Answer:
1. Vapor pressure of dry oxygen gas = 747.68 torr
2. Volume at STP = 39.97 mL
3. Number of oxygen gas molecules = 1.074 × 10²¹ molecules
4. Percent purity of KClO3 = 97.3 %
Explanation:
The balanced equation for the reaction is given below :
2 KClO3 (s) ------> 2 KCl (s) + 3 O2 (g)
1) Since the water level in the eudiometer was below the outside water level in the beaker,
Vapor pressure of dry oxygen gas = Total pressure + pressure due to difference in water levels - vapor pressure of water
Vapor pressure of water at 20 °C is 17.535 mm (torr).
Pressure due to difference in water level = 4.22 cm × 10mm/cm / 13.534 (13.534 is the density of mercury) = 3.118 mm (torr).
Vapor pressure of dry oxygen gas = 762.10 torr + 3.118 torr - 17.535 torr
Vapor pressure of dry oxygen gas = 747.68 torr
2) P₁ = 747.68 torr; V₁ = 43.60 ml; T1 = 20 °C + 273.15 = 293.15 K
P₂ = 760 torr; T₂ = 273.15 K; V₂ = ?
Using the general gas equation = P₁V₁/T₁ = P₂V₂/T₂
V2₂= P₁V₁T₂ / P₂T₁
V₂ = (747.68 × 43.60 × 273.15 ) / (760 × 293.15)
V₂ = 39.97 ml
Volume of dry oxygen gas at STP = 39.97 mL
3) Volume of oxygen gas at STP 39.97 mL = 0.03997 L
Number of moles of oxygen gas in 0.03997 L = volume of gas at STP /molarvolume at STP
Number of moles of oxygen gas = 0.03997/22.4 L
Number of molecules of oxygen gas = 0.03997/22.4 L × 6.03 × 10²³ molecules
Number of oxygen gas molecules = 1.074 × 10²¹ molecules
e) Number of moles of oxygen gas = 0.03997/22.4 = 0.001784 moles
From the equation, mole ratio of oxygen gas and potassium chlorate is 3 : 2
Moles KClO3 = 2/3 × 0.001784 moles = 0.001189 moles
Molar mass of KClO3 = 39 + 35.5 + 3 × 16 = 122.5 g
Actual mass of KClO3 decomposed = 122.5 grams × 0.001189 mole = 0.146 grams
Percent purity = (actual mass KClO3 decomposed / sample mass of impure KClO3) × 100%
Percent purity = (0.146/0.150) × 100% = 97.3 %
what happens when a star dies
Answer:
They become a supernova
Explanation:
answer:
a supernova happens and it's quite a beautiful thing. a supernova happens when a star runs out of fuel (hydrogen) and once there isn't any fuel left the star begins to collapse and the outer layer explodes into a supernova. cool right? ( now not all stars explode into supernovas just the red giants. some other stars just fade away.)
explanation:
https://www.sciencefocus.com/space/how-do-stars-die/
good luck :)
i hope this helps
brainliest would be highly appreciated
have a nice day!
WHAT IS A ROCK?
Please put the answer below
DO ITTT NOWWWWWWWWWWWWWW
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Which is a LIMIT that authors telling stories using aural media, such as radio plays, must deal with?
A. listeners can hear how each actor says lines of dialogue
B. sound effects can enhance the story's action
C. music can reinforce the story's emotional moments
D. characters thoughts and feelings must be spoken aloud
how many atoms are in 14 moles of cadium
Answer:
14x6.02x10^23=8.428x10^23 atoms
Answer:
atoms are in 14 moles of cadmium. Cadmium is present in some foods and is emitted when fossil fuels like as coal and oil is used, smoking cigarettes. It is used in craft glazes, metal batteries, and coatings. We know that 1 mole of Cadmium (Cd contains) 6.023*1023 atoms, which is Avogadro's number
Explanation:
In the formula H2SO4, what is the 4 called?
Answer:
Well 4 in H2SO4 would be called Sulfuric Acid
Explanation:
The Reason why its called by its name because the form lua is called this its because its a colorless Acid that burns it also has dissolving metals and other stuff inside of it. it has another name called oil of vitriol. hopefully this helps ^^!
DESCRIBE HOW THE INTESTINES, LIVER, STOMACH, AND PANCREAS ALL WORK TOGETHERbrainlist if its right and not actually stup/d answers BTW GIVING MY POINTS IF ITS RIGHGT LOTS OF DETAUKL BUT PUT IT IN 5TH GRADE LAUNGE
Answer:
Explanation:
here to give other person brainlist
HELP PLISSS !!!!! what did a criminal often use to poison? A. Eye medication. B. potassium cyanide
Answer:
potassium cyanide
Explanation:
while eye medications do harm your immune system it is not enough to kill someone. criminals mainly used potassium cyanide because it was cheap. it serves as a substitute for ethanol.
10. An aqueous solution is made from 0.315 mol of Na,Cr2O7. If the volume of the
solution is .025 L, what is the molarity of the solution? (Answer with significant
digits. Example: 00.0)
Answer:
Its 12.6M
Explanation:
It came to the conclusion and got these answers
2.22
20.5
10
12.6
12.6 is the correct answer
How can a cation be formed?
Add 1 clectron
Take away 1 clectron
Add 1 proton
Take away 1 prekon
How does sunlight hits earths surface closer to the poles?
Answer:
When the sun's rays strike Earth's surface near the equator, the incoming solar radiation is more direct (nearly perpendicular or closer to a 90˚ angle). Therefore, the solar radiation is concentrated over a smaller surface area, causing warmer temperatures.
Explanation:
250 mL of a solution of calcium oxalate is the evaporated until only a residue of solid calcium
oxalate is left. The mass of the residue recovered from the container was 154 mg. What is the
solubility product of calcium oxalate?
Answer:
2.3 * 10^-5
Explanation:
Recall that the solubility of a solute is the amount of solute that dissolves in 1 dm^3 or 1000cm^3 of solution.
Hence;
Amount of calcium oxalate = 154 * 10^-3/128.097 g/mol = 1.2 * 10^-3 mols
From the question;
1.2 * 10^-3 mols dissolves in 250 mL
x moles dissolves in 1000mL
x = 1.2 * 10^-3 mols * 1000/250
x= 4.8 * 10^-3 moldm^-3
CaC2O4(s) ------->Ca^2+(aq) + C2O4^2-(aq)
Hence Ksp = [Ca^2+] [C2O4^2-]
Where;
[Ca^2+] = [C2O4^2-] = 4.8 * 10^-3 moldm^-3
Ksp = (4.8 * 10^-3)^2
Ksp = 2.3 * 10^-5
How many grams of potassium carbonate are needed to make 300ml of a 4.5M solution?
Answer:
186.3g
Explanation:
4.5moles of K₂CO₃ is in 1000ml
? moles of K₂CO₃ is in 300 ml
(4.5 × 300)/ 1000 = 1.35 moles of K₂CO₃
1 mole of K₂CO₃ = (39 × 2) + 12 + (16 × 3) = 78 + 12 + 48 = 138g
1.35 moles of K₂CO₃ = ?
= (1.35 × 138)/1 = 186.3g
Which types of electron orbitals will have a higher energy than a 4 d orbital?
Answer:
shell
Explanation:
it is because the shell contains many electrons
15.
A tank containing 173 grams of methane, CH (9), registers 15.1 atmospheres at 298 Kelvin. What is the volume of the tank (assuming the entire volume is available to the gas)?
A 3,410L
B. 213
C.O 175L
D. 280.
Chemistry 4/28 5454
Copyright © 2021 Illuminate Education, Inc. All Rig
Answer: The volume of tank is 17.5 L.
Explanation:
Given: Mass of methane = 173 g
Pressure = 15.1 atm
Temperature = 298 K
Molar mass of methane is 16.04 g/mol.
Therefore, moles of methane are calculated as follows.
[tex]No. of moles = \frac{mass}{molar mass}\\= \frac{173 g}{16.04 g/mol}\\= 10.78 mol[/tex]
Now, ideal gas equation is used to calculate the volume as follows.
PV = nRT
where,
P = pressure
V = volume
n = no. of moles
R = gas constant = 0.0821 L atm/mol K
T = temperature
Substitute the values into above formula as follows.
[tex]PV = nRT\\15.1 atm \times V = 10.78 mol \times 0.0821 L atm/mol K \times 298 K\\V = \frac{10.78 mol \times 0.0821 L atm/mol K \times 298 K}{15.1 atm}\\= 17.5 L[/tex]
Thus, we can conclude that volume of the tank is 17.5 L.
How do I turn on a Girl???
Answer:
7 Ways to turn a woman on. ...
Ask her what she likes, and do your homework. ...
Know the three parts of foreplay. ...
Be creative: Not all women are the same. ...
Know her body. ...
Help her feel comfortable receiving oral sex. ...
Play with lube or toys. ...
Remember that great sex won't happen overnight.
Explanation:
Answer: Ask her what she likes, and do your homework. ...
Know the three parts of foreplay. ...
Be creative: Not all women are the same.
Hope this helps
3. What are the factors needed for phase change to happen?
A. Heat and pressure
C. Sound and radiation
B. Power and radiation
D. Force and velocity
Answer:
A. Heat and pressure
Explanation:
Explain three factors that can affect the size of a line in a spectrum.
Answer:For atoms and molecules, the width of spectral lines is governed mainly by the broadening of the energy levels of the atoms or molecules during interactions with surrounding particles and by the broadening of the spectral lines as a result of the Doppler effect.
Explanation:
Bats and marine mammals are able to locate prey and to communicate by sending and receiving sound waves that echo off surface. Echos demonstrates the wave property of A: absorption, B: diffusion, C: transmission, or D: reflection
Given that the nucleophilic substitution reaction used 5.0 mL of t-pentyl alcohol and 12.0 mL of conc. hydrochloric acid to produce t-pentyl chloride, what is the theoretical yield of t-pentyl chloride, in grams
Answer:
4.90 g
Explanation:
Given that:
volume of t-pentyl alcohol = 5 mL
the standard density of t-pentyl alcohol = 0.805 g/mL
Recall that:
density = mass(in wt) /volume
mass = density × volume
mass = 0.805 g/mL × 5 mL
mass = 4.03 g
Volume of HCl used = 12 mL
The reaction for this equation is shown in the image attached below.
From the reaction,
88.15 g of t-pentyl alcohol reacts with concentrated HCl to yield 106.59 g pf t-pentyl chloride.
4.03 g of t-pentyl alcohol forms,
[tex]= \dfrac{106.59 \ g \times 4.03 \ g}{88.15 \ g}[/tex] of t-pentyl chloride.
Therefore,
Theoretical yield of t-pentyl chloride = 4.90 g
100.0 g of water was placed in a simple, constant-pressure calorimeter. The temperature of the water was recorded as 295.0 K. A 20.0 g copper block was heated to 353.0 K and then dropped into the water in the calorimeter. What was the final temperature of the water if the specific heat capacities of copper is 0.385 J/g K
Answer:
[tex]296.05\ \text{K}[/tex]
Explanation:
[tex]m_w[/tex] = Mass of water = 100 g
[tex]c_w[/tex] = Specific heat of water = [tex]4.184\ \text{J/g K}[/tex]
[tex]m_c[/tex] = Mass of copper = 20 g
[tex]c_c[/tex] = Specific heat of copper = [tex]0.385\ \text{J/g K}[/tex]
[tex]\Delta T_w[/tex] = Temperature change in water = [tex](T-295)[/tex]
[tex]\Delta T_c[/tex] = Temperature change in cooper = [tex](353-T)[/tex]
T = Final temperature of the system
The heat balance of the system is given by
[tex]m_wc_w\Delta T_w=m_cc_c\Delta T_c\\\Rightarrow 100\times 4.184\times (T-295)=20\times 0.385\times (353-T)\\\Rightarrow 418400\left(T-295\right)=7700\left(353-T\right)\\\Rightarrow 418400T-123428000=2718100-7700T\\\Rightarrow T=\frac{1261461}{4261}\\\Rightarrow T=296.05\ \text{K}[/tex]
The final temperature of the water is [tex]296.05\ \text{K}[/tex].
The final temperature of the water when placed in a calorimeter is 296.05K
HOW TO CALCULATE FINAL TEMPERATURE:
The final temperature of water placed in a calorimeter can be calculated using the following expression:Q(water) = - Q(copper)(m × c × ∆T) water = - {m × c × ∆T} copperWhere;
Mass of water = 100 gSpecific heat of water = 4.184 J/g KMass of copper = 20 gSpecific heat of copper = 0.385 J/g KTemperature change in water = T - 295KTemperature change in copper = T - 353K100 × 4.184 × (T - 295) = - {20 × 0.385 × (T - 353)}418.4T - 123428 = - (7.7T - 2718.1)418.4T - 123428 = -7.7T + 2718.1418.4T + 7.7T = 123428 + 2718.1426.1T = 126146.1T = 126146.1 ÷ 426.1T = 296.05KTherefore, the final temperature of the water when placed in a calorimeter is 296.05K.Learn more at: https://brainly.com/question/10987564?referrer=searchResults
 How many moles of ammonium hydroxide are present in 140.0 g of the substance?
I believe the answer is 18.
A 3mL sample of a 200 Molar solution is left open on a lab
counter for two weeks, after which the concentration of the solution is 6 M. What is the new volume of the solution?
Answer: New volume of the solution is 100 mL.
Explanation:
Given: [tex]V_{1}[/tex] = 3 mL, [tex]M_{1}[/tex] = 200 M
[tex]M_{2}[/tex] = 6 M, [tex]V_2[/tex] = ?
Formula used to calculate the new volume of solution is as follows.
[tex]M_{1}V_{1} = M_{2}V_{2}[/tex]
Substitute the values into above formula as follows.
[tex]M_{1}V_{1} = M_{2}V_{2}\\200 M \times 3 mL = 6 M \times V_{2}\\V_{2} = \frac{200 M \times 3 mL}{6 M}\\= 100 mL[/tex]
Thus, we can conclude that new volume of the solution is 100 mL.
how do you identify whether a solution is a buffer solution or not
Answer:
You check whether the PH level changes when you add little amounts of strong acid or base. If you see that there is little to no change in the PH, then it is a buffer solution.
Hope that answers your question
Explanation:
what's the relation between Kp and Kc
Answer:
the relation between Kp and Kc is
[tex] \colorbox{red}Kp=Kc{[RT]}^{∆n}[/tex]
where
∆n=no.of moles of gaseous product - no.of moles of gaseous reactant in the balanced chemical equation.
R=universal gas constant
T=temperature.
Why is it important that the perodic table is structured as a table rathe than a list of elements. please answer me
Answer:
According to the b word, this is the answer
Explanation:
Learning a periodic table is more important as it is systematically arranged to give a lot of information about the elements and the way they relate to each other in various ways. Moreover, chemistry is all more about chemical elements. Hence a good understanding of the chemical elements will discover more about chemistry.
The Ksp of silver bromide at 25°C (298 K) is 5.0 x 10-13. Write the solubility expression hydrogen oxygen for this compound and show the dissociation equation for AgBr.
The volume of a gas is 5.0 L, when the temperature is 5.0 degrees Celsius. If the temperature is increased to 10.0 degrees Celsius with no change in pressure, what is the new volume?
Answer:5.1L
Explanation:
Which statement describes the best way to determine how different levels of light affect the growth of seedling plants?
Choose three different light levels, and place four identical plants under each light level to observe the light’s effect on multiple plants.
Choose five different light levels, and place one identical plant under each of the light levels for exactly one week.
Choose four different light levels, and place eight different plant types under the light levels, two under each one, and observe them every day.
Choose one type of light and one type of plant, and then observe the plant for at least four weeks, measuring it each day.
Answer:
Choose three different light levels, and place four identical plants under each light level to observe the light’s effect on multiple plants.
Explanation:
(b) How many moles of hydrogen are needed to make 30 moles of Fe?
PLEASE HELP ASAP
Answer:
1 mole of Fe is 55.85 g per mole
Explanation:
hope it helps
The moles of hydrogen that are needed to make 30 moles of Fe is 45 moles.
What are moles?Moles is a measurement unit. It is the quantity amount of substance.
The balanced equation is
Fe2O3 + 3H2 ---> 2Fe + 3H2O
Given the moles of iron is 30
To find the moles of hydrogen is?
According to the given balanced equation, the ratio of moles of hydrogen and iron is 3 : 2
To produce 30 moles of Fe
30 x 3 / 2 = 45 moles.
Thus, the number of moles of hydrogen is 45 moles.
To learn more about moles, refer to the link:
https://brainly.com/question/20486415
#SPJ5
Your question is incomplete. Your most probably complete question is given below:
One way to change iron are, Fe2O3, into metallic iron is to heat it together with hydrogen:
Fe2O3 + 3H2 ---> 2Fe + 3H2O
How are a desert and a tundra similar?
They both have high levels of precipitation.
They have many trees and a lot of vegetation.
They have high average temperatures.
They have low humidity and low levels of precipitation.
Answer:
They have low humidity and low levels of precipitation.
Explanation:
Both the desert and the tundra are two extreames, one is really hot while the other is really cold. Deserts only receive less than 300 mm of rain each year. While the tundra receives 150 to 250 mm of precipitation each year, including melted snow. Which is less than the majority of the world's deserts.
Answer: They have low humidity and low levels of precipitation.
Explanation:
Differences: Tundra's are extremely cold, and doesn't get much rain.
Differences: The Dessert is Extremely hot and doesn't get rain.
Explanation: There is already our answer here, If we compare there differences the we will find our answer. This is what I found as the same "doesn't get rain." And we know that precipitation is rain so your answer would be precipitation. Your answer: They have low humidity and low levels of precipitation.