A silver block of silver block of density 10.5 g/cm3 has a volume of 30 cm3. Which of the following is the correct mass of the block ​

Answer: his distance from the pole is 90.16 ft

Explanation:

based on the diagram of the question i will upload along this answer;

45 - d is equal to part of the pole below the horizontal line

d/x = tan(16) ; x = d/tan(16)............equ1

(45-d) / x = tan(12); x = (45-d) / tan(12)-----------equ2

∴ d/tan(16) = (45-d) / tan(12)

d.tan(12) = (45-d).tan(16)  

d.tan12 = (45×tan16) - d.tan16

0.2125d = 12.9034 - 0.2867d

0.2125d + 0.2867d = 12.9034

0.4992d = 12.9034

d = 12.9034/0.4992

d = 25.85 ft

now substitute value of d into any of our previous equation, lets take equation 1

x = 25.85 / tan(16)

x = 25.85 / 0.2867

x = 90.16 ft

Therefore his distance from the pole is 90.16 ft

Answer:

W23e45rdfytg

Explanation:

Eawsredtrftgvbyhgtfrd54e

One multicellular organism is a cube. Each of its sides is 3 cm long. If each of its cells is 1 cm, then it would have 27 cells, if each side doubles its length then it would have 216 cells.

Anything which has mass and occupies space is known as matter , mainly there are four states of matter solid liquid gas, and plasma.

These different states of matter have different characteristics according to which they vary their volume and shape.

As given in the problem, one multicellular organism is a cube. Each of its sides is 3 cm long. Each of its cells is 1 cm.

The volume of the  multicellular organism = 3 × 3× 3

                                                                      = 27 cm³

The number of cells = 27 cm³ / 1 cm³

                                  = 27

Thus, If each of its cells is 1 cm, then it would have 27 cells, if each side doubles its length then it would have 216 cells.

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◈ Electric current :

Electric current is defined as the rate of charge flow. (per unit time)

I denotes current

Q denotes charge

t denotes time

Given : I = 2A and t = 2s

To Find : Charge flow in wire (Q)

[tex]:\implies\sf\:I=\dfrac{Q}{t}[/tex]

[tex]:\implies\sf\:2=\dfrac{Q}{2}[/tex]

[tex]:\implies\:\boxed{\bf{\red{Q=4\:C}}}[/tex]

A flow of electrical charge carriers, generally electrons or electron-deficient atoms, is referred to as current.  The charge that will be in the wire is 4 C.

A flow of electrical charge carriers, generally electrons or electron-deficient atoms, is referred to as current. The capital letter I is a typical sign for current. The ampere, abbreviated as A, is the standard unit.

As it is given to us that the current in the wire is 2A, while the time for which the current flows through the wire is 2 seconds.

[tex]\rm I=\dfrac Qt[/tex]

Substitute the value we will get,

[tex]\rm 2\ A = \dfrac{Q}{2\ sec}\\\\Q = 4\ C[/tex]

Thus, the charge that will be in the wire is 4 C.

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Answer:

Lost Money = $ 53200

Explanation:

First, we calculate the selling price of the cloth:

Selling Price = (Area of Bought Fabric)(Unit Price in America)

Selling Price = (500 m²)($ 120/yard²)(1 yard/0.9144 m)²

Selling Price = $ 71759.4

Now, we calculate the amount that the cloth maker paid (cost) for buying the fabric from America:

Cost = (Area of Fabric Bought)(Unit Selling Price)

Cost = (500 m²)(400 tepizes/ m²)($ 0.625/1 tepize)

Cost = $ 125000

Hence, the money lost is given as:

Lost Money = Cost - Selling Price

Lost Money = $ 125000 - $ 71759.4

Lost Money = $ 53240

Rounding off to 3 significant figures, we get:

Lost Money = $ 53200

Answer:

A. Using

I= P/ A

So = P/ 2π R²

So=777E3 watt/ 2*πx (²5.5E3m)

4.3*10^ -3W/m²

So pressure= 2I/c

=2* 4.3*10^ -3W/m²/ 3*10^ 8

2.7*10^-11p.a

B.

Using Emax= √2I/Eoc

So

√ 2*4.3*10^-3/8.8E-12*3*10^8

= 5.48V/m

So

Bmax= Emax/c

5.58/3E8

= 1.83*10-9T

D.average density is given by

= Eo(Emax/√2)²

= 8.85E-12(5.48/√2)²

1.3*10^10W/m²

Answer:

1. OK the

1. The horizontal axis of a osclloscope is generally TIME axis.

2. given T =25 micro second

That is = 25E-6 s

Then We f = (1/T) .

So f = 1/(25 x 10^-6) = 40000 Hz =

40 KHz.

3. First Band will be Yellow

Second Band will be Violet

Third Band will be Red

And

Fourth Band will be Gold

Thus, the value of the resistance = (47 x 100)plus or minus 5%

= (4700 plus or minua5%) ohm

the range of the acceptable value of the resistance will now be

= 4465 ohm to 4935 ohm

(4)

The level provided by the wall outlet = 120 x √2 = 169.68 V

The √2 is because the multimeter measures RMS voltage rather than peak voltage and

RMS Voltage is = √2 x peak voltage

Answer:

The answer is a

Explanation:

Answer:

Immune

Explanation:

because I remember taking that test and I I specifically remember that question and that's the answer

Answer:Newton’s law also states that larger bodies with heavier masses exert more gravitational pull, which is why those who walked on the much smaller moon experienced a sense of weightlessness, as it had a smaller gravitational pull. To help explain his theories of gravity and motion, Newton helped create a new, specialized form of mathematics.

Explanation:

Answer: newtons 2nd law of motion because in order to push the object you must put force to the mass and move it causing motion

Explanation:

The magnitude of Dot product of two vectors is 3.

     [tex]A= 4j - 2i - 3k[/tex]  and [tex]C= -4i -2j - 3k[/tex]

        [tex]A\cdot C=(-4*4)+(-2*-2)+(-3*-3)\\\\A\cdot C=-16+4+9\\\\A\cdot C=-16+13=-3[/tex]

Thus,  The magnitude of Dot product of two vectors is 3.

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The complete question is;

In electronic circuits it is not unusual to encounter currents in the microampere range. Assume a 35 μA current, due to the flow of electrons. What is the average number of electrons per second that flow past a fixed reference cross section that is perpendicular to the direction of flow?

Answer:

2.185 × 10^(14) electrons/seconds

Explanation:

We are given current as 35 μA = 35 × 10^(-6) Amperes

The value of the charge on one electron is; e = 1.602 × 10^(-19) coulombs

Now, from conversions;

One ampere = one coulomb/second =

Then, 35 × 10^(-6) Ampere's would give;

35 × 10^(-6) Coulombs/sec

Now,

1.602 × 10^(-19) coulombs = 1 electron

Thus;

35 × 10^(-6) Coulombs/sec gives;

(35 × 10^(-6))/(1.602 × 10^(-19)) = 2.185 × 10^(14) electrons /sec

The average number of electrons per second that flow past a fixed reference cross-section perpendicular to the direction of flow is 2.185 × 10⁻¹⁴ electrons /sec

The question is as given below:

In electronic circuits, it is not unusual to encounter currents in the microampere range. Assume a 35 μA current, due to the flow of electrons. What is the average number of electrons per second that flow past a fixed reference cross-section that is perpendicular to the direction of flow?

Given information:

Current I = 35 μA = 35 × 10⁻⁶ A

charge on electron e = 1.602 × 10⁻¹⁹C

We know that:

I = de/dt, rate of flow of charge.

1A = 1C/s

Thus,

35 × 10⁻⁶ A = 35 × 10⁻⁶ C/s

Now, one electron has a charge of  1.602 × 10⁻¹⁹C

So, the number of electrons for a current of 35 × 10⁻⁶ C/s will be:

n = (35 × 10⁻⁶ C/s) ÷ (1.602 × 10⁻¹⁹C)

n = 2.185 × 10⁻¹⁴ electrons /sec

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Answer:

This is caused by the rotation and position of the Earth with respect to the sun.

Explanation:

The constant change of the Moon's surface relative to Earth is called "The moon phases".

These modifications in our satellite are due to the change of position of the satellite with respect to the Earth and the Sun.

During the lunar phases of the third quarter and the first quarter, the moon lights up just a half, being that both only light half, the first quarter lights the right side of the moon, and the last quarter lights the left side.

Answer:

a= 18.4m

b= 26.2m

Explanation:

Please see the attached picture for full solution.

Answer:

Pluto

Explanation:

In our solar system, we have several planet. Pluto is one of the. Pluto is a planet that is highly oval shaped orbit and eccentric that brings it inside the another orbit. It get inside the orbit of Neptune. Sometimes even Neptune get far away from sun in comparison to the dwarf planet Pluto.

It is very strange happening in the world of planet. it occurs in the year of 1979 and 1999. But Pluto never ever crashed into Neptune. It happen because Neptune takes every three lapse that takes around the sun but Pluto makes only two lapse. This happening prevents two bodies from clashes.

Answer:

Valid Expressions are; t = ∛(d²/va), a = d/t², a = √(vd/t³), v = at

while the Invalid expressions are;  v = a/t and  d = at

Explanation:

Given expressions

1) v = a/t

2) t = ∛(d²/va)

3) d = at

4) a = d/t²

5) a = √(vd/t³)

6) v = at

First we get our units of parameters

V = m/s, t = sec, d = m, a = m/s²

so

1)

v = a/t

we substitute in our units of parameters

v = m/s² / s = m/s² × 1/s = m/s³

v ≠ m/s³

therefore it is false

2)

t = ∛(d²/va)

we substitute

t = ∛(m² / m/s × m/s²)

t = ∛(m² / m²/s³)

t = ∛(s³)

t = s

correct, the expression is true

3)

d = at

we substitute

d = m/s² × s

d = m/s² × s/1 =  ms/s² = m/s

d ≠ m/s (because d = m)

so expression is false

4)

a = d/t²

we substitute

a = m / s² = m/s²

correct

the expression is true

5)

a = √(vd/t³)

we substitute

a = √(m/s×m / s³) = √(m²/s / s³) = √(m²/s × 1/s³)  = √(m²/s⁴) = m/s²

so a = m/s²

correct

the expression is true

6)

v = at

we substitute in the units

v = m/s² × s = m/s² ×s/1 = ms/s² = m/s

v = m/s

correct

the expression is correct

Distance = (speed) x (time)

Distance = (10 meter/second) x (2 minutes)

Distance = (10 meter/second) x (2 minutes) x (60 second/minute)

Distance = (10 x 2 x 60) (meter-minute-second / second-minute)

Distance = 1,200 meters

Answer:

Explanation:

what is surface tension?

simply put, surface tension is the ability of water to act or behave as if it were or were covered by an elastic skin.

other notable examples of surface tension are

Examples of surface tension of water

1. Ants walking on water

2.Razor blades floating on water  

3. Capillary action (water rising or falling in a narrow capillary tube)

Should you need further clarification do not hesitate to let me know

Answer:

The  value  is  [tex]t = 10 \  s[/tex]

Explanation:

From the question we are told that

  The  height is  [tex]h = 500 \ m[/tex]

  The acceleration is  [tex]g =  10 \  m/s[/tex]

Generally from the second equation of motion we have that

    [tex]h  =  ut  +  \frac{1}{2} a t^2[/tex]

Here  the initial velocity u =  0  m/s  given that the stone started from rest

       So

            [tex]500 =  0 (t) +0.5 *  (10) t^2[/tex]

=>         [tex]t = 10 \  s[/tex]

Answer:

Heat required in converting 1g of ice at −10∘C into steam at 100∘C is: latent heat of fusion= 80 cal/g80 cal/g. latent heat of vaporization=540 cal/g.

Answer:

50280 meters

Explanation:

33.52 meters/seconds is 2011.2 meters/minutes (multiply by 60)

2011.2 meters/m * 25 minutes = answer

Answer:

We are given x= bt +ct²

So

A. bxt= m

Because m/s*s= m

So b= m/s and c= m/s²

B.

x= bt-ct²

So at x=0 t=0

x=0 t= 2

We have

bt = ct² so t = b/c at x= 0

So b-2ct= 0

B. To find velocity we use

dx / dt = b - 2 Ct

C. At rest wen V= 0

We have t= b/2c

D. To find acceleration we use

dv / dt = - 2C

When We are given x= bt +ct²

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You probably already took this but if anyone wanted to know the answer it's D. "A system where matter and energy cannot enter or leave the system".

(I also took the quiz for it and got it correct)

A closed physical system is a system where matter and energy cannot enter or leave the system. The correct option is D.

A physical system is any item or part of an object that can be analyzed using physics laws.

An atom and lake water are both examples of physical systems. Everything outside the system is referred to as the environment, and it is ignored in the analysis except for its effects on the system.

A physical system is a collection of parts or elements that, when combined, exhibit behavior that the constituents do not. Matter and energy make up physical systems.

A closed system is a natural physical system that does not allow the transfer of matter into or out of the system, though it does allow the transfer of energy in contexts such as physics, chemistry, or engineering.

Thus, the correct option is D.

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Answer:

Option C. The delivery van has the greatest kinetic energy because its mass is greater than that of the other

vehicles.

Explanation:

Kinetic energy is the energy of an object in motion. Mathematically, it is expressed as:

K.E = ½mv²

Where:

K.E is the kinetic energy.

m is the mass of the object.

v is the velocity of the object.

From the formula above, we can say that:

Kinetic energy is directly proportional to the mass of the object and the square of the velocity of the object. This simply means that objects with higher mass will have a greater kinetic energy than objects will lighter mass even if their velocities are the same.

From the question given above, it is obvious that the delivery van has a greater mass than the rest object.

Therefore, the delivery van will have the greatest kinetic energy because its mass is greater than that of the other

vehicles.

Answer:

The electric field inside the conductor is zero.

Explanation:

In electrostatic equilibrium charges are assumed to be in rest. Therefore no current.

I = 0

From the ohm's law

ΔV= IR = 0

⇒ΔV =0

Therefore, potential V is same through the conductor.

Also, E = -ΔV d = 0

Hence, The electric field inside the conductor is zero.

The answer is "the product of the object's moment of inertia and the object's angular velocity.

The correct definition of angular momentum would be that it is the product of the object’s moment of inertia and the object’s angular velocity, therefore the correct answer is option A.

It can be defined as the product of the mass and the speed of the particle, it represents the combined effect of mass and the speed of any particle, and the momentum of any particle is expressed in Kg m/s unit.

As given in the problem we have to find the correct definition of angular momentum,

The angular momentum of the object = the moment of the inertia of the object × the angular velocity of the particle

The right response is option A since the definition of angular momentum is that it is the product of an object's moment of inertia and its angular velocity.

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Answer:

90 m/s

Explanation:

Time taken = 4 sec

Distance travelled = 360 m

Speed = Distance / Time = 360/4 = 90 m/s

Distance travelled = 360m

Time taken = 4s

We have to find speed[tex].[/tex]

_________________________________

◈ Speed is defined as the ratio of distance travelled to the timr taken.

SI unit : m/s

➝ Speed = Distance / Time

➝ Speed = 360/4

➝ Speed = 90m/s

Complete Question

A boy throws a ball on a spring scales which oscillates about the equilibrium position with a period of T = 0.5 sec. The amplitude of the vibration is A = 2 cm. Assume the ball does not bounce from the scales’s surface afterwards. Assume the vibration of the scale is expressed mathematically as x(t) = Acos(t + ). Find:

a) frequency

b) the maximum acceleration

c) the maximum velocity

Answer:

a

[tex]f =  2  \ Hz[/tex]

b

[tex]a_{max} =  3.2 \ m/s^2[/tex]

c

[tex]v_{max} =  0.25 \  m/s[/tex]

Explanation:

From the question we are told that

   The period is  [tex]T  =  0.5 \ sec[/tex]

    The  amplitude is  [tex]A =  2 \ cm  =  0.02 \ m[/tex]

    The  vibration of the scale is  [tex]Acos(wt +  \phi )[/tex]

Generally the frequency is mathematically represented as

   [tex]f =  \frac{1}{T}[/tex]

=>   [tex]f =  \frac{1}{0.5}[/tex]

=>    [tex]f =  2  \ Hz[/tex]

The  maximum acceleration is mathematically represented as

    [tex]a_{max} =  A *(2 \pi f)^2[/tex]

=>    [tex]0.02 *  (2 * 3.142  *  2)^2[/tex]

=>  [tex]a_{max} =  3.2 \ m/s^2[/tex]

The  maximum velocity is mathematically represented as  

     [tex]v_{max} =  A *  (2 \pi f)[/tex]

=>    [tex]v_{max} =  0.02 *  (2 * 3.142 *  2)[/tex]

=>    [tex]v_{max} =  0.25 \  m/s[/tex]

Answer:

The  value is   [tex]\alpha =  0.002 Np/m[/tex]

Explanation:

From the question we are told that

  The first amplitude of the wave is  [tex]E_{max}1 =  98.02 \  V/m[/tex]

  The first  depth  is  [tex]D_1 =  10 \  m[/tex]

   The second amplitude is  [tex]E_{max}2 =  81.87 \  (V/m)[/tex]

   The second depth is [tex]D_2 = 100 \ m[/tex]

Generally from the spatial wave equation we have

   [tex]v(x) =  Ae^{-\alpha d}cos(\beta x  + \phi_o)[/tex]

=>       [tex]\frac{v(x)}{v(x)} =\frac{  Ae^{-\alpha d}cos(\beta x  + \phi_o)}{ Ae^{-\alpha d}cos(\beta x  + \phi_o)}[/tex]

So considering the ratio of the equation for the  two depth

[tex]\frac{A}{A_S}  =  \frac{e^{-D_1 \alpha }}{e^{-D_2 \alpha }}[/tex]

=>   [tex]\frac{98.02}{81.87}  =  \frac{e^{-10 \alpha }}{e^{-100 \alpha }}[/tex]

=>   [tex]\alpha  =  \frac{0.18}{90}[/tex]

=>    [tex]\alpha =  0.002 Np/m[/tex]

Answer:

  [tex]\sqrt{\dfrac{2g\lambda^3}{m}}[/tex]

Explanation:

We can write the expression here, but the point of the problem seems to be to see if you can manipulate the controls on the answer box to reproduce that expression.

  [tex]\boxed{\sqrt{\dfrac{2g\lambda^3}{m}}}[/tex]

Answer:

Explanation:

When a projectile is launched at some angle to the horizontal with some speed vi , and air resistance is negligible , it is definitely a freely falling body .

It is so because it is free to accelerate towards the earth with acceleration of g . Air has no resistance , hence no force is acting on it except the gravitational force . Hence it is a freely falling body .

b )

The acceleration in the vertical direction is due to force exerted by the earth that is gravitational force on it  . Hence its  acceleration is equal to g in vertically downward direction .

c )

It has zero acceleration in horizontal direction . It is so because no force is acting on it in horizontal direction . So no acceleration will be present in horizontal direction . It will move in horizontal direction with constant speed of vi cos θ where θ is the angle vi make with the horizontal .