Substances are composed of atoms, although I'm not sure if this is what you mean
You drive your car for 2.0 h at 40.0 km/h, then for 2.0 h at 60.0 km/h. What is your average
velocity?
Answer:
Simple as 50 km/h
Explanation:
Since the average being measured is of the hours and not distance, it is simply (60+40)/(2+2)
Potential energy is the energy an object has due to its:.
Answer:
its position relative to some zero position
Explanation:
your welcome
how are magnetic domians and magnetic fields connected
What is the momentum of a 3-kg object moving at 5 m/s?
Answer: 15 kg*m/s
Explanation:
Momentum = mass*velocity
Momentum = 3kg*5 m/s
Momentum = 15 kg*m/s
Answer:
15 kg m/s
Explanation:
Momentum = mass xvelocity
Momentum = 3kgx 5 m/s
Momentum = 15 kg m/s
After the softball leaves your hand, it rises, slowing down.
Answer:
yes it do rises and then fall down due to gravitational
May I get an answer?
Answer:
Explanation: all of them have made sentence structure (grammar point view) and from the physical aspect.
Why is soccer a great athletic sport
Answer:
that is the answer
Explanation:
look at it
Use the ratio version of Kepler’s third law and the orbital information of Mars to determine Earth’s distance from the Sun. Mars’s orbital period is 687 days, and Mars’s distance from the Sun is 2. 279 × 1011 m. 1. 49 × 1011 m 1. 49 × 1033 m 3. 34 × 1011 m 3. 34 × 1033 m.
Kepler's third law is used to determine the relationship between the orbital period of a planet and the radius of the planet.
The distance of the earth from the sun is [tex]1.50 \times 10^{11}\;\rm m[/tex].
What is Kepler's third law?
Kepler's Third Law states that the square of the orbital period of a planet is directly proportional to the cube of the radius of their orbits. It means that the period for a planet to orbit the Sun increases rapidly with the radius of its orbit.
[tex]T^2 \propto R^3[/tex]
Given that Mars’s orbital period T is 687 days, and Mars’s distance from the Sun R is 2.279 × 10^11 m.
By using Kepler's third law, this can be written as,
[tex]T^2 \propto R^3[/tex]
[tex]T^2 = kR^3[/tex]
Substituting the values, we get the value of constant k for mars.
[tex]687^2 = k\times (2.279 \times 10^{11})^3[/tex]
[tex]k = 3.92 \times 10^{-29}[/tex]
The value of constant k is the same for Earth as well, also we know that the orbital period for Earth is 365 days. So the R is calculated as given below.
[tex]365^3 = 3.92\times 10^{-29} R^3[/tex]
[tex]R^3 = 3.39 \times 10^{33}[/tex]
[tex]R= 1.50 \times 10^{11}\;\rm m[/tex]
Hence we can conclude that the distance of the earth from the sun is [tex]1.50 \times 10^{11}\;\rm m[/tex].
To know more about Kepler's third law, follow the link given below.
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Julia produces a 2 mA current by moving the south pole of a bar magnet into a solenoid. The solenoid contains 150 loops of wire. Which change should Julia make to generate a larger current? moving the magnet slower using more loops of wire in the coil using the north pole of the magnet setting the magnet down in the solenoid.
Julia has to increase the no of loops in the coil in order to increase the generation of current.
What is a solenoid?A solenoid is an electromagnet formed by a helical coil of wire. which generates a magnetic field when an electric current is passed through the coil.
According to Faraday's law of electromagnetic induction, the rate of change of magnetic flux linked with the coil is responsible for generating emf in the coil resulting in the vof the amount of current.
magnetic flux is defined as
Ф=NBA
[tex]EMF = \frac{d\phi}{dt} \\\\EMF = \frac{d(NBA)}{dt} \\\\[/tex]
[tex]EMF =NA \frac{d(B)}{dt} \\\\[/tex]
EMF is directly proportional to the amount of current. so that in order to increase the amount of current emf should be increasing and Emf is increased by the increasing no of the loop in the coil.
Hence Julia has to increase the no of loops in the coil in order to increase the generation of current.
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Answer:
BBBBBBBBB
Explanation:
A car driver traveling at a speed of 108km per hour ,sees a traffic light and stopped after travelling for 20seconds .Find the acceleration of the car
Answer:
– 2.5 m/s²
Explanation:
We have,
• Initial velocity, u = 180 km/h = 50 m/s
• Final velocity, v = 0 m/s (it stops)
• Time taken, t = 20 seconds
We have to find acceleration, a.
[tex]\longrightarrow[/tex] a = (v ― u)/t
[tex]\longrightarrow[/tex] a = (0 – 50)/20 m/s²
[tex]\longrightarrow[/tex] a = –50/20 m/s²
[tex]\longrightarrow[/tex] a = – 5/2 m/s²
[tex]\longrightarrow[/tex] a = – 2.5 m/s² (Velocity is decreasing) [Answer]
Difine velocity?
Thnx~~[tex] \: \: \: [/tex]
Velocity is simply defined as the rate of change of displacement per unit time. Mathematically, it can be expressed as
Velocity = displacement / time
How to determine velocityFor example: A car travels 400 m due north in 40 s. What is the velocity of the car.
From the question given above, we can obtain the velocity as follow:
Displacement = 400 m due north Time = 40 sVelocity =?Velocity = displacement / time
Velocity = 400 / 40
Velocity = 10 m/s
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any two difference between negative and positive charge of class 7 please fast
Answer:
any two difference between negative and positive charge
➢The matter is positively charged if it contains more protons than electrons, and it is negatively charged if it contains more electrons than protons.
Explanation:
I hope it will help you.....
[tex]kai6417[/tex]
#carryonlearning
What is the frequency of a wave with a time period of 0.08
s?
O
8 Hz
O
1.25 Hz
O
12.5 Hz
Answer:
12.5 hz
Explanation:
What are the characteristics of terristrial animals?
Answer:
They are provided with keen senses of sight, smell and hearing.
Answer:
Terrestrial animals
breathe through skin or nostrils, have differently adapted bodies, and exchange of gases is done from air, whereasA charged particle moves at 2. 5 × 104 m/s at an angle of 25° to a magnetic field that has a field strength of 8. 1 × 10–2 T. If the magnetic force is 7. 5 × 10–2 N, what is the magnitude of the charge? 3. 7 × 10–5 C 4. 1 × 10–5 C 8. 8 × 10–5 C 1. 0 × 10–4 C.
The force acting on a moving charge is known as the magnetic force. The force acting on the charge will be 3.75 N.
What is the force exerted on the charge?Magnetic fields only exert a force on a moving electric charge. A moving charge generates a magnetic field. With an increase in charge and magnetic field strength, this force rises.
when charges have higher velocities, the force is stronger. However, the magnetic force is always perpendicular to the velocity.
Mathematically the force exerted on the charge will be
F=qvBsinα
F= force acting on the charge= 7.5 ×10⁻²
v = velocity of charge=2.5 ×10⁴
q = charge=?
B= 8.1 ×10⁻²
F=qvBsinα
[tex]\rm{q= \frac{F}{vBsina}}[/tex]
[tex]\rm{q= \frac{7.5\times 10^-2}{2.4\times 10^-2 \times 8.1\times 10^-2 sin25^0}}[/tex]
q = [tex]8.8 \times 10^ {-5}\rm C[/tex]
Hence the value of the charge will be [tex]8.8 \times 10^ {-5}\rm C[/tex].
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A chair is pushed backward with a force of 100 N. The gravitational force of Earth on the
chair is 120 N downward, and the floor exerts a force of 120 N upward on the chair.
Draw a free-body diagram showing the forces acting on the chair.
Explanation:
he fell down with telling any one,
Sir Isaac Newton first explained the relationship between force and motion. True or false?
Answer:
true
Explanation:
sir isaac newton was the first person to explain the relationship between force and motion
A car accelerates from to at a constant rate of How far does it travel while accelerating?.
Distance is the measure of the length of ground covered by an object during its motion. Distance is a scalar quantity. The car will travel 69 m while accelerating.
What is the distance?
Distance is the measure of the length of ground covered by an object during its motion. While the displacement is defined as the shortest distance between the two paths.
Distance is a scalar quantity. While displacement is a vector quantity. Mathematically it is given as the product of speed and time.
The following data are given in the problem as
u is the initial speed=5.0 m/sec
v is the final speed=21 m/sec
s is the distance covered by the car =?
a= Acceleration of car =3.0 m/sec²
According to Newton's third equation of motion, the formula derived will be
[tex]\rm{v^2=u^2+2as \\\\[/tex]
[tex]\rm s = \frac{v^2-u^2}{2a} \\\\\rm s = \frac{(21)^2-(5)^2}{2\times3.0} \\\\ \rm s=69 m[/tex]
Hence the car will travel 69 m while accelerating.
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During a lightning storm, the bottom of a cloud gains a strong negative electric charge. If you were to measure the charge at the top of a tall metal pole directly under the cloud, what would you expect to observe?.
During a lightning storm, the bottom of a cloud gains a strong negative electric charge. If you were to measure the charge at the top of a tall metal pole directly under the cloud, what would you expect to observe? The top of the pole would have no charge. The top of the pole would have a positive charge.
In the given scenario, the positive charges within the pole concentrate at the top of the pole to be near the negatively charged cloud bottom.
What is lightning storm?A thunderstorm, also widely recognized as an electrical storm or even a lightning storm, is a type of storm that is distinguished by the presence of lightning and its acoustic effect on the Earth's atmosphere, which is known as thunder.
Thundershowers are thunderstorms that are relatively weak. Warm air rises and cools, condensing into small droplets of water.
If the air is sufficiently unstable, the updraft of warm air is rapid, and the water vapor forms a cumulonimbus cloud quickly. These cumulonimbus clouds typically form in less than an hour.
In the given scenario, the positive charges within the pole concentrate near the negatively charged cloud bottom at the pole's top.
Thus, this is the observation that can be expected.
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What is the basis for the sounds referred to as korotkoff sounds?.
Answer:Korotkoff Sounds. -tapping sounds created by turbulent blood flow in arm. -pressure is slowly being released from cuff, so systolic pressure is above that of the cuff, but diastolic is still below, so the artery opens in systole and collapses in diastole.
Explanation:
if a 2 kg balls thrown straight upward with a KE of 500 j. what maximum height will it reach?
Answer:
I think its 25.51 m!!
Explanation:
A circular disk of moment of inertia [tex]I_t[/tex] is rotating in a horizontal plane, about its axis , with a constant angular speed [tex]\omega_i[/tex] . Another disc of moment of inertia [tex]I_b[/tex] is dropped coaxially onto the rotating disk. Initially the 2nd disc has 0 angular speed. Eventually both the disks rotate with a constant angular speed [tex]\omega_f[/tex] . The energy lost initially rotating disk to friction is ?
The kinetic energy of the circular disc in initial state is,
[tex]K^{1r} = \frac{1}{2}I^{t}ω^{ \frac{2}{i} } [/tex]
The initial kinetic energy of the other disc dropped on the first disc is,
[tex]K^{2r} = \frac{1}{2}I^{b}(0)^{2}[/tex]
[tex] = > K^{2r} = 0J[/tex]
As both the disc in the final state are moving with the same angular velocity, thus, the net kinetic energy in the final state is,
[tex]E^{f} = \frac{1}{2}(I^{t} + I^{b})ω^{ \frac{2}{f} }[/tex]
The net kinetic energy in the initial state is,
[tex]E^{i} = K^{1r} + K^{2r}[/tex]
[tex] = > E^{i} = \frac{1}{2} I^{t}ω^{ \frac{2}{i} } + 0[/tex]
[tex] = > E^{i} = \frac{1}{2} I^{t}ω^{ \frac{2}{i} }[/tex]
Thus, the change in the kinetic energy during the change of state is,
[tex]dE = E^{f} - E^{i}[/tex]
[tex] = > dE = \frac{1}{2} (I^{t} + I^{b})ω^{ \frac{2}{f} } - \frac{1}{2}I^{t}ω^{ \frac{2}{i} } [/tex]
[tex] = > dE = \frac{1}{2} I^{t}(ω^{ \frac{2}{f} } - ω^{ \frac{2}{i} }) + \frac{1}{2}I^{b}ω^{ \frac{2}{f} } [/tex]
This change in value of energy is the energy lost initially rotating the disk to friction.
Hence, the energy lost in the given case is [tex]dE = \frac{1}{2} I^{t}(ω^{ \frac{2}{f} } - ω^{ \frac{2}{i} }) + \frac{1}{2}I^{b}ω^{ \frac{2}{f} } [/tex]
The energy lost initially by the rotating disk to friction is equal to [tex]\frac{1}{2}I_t (\omega_f^2 - \omega_i^2)+\frac{1}{2} I_b\omega_f^2[/tex]
Given the following data:
Angular speed = 0How to calculate the energy lost.At the initial state, the kinetic energy of the circular disc is given by this formula:
[tex]K.E = \frac{1}{2} I_t\omega_i^2[/tex]
For the second disc, the initial kinetic energy is given by this formula:
[tex]K.E_2 = \frac{1}{2} I_b\omega_f^{2 }\\\\K.E_2 = \frac{1}{2} I_b(0)^{2 }\\\\K.E_2 = 0[/tex]
At the final state, the discs would move with the same angular velocity and the net kinetic energy is given by this formula:
[tex]E_f = \frac{1}{2} (I_t + I_b)\omega_f^2[/tex]
For the energy lost:
Also, the change in the kinetic energy is given by this formula:
[tex]\Delta E = E^f - E^i\\\\\Delta E = \frac{1}{2} (I_t + I_b)\omega_f^2 - \frac{1}{2} I_t\omega_i^2\\\\\Delta E = \frac{1}{2}I_t (\omega_f^2 - \omega_i^2)+\frac{1}{2} I_b\omega_f^2[/tex]
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Help pls I dont want to fail my class
How fast would a penny be falling when it reaches ground level if dropped from rest off the 102nd floor observation deck of the empire state building? (381 meters above the ground) You may treat air resistance as negligible.
Air resistance is negligible
Distance=381m=sAcceleration due to gravity=g=10m/s^2Initial velocity=u=0m/sFinal velocity=v=?Apply third equation of kinematics
[tex]\\ \tt\longmapsto v^2=u^2+2gs[/tex]
u=0[tex]\\ \tt\longmapsto v^2=2(10)381[/tex]
[tex]\\ \tt\longmapsto v^2=7620[/tex]
[tex]\\ \tt\longmapsto v=87.29ms^{-1}[/tex]
Answer:
According to the Given Statement
Penny is dropped from rest of the 102nd floor which is 381 metres above from the ground.
we 'll take here the acceleration due to gravity (g ) is 9.8m/s²
Its initial velocity u be 0 m/s ( as it is at rest)
Using Kinematic Equation
v² = u² + 2ghhere h is the height of 102nd floor
➥ v² = 0² + 2 × 9.8 × 381
➥ v² = 0 + 19.6 × 381
➥ v² = 7467.6
➥ v = √7467.6
➥ v = 86.41 m/s
So, 86.41 m/s penny would be fall.
When a car of mass 1167 kg accelerates from 10.0 m/s to some final speed, 4.00 10 5J of work are done. Find this final speed.
Apply Newton's second law
[tex]\\ \tt\hookrightarrow F=ma[/tex]
[tex]\\ \tt\hookrightarrow F=1167(4)=4668N[/tex]
Now
[tex]\\ \tt\hookrightarrow W=Fd[/tex]
[tex]\\ \tt\hookrightarrow d=\dfrac{W}{F}[/tex]
[tex]\\ \tt\hookrightarrow d=\dfrac{105}{4668}[/tex]
[tex]\\ \tt\hookrightarrow d=0.022m[/tex]
Now
d be sAccording to third equation of kinematics
[tex]\\ \tt\hookrightarrow v^2=u^2+2as[/tex]
[tex]\\ \tt\hookrightarrow v^2=10^2+2(4)(0.022)[/tex]
[tex]\\ \tt\hookrightarrow v^2=100+8(0.022)[/tex]
[tex]\\ \tt\hookrightarrow v^2=100+0.176[/tex]
[tex]\\ \tt\hookrightarrow v^2=100.176[/tex]
[tex]\\ \tt\hookrightarrow v=10.001m/s[/tex]
A ball is dropped from the top of a building. When does the ball have the LEAST kinetic energy?
A: After it has hit the ground
B: Just before it hits the ground
C: Halfway through the fall
D: Just after it is released
Answer:
The answer is probably A
The area of a room that is 10 feet wide and 12 feet long is
13.3 square feet
14 square yards
120 square feet
12 squa2 yards
A lightening rod saves us from lightening give reason
Can you tell me by looking this book
Please fast
Answer:
Because Rod protect house from burning down and people from electrocution.
How much power does it take to do 400 joules of work in 5 seconds?
Answer:
Explanation:
Power = work / time
P = 400 J / 5 s
P = 80 watts
Jill runs for 20 seconds at 10 m/s, how far did she travel?
Answer:
200 (m) for 20 seconds
10 times 20 is 200
Answer:
200
Explanation:
Jill is running at 10 meters per second
20 * 10 = 200
3. What appears to be creating the magnetic field being represented here? How can moving the compass around confirm that? Why do you suppose the magnetic field surrounding the compass is not being represented by the simulation in this instance?
Movement occurs on the compass when there is magnetic field in the surrounding environment.
The movement of the needle appears which represents the presence of magnetic field. The moving compass around confirm that there magnetic field present in that region because the magnetic field is detected by the compass.
What is magnetic field?A magnetic field is invisible force which can be detected by a compass. A compass contains a small bar magnet which can rotate when it experience magnetic field around it so we can conclude that movement occurs on the compass when there is magnetic field in the surrounding environment.
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