The independent variables of measuring physical properties are given below -
What is physical properties?
A physical properties in any property that is measurable, whose value describe a state of physical system.
The changes in the physical properties of a system can be used to describe its changes between the momentary that state of
Physical properties are often referred to as observables.
They are not modal properties.
Any variable that can be attributed a value without attributes a value to any to any other variables is called independent variables.
It is a variable that stands alone and isn't changed by other variables you are trying to measure.
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A driver is going 25 m/s down the road when they spot a deer jump out in front of them. It takes them 0.75 seconds to react and apply the brakes. The brakes provide an acceleration of -8 m/s/s. How far do they travel before coming to a stop from the moment they saw the deer? (round your answer to the nearest whole meter)
16.5 m distance they travel before coming to a stop from the moment they saw the deer.
velocity=25 m/s
time=0.75 sec
acceleration= -8 m/s²
s=vt+at²/2
s=25×0.75-8×0.75×0.75÷2
s=18.75-2.25
s=16.5 m
Distance is the length between two locations or things, independent of direction. Since distance is a scalar property, it only takes into consideration the total magnitude and ignores the start and finish positions. Since distance is a scalar attribute, it can only have a positive or zero value; it cannot have a negative value.
The most common unit of measurement for distance is the meter (m), while larger distances can also be stated in kilometers (km), while smaller distances can be expressed in centimeters (cm) or millimeters (mm). When calculating distance, the letter D is often used to represent the distance traveled.
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can someone help me scale this into a smaller one in cm?
The resultant displacement of the bullet is 1,418.6 m.
What is the resultant displacement of the bullet?
The resultant displacement of the bullet is the total displacement of the bullet obtained by resolving the displacement into x and y component.
the horizontal component of the displacement (x) = d cosθ
the vertical component of the displacement (y) = d sinθ
where;
d is the displacementθ is the directionFor the first displacement;
x = 850 m x cos(0) = 850 m
y = 850 m x sin(0) = 0
For the second displacement;
x = 640 m x cos(36) = 517.8 m
y = 640 m x sin(36) = 376.2 m
Net horizontal and vertical displacement;
∑x = 850 m + 517.8 m = 1,367.8 m
∑y = 376.2 m + 0 = 376.2 m
The resultant displacement of the bullet is calculated as;
d = √(∑x² + ∑y²)
d = √(1,367.8² + 376.2²)
d = 1,418.6 m
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Derive an expression for the mass ms of the star in terms of b, t, and g the universal gravitational constant.
The change in gravitational potential energy stored in 16 Jule.
What is gravitational potential energy?
gravitational potential energy
In classical mechanics, of the gravitational potential at in a location is equal to the work per unit mass that's would be needed to Move an object to that locations from a fixed references location. It is analogous to the electric potential with the mass playing the role of charge.
Sol-As per the given question ∆PE = mgh
M= skg
g= 4m/s^2
∆h = 2m
∆PE = 2m×4m×2m
= 16 Joules.
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What is the impulse on a 5 kg mass that is moving from rest to a velocity of 5 m/s?.
The impulse on the object with a mass of 5 kg and a velocity of 5 m/s is 25 kg m/s. The result is obtained by using the Impulse-Momentum Theorem.
What is Impulse-Momentum Theorem?The Impulse-Momentum Theorem states that impulse of an object equals to the change of the momentum. It can be expressed as
I = Δp
I = mΔv
Where
I = Impuls (Ns or kg m/s)Δp = change of momentum (Ns or kg m/s)m = mass of an object (kg)Δv = change of velocity (m/s)If an object has a mass of 5 kg and moves from rest to a velocity of 5 m/s, what is the impulse?
Since the object moves from rest, the initial velocity of the object is 0.
The impulse is
I = mΔv
I = 5 kg × (5 m/s - 0)
I = 5 kg × 5 m/s
I = 25 kg m/s
Hence, the impulse on the moving object is 25 kg m/s.
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a cyclotron with dee radius 48.0 cm is operated at an oscillator frequency of 13.0 mhz to accelerate protons. what is the kinetic energy of a proton emerging from the cyclotron?
The size of the field needed to create resonance is
= [tex]2\pi fmp/q[/tex]
= [tex]2\pi (12.0X10[/tex]⁶)([tex]1.67X10[/tex]⁻²⁷kg)
= 0.787T.
What is Kinetic energy?
A particle or an item that is in motion has a sort of energy called kinetic energy. When work, which entails the transmission of energy, is done on an object by applying a net force, that object acquires kinetic energy.
Therefore, the Kinetic energy is given by
K = 1/2 mv²
= 1/2m[tex](2\pi Rf)[/tex]²
= 1/2[tex](1.67X10[/tex]⁻²⁷kg)4[tex]\pi[/tex]²(0.530m)²(12.0X10⁶Hz)²
= 1.33X10⁻12J
= 8.34X10⁶eV.
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the frequency of the fundamental of the guitar string is 320 hz . at what speed v do waves move along that string? express your answer in meters per second.
The Speed of waves is 640L.
Given
The frequency of string is 320 Hz.
To find at what speed v do waves move along that string , we can use following equation-
[tex]f=\frac{V}{2L}[/tex]
Frequency means reciprocal of time period , i.e. a parameter that decides quality factor of sound / harmonics.
f , V , L represents frequency , speed and length of string.
[tex]V=2Lf[/tex]
V= 2L(320)
V= 640L
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what is a mass of 400ml of liquid that has a density of 4g/ml
if highest high tide occurs at 2pm on day 1, at what time of day will the next highest high tide occur?
The height between high tide and low tide is referred to as the tidal range. tides are the peaks and valleys in sea levels brought on by the gravitational pull of the Moon, Sun, and Earth's rotation.
Tidal range is influenced by time and place. When the gravitational pulls of the Moon and Sun are in harmony, spring tides (spring range) occur, which have a larger tidal range. 0.6 metres (2 feet) is the average tidal range in the open ocean (blue and green on the map on the right). This range increases significantly closer to the coast at gravitational, there are several different coastal tidal ranges that range from almost zero to over 16 metres (52 ft).
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a swimming pool of width 9.0 m and length 12.0 m is filled with water to a depth of 3.0 m. calculate pressure on the bottom of the pool due to the wate
The pressure on the bottom of the pool due to the water is 22540pa.
What is density?
A substance's density determines how closely it can be packed. The definition of it is the mass per unit volume. The formula for density is D = m/V, where D stands for density, m for mass, and V for volume, which stand in for the object's mass and volume, respectively.
What is volume?
Volume is simply the quantity of space that a three-dimensional solid occupies. One of these solids can be a cube, a cuboid, a cone, a cylinder, or a sphere.
volume of water : 10*8*2.3m³
mass of water = density of water*volume
1000 kg/ m³* 1.84 m³
184000 kg
force extracted by water on the bottom surface = mass of water xg
=184000 kg * 9.8m/s²
=1803200N
pressure : force / area
1803200N/80m²
=22540Pa
Therefore, pressure on the bottom of the pool due to the water is 22540pa.
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Based on the excerpt, which type of government is the city of springfield using?.
The type of government the city of Springfield using is council Management system.
The council management government is a form of local government used for municipalities, counties, or other equivalent regions.
The basic structural feature of council- manager structure include a city or town council elected by the voters to exercise overall control of the local government and a chief executive- the city/town manager- appointed by and is totally responsible to the council.
The elected city council members represent their community and develop a long range visions for its future. They establish policies that affects the overall operations of the community and are responsive to residents needs and wishes.
it most resembles the structure of the federal government
The city benefits from the council management form of government in many ways like -
1. The manager carries out the policies which is established by the elected governing body.
2. Here the decisions on policy and the future of the community are made by the entire governing body rather than a single individual
3. The manager carries out the policies established by the elected governing body with an emphasis on effective, efficient and equitable service.
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does it take more energy to go fast or go high? an 80 metric-ton airplane is flying with speed 200 m/s at a height of 11 km. the energy from the ground up to this height was provided by fuel. find the airplane: kinetic energy in gj. gravitational potential energy in gj (ground as zero).
The kinetic energy flying with a speed 200 m/s is gJ is 16gJ.
The gravitational potential energy of an object is directly proportional to its height above the zero position.
Since the gravitational potential energy of an object is directly proportional to its height above the zero position, a doubling of the height will result in a doubling of the gravitational capacity electricity. A tripling of the height will bring about a tripling of the gravitational ability electricity.
Calculation:-
mass = 80 metric ton = 8000 kg
Kinetic energy = 1/2mv²
= 1/2 × 8000 × 200²
= 4000 × 200 × 200
= 160000000 J
Opposite to potential energy, the kinetic energy of an object is relative to different stationary and shifting items found in its immediately environment. as an instance, the kinetic energy of the item may be better if the object is located at a more height.
If the tennis ball is dropped from a bigger height, the share of potential energy misplaced may be greater because the ball will fall a for a longer quantity of time, which means it will lose extra electricity via air friction and from the bigger effect of the ground.
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Disclaimer:- your question is incomplete, please see below for the complete question.
does it take more energy to go fast or go high? an 80 metric-ton airplane is flying with speed 200 m/s at a height of 11 km. the energy from the ground up to this height was provided by fuel. find the airplane: kinetic energy in gj. gravitational potential energy in gj (ground as zero).
A.True
B. False
2. As a shot putter in track, you want to throw as far as you can. You as the coach give your
best advice based on the Physics you learned. Give 2 suggestions to help your student and
explain why?
Answer:
Below
Explanation:
Throw it faster and closer to 45° to get the furthest horizontal distance
suppose a ray of light traveling in a material with an index of refraction na reaches an interface with a material having an index of refraction nb. which of the following statements must be true for total internal reflection to occur? check all that apply. suppose a ray of light traveling in a material with an index of refraction na reaches an interface with a material having an index of refraction nb. which of the following statements must be true for total internal reflection to occur?check all that apply. the angle of incidence must be less than the critical angle. na > nb the angle of incidence must be greater than the critical angle. the angle of incidence must be equal to the critical angle. na
The statement na>nb must be true for total internal reflection to occur.
Total internal reflection is known to occur when a light beam prefers to move from a denser to a rarer medium.
The refractive index of a denser medium is higher than that of a rarer one. This indicates that the medium's refractive index is higher than the medium in the particular situation.
This implies that the incident angle must be bigger than the medium's critical angle.
Total internal reflection is the complete reflection of a light ray from the surrounding surfaces back into a medium, such as glass or water, in physics. If the incidence angle exceeds a specific limitation angle known as the critical angle, the phenomenon will manifest.
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While spinning down from 500. 0 rpm to rest, a solid uniform flywheel does 5. 1 kj of work. If the radius of the disk is 1. 2 m, what is its mass?.
While spinning down from 500. 0 rpm to rest, a solid uniform flywheel does 5. 1 kJ of work. If the radius of the disk is 1. 2 m, its mass will be 28.33 kg
Work done = change in kinetic energy
kinetic energy = 1/2 * I * [tex]omega^{2}[/tex]
since , moment of inertia of disk = m[tex]r^{2}[/tex] / 2
kinetic energy = 1/2 * m[tex]r^{2}[/tex] / 2 * [tex]omega^{2}[/tex]
5100 = 1/4 * m * [tex]1.2^{2}[/tex] * 500
mass = 28.33 kg
If the radius of the disk is 1. 2 m, its mass will be 28.33 kg
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A 100 g ball and a 200 g ball are connected by a 30 cm long massless rigid rod. The balls rotate about their center of mass at 120 rpm. What is the speed of the 100 g ball?.
The speed of the 100 g ball if the 100 g ball and a 200 g ball are connected by a 30 cm long massless rigid rod and if the balls rotate about their center of mass at 120 rpm is 2.5 m / s
Xcm = m1 r1 + m2 r2 / ( m1 + m2 )
Xcm = Center of mass
m1 = Mass 1
m2 = Mass 2
m1 = 100 g
m2 = 200 g
The center of mass of the two balls measured from the 100 g ball,
Xcm = [ ( 100 * 0 ) + ( 200 * 30 ) ] / ( 100 + 200 )
Xcm = 6000 / 300
Xcm = 20 cm
v1 = r ω
v1 = Speed of m1
r = Distance about which the balls rotate
ω = Angular velocity
r = 20 cm = 0.2 m
ω = 120 rpm
ω = 120 * 2 π / 60
ω = 12.56 rad / s
v1 = 0.2 * 12.56
v1 = 2.5 m / s
Therefore, the speed of the 100 g ball is 2.5 m / s
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When a pole vaulter reaches the top of her vault, how does her potential energy compare to her kinetic energy?.
Kinetic energy is twice the potential energy.
What type of energy is used in pole vaulting?A pole vaulter has kinetic energy when running forward. When a pole vaulter lowers the pole and jumps, it slows down and bends the pole. Their kinetic energy is transformed into polar elastic potential energy. When the pole is raised, the pole vaulter is lifted higher. After the start, the athlete and pole rotate around his starting box, converting some of the athlete's kinetic energy into gravitational potential energy. Also, during the jump, the momentum of the athlete causes the pole to flex, temporarily storing elastic stretch energy in the pole.
Mechanical energy depends on the position and motion of an object, and its force is the sum of kinetic energy (kinetic energy) and stored (potential) energy. That is, mechanical energy is produced when the potential energy of an object combines with its kinetic energy.
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a 70 kg astronaut floating in space in a 110 kg mmu (manned maneuvering unit) experiences an acceleration of 0.029 m/s2 when he fires one of the mmu's thrusters. for related problemsolving tips and strategies, you may want to view a video tutor solution of
5.22N is the thrust of the thruster.
How much thrust does the rocket have?The thrust is the force that propels the rocket through the atmosphere and into space. Newton's third law of motion, which states that every action has an equal and opposite reaction, is used to generate thrust by the rocket's propulsion system.
[tex]m_{A}[/tex] = 70kg
M = 110kg
a = 0.029m/s²
[tex]V_{N_{2} }[/tex] = 490m/s
The gas (mass)[tex]d_{m}[/tex] ejected by the thruster and the thrust can now be calculated using the two equations below F:
a = - [tex]V_{N_{2} }[/tex]/m dm/dt (1)
F = - [tex]V_{N_{2} }[/tex] dm/dt (2)
Where,
m = [tex]m_{A}[/tex] +M
m = 70+110
m = 180kg
The entire mass of the astronaut-MMU system is 180 kg.
[tex]d_{m}[/tex] is the fuel's ejected mass
dt =5sec is the window of time during which this occurs
Since the mass of the fuel is so small in relation to the total mass, we must separate from (1) here and assume it to be constant:
dm = -ma/[tex]V_{N_{2} }[/tex] dt
dm = - (180)(0.029)/490 ×5
dm = -0.053kg
The reason for the negative sign is that the ejected mass is moving in the opposite direction from where the astronaut-MMU system is moving. The value of is 0.053 kg, though.
Use equation (2) and the results from the calculation in
F = -490× -0.0593/5
F = 5.22N.
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uniform electric fields: two very large parallel metal plates, separated by 0.20 m, are connected across a 12-v source of potential. an electron is released from rest at a location 0.10 m from the negative plate. when the electron arrives at a distance 0.050 m from the positive plate, how much kinetic energy has the electron gained?
The kinetic energy gained by the electron if it is released from rest at a location 0.10 m from the negative plate and arrives at a distance 0.050 m from the positive plate is 2.4 * [tex]10^{-19}[/tex] J
E = Q / 2 εo A
F = q E
E = Electric field inside a parallel plate capacitor
Q = Charge on capacitor
A = Area of one of the plates
F = Electric force on electron
q = Charge of electron
F = q Q / 2 εo A
C = εo A / d = Q / V
C = Capacitance
d = Distance between plates
V = Voltage
V = 12 V
d = 0.2 m
Q / εo A = V / d
Q / εo A = 12 / 0.2
Q / εo A = 60
F = q Q / 2 εo A
F = q * 60 / 2
F = 30 q
ΔKE = F x
q = 1.6 * [tex]10^{-19}[/tex] C
ΔKE = 30 * 1.6 * [tex]10^{-19}[/tex] * 0.05
ΔKE = 2.4 * [tex]10^{-19}[/tex] J
Therefore, the kinetic energy gained by the electron is 2.4 * [tex]10^{-19}[/tex] J
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a 160 turn coil has an area of 3 cm2 and rotates in a magnetic field of 0.5 t. (a) what frequency will generate a maximum emf of 10 v?
If we rearrange the circuit so that the inductor and capacitor were connected in series,the impedance would be Decreased and the resonant frequency would be unchanged.
What is frequency?
Frequency is the rate at which something occurs over a particular period of time or in a given sample.
Sol-An LC circuit is made up of an inductor (L) and a capacitor (C). At the resonance condition of the LC circuit, the inductive reactance XL. becomes equal to the capacitive reactance Xc.
It is defined as-
XL= 2πfL
Xc= 1/2πfC
So when reactance are equal we have-
XL=Xc
2πfL= 1/2πfC
f^2=1/4π^2LC
f=1/2π√LC
The resonance condition is the same for both the parallel and series LC circuit, so the resonance frequency will not change.
The impedance of a parallel LC circuit is:
Z(w)= jL w^2-w^2•/w
In a series LC circuit, when w
, the impedance becomes equal to 0.
Therefore the impedance of a series LC circuit will decrease and the resonant frequency will remain the same.
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use the clausius-clapeyron equation to answer the following questions: 1) derive the relationship of pressure and temperature for a system consists of vapor and condensed (liquid or solid) phases, clearly state each of your assumptions.
On Clausius-Clayperon equation, the relationship between pressure and temperature for a system consists of vapor and condensed is the higher the pressure will required higher temperature on equilibrium.
Clausius-Clayperon have several assumptions for the equation to predict the actual condition of the system:
1. Saturated vapor is an ideal gas
2. Molar volume of the saturated vapor is much greater than the molar volume of the saturated liquid.
3. The heat of vaporization is constant over the temperature range of interest.
The equation of Clausius-Clayperon stated as:
[tex]LnP^{*}\\[/tex]=[tex](-\frac{dH_{vap} }{R})[/tex] [tex]\frac{1}{T}+C[/tex]
Based on the equation, we can conclude the temperature will be higher if the saturated pressure increased.
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problem 7-16 determine the internal normal force, shear force, and moment at points c and d of the beam. given: w1
The internal Normal force is equal to
The internal Shear force is equal to
Moments at points between C and D is
Internal Normal force :
The normal force at any section of a structure is defined as the algebraic sum of the axial forces acting on either side of the section.
Shear force:
The shearing force (SF) is defined as the algebraic sum of all the transverse forces acting on either side of the section of a beam.
Bending moment
The bending moment (BM) is defined as the algebraic sum of all the forces’ moments acting on either side of the section of a beam.
let Ax and Ay be horizontal and vertical component of A .
we have given that W₁ = 200 N/m × 6 m = 1200 N
and W₂ = 1/2 × 200 N/m× 6m = 600 N ( for triangle)
the distance between B and W₂ (x₂) = 1/3×6 = 2m
the distance between B and C (x₁) = 1/2×6 = 3m
Forces act in horizontal direction (Fₓ) ,
summation Fₓ = 0 = > Aₓ= 0
now, for vertical direction as Ay act upward and W1 and W2 acting downward direction.
summation M = 0
=> - Ay × 6 + W₁× 3 + W₂× 2 = 0
=>- 6Ay + 3600 N-m + 1200 N-m = 0
=> -Ay× 6 = - 4800 => Ay = 800 Nm
As we know total sum of force acting free body
= 0
=> Aₓ + N꜀ = 0 where N꜀ is normal force on C
but Ax= 0 so, Nc = 0
for Shear forces , Summation Fy = 0
=> Ay - W₁ - W₂ - V꜀ = 0 , where V꜀ is shear force
V꜀ = 800 - 200× 3 - 200 × 3/2 = -100 N
sum of moments Mc = 0
=> M꜀ - Ay ×3 - W1 × 3/2 - W2×1/3 ×3 = 0
=> M꜀ - 2400 - 1200× 3/2 - 600 × 1 = 0
=> M꜀ = 4.8 kNm
Hence , Internal Normal force is zero
shear force is 100 N and moment of force between C and D is 4.8 kNm.
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Please help me out with these questions! Really need help Thanks!!
2.a) The two reason of using isotope of gamma radiation over isotope of alpha radiation is:
Gamma radiation is neutral in nature where alpha radiation is positive in charge. So, charges of alpha radiation can harm human organs.Penetrating power of alpha ray is less than gamma ray. So, alpha ray may reflect inside the body and cause harm.b) i) According to the graph, the radioactive isotope remains inside left kidney for a long time period and it comes out from right kidney after some time.
ii) Only right kidney works properly because in left kidney the radioactive material remains for a long time which is not natural.
c) i) half life time of a radioactive material is a time in what the material decays into half.
ii) Short half life means the radioactivity of the material remains for short time which is less harmful for patient. So, doctor use it.
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the distance between two consecutive nodes of a standing wave is 24.5 cm. the hand generating the pulses moves up and down through a complete cycle 3.91 times every 8.76 s. find the velocity of the wave. answer in units of m/s. 014 10.0 po
The minimum distance in which car will stop is 256m.
What is distance?
distance is the length of the space between two points.
Distance is a numerical or its the occasionally qualitative measurement of how to far apart objects or points .
Sol-here we can apply Newton’s second law to the car of to determine of the maximum static friction to the force acting on the car:
€Fy=ma^y+ n-mg=0
Fs≤us mg
This maximum magnitude of static friction acts so long as the tires roll without skidding.
€Fx=ma^x-----> -fs=ma
The maximum acceleration is
a=-u^s g
The initial and final conditions are- xi=0, vi=50.0mi/h =22.4 m/s and vf =0.Then,
v^2=v^2+2a(xf-xi)---->v^2
f i I
Xf=(22.4m/s)^2/2(0.100)(9.80m/s^2)=256
Thus through the minimum distance in which car will stop is 256m.
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The recurrence interval is equal to (N + 1)/M where N is the number of years of flood records and M is _______________________.
Group of answer choices
the numerical rank of each year’s maximum flood discharge
minimum amount of discharge needed to produce a flood
mass of water moved in each year’s maximum flood
the absolute value of the slope of the falling limb on the hydrograph of a 50-year flood
The recurrence interval is equal to (N + 1)/M where N is the number of years of flood records and M is the numerical rank of each year’s maximum flood discharge.
Thus, the correct answer is A.
How to calculate the recurrence interval?In eаch of the two аrrаys, the аnnuаl series аnd the pаrtiаl-durаtion series, the tаbulаted floods were numbered in order of their mаgnitude, beginning with the biggest. The recurrence intervаl of eаch flood wаs then computed by the formulа T = (N + 1)/M for determining plotting position, in which T is the recurrence intervаl in yeаrs, M is the relаtive mаgnitude of the flood, аnd N is the totаl number of yeаrs. This formulа is bаsed on the premise that for any number of item (N) in аn аnnuаl series there аre N + 1 intervаls into which аny subsequent flood will fаll.
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a drag racer starts her car from rest and accelerates at 6.8 m/s 2 for the entire distance of 340 m. how long did it take the car to travel this distance? answer in units of s
Since the car is at rest, its starting speed is 0 m/s, its acceleration is 6.8 m/s2, and the distance the car must travel is 340 m. t =100s
How fast are they moving initially and ultimately?An object's initial velocity is the rate at which gravity exerts its first force on it. However, the final mass and velocity quantity that gauges the speed and direction of a moving object after it has reached the maximum level acceleration.
Is there a constant initial speed?The starting velocity of an automobile is zero while it is at rest. Its initial velocity would be greater than zero if a projectile is thrown into the area. The starting velocity will be greater than zero but will become zero if a car stops after pressing the brakes.
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A baseball player hits a ball straight up into the air. It leaves the bat with a speed of 120 km/h. In the absence of air resistance, how fast would the ball be traveling when the catcher catches it?
The speed of ball when the catcher catches it is 120km/h.
Speed is the rate of change of displacement with respect to time.
In this case, if the acceleration is constant, use the third equation of motion to determine the initial and final velocities.
The third equation of motion is
v² - u² = 2gS
where v---> final velocity
u---> initial velocity
g---> gravitational acceleration
S---> height
Given Data:
Initial Velocity of the Ball (u) = 120 km/h
Initially the ball is moving up, so the acceleration of the ball is g = - 9.81 m/s²
The final velocity of the ball is v = 0 m/s
The height of the ball above the ground can be calculated by using above formula
0 - (120×5/18 m/s)^2 = 2× (-9.81 m /s²) × S
=> S = 56.7 m
When the ball is above the hit point, the initial velocity of the ball at this point is u = 0 m/s.
Using above relation we can calculate the final velocity,
56.7 × 2 × (9.81) = v²-0 = v²
=> v² = 1112.45 m/ s => v= 33.45 m/ s
or v = 120 km/h.
Therefore the velocity of the ball when caught by the catcher is 120 km/h.
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claire is investigating potential and kinetic energy using a large ball. for her investigation, claire will stand at the top of a hill and push the ball down the hill. the picture shows claire's investigation. how will the ball's potential and kinetic energy change as it rolls down the hill? responses the ball's potential energy will increase, and its kinetic energy will decrease. the ball's potential energy will increase, and its kinetic energy will decrease. the ball's potential and kinetic energy will both decrease. the ball's potential and kinetic energy will both decrease. the ball's potential and kinetic energy will both increase. the ball's potential and kinetic energy will both increase. the ball's potential energy will decrease, and its kinetic energy will increase. the ball's potential energy will decrease, and its kinetic energy will increase.
As the ball is pushed from the top of hill, its potential energy will decrease and Kinetic energy will increase.
The ball is pushed from height, it starts moving/rolling and it gains some velocity, so it would definitely gain some Kinetic energy as
K.E. = [tex]\frac{mv^{2} }{2}[/tex]
The ball was initially at some height so it had some Potential Energy which is given as
P.E. = mgh
Where m is mass, h is height and g is the acceleration due to gravity.
So according to Law of Conservation of Energy, the potential energy will decrease as the kinetic energy starts increasing due to the gained velocity.
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Answer:
the answer is D
Explanation:
D
what are the main drivers of deep ocean currents? question 2 options: fluctuations of wind speed and precipitation the gravitational influences of the moon changes in viscosity of ocean water variations of temperature, salinity, and density
Deepwater currents are produced by upwelling currents that surface wind-driven currents produce in conjunction with landforms.
Thermohaline circulation is a phenomenon that can create currents by altering the density of water masses as a result of changes in temperature and salinity. The wind, tides, Coriolis effect, sun, solar energy, and changes in water density all contribute to the ocean's complex current or circulation system. Variations in temperature and salinity are the root causes of these discrepancies. As ocean water evaporates, salt is left behind, increasing the salt concentration in the ocean, making oceans much saltier than river water. a flow of ocean water in one direction; surface currents are caused by constant winds over the ocean's surface; deep currents are caused by density changes brought on by variations in temperature and salinity.
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If the internal energy of a thermodynamic system is increased by 300. J while 75 j of expansion work is done, how much heat was transferred and in which direction, to or from the system?.
U = q+w
According to this, internal energy is the result of adding work and heat. You can tell that the system is losing 75 joules of work because as you push against your surroundings to perform expansion work, you are using up energy.
You can now connect those in and find a heat solution. The indicator on your heat indicates which way the flow was.
Positive indicates that internal energy increased, which caused heat to be sent to the system; negative indicates that internal energy decreased, which, if true, caused energy to leave the system by way of heat.
Now, 300 = q-75
The terms exothermic and endothermic simply signify whether or not heat is entering or exiting the system. In this scenario, which is positive, we can thus conclude that it is endothermic because it absorbed heat.
what in exothermic?
When energy is released as heat or light, the reaction is said to be exothermic. An exothermic reaction releases energy into the environment as opposed to an endothermic process, which absorbs energy from its surroundings.
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+375 J was transferred in exothermic and in which direction, to or from the system.
What in exothermic?
Exothermic reactions are those in which energy is discharged as heat or light. An exothermic reaction releases energy into the environment as opposed to an endothermic process, which absorbs energy from its surroundings.
According to first law of thermodynamics,
dE = Q – W
Where
Q = amont of heat = ?
dE = change in internal energy = +300 J
W = work done = +75 J Since work is done by the system
Plug the values we get
Q = dE + W
= +300 J + 75 J
= +375 J
Since Q is +ve so heat is transferred from the system
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3 problems Mark Watney Face In The Martian and how he solved?
Answer:The first major problem Watney faces is getting stranded and wounded on Mars. The second problem Watney faces is how he is going to survive on mars till help can come. The final problem he faces is how is he going to get to the Ares, so he can leave Mars.
Explanation: I'm not too sure if this was what u were talking about but hope it helps!