The minimum speed of the car at the top of the loop for it to stay on track be 1.57 m/s.
What is speed?The speed of an item, which is a scalar quantity in everyday usage and kinematics, is the size of the change in that object's position over time or the size of the change in that object's position per unit of time.The speed at which an object's location changes in any direction.The distance traveled in relation to the time it took to travel that distance is how speed is defined.As a result, the fundamental unit of time and the basic unit of distance are combined to form the SI unit of speed. Thus, the metre per second (m/s) is the SI unit of speed.To learn more about speed refer to:
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A lighthouse that rises 49 feet above the surface of the water sits on a rocky cliff that extends 19 feet from the base. A sailor on the deck of a ship sights the top of the lighthouse at an angle of 30.0 degrees about the horizontal.
If the sailor’s eye level is 14 feet above the water, how far is the ship from the rocks?
If the sailor’s eye level is 14 feet above the water, So the ship from the rocks is 41.62 feet far from the sailor.
The main concepts required to solve this problem are the trigonometric properties and the distance. Later, use the tangent function and substitute the values. Finally, rearrange the tangent equation to calculate the distance of the ship from the rocks.
tan30.0°=35ft./19ft.+x
1/√3=35ft./19ft.+x
x=(35ft.) ([Equation]3)-19ft.
=41.62ft.
A tangent equation is an equation that describes a line that touches a given curve at a single point. It is usually expressed in the form y=mx+b, where m is the slope of the line and b is the y-intercept. To find the equation of a tangent, one must calculate the slope of the line at the point of tangency. This can be done by taking the derivative of the equation of the curve at that point.
The derivative will be the slope of the tangent, so this can be substituted into the tangent equation. The y-intercept can be found by plugging the x-coordinate of the point of tangency into the equation of the curve and solving for y. This will give you the y-intercept of the tangent equation. Through this process, one can find the equation of a tangent to any given curve.
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A 55 kg skater pushed by a friend accelerates 3 m/s2. How much force did the friend apply?
Answer: 165 N.
Explanation: To find out how much force was applied by the friend, you need to use the following formula:
F = ma where F is force, m is mass, and a is acceleration. Now we can plug in the values given.
F = 55 x 3 = 165
F = 165
The amount of force the friend applied is 165 N.
Hope this helps! :)
Explain why the speed of a competitor changes during the race. [4 marks]
AQA combined science physics paper 1 2022
The reason that speed of a competitor changes during the race is that
Physical conditionTerrainWeatherStrategyTacticsInjuryWhat is the race about?The speed of a competitor during a race can change for a variety of reasons. Some of the most common include the following:
Physical condition: A competitor's physical condition can change during a race, leading to a change in their speed. For example, a runner may start off strong but tire as the race progresses, causing their speed to decrease.
Terrain: The terrain of the race can also have an impact on a competitor's speed. Running uphill, for example, typically requires more effort and can slow a competitor down, while running downhill can allow them to pick up speed.
Weather: Weather conditions can also affect a competitor's speed during a race. Running in hot, humid conditions, for example, can make it more difficult for a competitor to maintain a high level of performance.
Strategy: Competing athlete has a strategy to maintain a sustainable pace which he could not change that often, it could lead to either decrease or increase in speed.
Tactics: Athletes may also adjust their tactics during a race in response to the competition. For example, a runner may slow down to conserve energy in the early stages of a race in order to have a stronger finish.
Injury: Sometimes, an injury can happen during a race and it can force the athletes to adjust their speed to adapt.
In all, the speed of a competitor during a race can change for a variety of reasons related to their physical condition, the terrain, weather, strategy, tactics and injury.
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2.1 The sketch below shows a large suitcase with a mass of 32 kg rests on a rough incline at an angle of 30 to the ground. 2.1.1 Define normal force in words. 2.1.2 Draw a labelled free-body diagram of all the forces acting on the suitcase. 2.1.3 Calculate the magnitude of the force of friction that keeps the suitcase stationery on the incline. (2) (3) (3) 2.1.4 Calculate the coefficient of static friction between the suitcase and the incline, if the suitcase is just about to move on the incline. (3)
Answer:
Explanation:
1) Normal force is the upward force applied by the ramp (incline) on the suitcase as the reaction to the downward force of the Weight (Fg) of the suitcase
2) sorry, can't supply a FBD. Brainly doesn't have drawing tools available.
3) Fg = mg = (32 kg)(9.8 m/s²) = 313.6 N
N= y-component of Fg = cos30(313.6 N) = 271.6 N
Ff = (coeff. friction)(N)
3) Ff = x-component of Fg = sin30(313.6) = 156.8 N
4) coeff. friction = Ff/N = 156.8N/271.6N = 0.58
Two speakers are driven by the same amplifier. The first speaker is placed in the origin, the second one is free to move along the x-axis (see figure). A receiver is placed on the on the y-axis, a distance L from the origin. The speakers emit sound at frequency f, the velocity of sound in the air is v. The second speaker is initially in the origin and it is the slowly moved toward the positive x-axis. Write the results in terms of L, f, and v.
a) What is the wavelength of the sound waves in the air?
b) Find the first position x of the second speaker at which the receiver does not get any sound (destructive interference).
c) Find the first position x of the second speaker at which the receiver gets maximum intensity (constructive interference). Exclude the x=0 position
The results in terms of wavelength, velocity, and frequency i.e (L,f,v) are as follow,.
(a) λ = v/f
(b) The value of the first minimum will be [tex]x =\sqrt{\frac{v^2}{4 f^2}+\frac{v L}{f}}[/tex]
(c) The position for the first maxima of 2nd speaker = [tex]$$x=\sqrt{\frac{v}{f}\left(\frac{v}{f}+2 L\right)}$$[/tex]
A waveform signal that is carried in space or down a wire has a wavelength, which is the separation between two identical places (adjacent crests) in the consecutive cycles. This length is often defined in wireless systems in meters (m), centimeters (cm), or millimeters (mm) (mm).
(a) Relation among velocity, wavelength and frequency can be defined the expression: v = fλ
From above, we can write, (λ) (wavelength) can be equal to velocity (v) / Frequency (f)
So, λ = v/f
(b) path difference can be determined by using the expression: [tex]\Delta x=x_2-x_1 \\[/tex]
[tex]\Delta x=\sqrt{L^2+x^2}-L\end{aligned}$$[/tex]
So, for the first minimum, we can conclude the following:
[tex]$\left\{n x=\frac{d}{2}=\frac{v}{2 f}\right.$$$\frac{v}{2 f}=\sqrt{L^2+x^2}-L$$[/tex]
[tex]\left(\frac{v}{2 f}+L\right)^2 & =L^2+x^2 \\\\x^2 =\frac{v^2}{4 f^2}+L^2+\frac{v L}{f}-L^2 \\\\x =\sqrt{\frac{v^2}{4 f^2}+\frac{v L}{f}}[/tex]
(c) for first order maxima
[tex]$$\begin{aligned}& \Delta x=\lambda \\& \frac{v}{f}=\sqrt{L^2+x^2}-L\end{aligned}$$[/tex]
[tex]$$\begin{aligned}x^2 & =\frac{v^2}{f^2}+L^2+\frac{2 V L}{f}-L^2 \\x & =\sqrt{\frac{v^2}{f^2}+\frac{2 v L}{f}}\end{aligned}$$[/tex]
So, the position for the first maxima of 2nd speaker will be:
[tex]$$x=\sqrt{\frac{v}{f}\left(\frac{v}{f}+2 L\right)}$$[/tex]
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The missing diagram is attached below:
Please explain what the above equation shows and justify your answer. Does this equation prove that gamma radiation cannot be produced by this type of nuclear decay? Please explain your answer.
This is not a gamma radiation because there is a change in the atomic number of the daughter nucleus. It is rather a beta decay.
What is a nuclear decay?We have to note that when we talk about a decay we are talking about the manner that we can be able to break up the atom of a radioactive substance so that we can be able to produce a new substance.
We can see now that what we have here is the loss of a beta ray or an electron from the specie that is shown. This is evidenced by the change in the atomic number of the daughters nucleus.
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when the time of day for a certain ship is 12 noon the time of day at the Prime Meridian is 5 p.m. what's the ship's longitude
The required longitude of the certain ship when the time of the day is 12 noon at the Prime Meridian is 5 p.m is 75° West.
The sun is highest in London, but will not pass the ship for another 5 hours.
Given that,
The time of day for a certain ship is 12 noon at the Prime Meridian is 5 p.m.
The ship must be five hours west of Greenwich since the sun goes from east to west.
Each hour of sun motion is 15° of longitude. The ship is located at (5 x 15°) = 75° West longitude.
Thus, the ship's longitude is 75° West.
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(ii) a large electroscope is made with "leaves" that are 78-cm-long wires with tiny 21-g spheres at the ends. When charged, nearly all the charge resides on the spheres. If the wires each make a 26° angle with the vertical (fig. 16–55), what total charge q must have been applied to the electroscope?
The electroscope must have received a total charge of 2.45 x q if the wires are each at a 26° angle with the vertical.
The electroscope is what?An electroscope is a scientific tool which is used to find the existence of an electric charge on a body. The first electroscope with a pivoting needle, known as a versorium, was created by British physician William Gilbert in the year 1600.
What are the many varieties of electroscope?An electroscope is a piece of equipment used in science to determine whether and how much electric charge is present on a body. There are three traditional electroscope types: the needle electroscope, the gold-leaf electroscope, and the pith-ball electroscope (third). For each of them, we have simulators available.
Briefing:Equilibrium condition = mgsin∅ = 2.45 x [tex]10^{-6}[/tex]
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A 2.5-kg cart is rolling along a frictionless, horizontal track towards a 1.3-kg cart that is held initially at rest. The carts are loaded with strong magnets that cause them to attract one another. Thus, the speed of each cart increases. At a certain instant before the carts collide, the first cart's velocity is 4.6 m/s, and the second cart's velocity is -1.8 m/s. (a) What is the total momentum of the system of the two carts at this instant
The required total momentum of the system at this instant is calculated to be 9.16 kg m/s.
Given that,
Mass of the first cart, m₁ = 2.5 kg
Mass of the second cart, m₂ = 1.3 kg
Velocity of the first cart before collision, u₁ = 4.6 m/s
Velocity of the second cart before collision, u₂ = -1.8 m/s
The total momentum of the system before collision is calculated as follows,
P t = P₁ + P₂
P t = m₁ u₁ + m₂ u₂ = 2.5 × 4.6 + (1.3 × -1.8) = 11.5 - 2.34 = 9.16 kg m/s
Thus, total momentum of the system of the two carts at this instant is 9.16 kg m/s.
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A certain light truck can go around a flat curve having a radius of 150 m with a maximum speed of 34.5 m/s. With what maximum speed can it go around a curve having a radius of 60.0 m
With 20.23 ms⁻¹, maximum speed can it go around a curve having a radius of 60.0 m
What's the maximum speed?The highest rate of speed a person can reach is called maximum speed. When athletes alter the magnitude (how quickly they are moving) or direction (or both) of their motion, or both, their acceleration changes as well since acceleration is related to velocity, which has both a magnitude and a direction connected with it.
ac max = V² max / R ....(1)
Inserting given values we get
ac, max = (34.5)² / 150 = 7.935 ms⁻²
For a changed radius of the curve of 60.0 m, the maximum safe speed from (1) becomes
Unew, max= √ac, max R new
Unew, max = √6.826 x 60
Unew, max 1 = 20.23 ms⁻¹, rounded to one decimal place.
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Of the following objects, on which one would time on its surface run most slowly?
a. An object with the same mass as the Sun but twice as large in radius
b. The Sun
c. An object with the same mass as the Sun but only half as large in radius
The time on the surface of an object would run most slowly on an object with the same mass as the Sun but twice as large in radius.
What is mass?
Mass is a measure of the amount of matter in an object and is typically expressed in kilograms (kg). It is an intrinsic property of matter and is different from weight, which is a measure of the force of gravity acting on an object. Mass is an important factor in determining the physical properties of an object, such as density, momentum, and inertia. Mass is also used to calculate the gravitational force between two objects, as well as the energy required to move it.
This is because the surface gravity of an object is inversely proportional to the square of its radius. Therefore, the object with the same mass as the Sun but twice as large in radius would have a much lower surface gravity, and time would run more slowly on its surface.
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A brain-imaging method using radio waves and magnetic fields of the body to produce detailed images of the brain is called __________.
Magnetic Resonance Imaging is a technique for producing precise pictures of the brain that uses radio waves and the magnetic fields of the body.
What imaging processes make use of magnetic fields and radio waves?A magnetic field and radio waves produced by a computer are used in the medical imaging procedure known as magnetic resonance imaging (MRI), which produces precise pictures of your body's organs and tissues.
Describe an MRI picture.The noninvasive medical imaging procedure known as magnetic resonance imaging, or MRI, creates precise pictures of virtually every internal bodily structure, including the organs, bones, muscles, and blood arteries. A sizable magnet and radio waves are used in MRI scanners to produce pictures of the human body.
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Calculate where an additional 15kg pile of bricks would need to be placed to balance the beam (shown below). Show all calculations.
Placing the diagonal of the square along the line of the first distance mark on the beam, place one square load, one unit of length, along the beam from the pivot. One square load should be placed on the opposite side of the pivot to roughly balance this.
Why do we employ beam balance?For calibrating masses between 10 mg and 1 kg, a beam balance is utilised. Depending on the calibre and sharpness of the knife edge used to make the pivot, a given measurement can be made with a given resolution and accuracy.
What is a balance in the body?A physical balance is essentially just a tool for gauging weight. With the aid of another object whose weight is known, it is used to determine the weight of any unknown object.
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The motion of particles in different states is difficult to observe. A student used computer software to represent the movement of particles in the solid state. Which type of scientific model did the student use
A simulation because it replicates a molecule's internal operation.
What causes the motion of atoms?Heat is the primary source of particle motion on Earth. The temperature of any substance is correlated with the energy of the atoms and molecules that comprise it. Energy is conserved, thus if one particle loses energy, another one acquires it.
What is the name for atomic movement?Translational motion is the term used to describe how an atom may travel from one place in space to another. Additionally, molecules composed of several atoms can vibrate because of chemical bonds, which cause the atoms to move about their equilibrium position like springs.
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4. What is the frequency of an electromagnetic wave if it has a wavelength of 1.0 km?
The radio wave's wavelength is 1.0 m. A waveform signal that is carried in space or down a wire has a wavelength, which is the separation between two identical places (adjacent crests) in the consecutive cycles.
Calculation:The following formula was used to determine the frequency:
radio wave speed, c = radio wave frequency / radio wave length
c = f x λ
Because a radio wave is an electromagnetic wave and travels at the same speed as light, its speed, c = 3 x 108 m/s, is equal to the speed of light in this case.
When the formula
3 x 108= f x 1.0
f = 3 x 108/1
f = 3 x 108 Hz is used,
Radio waves therefore have a frequency of 3 x 108 Hz.
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What is the torque on the lever?
The torque of a lever is equal to the perpendicular force multiplied by the length of the lever arm, which is the distance from the fulcrum of the lever.
Where can I find torque?The formula for torque is rF=rFsin(r). Torque is, in other words, the cross product of the distance vector (the distance between the pivot point and the point at which force is applied) and the force vector, where the angle 'a' between r and F is.
What is torque, and what is its SI unit?The SI unit for torque is the Newton-metre, or kgm2sec-2. Taking into account the formula Torque = Force X Distance While distance and force are measured in meters and newtons, respectively, torque is measured in newton-meters.
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To report the position of an object, first choose a reference point. Then, describe the of the object with respect to the reference point. Next, measure the from the reference point to the object.
We will understand the given concept through an example
The rat serves as your point of reference if you mentioned that the rabbit was to the left of it. You are expressing its position when you specify the distance and direction. The present separation and direction of an object from a reference point is its position.
When something moves with relation to a reference frame, like when a passenger gets off an airline or a lecturer gets up to leave, the object's position changes.the right in relation to a whiteboard. Displacement describes this shift in location.Every location helps you to achieve various location positions.Your position is defined by how you describe your place. The separation in the first illustration is one meter. The reference point helps to locate each and every point.To know more about reference point here
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Justine is ice-skating at the Lloyd Center. What is her final velocity if she accelerates at a rate of 2. 0 m/s for 3. 5 seconds?
2. How long would it take Jesse with an acceleration of -2. 50 m/s2 to bring his bicycle with an initial velocity of 13. 5 m/s to a complete stop?
When Justine is ice-skating, her final velocity if she accelerates at a rate of 2.0 m/s² for 3. 5 seconds is 7 m/s and it would take Jesse 5.4 seconds to stop the bicycle moving at an initial velocity of 13.5 m/s by accelerating at -2.50 m/s².
To find Justine's final velocity, we can use the equation:
v = u + at
where v is the final velocity, u is the initial velocity (which is assumed to be 0 in this case), a is the acceleration, and t is the time. So
v = 0 + (2.0 m/s²) × (3.5 s) = 7.0 m/s
To find the time it would take for Jesse to bring his bicycle to a stop, we can use the equation:
v = u + at
where v is the final velocity (which is assumed to be 0 m/s in this case as bicycle is brought to a stop), u is the initial velocity, a is the acceleration, and t is the time.
Given that a = -2.5 m/s² (negative sign indicates deceleration) and u = 13.5 m/s.
so t = (v - u) / a = (0 - 13.5 m/s) / -2.5 m/s² = 5.4 seconds
It would take Jesse 5.4 seconds to bring his bicycle to a complete stop.
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When there is no motion between objects, what is the relationship between the magnitude of the static friction, f, and the normal force, N?
The static friction and the normal force are related to each other as ≤.
Static friction is a force that prevents an item from moving. The friction encountered when persons attempt to move a stationary object on a surface without actually causing any relative motion between the body and the surface on which it is located. Static friction occurs between two fixed things, whereas kinetic friction occurs when two items move. Static friction varies while kinetic friction remains constant.
The normal force is the force exerted by surfaces to prevent solid objects from passing through them. A contact force is normal force. According to Newton's third law, this force on the platform must be followed by an equal and opposite force delivered to the man by the platform. This force is identical to the normal force.
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What is the wavelength of longitudinal wave
During a walk-around inspection, ensure there are no cracks on the brake drums that are more than ____ of the width of the friction area.
It's crucial to inspect the brake drums as part of your walk-around examination before setting off on a journey. If any brake drum has a crack that is more than half the breadth of the friction region.
What causes brake drums to crack?Overheating and undercooling of the brake pedal during operation might result in cracked drums.
What should you do if the brake drum develops a crack?Drums with cracks need to be changed right away. Blue ground -High temperatures, braking imbalance, abrupt stops, dragging brakes, or glazed brake pads can all result in blue drums. If no cracks have appeared, blue drums can still be utilized.
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How to solve this electrical circuit?
The resistor that is equivalent to the resistance of the circuit is 1 2/7 Ohms
What is an equivalent resistance of a circuit?The equivalent resistance of a circuit is the (single) resistance that can replace the combination of resistances in the circuit such that the current flowing in the circuit remains the same.
Please find attached the drawing of the circuit, created with an online circuit building tool.
Whereby the capacitor also acts as a resistor of 6 Ohms, we get;
Resistors R₄, R₅, and R₆ are parallel
The resistor equivalent to the three resistors is found as follows;
Req₁ = 1/(1/R₄ + 1/R₅ + 1/R₆)
Therefore, Req₁ = (1/(1/2 + 1/1 + 1/6)) = 0.6
Req₁ is in series with R₁, therefore;
Req₂ = Req₁ + R₁ = 0.6 + 3 = 3.6
Req₂, (Req₁ + R₁ combined) is parallel to R₂ and R₃, therefore;
Req₃ = 1/(1/Req₂ + 1/R₂ + 1/R₃)
Req₃ = 1/(1/3.6 + 1/3 + 1/6) = 9/7 = 1 2/7
The equivalent resistor of the circuit is 1 2/7 ohms
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A copper rod of length 0.77 m is lying on a frictionless table (see the drawing). Each end of the rod is attached to a fixed wire by an unstretched spring that has a spring constant of k = 76 N/m. A magnetic field with a strength of 0.14 T is oriented perpendicular to the surface of the table.
(a) What must be the direction of the current in the copper rod that causes the springs to stretch?
The current flows (left-to-right/right-to-left) in the copper rod.
(b) If the current is 14 A, by how much does each spring stretch?
________ m
Answer:
a) The direction of the current in the copper rod that causes the springs to stretch is left-to-right. This is because the magnetic field is oriented perpendicular to the surface of the table and the force exerted on the rod by the magnetic field is given by F = qVB, where F is the force, q is the charge of the particle, V is the velocity of the particle, and B is the strength of the magnetic field. Since the force is perpendicular to the velocity of the particle, the direction of the current that produces this force must be parallel to the magnetic field. In this case, the magnetic field is oriented perpendicular to the surface of the table, so the current must flow in the direction left-to-right to produce a force that stretches the springs.
b) To find by how much each spring stretches, you can use the formula F = kx, where F is the force exerted by the spring, k is the spring constant, and x is the distance the spring stretches. In this case, the force exerted by the spring is given by F = qVB, and the spring constant is k = 76 N/m. The charge of the particle is q = Ie, where I is the current and e is the charge of an electron. The velocity of the particle is V = L / t, where L is the length of the rod and t is the time it takes the particle to travel the length of the rod. Since the current is 14 A and the length of the rod is 0.77 m, the velocity of the particle is V = 0.77 m / (1 / 14 A) = 10.78 m/s. The strength of the magnetic field is 0.14 T, so the force exerted by the spring is F = (14 A)(1.60 x 10^-19 C)(10.78 m/s)(0.14 T) = 2.40 x 10^-17 N. Therefore, the distance each spring stretches is x = F / k = 2.40 x 10^-17 N / 76 N/m = 3.16 x 10^-19 meters.
an astronomer observes a magnitude 18 star, but needs 10 times as many. what's the faintest star he can see and still get enough photons.
As according Scientific American, even one photon can result in a visible burst of light.
How so many photons are necessary for you to see a star?The human eye can see about 10 photons.To an eye accustomed to the dark, the weak light may appear to be flashing, yet each twinkling just represents a few photons.When shooting images of the cosmos from orbit with very sensitive equipment at very low temperatures, a photon stream would be sufficient.
Can you see a single photon?The answer is yes because the receptors in the retina can respond to a single photon.However, brain filters only allow a signal to pass through and activate the brain when five to nine additional signals do the same in less than a hundred milliseconds.
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(TCO A) The primary reason for networking standards is to
Student Answer:simplify cost accounting for networks. Make it more difficult to develop hardware and software that link different networks. Ensure that hardware and software produced by different vendors can work together. Ensure that all network components of a particular network can beprovided by only one vendor. Lock customers into buying network components from one vendor
Make sure that software and hardware developed by various manufacturers can cooperate.
What exactly do vendors mean?A vendor is generally anybody who buys and sells goods or services. A vendor purchases products and services to resale them to different companies or individuals. Several different vendors provide the goods that big box stores like Target buy at deep discounts and then resale at higher retail rates.
The five major types of vendors are manufacturers, wholesalers, merchants, services and maintenance providers, independent vendors, and trade show representatives. Suppliers are sometimes referred to as the first link in a supply chain because they exclusively conduct business with other businesses. Contrarily, a vendor is a business or person that purchases things from a company and then sells them to another party.
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An airplane starts from rest and accelerates at a constant 3.00 m/s2 for 30.0 s before leaving the ground. a. How far did it move
The airplane that starts from rest and accelerates at 1 constant 3 m/s2 for 30 s before leaving the ground moved by the distance of 1350m.
Acceleration is given as 3.00 m/s2
Time is 30 sec.
The formula we can use in this case is:
s = ut + 0.5 at^2
v = at + u
where,
s is distance travelled
u is initial velocity = 0 since at rest
t is time travelled
a is acceleration
v is the final velocity when it took off
a. s = 0 + 0.5 * 3 * 30^2
s = 1350 m
The distance moved by the airplane is 1350 m.
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The hammer throw is a track-and-field event in which a 7.1-kg ball (the ''hammer''), starting from rest, is whirled around in a circle several times and released. It then moves upward on the familiar curving path of projectile motion. In one throw, the hammer is given a speed of 26.0 m/s. For comparison, a .22 caliber bullet has a mass of 2.6 g and, starting from rest, exits the barrel of a gun with a speed of 403 m/s. Determine the work done to launch the motion of both the hammer and the bullet.
The work done to launch the motion of both the hammer and the bullet are 3.1×10³ Joule and 2.2×10² Joules respectively.
As we know,
Work = Kinetic Energy
= (0.5)(mv^2)
For Work in Joules, the mass is in units of Kg, and the velocity is in units of m/s.
KE(hammer) = 1/2mv^2 = 1/2 x 7.3 x (29)^2 = 3.1 x 10^3 J
and KE(bullet) = 1/2mv^2 = 1/2 x 2.6 x 10^-3 x (410)^2 = 2.2 x 10^2 J
To solve this problem, we must assume that energy is conserved. (This isn't stated in the problem, and is not true in general in these real-world examples, however we must assume conservation of energy in order to solve the problem with the information given).
When an object moves while a force is being exerted on it, then work is being done on the object by the force. If an object moves through a displacement d while a constant force F is acting on it, the force does an amount of work equal to W = F · d = F d cos φ where φ is the angle between d and F.
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The scale on a map states that 1 centimeter corresponds to 20 kilometers. On the map, two cities are 0.3 cm apart. Find the actual distance.a.6 kmc.0.6 kmb.600 kmd.60 km
The actual distance is 6 km. The solution to the problem is as follows: By ratio and proportion: 1:20 = 0.3:x, Cross multiplying: 20(0.3) = x, x = 6
Therefore the answer is the first choice or letter A which is 6 km.
How would a surface without friction feel?It just seems slick, almost like touching ice but without the frigid sensation, according to my firsthand experience of both. Sorry, it's really nothing exceptional. Any surface would be sufficient if it had some lubrication oil on it.
Is there any surface in the world without friction?In reality, there are no frictionless planes. If they did exist, items on them would almost certainly behave exactly as Galileo predicted if they did. Despite not existing, they are extremely valuable for designing things like engines, motors, roads, and even tow truck beds, to mention a few.
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The chord of a circle of radius 5 cm subtends a right angle at its centre. Find the length of the chord (in cm).
The length of the chord of the circle in cm will be equal to 7.07cm.
A chord can be defined as that line segment which joins any two points on the circumference of a circle. The chord of a particular circle is subtending a 90° angle at its center. The radius of the circle is OA = OB =5cm.
To find the length of the chord AB, we use the Pythagorean Theorem
OA² + OB² = AB²
⇒ 5² + 5² = AB²
⇒ AB = √50 = 7.07 cm
The length of the chord AB is equal to 7.07cm.
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A plane can fly 3952 kilometers in 3 hours. If the plane flies in
cloudy skies, it can fly 184 less kilometers than usual within the
same time. What is the speed for the plane flies in cloudy
skies?
km/h
Speed is a scalar quantity that is independent of direction. It is equal to the total distance traveled divided by the total time spent. This means that a plane can normally travel 3952 kilometers in three hours.
How is the total distance traveled calculated?Step 1: Make a note of each time the direction changes. Step 2: Determine the distance traveled between each change in direction. Step 3: The total distance traveled is the sum of all the distances from step 2.
As a result, its typical speed is Speed = total distance / total time Speed = 3952 / 3 Speed = 1317.33 km/h.
However, under cloudy conditions, it will travel 184 km less in the same amount of time.
Then, we want to determine the speed under cloudy conditions. Since speed is equal to the total distance divided by the total amount of time, we need to know the total distance under cloudy conditions.
Total distance is equal to the normal distance traveled minus the delay caused by cloudy conditions Total distance. = 3952 - 184 Total distance = 3768 km Total time = 3 hours Speed = 3768 / 3 Speed = 1256 km/hr The plane is traveling at a speed of 1256 km/hr in cloudy conditions. Because it covered less ground in the same amount of time, its speed decreases.
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