A stone sphere of radius 7.00 m rests in a flat field. Relative to the ground, what is the gravitational potential energy of a 90.0-kg person sitting on the very top of the sphere?
a. 7.76 x 104 J
b. 1.23 x 104 J
c. 3.88 x 104 J

Answer:

It is Newton's first law of motion also referred  to as the law of inertia.

Explanation:

Answer:

When elements bond together or when bonds of compounds are broken and form a new substance

Explanation:

Answer:

Concave Lens Uses. Telescope and Binoculars Spectacles Lasers Cameras FlashlightsPeepholes. ...

Used in telescope and binoculars. ...

Concave lens used in glasses. ...

Uses of concave lens in lasers. ...

Use of concave lens in cameras. ...

Used in flashlights. ...

Concave lens used in peepholes.

Answer:

1. acceleration due to gravity

2. =$B$2-9.8*C2

3. the total energy stays the same over time

4. the total energy of the object will decrease

5. the initial potential energy will increase

Explanation:

Answer:

The person below or above me is correct use this answer.

Explanation:

Answer:

wave is in the y-direction, the wave is traveling in the

Explanation:

Answer:

1) f= 8.6 GHz

2) t= 0.2 ms

Explanation:

1)

        [tex]v = \lambda * f (1)[/tex]

       [tex]f =\frac{c}{\lambda} =\frac{3e8m/s}{0.035m} = 8.57e9 Hz (2)[/tex]

⇒     f = 8.6 Ghz (with two significative figures)

2)

       [tex]v =\frac{d}{t} (3)[/tex]

       where v= c= speed of light in vacuum = 3*10⁸ m/s

       d= distance between mountaintops = 52 km = 52*10³ m

       [tex]t = \frac{d}{c} = \frac{52e3m}{3e8m/s} = 17.3e-5 sec = 0.173e-3 sec = 0.173 ms (4)[/tex]

       ⇒  t = 0.2 ms (with two significative figures)

Answer:

when u learn something new it goes to ur short term memory

Assuming both forces act horizontally, the net force is in Kathryn's direction with a magnitude of 5 N.

If "towards Kathryn" is taken the be the positive direction, then the net force is

∑ F = 20 N - 15 N = 5 N

Answer:

A. heat is released from the ocean and land causing wind.

Answer: 0.6cm

Explanation:

Strain is defined as  how much an object can be stretched or deformed  when force is applied to it .  it measures the  fractional change of the object’s length when the object faces  tensional stress. It is calculated  by using the formulae

Strain =  ΔL/ L

where strain = 6%

L= Original length

ΔL= change in length

 6% = ΔL/ 10 cm

ΔL= 10cm X 0.06

ΔL=0.6cm

Answer:

∝ = 28.92 rad/s²

Explanation:

Applying third equation of motion to the angular motion, we have:

2∝θ = ωf² - ωi²

where,

∝ = angular acceleration = ?

θ = angular displacement = (27 rev)(2π rad/1 rev) = 169.64 rad/s

ωf = final angular velocity = 99 rad/s

ωi = initial angular velocity = 0 rad/s

Therefore,

(2)∝(169.64 rad) = (99 rad/s)² - (0 rad/s²)

∝ = (9801 rad²/s²)/(38.8 rad)

∝ = 28.92 rad/s²

Answer:

mass and volume

Explanation:

matter is anything that has mass and occupies space(volume)

Answer:

Four states of matter are observable in everyday life: solid, liquid, gas, and sometimes plasma.

Shape is a characteristic property of matter.

The amount of matter in an object doesn't really affect the characteristic properties of the object

Explanation:

Answer:

velocity = 44.98 m/s

Explanation:

given data

velocity = 45.0 m/s

angle = 30.0 degrees

solution

first we get here time that is

time = 2u × sin θ ÷ g   .............1

time = 2×45 × sin 30 ÷ 9.8

time = 4.59 sec

and

velocity = [tex]\sqrt{vx^2+vy^2}[/tex]   .....................2

here

vx = 45 cos30 = 38.97 m/s

vy = uy - gt

vy = 45 sin30 - 9.8 ×  4.59  = -22.48 m/s

so velocity will be

velocity = [tex]\sqrt{38.97^2+22.48^2}[/tex]

velocity = 44.98 m/s

Answer:240 meters

Explanation:60×4

It would be

O A) It is a eukaryotic cell.

Answer:

B. During condensation, the heavier elements tended to sink nearer the Sun and, being rare, only provided enough material to build the relatively small terrestrial planets.

D. During the collapse of the gaseous nebula, most of the material tended to collect far from the Sun because of the large centrifugal forces, which provided the necessary material to build the large Jovian planets.

Explanation:

The solar nebular hypothesis is the theory of how the earth came to be as proposed and believed by most scientists. It states that the solar system was formed from a nebular which is a large collection of dust. As the condensation of the nebular progressed, the heavier materials which could withstand higher temperatures formed closer to the sun. Because these materials were not so much the planets formed by them were not large in size.

However, the Jovian planets formed beyond the frost line which could sustain icy compounds. The ices that formed these planets were much thus accounting for their larger sizes. Solar winds blew off the lighter hydrogen and helium elements leading to their accumulation far away from the sun.

Answer:

D) 763 nm

Explanation:

Calculation for the wavelength of light

Using this formula

Wavelength of light=Delta Y*Distance / Length

Where,

Delta Y represent the 2nd order bright fringe

Length represent the distance between both the slits and the screen

Distance represent the Distance between the slits

Let note that cm to m = (4.2) x 10^-2 and mm to m= ( 0.0400x 10^-3)

Now Let plug in the formula

Wavelength of light=[(4.2 x 10^-2m)(0.0400 x 10^-3m) / 2(1.1m)]*10^-7 meters

Wavelength of light=[(0.042m) (0.0004m)/2.2m]*10^-7 meters

Wavelength of light =(0.0000168m/2.2m)*10^-7 meters

Wavelength of light =7.63 *10^-7 meters

Wavelength of light =763 nm

Therefore the Wavelength of light will be 763 nm

Answer:

S = 40.8m

Explanation:

Given the following data;

Initial velocity, u = 2m/s

Acceleration, a = 1.6m/s²

Time, t = 6secs

Required to find the displacement

Displacement, S = ?

The displacement of an object is given by the second equation of motion;

[tex] S = ut + \frac {1}{2}at^{2}[/tex]

Where;

Substituting into the equation, we have;

[tex] S = 2*6 + \frac {1}{2}*(1.6)*6^{2}[/tex]

[tex] S = 12 + 0.8*36[/tex]

[tex] S = 12 + 28.8 [/tex]

S = 40.8m

Therefore, the displacement of the skateboarder during this game is 40.8 meters.

Answer:

a = 2m/s^2

Explanation:

Force (F) = 100 N

Mass (m) = 50 kg

Here,

F = m×a

100 = 50 × a

a = 100÷50

a = 2m/s^2

Thus, the acceleration on the cart is a = 2m/s^2

-TheUnknownScientist

Answer:

i think its 2.5 as well

Explanation:

Answer:

Earth would suddenly warm up because more heat from the Sun would be allowed to enter the atmosphere.

Explanation:

The greenhouse gasses would make the ozone layer thinner letting in more harmful rays on the sun.

Hope this helps!! :)

Also I need one more brainliest if you dont mind giving it to me :)

Answer:

Earth would cool down because it would reflect more solar radiation.     it would be A.

Explanation:

Answer:

no

Explanation:

This downward force and acceleration results in a downward displacement from the position that the object would be if there were no gravity. The force of gravity does not affect the horizontal component of motion; a projectile maintains a constant horizontal velocity since there are no horizontal forces acting upon it.

Answer:

wazzam blood

Explanation:

Answer:

volt ÷ ampere

Explanation:

The mathematical form of Ohms law is given by :

V = IR

Where V is voltage

I is current

R is resistance

[tex]R=\dfrac{V}{I}[/tex]

The unit of voltage is volt and that of current is ampere

Unit of resistance :

[tex]R=\dfrac{\text{volt}}{\text{ampere}}[/tex]

So, volt ÷ ampere is the same as the unit of resistance. Hence, the correct option is (a).

Answer:

The answer is: volt ÷ ampere

Explanation:

Hope this helps. :)

If it's right, can you mark me as Brainliest.

Answer:

F= 99 N

Explanation:

Dynamics and Kinematics

This problem is a combination of dynamics and kinematics because we need formulas and concepts of both branches of physics to solve it.

We need to calculate the force required to launch horizontally a pumpkin of m=1 Kg a distance of d=10 m away from a height of h=5 m.

Since the force is:

F = m.a

We need to calculate the acceleration required to move the pumpkin from rest (vo=0) to the launching speed (vf) in a time t=0.1 seconds.

The acceleration can be calculated by using the kinematic equation:

[tex]\displaystyle a=\frac{v_f-v_o}{t}[/tex]

The final launching speed vf can be calculated knowing the height and maximum horizontal distance reached by the pumpkin.

When an object is thrown horizontally with a speed vf from a height h, the range or maximum horizontal distance traveled by the object can be calculated as follows:

[tex]\displaystyle d=v_f\cdot\sqrt{\frac {2h}{g}}[/tex]

Solving for vf:

[tex]\displaystyle v_f=d\cdot\sqrt{\frac {g}{2h}}[/tex]

Substituting:

[tex]\displaystyle v_f=10\cdot\sqrt{\frac {9.8}{2\cdot 5}}[/tex]

Calculating:

[tex]v_f=9.9\ m/s[/tex]

Now we calculate the acceleration:

[tex]\displaystyle a=\frac{9.9-0}{0.1}[/tex]

[tex]a= 99\ m/s^2[/tex]

Thus, the force required is:

[tex]F=1\ Kg\cdot 99\ m/s^2[/tex]

F= 99 N

Answer:

A. 5.03 solar mass.

B. the masses of Star A and B are 1.01 solar mass and 4.02 solar mass respectively.

Explanation:

A. The sum of their two masses can be found using Kepler's third law:

[tex]\frac{P^{2}}{a^{3}} = \frac{4\pi^{2}}{G(m_{A} + m_{B})}[/tex]

Where:

P: is the period = 5 y = 1.58x10⁸ s

a: is the separation between the stars = 5 AU = 7.5x10¹¹ m

G: is the gravitational constant = 6.67x10⁻¹¹ m³kg⁻¹s⁻²

[tex]m_{A}[/tex] and [tex]m_{B}[/tex] are the masses of Star A and Star B respectively.    

[tex]m_{A} + m_{B} = \frac{4\pi^{2}a^{3}}{P^{2}G} = \frac{4\pi^{2}(5 AU*\frac{1.5\cdot 10^{11} m}{1 AU})^{3}}{(1.58 \cdot 10^{8} s)^{2}6.67 \cdot 10^{-11} m^{3}*kg^{-1}*s^{-2}} = 1.00 \cdot 10^{31} kg*\frac{1 M_{\bigodot}}{1.989\cdot 10^{30} kg} = 5.03 M_{\bigodot}[/tex]    

Hence, the sum of their two masses is 5.03 solar mass.  

B. Their individual masses can be found using the center of the mass equation:

[tex] a_{B} = (\frac{m_{A}}{m_{A} + m_{B}})a [/tex]

Where:

[tex]a_{B}[/tex] is the distance of Star B from the center of the mass

Since, [tex]a_{A}[/tex] is four times [tex]a_{B}[/tex] and a = 5 AU we have:

[tex] a_{A} = 4a_{B} [/tex]

[tex] a = a_{A} + a_{B} [/tex]

[tex] a_{B} = a - a_{A} = a - 4a_{B} \rightarrow a_{B} = \frac{a}{5} [/tex]      

Then, their individual masses are:

[tex]\frac{a}{5} = (\frac{m_{A}}{5.03 M_{\bigodot}})a[/tex]  

[tex]m_{A} = \frac{5.03 M_{\bigodot}}{5} = 1.01 M_{\bigodot}[/tex]

Now, the mass of Star B is:

[tex]m_{B} = m_{T} - m_{A} = 5.03 M_{\bigodot} - 1.01 M_{\bigodot} = 4.02 M_{\bigodot}[/tex]

Therefore, the masses of Star A and B are [tex]1.01 M_{\bigodot}[/tex] and [tex]4.02 M_{\bigodot}[/tex] respectively.

I hope it helps you!                              

Answer: The height of its fourth bounce = 0.43m

Explanation:

The coefficient of restitution denoted by (e), is the ratio that shows the  final velocity to initial relative velocity between two objects after collision

IT is given by the formula in terms of height as

Coefficient of Restitution, e  = √(2gh))/√(2gH) = √(h/H)

Where

Coefficient of Restitution, e= 0.821

H = 2.07 m

At fourth bounce ,   we have that

Coefficient of Restitution, e⁴  =√(h₄/H)  

Putting the given values and solving , we have,

e⁴  =√(h₄/H)  

= 0.821⁴ = √(h₄/2.07)

 (0.821⁴ )² =h₄/2.07

0.2064 x 2.07 = 0.427 = 0.43

At  fourth bounce,  h₄ height = 0.43m