A small, 300 g cart is moving at 1.10 m/s on an air track when it collides with a larger, 4.00 kg cart at rest. After the collision, the small cart recoils at 0.890 m/s. What is the speed of the large cart after the collision (answer in m/s please)?

Answers

Answer 1

Answer:

0.0158m/s

Explanation:

Using the law of conservation of energy which states that the sum of momentum before collision is equal to the sum after collision. It is expressed mathematically as;

m1u1 + m2u2 =  m1v1 + m2v1

m1 and m2 are the masses of the object

u1 and u2 are the initial velocities

v1 and v2 are the final velocities

Given

m1 = 300g  = 0.3kg

u1 = 1.10m/s

m2 = 4.00kg

u2 = 0m/s (at rest)

v1 = 0.890

v2 = ?

Substitute the given values into the formula;

0.3(1.10) + 0 = 0.3(0.89) + 4v2

0.33 = 0.267 + 4v2

0.33-0.267 = 4v2

0.063 = 4v2

v2 = 0.063/4

v2 = 0.0158m/s

Hence the speed of the large cart after the collision is 0.0158m/s

Answer 2
The speed of the large cart will be "0.0158 m/s".

According to the question:

Mass,

[tex]m_1 = 300 \ g = 0.3 \ kg[/tex][tex]m_2 = 4.00 \ kg[/tex]

Final velocity,

[tex]u_1 = 1.10 \ m/s[/tex][tex]u_2 = 0 \ m/s[/tex]

Initial velocity,

[tex]v_1 = 0.890 \ m/s[/tex][tex]v_2 = \ ?[/tex]

By using the law of conservation, we get

→ [tex]m_1 u_1 +m_2 u_2 =m_1 v_1 +m_2 v_1[/tex]

By substituting the values, we get

→ [tex]0.3(1.10)+0 = 0.3(0.89)+4v_2[/tex]

→              [tex]0.33=0.267+4 v_2[/tex]

   [tex]0.33-0.267 = 4 v_2[/tex]

              [tex]0.063 =4v_2[/tex]

                   [tex]v_2 = \frac{0.063}{4}[/tex]

                       [tex]= 0.0158 \ m/s[/tex]

Thus the response above is appropriate.

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Related Questions

The motion of a nightingale's wingtips can be modeled as simple harmonic motion. In one study, the tips of a bird's wings were found to move up and down with an amplitude of 8.0 cm and a period of 0.80 s.
Part A: What is the wingtips' maximum speed?
Part B: What is the wingtips' maximum acceleration?

Answers

Answer:

PART A: Maximum speed = 0.314 m/s

PART B: Maximum acceleration = 1.23 m/s²

Explanation:

A simple Harmonic motion is a repetitive motion through an equilibrium point.

Amplitude = 8.0cm = 8/100 = 0.08m (highest displacement)

period (T) = 0.80s

A) maximum speed [tex](V_{max)[/tex]

[tex]V_{max} = 2\pi fA\\where:\\A = Amplitude = 0.08m\\f = frequency = \frac{1}{period(T)} = \frac{1}{0.8} = 1.25 Hz\\\therefore 2\pi fA = 2\pi \times 1.25 \times 0.08\\= 0.314\ m/s[/tex]

B) maximum acceleration [tex](a_{max})[/tex]

[tex]a_{max} = (2\pi f)^2A\\where:\\f = 1.25Hz\\A = 0.08m\\a_{max} = (2\pi \times 1.25)^2 \times 0.08\\= 1.23\ m/s^2[/tex]

calculate the force necessary to keep a mass of 2 kg moving on a circular path of radius 0.2 m with a period of 0.5 second. what is the direction of force

Answers

Answer:

jjjjj

Explanation:

dkcdzjc

If you add a light bulb to the circuit, the filament in the bulb will resist the flow of
electrons and convert energy into____and_____

a.)light and heat
b.)electrons and neutrons
c.)energy and matter
d.)electrons and protons

Answers

Answer:

Light and heat!

Explanation:

This is correct<3

Answer:

light and heat

Explanation:

i love science

A certain electrical circuit contains a battery with three cells, wires, and a light bulb. Which of the following would cause the bulb to shine less brightly?


A. decrease the resistance of the circuit


B. increase the resistance of the circuit

Answers

The answer is B increase the resistance of the circuit



At a sports event, the car starts from rest. in 5.0 s its acceleration is 5.0 m/s2.
Calculate the distance travelled by car.

Answers

Answer:

62.5m

Explanation:

Given parameters:

Initial velocity  = 0m/s

Time  = 5s

Acceleration  = 5m/s²

Unknown:

Distance traveled  = ?

Solution:

To solve this problem, we use the motion equation given below:

S = ut + [tex]\frac{1}{2}[/tex] at²

S is the distance traveled

u is the initial velocity

a is the acceleration

t is the time taken

Now, insert the parameters and solve;

 S =( 0 x 5) +( [tex]\frac{1}{2}[/tex] x 5 x 5²) = 62.5m

A 1kg dictionary is resting on a table that is 1.5m high. How much potential energy
does it have?

Answers

Answer:

Potential energy = 14.7 Joules.

Explanation:

Given the following data;

Mass, m = 1kg

Height, h = 1.5m

We know that acceleration due to gravity is equal to 9.8m/s²

Potential energy can be defined as an energy possessed by an object or body due to its position.

Mathematically, potential energy is given by the formula;

[tex] P.E = mgh[/tex]

Where, P.E represents potential energy measured in Joules.

m represents the mass of an object.

g represents acceleration due to gravity measured in meters per seconds square.

h represents the height measured in meters.

[tex] P.E = mgh[/tex]

Substituting into the equation, we have;

[tex] P.E = 1*9.8*1.5[/tex]

P.E = 14.7 Joules.

The index of refraction of quartz is anisotropic. Suppose that visible light is passing from one grain to another of different crystallographic orientation and at normal incidence to the grain boundary. Calculate the reflectivity at the boundary if the indices of refraction for the two grains are 1.545 and 1.555 in the direction of light propagation. Enter your answer in accordance to the question statement

Answers

Answer:

1.04*10⁻⁵

Explanation:

light wave do showcase some behaviors whenever there is encounters with the end of the medium, some of the behaviors are - reflection, refraction, as well as diffraction. When visible light wave strikes a boundary that exist two different media, a portion of the energy will be transmitted into the new medium and some reflected.

Reflection of a light wave can be regarded as bouncing off of light wave from boundary. refraction on other hand is bending of the path of a light wave.

We were to calculate the reflectivity at the boundary,

reflectivity at the boundary can be calculated using the expression below

Reflectivity= (n₂ - n₁)² /(n₂ + n₁ ) ²

where

n₁= Indices of refraction at first grain= 1.545

n₂= Indices of refraction at second grain=

1.555

(1.555 - 1.545)² / (1.555 - 1.545)²

=(0.01)²/ (3.1)²

= 0.0001/ 9.61

= 1.04*10⁻⁵

Hence, the reflectivity at the boundary if the indices of refraction for the two grains are 1.545 and 1.555 in the direction of light propagation is 1.04*10⁻⁵

Multiply.
(2x + 4)(x - 4)

Answers

Answer:

(2x + 4)(x - 4)=2x^2-4x-16

A car is moving at 25.5 m/s when it accelerates at 1.94 m/s^2 for 2.3 s. What is the car's final speed? (Keep in mind direction and round to 2 decimals)

Answers

Answer:

29.96m/s

Explanation:

Given parameters:

Initial speed  = 25.5m/s

Acceleration  = 1.94m/s²

Time  = 2.3s

Unknown:

Final speed of the car  = ?

Solution:

To solve this problem, we are going to apply the right motion equation:

    v = u  + at

v is the final speed

u is the initial speed

a is the acceleration

t is the time taken

 Now insert the parameters and solve;

      v  = 25.5 + (1.94 x 2.3)  = 29.96m/s

A convex mirror has a focal length of -12 cm. A lightbulb with
a diameter of 6.0 cm is placed 60.0 cm in front of the mirror.
Locate the image of the lightbulb. What is its diameter?​

Answers

Answer:

PLEASE MARK AS BRAINLIEST!!

Explanation:

ANSWER IS IN THE IMG BELOW

how would you write 4.3756 in standard decimal form

Answers

It can be 5.64x10^-7
5.64x 10^8

Why did scientist struggle for thousands of years to accurately describe the solar system

Answers

Answer: C- The planets appeared to move backward in the sky occasionally.

A thin, uniform stick of mass M and length L is at rest on a flat, frictionless surface to which one end of it is pinned. A small mass m traveling at speed v collides with and attaches to the stick at a distance 2L/3 away from the end through which it is pinned to the surface. (a) Find an expression for the moment of inertia of the stick mass object after the collision. (b) Find an expression for the final angular speed of the combined object

Answers

Answer:

a)  I = ([tex]\frac{M}{3}[/tex] + [tex]\frac{4m}{9}[/tex]) L²  ,   b)     w = (\frac{27 M}{18 m} + 2)⁻¹  Lv₀

Explanation:

a) The moment of inertia is a scalar that represents the inertia in circular motion, therefore it is an additive quantity.

The moment of inertia of a rod held at one end is

         I₁ = 1/3 M L²

The moment of inertia of the mass at y = L

        I₂ = m y²

 

The total inertia method

        I = I₁ + I₂

        I = \frac{1}{3} M L² + m (\frac{2}{3} L)²

        I = ([tex]\frac{M}{3}[/tex] +[tex]\frac{4m}{9}[/tex] ) L²

   

b) The conservation of angular momentum, where the system is formed by the masses and the bar, in such a way that all the forces during the collision are internal.    

Initial instant. Before the crash  

       L₀ = I₂ w₀  

angular and linear velocity are related  

       w₀ = y v₀  

      w₀ = [tex]\frac{2}{3}[/tex]L v₀  

      L₀ = I₂ y v₀  

Final moment. After the crash  

      [tex]L_{f}[/tex] = I w

 

how angular momentum is conserved  

      L₀ = L_{f}

      I₂ y v₀ = I w

substitute

      m ([tex]\frac{2L}{3}[/tex])² (\frac{2L}{3} v₀ =  ([tex]\frac{M}{3}[/tex] +[tex]\frac{4m}{9}[/tex] ) L²  w

      [tex]\frac{6}{27}[/tex]  m L³ v₀ = ([tex]\frac{M}{3}[/tex] +[tex]\frac{4m}{9}[/tex] ) L²  w

        [tex]\frac{6}{27}[/tex]  m L v₀ = ([tex]\frac{M}{3}[/tex] +[tex]\frac{4m}{9}[/tex] )   w

        L v₀ = [tex](\frac{27 M}{18 m} + 2)[/tex]  w     

       w = (\frac{27 M}{18 m} + 2)⁻¹  Lv₀

 

A rightward force of 4.0 N is exerted upon an object for a distance of 3.0 meters.
What is the work done on the object?

Answers

Answer:

W = 12 J

Explanation:

Given that,

Force, F = 4 N

The object moves in rightward direction for a distance of 3 m.

Work done on the object is given by :

[tex]W=F\times d\\\\=4\ N\times 3\ m\\\\=12\ J[/tex]

So, the work done on the object is 12 J.

What’s the answer to this

Answers

The Cartesian product of two sets is the set of all possible ordered pairs whose first component is a member of the first set and whose second component is a member of the second set {{1.09m, 12.8s}}

Ishan is testing materials to see whether they will stick to a magnet. How can
he use his imagination in this experiment?
OA. To think of different materials to test
OB. To carefully record the results in a chart
O C. To do the test the same way each time
O D. To remember which materials are magnetic

Answers

Answer:

The Answer is A "To think of different materials to test"

Explanation:

APE X

which model best represents a pattern

Answers

Where is the options ?

Answer:

A

Explanation:

Where are you atera11

Answers

Answer:

? who is atera11?

Explanation:

What best describes the speed of light waves in solids, liquids, and gases?
The speed is fastest in solids.
The speed is fastest in liquids.
The speed is fastest in gases.
The speed is the same in all matter.

Answers

Answer: It’s fastest in gases. Letter C !

Explanation:

Answer:

its c

Explanation:

Two spheres of equal mass, A and B, are projected off the edge of a 1.0 m bench.    Sphere A has a horizontal velocity of 10 m/s and sphere B has a horizontal velocity of 5 m/s.

__ 5.    If both spheres leave the edge of the table at the same instant, sphere A will land
a.    at some time after sphere B.
b.    at the same time as sphere B.
c.    at some time before sphere B.
d.    There is not enough information to decide.

__ 6.    If both spheres leave the edge of the table at the same instant, sphere A hits the floor at the spot marked X.  Sphere B will hit the floor
a.    at some point between the edge of the table and X.
b.    at some point past X.
c.    at the same distance from the table as X.
d.    there is not enough information to decide.

Answers

Answer:

c. because A will land first becuase its heavier

and D.

Explanation:

A particle starts from rest and moves with a constant acceleration. It travels the first 16 m in 4 s.
The time (in second) at which the velocity of the particle becomes. 8. m/s is:
a) 3
b) 4
c) 5
d) 6
e) 7

Answers

Answer:

B

Explanation:

Secretariat is known as the horse with the fastest run in the Kentucky Derby. If Secretariat's record 1.25 mi run lasted 1 minute 59.2 seconds, what was his average speed in m/s

Answers

Answer:

v = 16.87 m/s

Explanation:

Given that,

Distance, d = 1.25 miles

d = 2011.68 m

Time, t = 1 minute 59.2 seconds

= 60 s + 59.2 s

= 119.2  s

We need to find the average speed of the horse. It is given by total distance covered divided by total time.

[tex]v=\dfrac{2011.68 \ m}{119.2\ s}\\\\=16.87\ m/s[/tex]

So, his average speed is 16.87 m/s.

The voltage between two points in a circuit is 3.6 V. If the resistance between
the points is 75 , what is the current, according to Ohm's law?
A. 76.6 A
B. 0.048 A
C. 20.8 A
D. 270 A

Correct answer is B!

Answers

Considering the Ohm's law, the correct answer is option B. the current is 0.048 A.

Definition of current

The flow of electricity through an object, such as a wire, is known as current (I). Its unit of measure is amps (A). So the current is a measure of the speed at which the charge passes a given reference point in a specified direction.

Definition of voltage

The driving force (electrical pressure) behind the flow of a current is known as voltage and is measured in volts (V) (voltage can also be referred to as the potential difference or electromotive force). That is, voltage is a measure of the work required to move a charge from one point to another.

Definition of resistance

Resistance (R) is the difficulty that a circuit opposes to the flow of a current and it is measured in ohms (Ω).

Ohm's law

Ohm's law establishes the relationship between current, voltage, and resistance in an electrical circuit.

This law establishes that the intensity of the current that passes through a circuit is directly proportional to the voltage of the same and inversely proportional to the resistance that it presents.

Mathematically, Ohm's law is expressed as:

[tex]I=\frac{V}{R}[/tex]

Where I is the current measured in amps (A), V the voltage measured in volts (V); and R the resistance that is measured in ohms (Ω).

This case

In this case, you know that the voltage between two points in a circuit is 3.6 V and the resistance between the points is 75 Ω.

Replacing in the Ohm's Law:

[tex]I=\frac{3.6 volts}{75 ohm}[/tex]

Solving:

I= 0.048 amps

Finally, the correct answer is option B. the current is 0.048 A.

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12) Consider two identical bricks, each of dimensions 20.0 cm x 10.0 cm x 6.0 cm. One is stacked
on the other, and the combination is then placed so that they project out over the edge of a
table. What is the maximum distance that the end of the top brick can extend beyond the table
edge without toppling?
A) 7.5 cm
B) 10 cm
C) 12.5 cm
D) 15 cm

Answers

Answer:

7.5

Explanation:

why is it difficult to lift out the bucket form well

Answers

because of gravitional pull

Using a light microscope, a student identified the following characteristics of four organisms found in a sample of pond water. Based on the observations of the student,
which organisms most likely belong to the taxonomic group for bacteria?
Pond-Water Organisms
Organism 1 Single-celled, nucleus, large vacuole
Organism 2 Single-celled, no nucleus, cell wall
Organism 3 Single-celled, no nucleus
Organism 4 Single-celled, nucleus
Organism 1 and 4
Organism 1 and 2
Organism 3 and 4
Organism 2 and 3

Answers

Answer:

Organisms 2 and 3

Explanation:

Can hurricanes produce tornadoes

Answers

Answer:

No

Explanation:

Answer:

No

Explanation:

Tornadoes are usally produced in the Midwest regions. Hurricanes are made with water, not clouds. So, no, hurricanes cannot produce tornadoes.

A 100 kg gymnast comes to a stop after tumbling. Her feet do 5,000 J of work to stop her.

Which of the following was the girl's velocity when she began to stop?

Answers

Answer:10 m/s

Explanation:

A 100 kg gymnast comes to a stop after tumbling. Her feet do 5,000 J of work to stop her. The girl's velocity when she began to stop is 10 m/sec.

What is velocity?

When an item is moving, its velocity is the rate at which its direction is changing as seen from a certain point of view and as measured by a specific unit of time. Velocity is vector quantity.

Uniform motion an object is said to have uniform motion when object cover equal distance in equal interval of time within exact fixed direction. For a body in uniform motion, the magnitude of its velocity remains constant over time. Here in the question velocity is changing by using work energy theorem we have,

work done = change in kinetic energy

5000 = (.5).m.v² , where v is velocity.

5000 = (.5).100.v²

v = 10 m/sec

A 100 kg gymnast comes to a stop after tumbling. Her feet do 5,000 J of work to stop her. The girl's velocity when she began to stop is 10 m/sec.

To learn more about velocity refer the link:

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#SPJ6

Which of the following examples best represents an object with balanced forces acting upon it?

A - A boat accelerating through the water.
B - A book sitting at rest on a high shelf.
C- A wagon rolling down a steep hill.
D- A baseball thrown into the air.

Answers

D-a is the answer can I get braillist

Answer:the answer is “A book sitting on a high shelf” :)

Explanation:

A storm front moves in and Rachel and Pam notice the column of mercury in the barometer rises only to 736 mm. Assume the density of mercury is 13, 000 kg/m 3
(a) What is the change in air pressure?
(b) What if their barometer was filled with water instead of mercury, how high does the column rise? Density of water = 1000 kg/m

Answers

Answer:

a

 [tex]\Delta P = 7558.6 \ Pa[/tex]

b

 [tex]h_1 = 10 \ m[/tex]

Explanation:

From the question we are told that

   The position of the column of mercury in the barometer is  [tex]h = 736 \ mm = 0.76 \ m[/tex]\

   The density of mercury is  [tex]\rho = 13,000 \ kg / m^3[/tex]

Generally the  pressure of the atmosphere at that column is mathematically represented as  

         [tex]P = \rho * g * h[/tex]

=>      [tex]P =13 000 * 9.8 * 0.736[/tex]

=>      [tex]P = 93766.4 \ Pa[/tex]

Generally the atmospheric pressure at sea level (Generally the pressure before the change in level of the mercury column)  is  [tex]P_a = 101325 \ Pa[/tex]

Generally the change in air pressure  is mathematically represented as

      [tex]\Delta P = P_a - P[/tex]

=>   [tex]\Delta P = 101325 - 93766.4[/tex]

=>   [tex]\Delta P = 7558.6 \ Pa[/tex]

Generally the height which the column will rise to is mathematically evaluated as  

         [tex]h_1 = \frac{P}{ \rho_w * g }[/tex]

Here [tex]\rho_w[/tex] is the density of water with value  [tex]\rho_w = 1000 \ kg/m^3[/tex]

So

       [tex]h_1 = \frac{ 93766.4}{ 1000 * 9.8 }[/tex]

=>   [tex]h_1 = 10 \ m[/tex]

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