A satellite of mass 1000kg is in a circular orbit around a planet. The centripetal acceleration of the satellite in its orbit is 5m/s^2. What is the gravitational force exerted on the satellite by the planet?

A. 0N
B. 200N
C. 5000N
D. 10000N

Answer:

distance is how much space is between, speed is how fast they are going, velocity is money and acceleration is going

Explanation:

Answer:

as fuel is combusted,the rocket pushes the gas is backward and the gas is pushed the rocket forward

Explanation:

hope this helps :]

Answer:

bus , running boy etc

Explanation:

moving body is called motion .

e.g. running boy , bus, birds flying etc

Answer:

The spiral staircase will require more work

Explanation:

This is because, work can be calculated as force (which is mass of the individual climbing the stairs in this case) multiplied by distance (or length) of the stairs. The only variable that changes in the work done while climbing any of the two (ladder or spiral staircase) is the distance and it is obvious the length of the spiral staircase will be longer; thus the spiral staircase will involve more work.

The two fundamental forces that are only attractive is  A. Gravitational and strong nuclear.

The "strong" nuclear force outperforms gravity by a factor of 10 to the 38th. While gravitational and electromagnetic forces have relatively large ranges of action, the strong and weak nuclear forces operate at close ranges. All objects are affected by the strong and weak nuclear forces, whereas smaller objects are affected by gravitational and electromagnetic forces.

Nuclear forces are the most enticing of the four fundamental forces. There was no explanation provided as to how the nucleus in the atom is kept together by electromagnetism, which maintains matter together.

Therefore, option A is correct.

Learn more about forces at:

https://brainly.com/question/12970081

#SPJ1

Answer:

0.2

Explanation:

3/15

Answer:

a

Explanation:

Answer:

D. Sound waves

Explanation:

The following options are missing:

A. radio wave

B. X-rays

C. Light waves

D. Sound waves

There are two kinds of waves: longitudinal and transverse.

In longitudinal waves, the vibrations are parallel to the direction of wave travel. Examples of longitudinal waves include: sound waves  and ultrasound waves.

In transverse waves, the vibrations are at right angles to the direction of wave travel. All electromagnetic waves (e.g. light waves, microwaves, radio waves and X-rays) are transverse waves.

Answer:

C

Explanation:

Answer:

Environment

Explanation:

Your Environment, More Than Genetics, Determines Your Immune Health. When it comes to immunity, the environment you grow up in, or how you were 'nurtured' , is more important than nature, a new study suggests. Particularly as you get older.

Answer:

A

Explanation:

Answer:

No, they do not function in the same manner.

Explanation:

I actually don't know why.

Because of the buoyancy of the salt particles

Answer:

114N

Explanation:

gravity on earth: 10m/s (exact: 9.82)

mass if chicken = 300/10 = 30Kg

weight of chicken on mercury = 3.8 x 30 = 114N (you wrote 0.38 but Mercury's gravity is about 3.7)

Answer:

113.15 g

Explanation:

That's because the planets weigh different amounts, and therefore the force of gravity is different from planet to planet. For example, if you weigh 100 pounds on Earth, you would weigh only 38 pounds on Mercury. That's because Mercury weighs less than Earth, and therefore its gravity would pull less on your body.

Answer:

True

Explanation:

Answer:

True.

Explanation:

Hope this helps!!! <3

solid, liquid,gasses

Answer:

0.67 m/s

Explanation:

Mass of car 1, m₁ = 5000 kg

Mass of car 2, m₂ = 10,000 kg

Initial speed of car 1, u₁ = 2 m/s

Final speed of car 2, u₂ = 0 (at rest)

We need to find the final velocity of both cars when inelastic collision occurs. The momentum will remain conserved in case of inelastic collision. Using the conservation of momentum. Let V is the final speed.

[tex]m_1u_1+m_2u_2=(m_1+m_2)V\\\\\V=\dfrac{m_1u_1+m_2u_2}{(m_1+m_2)}\\\\V=\dfrac{m_1u_1}{(m_1+m_2)}\\\\V=\dfrac{5000\times 2}{(5000+10000)}\\\\V=0.67\ m/s[/tex]

So, after the inelastic collision, they will move with a speed of 0.67 m/s.

Complete Question

You are helping your friend move a new refrigerator into his kitchen. You apply a horizontal force of 280 N in the positive x direction to try and move the 63 kg refrigerator. The coefficient of static friction is 0.55.

(a) How much static frictional force does the floor exert on the refrigerator? Give both magnitude and direction.

magnitude            N

direction          

   (b) What maximum force do you need to apply before the refrigerator starts to move?

Answer:

a

   The magnitude  is [tex]F_f = 339.57 \ N[/tex]

    The direction is  [negative x - axis ]

b

   The maximum force to be applied for the refrigerator to start moving is  

      [tex]F_{max} = 339.57 \ N[/tex]

Explanation:

From the question we are told that

   The horizontal force applied is [tex]F_a = 280 \ N[/tex] the direction is  +ve  x-axis

   The mass of the refrigerator is  [tex]m = 63 \ kg[/tex]

    The coefficient of static friction is  [tex]\mu_s = 0.55[/tex]

Generally the frictional force exerted on the refrigerator is mathematically represented as

            [tex]F_f = \mu * m * g[/tex]

=>         [tex]F_f = 0.55 * 63 * 9.8[/tex]

=>         [tex]F_f = 339.57 \ N[/tex]

From the value obtained we see that the static force  exerted by the floor on the refrigerator  is  greater than the force (280 N ) exerted by the person and the direction is  -ve x-axis

Generally the maximum force that is to be applied by the person is mathematically  equal to the force exerted by the floor on the refrigerator but the direction is in the positive x-axis  i.e

         [tex]F_{max} = F_f = 339.57 \ N[/tex]

Answer:

I thick it's ccc not for sure

Answer:

0.25m/s

Explanation:

Given parameters

m₁  = 5kg

v₁ = 1.0m/s

m₂ = 15kg

v₂ = 0m/s

Unknown:

velocity after collision = ?

Solution:

Momentum before collision and after collision will be the same. For inelastic collision;

    m₁v₁ + m₂v₂  = v(m₁ + m₂)

Insert parameters and solve for v;

   5 x 1  + 15 x 0 = v (5 + 15 )

          5  = 20v

          v = [tex]\frac{5}{20}[/tex]   = 0.25m/s

Answer:

El trabajo realizado para subir los últimos 500 metros es 318727,5 joules.

Explanation:

Por la definición de trabajo sabemos que el montañero debió contrarrestar trabajo causado por la gravedad terrestre. Si asumimos que el cambio de la altura es muy pequeño en comparación con el radio del planeta (6371 kilómetros vs. 0,5 kilómetros), entonces podemos considerar que la aceleración gravitacional es constante y la ecuación de trabajo ([tex]\Delta W[/tex]), medido en joules, que reducida a:

[tex]\Delta W = m\cdot g\cdot \Delta z[/tex] (1)

Donde:

[tex]m[/tex] - Masa del montañero, medido en kilogramos.

[tex]g[/tex] - Aceleración gravitacional, medida en metros por segundo al cuadrado.

[tex]\Delta z[/tex] - Distancia vertical de ascenso del montañero, medida en metros.

Si tenemos que [tex]m = 65\,kg[/tex], [tex]g = 9,807\,\frac{m}{s^{2}}[/tex] y [tex]\Delta z = 500\,m[/tex], entonces el trabajo realizado por el montañero para subir es:

[tex]\Delta W = (65\,kg)\cdot \left(9,807\,\frac{m}{s^{2}} \right)\cdot (500\,m)[/tex]

[tex]\Delta W = 318727,5\,J[/tex]

El trabajo realizado para subir los últimos 500 metros es 318727,5 joules.

Answer:

v=v(initial)+at

45=0+15a

a= 3m/sec²

Explanation:

edge 2020

Answer:

The Science of Round Bubbles

But once a bubble is sealed and removed from the wand, the tension in the bubble shrinks it to the smallest possible shape for the volume of air inside of it. That's a sphere, which is the familiar round shape we see when bubbles float through the air.

Explanation:

Answer:

asd

Explanation:

Answer: Distance-time graph is the plot of distance travelled by a body against time.  Below is an example of a distance-time graph, if it is a straight horizontal line than the body is stationary, its speed is zero, if the line is diagonal than its moving with a constant speed and if it is anything other than a straight line then the speed is varying. Distance-Time Graph for Uniform Motion Let us now consider a distance-time graph in which the body is moving with uniform motion. A body is said to be in uniform motion when the body covers the equal distance in equal time intervals. Let’s consider a time interval of 1 second, If a body covers 10 meters in the first 1-second then it should cover 10 meters in every second from there on, this will indicate that the body is in uniform motion.

Explanation: I hoped that helped!!

Answer:

C. transverse