A student experimentally determines the gas law constant, R, by reacting a small piece of magnesium with excess hydrochloric acid and then collecting the hydrogen gas over water in a eudiometer. Based on experimentally collected data, the student calculates R to equal 0.0832

Answer:

Use the Rydberg Equation 1/λ = R(1/n²(final) - 1/n²(initial) where R = 109,678 cm⁻¹. Substitute initial orbital number and final orbital number and solve for wavelength (λ).

Explanation:

Example:

Assume an electron transition from n = 5 to n = 2.

1/λ = 109,678cm⁻¹(1/2² - 1/5²) = 109,678(0.25 - 0.04)cm⁻¹ = 23,032cm⁻¹

λ = 1/23,032cm⁻¹ = 4.34 x 10⁻⁵cm x 10⁻²m/cm x 10⁹nm/m = 434nm

Answer:

385 cm^3

Explanation:

375cm3 of a gas has a pressure of 770 mm Hg, find it Volume if the pressure is reduced to 750 mm Hg

​if we reduce the pressure, the volume increase since since PV is constant

so the new volume = 0.375 cm^3 X 770/750 = 385 cm^3

63

Answer:

C

Explanation:

Option C should be the correct one, since you have two methyl groups in the alkane (parent) chain.

Answer:

Explanation:

Determine the treatments you’ll be using on your eggs, and prepare the substances you’ll need. You can make salt-water solutions by dissolving different amounts of table salt in containers of water (e.g. 100g, 200g, 300g of salt (NaCl) per liter). You can make solutions of food coloring by adding a few drops of each color into containers of  

The Eggsperiment with Vinegar solution. The first experiment conducted was the egg placed in vinegar solution which allowed the egg to become soft and bouncy . Vinegar is a weak acid which is 5% acetic acid in water (meaning vinegar is largely just water). The egg has a shell that is made up of calcium carbonate   an air cell forms at the large end of the egg. While the embryo is growing, the shell membranes surround and contain the white or albumen of the egg. The albumen provides the liquid medium in which the embryo develops, and it also contains a large amount of the protein necessary for proper development. I hope this was hopeful

When comparing an electron's ground state with that of its excited state;

Discussion:

Entropy is simply defined as the degree of randomness otherwise termed disorderliness in a system.

Electrons in their ground state are localized and have lower energy. As such, the entropy is lower.

On the contrary; Electrons in their excited state are delocalized and have higher energy. As such, the entropy is higher.

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Explanation:

option C is correct!

hope this answer helps you dear!

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The Correct choice is ~ C

Atomic mass of Sulfur (S) is 32.1 u

Answer: ELEMENT

Explanation:

Answer:

MgCO 3 is an inorganic salt with chemical name Magnesium Carbonate. It is also called Magnesite or Hydromagnesite or Barringtonite. Hydrated forms of magnesite such as di, tri, tetrahydrates are present as minerals. It acts as a fertilizer and as an antacid.

The alcohol content is 450 proof

In the given example, the measurement of the alcohol content is said to be measured in alcohol proof.

We are going to multiply the given proof of the alcohol with the vodka drink divided by 100 to determine the content of alcohol in the alcoholic beverage.

i.e.

= (750 × 60)/100 proof

= 450 proof

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Answer:

i) In thee mitochondrion, pyruvate carboxylase converts pyruvate to oxloacetate.

ii) Malate dehydrogenase in the mitochondrion reduces oxaloacete to to malate.

iii) Malate dehydrogenase in the cytoplasm oxidizes malate to oxaloacetate.

iv) Phosphoenolpyruvate carboxykinase decarboxylates and phosphorylates oxaloacetate.forming phosphoenolpyruvate.  

Explanation:

Gluconeogenesis is the synthesis of glucose from non - carbohydrate compounds. The substrates for gluconeogenesis are lactate, pyruvate, amino acids, propionate and glycerol.

Gluconeogenesis occurs only in cytosol but the precursor is produced in mitochondria. In the conversion of pyruvte to phosphoenolpyruvate occur in mitochondria and cytosol.

Step -1:

Pyruvate carboxylase is a biotin dependent enzyme located in mitochondria. It converts pyruvate to oxlaoacetate and carbondioxide in the presence of ATP.Oxlaocetate synthesized in mitochondrial matrix has to be transported to cytosol for gluconeogenesis. Oxaloacetate is impermeble, cannot be sent out of mitochondria. So it has to be converted to malate.

Step -2:

Malate dehydrogenase in mitochondria converts oxaloacetate synthesized in mitochondrial matrix to malate. And then  it is transported to cytosol.

Step 3:

Malate dehydrogenase responsible for reversible reaction in cytosol converts malate to oxaloacetate.

Step -4

Phosphoenolpyruvate carboxy-kinase in cytosol converts oxaloacetate to PEP. The enzyme transfer high energy phosphate bond from GTP to oxaloacetate to from PEP and liberated carbondioxide.

Therefore, the steps of glycolysis converts phosphoenolpyruvate to pyruvate are as follows.

i) In thee mitochondrion, pyruvate carboxylase converts pyruvate to oxloacetate.

ii) Malate dehydrogenase in the mitochondrion reduces oxaloacete to to malate.

iii) Malate dehydrogenase in the cytoplasm oxidizes malate to oxaloacetate.

iv) Phosphoenolpyruvate carboxykinase decarboxylates and phosphorylates oxaloacetate.forming phosphoenolpyruvate.

Explanation:

Answer:

You are correct it is NaCl

Answer:

205 calories.

Explanation:

According to the USDA, "Carbohydrates provide 4 calories per gram, protein provides 4 calories per gram, and fat provides 9 calories per gram." 9 grams of fat at 9 calories per equals 81 calories + 6 grams of protein at 4 calories per gram which equals 24 calories + 25 grams of carbohydrate at 4 calories per gram which is equal to 100 calories.

Total that all up and you get 81 cal + 24 cal + 100 cal=205 calories.

I don't know what kind of course this is for, but if they are incredibly picky, what we refer to as "calories" are actually kilocalories, which are equal to one thousand "real" calories each. However, I'm very confident that the correct answer is 205 calories.

The sandwich will provide 205 calories.

A calorie is an energy unit. It's the quantity of heat needed to increase the temperature of one gramme of water by [tex]1^{0} C[/tex] at one atmosphere of pressure.

Its is given that, Fat = 9 g, protein = 6 g, carbohydrate = 25 g.

It is known that, fat contains 9 calories / gram , carbohydrate contains 4 calories / gram and protein contains 4 calories / gram.

Now, adding all terms.

Total calories = (9×9) +(6×4) +(25×4)

= 205 calories.

Therefore, the sandwich will provide a total of 205 calories.

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Answer:

17) b

18) c

19) c

20) c

21) b

22) D

23) b

24) b

25) a

26)?

27) D

28) b

29) D

30) c

The best way to balancing a combustion equation of an organic compound, like the one in the question, is to start balancing the carbon, then the hydrogen and finish with the oxygen. For that you have to split the hydrocarbon into individual elements. And once you have finished you shall always try to reduce the coefficient if possible. Therefore, the answers are A. and C.

will share 2 elctrons with 2 Cl to form

S in column 16 WILL SHARE 2 ELECTRONS WITH 2 /Cl to form

SCl2

,

Answer:

a. carbon    CCl4

b. nitrogen NCl3

c. aluminum AlCl3  

d. sulfur SCl2

Explanation:

10. Based on their valence electrons, how many

atoms of chlorine are expected to bond

with each of the following elements?

a. carbon    CCl4

b. nitrogen NCl3

c. aluminum AlCl3  

d. sulfur SCl2

Cl is in Periodic Table column 17, so it has 7 valence  and needs 1 more to have an electronic structure like its nearest noble gas, Ar.

It then has an oxidation state 0f -1.

Carbon in column  has  +/-4 charge, so 4 Cl will bond with 1 C to make

covalent CCl4

Nitrogen in column 15  is -3.  It will share 3 electrons with 3 Cl to form

covalent NCl3

Al in column 13 give away 3 electrons to 3 Cl to form

ionic AlCl3

S in column 16 will share 2 electrons with 2 Cl and frorm

SCl2

Answer: 2.43 x 10^23 molecules

Explanation:

Molar mass of H2S: 2(1.008) + 32.06 = 34.1 g/mole

Avogadro’s number for converting moles to atoms or molecules: 6.02 x 10^23

(13.751375g H2S)(1 mole H2S)(6.02x10^23 molecules) / (34.1g/mole H2S)(1mole H2S) = 2.43 x 10^23 molecules H2S

Answer:

Glycerin

Explanation:

The stronger the intermolecular forces of attraction the more energy is required to break those forces, if you need more energy to break these forces it means that these certain elements would have a higher boiling point. Which is why the answer is Glycerin, the highest boiling point of an element means that it has the strongest forces, which in this case is electrostatic forces.

Answer:

Glycerin

Explanation:

Before

P1 : 748 mmHg

V1 : 22.5 L

After

P2 : 725 mmHg

V2 : ?

748 mmHg / 22.5 L = 725 mmHg / V2

Cross Multiply...

748 mmHgV2 = 16312.5 mmHgL

748 mmHgV2 / 748 mmHg = 16312.5 mmHgL / 748 mmHg

V2 = 21.808155 L

V2 = 21.8 L (sig figs)

Answer:

21.86 grams

Explanation:

It is important to note that for every mol of Na3PO4 there is, 3 mols of Na ions are produced.

Na+=1m(0.4l), so mols of Na3PO4= 0.4/3= 0.13333... mols

the molar mass of Na3PO4 is 163.94 grams/mol. 0.1333*163.94=21.86 grams of Na3PO4.

Answer:

[tex]2al + 3h2so4 = > al2(so4)3 + 3h2 \\ eqvt \\ = > \frac{5.4}{27} = > \frac{5 \times 50}{1000} \\ .2 \: mol = > .25 \: mol \\ \\ so \: .25 \: is \: limiting \: reagent \\ according \: to \: ideal \: gas \: equation \\ pv = nrt \\ v = \frac{nrt}{p} \\ v = \frac{.25 \times .082 \times 300}{1} \\ = \frac{1}{4} \times 8.2 \times 3 \\ = 2.05 \times 3 \\ = 6.15litre \\ thank \: you[/tex]

Answer:

Firstly, try to Go through your chapter and pay attention to main keywords.

secondly try to watch 'Uube' videos related to specific topic instead of chapter and pay attention to it closely and watch it with a keen interest.

Discuss topics that you find harder with your friends or peer group members, Because you learn faster when you study with the people of your age.

Answer:

i think the best way to learn chemistry is study over things that involve it

Explanation:

The electrostatic forces between molecules of glycerin are the strongest.

We have 4 compounds with their respective boiling points.

The boiling point is the temperature at which a substance passes from the liquid state to the gaseous state.

A high boiling point indicates that the intermolecular forces are strong, so more energy is needed to separate the molecules in the vaporization.

Thus, glycerin, with the highest boiling point, is expected to have the strongest electrostatic forces between their molecules.

The electrostatic forces between molecules of glycerin are the strongest.

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Answer:

Glycerin

Explanation:

Answer:

C8H12

Explanation:

First find the molar mass

195/1.8 × 1 = 108.3 gmol-1

Then the molecular formula

Mass of C in 1 mole of compound = 88.82×108.3/100

= 96.2 g

Mass of H in 1 mol of.the compound = 108.3×11.18/100 = 12.11 g

Divide the mass by their molar masses to get no. of moles in 108.3 g of compound or 1 mole of compound

Moles of C in one Mole of compound = 96.2g/12 gmol-1 = 8 mol

Moles of H in 1 mole of compound = 12.11g/1 gmol-1 =12 mol

Since we need the molecular formula it's C8H12

Answer:

The answer is A and B

Explanation:

Answer:

oxygen

Explanation:

One mole of atoms of oxygen has a mass of 16 g, as 16 is the atomic weight of oxygen, and contains 6.02 X 1023 atoms of oxygen.

Answer:

D: Kinetic Energy​

Explanation:

Temperature is a measure of kinetic energy. Temperature is a measure of the average kinetic energy of the particles in an object. When temperature increases, the motion of these particles also increases.

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Answer:

The dipole forces (particularly H-bonds) that keep polar solute molecules together can be replaced by polar solute-solvent interactions, so substances that are predominantly polar (like glucose) dissolve in polar solvents like water but not in nonpolar solvents like hexane (H-bonds).

Explanation:

Answer:

see explanation

Explanation:

An AX₂E₂ geometry is derived from an AX₄ parent geometry and is based upon 4 regions of electron density about the central element and defines a tetrahedral geometry and the geometry is bent angular.

An example is the water molecule (H₂O) with two covalent O - H bonds and two free pair electrons on the central oxygen element.

Answer :

[tex] \: [/tex]

Concentration of Solutions

Recall that a solution consists of two components: solute (the dissolved material) and solvent (the liquid in which the solute is dissolved). The amount of solute in a given amount of solution or solvent is known as the concentration. The two most common ways of expressing concentration are molarity and molality.

Molarity

The molar concentration (M) of a solution is defined as the number of moles of solute (n) per liter of solution (i.e, the volume, V solution):

M = n / V solution

The units of molarity are mol/L, often abbreviated as M.

For example, the number of moles of NaCl in 0.123L of a 1.00M solution of NaCl can be calculated as follows:

[tex]0.123 \: l \: \: of \: solution \: \times \: \frac{1.00 \: mole}{1.00 \: l \: of \: solution \: } \: \\ = 0.123 \: moles[/tex]

Molality :

The molal concentration (m) of a solution is defined as the number of moles of solute (n) per kilogram of solvent (i.e., the mass of the solvent, msolvent):

[tex]m = \frac{n}{v \: solution} [/tex]

For example, the number of moles of NaCl dissolved in 0.123kg of H2O (the solvent), in order to make a 1.00m solution of NaCl, can be calculated as follows:

[tex]0.123 \: kg \: of \: solvent \: = \frac{1.00 \: mole}{1.00 \: kg \: of \: solvent \: } \\ = 0.123 \: moles[/tex]

Answer:

Rb, Zn, P, S, F, Ca, Co, Cr

Rb, Zn, P, S, F, Ca, Co, Cr elements in order of decreasing metallic character.

The metallic character of an element is defined as the properties typical of metal, especially the tendency to lose electrons in chemical reactions.

Metallic character depends on the ability of an element to lose its outer valence electrons. Examples of properties related to metallic character include thermal and electrical conductivity, metallic lustre, hardness, ductility, and malleability. The most "metallic" element is francium, followed by caesium.

Hence, Rb, Zn, P, S, F, Ca, Co, and Cr elements in order of decreasing metallic character.

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