A toy rocket is launched from the ground, the equation
h= -16t^2+ 80t, models the height of the rocket h in feet at any timet
in seconds.
For which interval of time will the rocket be higher than 64 feet off the
ground?
Answers
Answer:
Step-by-step explanation:
We can graph the function and determine the points where the y value line is greater than 64 feet. We could also solve the equation for h = 64.
Graphing:
A graph is attached. The intersections of the line at height = 64 feet are at (1,64) and (4,64). The first is going up and the second coming down. The period of time the rocket is above 64 feet is from 1 to 4 seconds.
Solving:
h= -16t^2+ 80t
64 = -16t^2+ 80t
-16t^2+ 80t - 64 = 0
Solve using the quadratic formula:
We get two answers: 1 and 4 (seconds)
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