HELP HARD FOR ME BUT EASY FOR OTHERS
Evaluate the integral by reversing the order of integration 7/2 cosx V1+cosx dc dụ.
The evaluated integral is (7/4) (π - (3√3)/6) (rounded to an appropriate decimal approximation based on the given values of π and √3).
To evaluate the integral ∫∫(7/2 cos(x)) dV, where the region of integration is given by V: 1 ≤ c ≤ 2 and 0 ≤ x ≤ cos⁻¹(2c-1), we can reverse the order of integration.
Step 1: Write the integral with reversed order of integration:
∫∫(7/2 cos(x)) dc dx
Step 2: Determine the limits of integration for the reversed order. The variable c now varies from 1 to 2, and x varies from 0 to cos⁻¹(2c-1). Therefore, the integral becomes:
∫[1,2] ∫[0,cos⁻¹(2c-1)] (7/2 cos(x)) dx dc
Step 3: Integrate with respect to x first. The integral with respect to x is straightforward:
∫[1,2] [sin(x)] [0,cos⁻¹(2c-1)] (7/2) dc
Step 4: Evaluate the inner integral:
∫[1,2] [sin(cos⁻¹(2c-1))] (7/2) dc
Step 5: Simplify the inner integral using the trigonometric identity sin(cos⁻¹(u)) = √(1 - u²):
∫[1,2] [√(1 - (2c-1)²)] (7/2) dc
Step 6: Integrate with respect to c:
(7/2) ∫[1,2] [√(1 - (2c-1)²)] dc
Step 7: Evaluate the integral:
Using the trigonometric substitution u = sin(t), du = cos(t) dt, and the limits change to t: π/6 ≤ t ≤ π/2.
(7/4) ∫[π/6, π/2] [√(1 - sin²(t))] cos(t) dt
Step 8: Simplify the integrand:
(7/4) ∫[π/6, π/2] [cos²(t)] dt
Step 9: Apply the double-angle formula for cosine:
(7/4) ∫[π/6, π/2] [(1 + cos(2t))/2] dt
Step 10: Split the integral into two separate integrals:
(7/4) [∫[π/6, π/2] (1/2) dt + ∫[π/6, π/2] (cos(2t)/2) dt]
Step 11: Integrate each term separately:
(7/4) [(t/2) + (sin(2t)/4)] evaluated from π/6 to π/2
Step 12: Substitute the limits and simplify:
(7/4) [((π/2)/2 + (sin(2(π/2))/4) - ((π/6)/2) - (sin(2(π/6))/4)]
Step 13: Simplify further:
(7/4) [(π/4 + 0 - π/12 - (1/4)(√3/2))]
Step 14: Simplify and calculate the final value:
(7/4) [(π/4 - π/12 - (√3/8))]
= (7/4) [(3π - π - 3√3)/12]
= (7/4) [(2π - 3√3)/12]
= (7/4) (π - (3√3)/6)
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g(x) = -3x-8g(x)=−3x−8g, left parenthesis, x, right parenthesis, equals, minus, 3, x, minus, 8
g\Big(g(g, left parenthesis
\Big)=10)=10
Answer:
try your best
Step-by-step explanation:
Use the function f=d+1 to find the value of f when d=5.
Answer:
f = 6
Step-by-step explanation:
Plug in what you know then solve:
f = d + 1
f = 5 + 1
f = 6
The curb weight of a new car is 3,347 pounds. How much does the car weigh?
Answer: 3,347 pounds
Step-by-step explanation:
Curb weight is simply the weight of a car with no passengers, cargo, or anyting other than the standard base model options.
Basically it's the weight of a base model car sitting on the dealership lot. Curb weight would be different if ANYTHING is added to the base model car such as a passenger, any cargo, or any upgrades aftermarket or otherwise.
Answer:
Not sure if this the correct type of way your looking but its between 1 and 2 tons which is 1000
Step-by-step explanation:
I think...
when comparing the f(x) = x2 2x and g(x) = log(2x 1), on which interval are both functions negative? (–[infinity], –2) (–2, 0) (–1, 1) (–[infinity], [infinity])
To find out on which interval are both functions f(x) = x^2 + 2x and g(x) = log (2x + 1) negative, we need to analyze the intervals of negative values of both functions.
We can plot their graphs to have a better understanding:
Graphs of f(x) = x² + 2x and g(x) = log(2x + 1)
Now, we need to observe the intervals where both functions lie below the x-axis: The function f(x) = x^2 + 2x is below the x-axis on the interval (-∞, -2).
The function g(x) = log(2x + 1) is below the x-axis on the interval (-1/2, 0).
Therefore, the interval on which both functions are negative is (-2, 0).Thus, the correct option is (–2, 0).
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How much interest is earned on a principal of $316 invested at an interest rate of 9%
compounded annually for four years?
Answer:
$130.06
Step-by-step explanation:
Interest is calculated as shown;
I = A - P
A is the amount
P is the principal
Given
Principal = $316
Rate R = 9% = 0.09
Time t = 4yrs
Substiutte and get Amount A
A =P(1+r)^n
A = 316 (1+0.09)^4
A = 316(1.09)^4
A = 316(1.4116)
A = 446.06
Interest = 446.06 - 316
Interest = 130.06
Hence the interest is $130.06
Which of the following variables could theoretically be measured on a continuous scale? (a) Method of contraception used (b) length of time of residence in a state (c) task completion time (d) intelligence (e) authoritarianism (f) alienation (g) county of residence.
The variable that could theoretically be measured on a continuous scale is task completion time.
Task completion time is the duration between the initiation and completion of a specific task. It is continuous as it can take a large range of values on a continuous scale without any gap. It is frequently calculated in various businesses and researches to determine the efficiency and productivity of a particular task or process.
The other variables, such as method of contraception used, length of time of residence in a state, intelligence, authoritarianism, alienation, and county of residence, are all discrete variables. These variables take non-numerical values and are separate from each other by a gap.
These variables can be classified and counted into different categories, such as the number of individuals using a particular method of contraception, number of years of residence in a particular state, number of individuals belonging to a particular county, or number of individuals showing authoritarianism.
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Can somebody help me please no links
Answer:
Lololololo9lolo9lkiujyhgdfbhjkifewkjuhgsdvcgfh
Step-by-step explanation:
How are youaefljsofjsnjvlsdnbvjklxfclkjmzlv
e. 15 = 1.5t t=? Solve please
Answer:
E Z
10
Step-by-step explanation:
15 = 1.5t
so t = 15/1.5
= 10
Answer: t = 10
1. Switch sides
- 1.5t = 15
2. Multiply both sides by 10
- 15t = 150
3. Divide both sides by 15
4. Simplify
t = 10
Eugenia gasto 10 euros en el quiosco, compro 5 bocaditos, un paquete de galletas que costaba 1 euro y pagó 4 euros que debia ¿cuanto cuesta cada bocadito?
Answer:
the each snack cost is 1
Step-by-step explanation:
Let us assume the each snack cost be x
So according to the question
The following equation would be applied
5x + 1 + 4 = 10
5x + 5 = 10
5x = 5
x = 1
hence, the each snack cost is 1
So the same would be considered and relevant too
write a quadratic function with leading coefficient 1 that has roots ofp.
A quadratic function with leading coefficient 1 and roots of p can be expressed as f(x) = (x - p)(x - p), which simplifies to f(x) = x^2 - 2px + p^2.
To construct a quadratic function with leading coefficient 1 and roots of p, we utilize the relationship between the roots and the factors of a quadratic equation. Since p is a root, the factors of the quadratic function would be (x - p) and (x - p). By multiplying these factors together, we obtain the quadratic function f(x) = (x - p)(x - p). Simplifying further, we can expand the expression:
f(x) = (x - p)(x - p) = x^2 - px - px + p^2 = x^2 - 2px + p^2
Hence, the quadratic function with leading coefficient 1 and roots of p is given by f(x) = x^2 - 2px + p^2. This form allows for easy identification of the coefficients and reveals that the constant term of the quadratic is p^2.
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The lenght of an arc in a circle with radius 8 inches is 3.2π. determine the measure of the arc
Answer:
72
Step-by-step explanation:
32pi×360/2pi(8)=72
central angle= arc length 360/2pi×r
The measure of the arc is 72 degree
What is mean by Circle?The circle is a closed two dimensional figure , in which the set of all points is equidistance from the center.
The measure of the arc, we use the formula:
⇒ Arc length = (angle measure / 360°) x 2πr
where r is the radius of the circle.
Now, We know that;
The radius is 8 inches, and that the arc length is 3.2π inches.
So, we can plug in those values and solve for the angle measure:
3.2π = (angle measure / 360°) x 2π(8)
3.2π = (angle measure / 360°) x 16π
Divide both sides by 16π:
0.2 = angle measure / 360°
Multiply both sides by 360°:
Angle measure = 72°
Thus, The measure of the arc is 72 degree
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can some one please help. 4789658953 round to the nearest 10th
mean =
mean absolute deviation =
Answer:
i believe your answer is.
4,789,658,950
Step-by-step explanation:
Find the common difference of the arithmetic sequence -3, -9, -15
Answer:
they are subtracting 6 from each number
Please help !!!!!!!!!
Answer:
5
Step-by-step explanation:
3x -12 = -36
-36 ÷ -3 = 12
-7 + 12 = 5
Answer:
The value of -7 + 3(-12) ÷ (-3) is 5
Step-by-step explanation:
First: -7 + -36 ÷ (-3)
Second: -7 + 12
Third: = 5
Therefore your value of this equation is 5.
your welcome.
Please please help I swear I will give you brainlist if it’s right and please explain for part a and part b thank you
Answer:
A. Reduction
B. 2
Step-by-step explanation:
A: A reduction is when the image is getting smaller. The apostrophes show the new, or second, image. It is called "prime." Because the prime is smaller than the original, it is a reduction.
B: Scale factor is when you divide, which number changes it. In other words, the image moved from 4 to 2, from 2 to 1, etc, which means we are DIVIDING by 2.
hi amazing people please help i’ll give brainliest thanks!
Answer:
to present another's viewpoint
Answer:-
D, to analyze specific data i guess
Veterinarians often use nonsteroidal anti-inflammatory drugs (NSAIDs) to treat lameness in horses. A group of veterinary researchers wanted to find out how widespread the price is in the United States. They obtained a list of all veterinarians treating large animals, including horses. They send questionnaires to all the veterinarians on the list. Such a survey is called a cemus. The response rate was 40%. What is the population of interest? a all veterinarians Oball veterinarians treating large animals e all veterinarians in the United States treating large animals, including horses d. All of the answer options are correct.
The population of interest in this case is (d) All of the answer options are correct. It includes all veterinarians, all veterinarians treating large animals, and all veterinarians in the United States treating large animals, including horses.
The population of interest in this study is defined as all veterinarians in the United States who treat large animals, including horses. This population includes all individuals who fit this criteria, regardless of their location or any other specific characteristics.
The researchers wanted to gather information about the prevalence of using nonsteroidal anti-inflammatory drugs (NSAIDs) for treating lameness in horses among veterinarians in the United States. To do this, they obtained a list of all veterinarians who treat large animals, including horses, and sent questionnaires to each of them.
The response rate refers to the percentage of veterinarians who completed and returned the questionnaires out of the total number of questionnaires sent. In this case, the response rate was 40%, meaning that 40% of the veterinarians who received the questionnaires responded to them.
By surveying a representative sample of veterinarians, the researchers can gather information and make inferences about the larger population of veterinarians in the United States who treat large animals, including horses. The data collected from the survey can provide insights into the widespread use of NSAIDs for treating lameness in horses and contribute to the overall understanding of veterinary practices in this context.
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y= 5x - 9; domain = { 1,3,7 }
what is the range values?
Answer:
Step-by-step explanation:
range = [-4,6,26]
Step-by-step explanation:
y = 5x - 9.....domain = [1,3,7]....the domain is ur x values, and I am assuming ur looking for the y values that go with the x ones
y = 5x - 9.....when ur domain (ur x) = 1
y = 5(1) - 9
y = 5 - 9
y = -4
y = 5x - 9...when ur domain (x) = 3
y = 5(3) - 9
y = 15 - 9
y = 6
y = 5x - 9...when ur domain(x) is 7
y = 5(7) - 9
y = 35 - 9
y = 26
so ur range (ur y valus) = [-4,6,26]
pls help i’ll give brainliest
Answer:
1/5x12 and 12/5
Step-by-step explanation:
both are dividing by five or equal to 2.4 which is the same as 1/5 of 12
Answer Of means to multiply so two correct answer would be B,D
Step-by-step explanation: hope this helps :)
Joe has been riding his bicycle at a speed of 12 mph and has gone 48 miles. How long has he been riding?
Answer:
Joe's been riding 4 hours because if you divide 48 by 12 it gives you 4 and it's by hours so it would be 4 hours. point blank period.
Step-by-step explanation:
Someone help what would my average be if I got 100% on my both of my tests? I just wanna know
Answer:
To figure out your average, you add them together then divide by2
Step-by-step explanation:
X^2-18x-2=0. Which number would have to be added to “complete the square”?
Step-by-step explanation:
its83
(a+b)^2=a^2+2ab+b^2
x^2+(-9)2x-2=0
b^2=81
83+(-2)=81
Suppose X is an exponential random variable, show that E(X²) = 2/λ²
The exponential distribution is a continuous probability distribution that is widely used in probability theory and statistics. In probability theory, an exponential random variable is a continuous random variable that represents the waiting time between events in a Poisson process.
Suppose X is an exponential random variable. We have to show that E(X²) = 2/λ². We can show this by using the definition of expectation that is, E(X) = ∫[0,∞] xf(x) dx
where f(x) is the probability density function of X.
Similarly, E(X²) = ∫[0,∞] x²f(x) dx
We know that the probability density function of an exponential distribution with parameter λ is given by f(x) = λe^(-λx)So, E(X²) = ∫[0,∞] x²λe^(-λx) dx
Using integration by parts, we have ∫[0,∞] x²λe^(-λx) dx= [-x²e^(-λx)/λ] + [2xe^(-λx)/λ²] + [(-2/λ³)e^(-λx)]∞ 0= (2/λ²)
E(X²) = 2/λ².
The exponential distribution is a continuous probability distribution that is widely used in probability theory and statistics. In probability theory, an exponential random variable is a continuous random variable that represents the waiting time between events in a Poisson process.
Suppose X is an exponential random variable. We have to show that E(X²) = 2/λ². We can show this by using the definition of expectation that is, E(X) = ∫[0,∞] xf(x) dx
where f(x) is the probability density function of X.
Similarly, E(X²) = ∫[0,∞] x²f(x) dx
We know that the probability density function of an exponential distribution with parameter λ is given by f(x) = λe^(-λx)So, E(X²) = ∫[0,∞] x²λe^(-λx) dx
Using integration by parts, we have ∫[0,∞] x²λe^(-λx) dx= [-x²e^(-λx)/λ] + [2xe^(-λx)/λ²] + [(-2/λ³)e^(-λx)]∞ 0= (2/λ²)Therefore, the main answer to this question is E(X²) = 2/λ².
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Solve for v.
6v-7+2(5v+1) = -2(v + 4)
Answer:
v = -1/6
Step-by-step explanation:
Combine all like terms, getting 18v = -3. Then, divide both sides by 18 to get -3/18, or v = -1/6
Hopefully this helps- let me know if you have any questions!
In a study of spat dating es were asked them in the same time to What other out of the popu 23,50710090 What is the concerto? D-lichte places need was the other the contacto OA TN repostane posting tone OR Weather to the memo and on dem O. We second have the end மொயமால மாமா mg 140 Newt 0 View an example Get more help Help me solve this C M a o 0 10 1 In a study of speed dating male subjects were asked to rate the attractiveness of their female dates, and a sample of the results is listed below (1 = not attractivo 10 = extremely attractive) Construct a confidence interval using a 95% confidence level What do the results tell about the mean attractiveness ratings of the population of all adult females? 6,9,3,9, 6, 6, 8, 8, 7, 10,5,9 What is the confidence interval for the population mean? [<<(Round to one decimal place as needed) west point(s) possible in a study of speed dating, male subjects were asked to rate the attractiveness of their female dates, and a sample of the results is listed below (1 = not attractive 10 = extremely attractive) Construct a confidence interval using a 95% confidence level What do the results tell about the mean attractiveness ratings of the population of all adult females? 6,9,3,9,6,6,8,8.7. 10,5,9 PO What is the confidence interval for the population mean? <-- (Round to one decimal place as needed) What does the confidence interval tell about the population of all adult fernales? Select the correct choice below and, if necessary, fill in the answer box(es) to complete your choice. ative Area from the LEF 02 O A. The results tell nothing about the population of all adult females, because participants in speed dating are not a representative sample of the population of all adult females 5000 5178 03 5120 5517 5990 5871
Confidence interval are 5.9 < μ < 8.5 for the population mean.
Given:
Let x = 6,9,3,9, 6, 6, 8, 8, 7, 10,5,9
N = 12, ∑x = 86 x = 86/12 = 7.16
[tex]s=\sqrt{\frac{(x-\bar x)^2}{N-1} } = \sqrt{\frac{(6-7.16)^2+.....+(9-7.16)}{12-1} }[/tex]
[tex]\sqrt{\frac{45.66}{11} } =2.03[/tex]
At 98% confidence interval.
[tex]z=1-\frac{95}{100} =0.05\\[/tex]
[tex]t=2.201[/tex]
Confidence interval.
[tex]\bar x \pm t\frac{s}{\sqrt{n} } = 7.16\pm 2.201(\frac{2.03}{\sqrt{12} } )[/tex]
[tex]5.9 < \mu < 8.5[/tex]
Therefore, 95% confidence interval are 5.9 < μ < 8.5
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