The pressure drop across the turbine if it delivers 60 kw is 75.4KPa.
The task of providing usable output shaft power to drive the propeller falls on the turbine section of the gas turbine engine. It must also deliver energy to run the compressor and other engine accessories. This is accomplished by expanding the gas at high pressure, temperature, and velocity and transforming the resulting gaseous energy into mechanical energy in the form of shaft power.
The turbine needs a significant volume of air to generate the required amount of electricity. The compressor provides this volume of air by pulling it into the engine and compressing it to provide high-pressure air for the turbine.
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The major advantage of using compound joint snips over a single joint tool is increased. A. Keep tension on the blade when not in use. B. you can begin the cut with a file. C. Apply pressure on the return stroke. D. don't apply pressure on the forward stroke
The major advantage of using compound joint snips over a single joint tool is option B: you can begin the cut with a file.
What are compound action snips used for?Standard compound-action snips are known to be a form of a hand tool that is said to be made to cut steel or softer materials, yet it is not harmful to use them sometimes on stainless steel.
Note that the key or the major merit or benefit of using compound joint snips than the use of a single joint tool is due to the fact that a person can be able to use it to cut a lot of steel.
Hence, option B is correct.
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superheated steam at 575'c is routed from a boiler to the turbine of an electric power plant through steel tubes (k ! 35 w/m!k) of 300-mm inner diameter and 30-mm wall thickness. to reduce heat loss to the surroundings and to maintain a safe-to-touch outer surface temperature, a layer of calcium silicate insulation (k ! 0.10 w/m!k) is applied to the tubes, while degradation of the insulation is reduced by wrapping it in a thin sheet of aluminum having an emissivity of ) ! 0.20. the air and wall temperatures of the power plant are 27'c
For applications involving fire resistance and the insulation of high-temperature pipelines and machinery, calcium silicate (CalSil) is employed. Prefabricated block, preformed pipe, and board are the three distinct ways it is produced and offered for sale.
Calcium silicate's insulating properties are due to the millions of microscopic air holes that are separated by crystalline walls with low thermal conductivity. It is a good high-temperature insulation material since very little infrared radiation may flow through it. To achieve fire endurance, calcium silicate, often known as "calsil," is used to insulate high temperature pipes and equipment. Prefabricated block, preformed pipe, and board are the three distinct ways it is produced and offered for sale. Table salt and other foods are prepared with calcium silicate as an anti-caking agent and as an antacid.
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A doctor is deciding how to treat a given disease. the doctor will precribe one medication, one dietary change, and one type of vitamin supplement. there are five medications, five dietary changes, and five types of vitamins the doctor might prescribe. how many combina-tions are possible?
The total combinations are possible is 125 combinations.
We need to know about math combinations to solve this problem. The combination is the number of ways to choose a sample of r elements from a set of n distinct objects where order does not matter and replacements are not allowed. It can be written as
nCr = n! / (r!(n-r)!)
where n is object and r is a sample
From the question above, we know that
1 vitamin supplement chosen has combination
5C1 = 5! / 1!(5-1)! = 5 combination
1 meditation chosen has combination
5C1 = 5! / 1!(5-1)! = 5 combination
and 1 dietary chosen has combination
5C1 = 5! / 1!(5-1)! = 5 combination
Hence, the total combination is
C = Cvitamin x Cmeditation x Cdietery
C = 5 x 5 x 5
C = 125 combinations
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5.12 an evaporative cooling tower (see fig. p5.12) is used to cool water from 110 to 80 °f. water enters the tower at a rate of 250,000 lbm/hr. dry air (no water vapor) flows into the tower at a rate of 151,000 lbm/hr. if the rate of wet airflow out of the tower is 156,900 lbm/hr, determine the rate of water evaporation in lbm/hr and the rate of cooled water flow in lbm/hr.
The rate of cooled water flow in lbm/hr is 244100 lbm/hr.
We need to know about the mass rate to solve this problem. The rate of cooled water will be the same as the rate of water enters the tower minus by the wet water releasing to the air.
m' cooled water = m'water - m'released
From the question above, the given parameters are
m' water = 250000 lbm/hr
m'dry air = 151000 lbm/hr
m' wet air = 156900 lbm/hr
Find the rate of water released to the air
m'released = m'wet air - m'dryair
m'released = 156900 - 151000
m' released = 5900 lbm/hr
Calculate the rate of cooled water flow
m' cooled water = m'water - m'released
m' cooled water = 250000 - 5900
m' cooled water = 244100 lbm/hr
Hence, the rate of cooled water flow in lbm/hr is 244100 lbm/hr.
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a 25-mm-diameter shaft is statically torqued to 230 nm. it is made of cast 195-t6 aluminum, with a yield strength in tension of 160 mpa and a yield strength in compression of 170 mpa. it is machined to final diameter. estimate the safety factor of the shaft
An estimate of the safety factor of the shaft is 1.10
We have the following:
Torque=230nm
Diameter=25mm
Yield tension=160mpa
Yield compression=170mpa
To estimate the safety factor of the shaft, we will have to find first the following:
Maximum shear stress:
Shear stress=[tex]\frac{16T}{\pi d^{3} }[/tex]
= [tex]\frac{16*230}{\pi *(25mm*\frac{10^{-3}m }{1mm})^{3} }[/tex]
=75MPa
We, now get the principle stress:
σ[tex]_{1}[/tex]=75MPa
σ[tex]_{2}[/tex]=-75MPa
The torsional yield strength:
Torsional yield strength=(yield strength in tension*yield strength in compression)/(yield strength in tension +yield strength in compression)
=(160*170)/(160+170)
=82.4MPa
Now, we can calculate the factor of safety using this given relation:
Factor of safety=(Torsional yield strength/Maximum shear stress)
=82.4MPa/75MPa
=1.0987
=1.10
Safety factor of the shaft, n=1.10
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Write a function named reverse that accepts a dictionary from integers to strings as a parameter and returns a new dictionary of strings to integers that is the original's "reverse". The reverse of a dictionary is defined here to be a new dictionary that uses the values from the original as its keys and the keys from the original as its values. Since a dictionary's values need not be unique but its keys must be, it is acceptable to have any of the original keys as the value in the result. In other words, if the original dictionary has pairs (k1, v) and (k2, v), the new dictionary must contain either the pair (v, k1) or (v, k2).
A function named reverse that accepts a dictionary from integers to strings as a parameter and returns a new dictionary of strings to integers that is the original's "reverse" is given below:
The Function# Function to create an empty stack. It
# initializes size of stack as 0
def createStack():
stack = []
return stack
# Function to determine the size of the stack
def size(stack):
return len(stack)
# Stack is empty if the size is 0
def isEmpty(stack):
if size(stack) == 0:
return true
# Function to add an item to stack . It
# increases size by 1
def push(stack, item):
stack.append(item)
# Function to remove an item from stack.
# It decreases size by 1
def pop(stack):
if isEmpty(stack):
return
return stack.pop()
# A stack based function to reverse a string
def reverse(string):
n = len(string)
# Create a empty stack
stack = createStack()
# Push all characters of string to stack
for i in range(0, n, 1):
push(stack, string[i])
# Making the string empty since all
# characters are saved in stack
string = ""
# Pop all characters of string and put
# them back to string
for i in range(0, n, 1):
string += pop(stack)
return string
# Driver code
s = "Geeksforgeeks"
print("The original string is : ", end="")
print(s)
print("The reversed string(using stack) is : ", end="")
print(reverse(s))
The OutputThe original string is : Geeksforgeeks
The reversed string(using stack) is : skeegrofskeeG
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a portion of the keystone pipeline connecting oil production in canada and refining in the united states consists of a 0.76 m diameter pipe that carries 500,000 bbl of crude oil per day over a distance of 1744 km. calculate the average velocity (in m/s) of the oil in the pipe. hint: 500,000 bbl of oil has a volume of (500,000 bbl)×(158.97 l/bbl)/(1000l/m^3)
The average velocity (in m/s) of the oil in the pipe is 2.04m/s.
What is the velocity?It should be noted that from the information, the oil that is transported on a day = 500000 bbl. Based on the information given, this is equal to 79491.256 cubic meter.
It should be noted that the flow rate will be calculated as:
= Oil transported / Time taken
= 79491.256 / (24 × 60 × 60)
= 0.92m³ per second
It should be noted that the area will be calculated as:
A = πr²
where
π = 3.14
r = radius = Diameter / 2 = 0.76/2 = 0.38
Area = πr² = 3.14 × (0.34)² = 0.45m²
Now, the velocity will be calculated thus:
= Flow rate / Area
= 0.92 / 0.45
= 2.04m/s
In conclusion, the velocity is 2.04m/s.
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an equal-tangent crest vertical curve connects a 2% initial grade with a -1% final grade, and is designed for 55mph. that station of the pvi is 233 40, with an elevation of 1203 ft. what is the elevation of the curve at station 234 00?
Equal-tangent crest vertical curve connects a 2% initial grade with a -1% final grade, and is designed for 55mph. that station of the pvi is 233 40, with an elevation of 1203 ft. the elevation of the curve at station 234 00 is 1202.102 ft
G1=+2%, Gz\s=-1%
Grade variance in absolute terms equals A = (G1 - G2) = (2 + 1) = 3%
V = 55 mph is the design speed.
V = 55 mph requires a stopping sight distance of SSD = 492.4 feet.
Assume SSD > Curve Length.
L=2SSD - 2158/A = 2x492.4 - 2158/3 = 265.47 ft Station of PVI = stapvi = 233 + 40 = 23340 ft
PVC Elevation = stave - stapvi - L/2 = 23340 - 265.47/2 = 23207.765 ft PVI Elevation = elevpri = 1203 ft
PVC's elevation is equal to elevpri- - GI(L/2) = 1203 - 0.02(265.47/2) = 1200.345 ft.
According to this theorem, if two tangents are traced to a circle from a single exterior point, their tangent segments must be equal. A tangent segment is a line that connects the external point and the tangency point.
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A comparison of parking fee changed at 4 randomly selected parking areas were 12 15 17 and 20 pesos per car find the mean the variance of the parking fees
The calculated mean value is 16. The sum of all values divided by the total number of values determines the mean (also known as the arithmetic mean, which differs from the geometric mean) of a dataset.
The term "average" is frequently used to describe this measure of central tendency. By dividing the sum of the given numbers by the entire number of numbers, the mean—the average of the given numbers—is determined. Mean is equal to (Sum of All Observations/Total Observations).
Mean=12+15+17+20/4
=16
Special road signage designate 10-cent zones. At the beginning and finish of the zone, there are signs. There is one space available for as long as three or four hours each day. Only specific hours of the day are subject to the 10 cent rate. There may be a Blue Zone in locations where paid parking is not (yet) in effect.
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Which of the following accurately describes the 5 why's accident investigation technique
According to the information, it can be inferred that the correct option is that the term 5 why's accident investigation technique refers to an interrogative technique to identify the causes and effects related to a problem (option B)
What is the 5 whys technique?5 Whys is a term that refers to an investigative technique used to identify cause and effect relationships related to a specific problem. This investigative technique is generally used in the work environment to identify the origin of an accident at work or production problems and was developed by Sakichi Toyoda.
This technique is mainly based on asking 5 times "Why?" to identify the root of the problem. For example:
The problem: An accident at work that causes an employee to break his armWhy did the employee fall? - Because there was a puddle of oil on the floorWhy was there a puddle of oil on the floor? - Because another employee dropped a bottle full of oilWhy did the other employee drop a bottle of oil? -Because he heard an explosion in the cellar next door and got scared.Why did he hear an explosion in the cellar next door? - Because one of the machines was damaged and exploded.Why did the machine explode? - Because it has not been maintained for more than 4 years.According to the above, it can be inferred that the correct answer is the option that refers to the 5 questions related to the cause and effect of a problem (option B).
Note: This question is incomplete because there is some information missing. Here is the complete information:
A. 5 questions for a job interview
B. 5 questions related to the cause and effect of a problem
C. 5 questions related to diseases in animals
D. 5 questions about injuries in athletes
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In basic spatial layout of a residential building, arrows can be added to show traffic patterns and the ________ of the arrows corresponds to the volume of traffic.
In basic spatial layout of a residential building, arrows can be added to show traffic patterns and the direction of the arrows corresponds to the volume of traffic.
Road markings known as "sharrows" or "shared lane markings" (SLMs) are used to designate a shared lane environment for cars and cyclists. Along with other advantages, shared lane markings support the validity of bicycle traffic on the roadway, advise optimal posture for cyclists, and can be set up to provide directional and navigational information. The shared lane marking is a pavement marking that can be used for a number of different purposes to support a full network of bikeways; it is not a facility type and should not be used in place of bike lanes, cycle tracks, or other separation treatments when such facilities are otherwise necessary or feasible.
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When two batteries are connected as a series additive power source, they produce a voltage that is less than either of the batteries connected by itself. True or false?.
A voltage that is lower than either of the batteries linked alone is produced when two batteries are connected in series to create an additive power source.
The sum of the separate voltages when voltage sources are coupled in series results in the total voltage. Voltage dips in a series circuit are additive, as was previously mentioned. Voltage decreased across a resistor is referred to as a voltage drop. The voltage drop across a resistor increases along with the resistor's resistance. The sum of the individual resistances in a series circuit is the overall resistance. To get the amperage in a series circuit, you must compute the circuit's overall resistance.
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question 3: washing machines does the price of an appliance convey something about its quality? washers are classified as top-load high efficiency (he), top-load agitator, and front-load washers. the best front-loaders clean better and are gentler than the best he top-loading washing machines while using less water. front-loaders take longer than he top-loaders but spin faster, extracting more water, and reducing dryer time. fifty-four different front-loading washers were ranked on characteristics ranging from an overall satisfaction score, washing performance (x1) , energy efficiency (x2) , water efficiency (x3) , gentleness (x4) , noise (x5) , vibration (x6) , capacity (x7) , and cycle time (x8)
Answer: that’s too much for me
Explanation:
Waa
Instantaneous rate of change what is it called in terms
Determine numerical values for each of the three mesh currents as labeled in
the circuit diagram of Fig. 4.58.
The numerical values for the mesh currents that we have in the question are given as:
1i = 0.9892 = 0.9892 amperei2 = 0.1501 amperei3 = 0.1570 ampereHow to solve for the values of the mesh currentWe first have to write the KVL
2 - 1(i₁ - i₂) + 3 - 5(i₁ - i₃) = 0
We have to expand the equation that we have above
2 - i₁ + i₂ + 3 - 5i₁ + 5i₃ = 0
take like terms
-i₁ - 5i₁ i₂ + 5i₃ = 5
= 6i₁ - i₂ - 5i₃ = 5
-1(i₂ - i₁) - 6 i₂ - 9(i₃ - i2) = 0
after expanding we would have
i₁ - 16i₂ + 9i₃ = 0------- equation 2
-5 (i3 - i1) - 3 - 9(i3 - i2) - 7i3 = 0
5i1 + 9i2 - 2i3 = 3 ------ equation 3
From the equations that we have in 1, 2 and 3, we would solve the system of equations to get
1i = 0.9892 = 0.9892 ampere
i2 = 0.1501 ampere
i3 = 0.1570 ampere
These are the mesh current that are in the labeled diagram.
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A performance (HC) curve for a given centrifugal pump shows that
A. Flow rate increases as the head required to overcome system resistance increases
B. Flow rate decreases as the head required to overcome system resistance increases
C. Flow rate is constant regardless of the head required to overcome system resistance
D. Pump head is constant regardless of flow rate
A performance (HC) curve for a given centrifugal pump shows that option B. Flow rate decreases as the head required to overcome system resistance increases.
How does the centrifugal pump perform?The Centrifugal pump curves are helpful because they display metrics for the performance of the pump based on the head (pressure) the pump produces and the water flow through the pump. Impeller diameter, head, as well as the pump speed all affect flow rates.
Note that an instrument that predicts a pump's head and flow performance is a centrifugal pump performance curve. Pumps provide low volume flow rates when pumping against high-pressure heads and high volume flow rates if they are said to be pumping against low-pressure heads.
Therefore, one can say that every centrifugal pump has a curve that it follows in order to function, and every curve has a start point (the shut-off or zero flow) and an end point (the end-of-curve or the maximum flow that can be achieved without overtaxing the motor).
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technician a says that the torque multiplication phase can occur when the stator one-way clutch begins to freewheel. technician b says that the torque multiplication phase can occur when the stator one-way clutch locks up. who is correct?
The correct statement is technician B, that says if the torque multiplication phase can occur when the stator one-way clutch locks up.
Torque multiplication can be defined as a multiplying factor that is used to determine how much added torque is being applied to a vehicles drivetrain. Torque multiplication is calculated with scientific and mathematical precision by rationalizing factory power against all influential physical forces.
In multiplying torque, the stator’s one-way clutch plays an important role. Vortex flow is the fluid circulating between the impeller and the turbine. Vortex flow exists only when there is a difference in rotational speed between the impeller and turbine.
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where a four-foot section of listed flexible metal conduit is installed in a rigid metal conduit run in a class i, division 2 location for a circuit rated at 30 amperes, equipment bonding jumpers are not required because the flexible metal conduit is less than six feet in length.
The overall specifications for electrical system bonding and grounding, for both grounded and ungrounded systems, are set forth in Section 250.4.
The service disconnecting equipment must be located either outside of a building or within, close to the point where the service conductors enter. Equipotential planes must be connected to the grounding system for electrical equipment.
The equipment grounding conductor must be one, more, or a mix of the following when it is run with or around the circuit conductors: a conductor made of copper, aluminum, or copper-clad aluminum. This conductor must take the form of a wire or a busbar and can be solid, stranded, insulated, covered, or bare.
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air enters a compressor steadily at 1 bar, 290k, and 6 m/s through an inlet duct with an area of 0.1 m2. air exits the compressor at 7 bar, 450k, and 2 m/s. there is heat loss from the compressor at a rate of 180 kj/min. determine the power required to drive the compressor in kw
The compressor's efficiency must be taken into account; it is equivalent to 0.72, resulting in a needed power of 156*0.72 = 216.8 kW.
The compressor motor nameplate on the majority of industrial three phase air compressors will indicate the line voltage, which is commonly 240 V or 480 V. In our experience, the power factor of 50 to 150 horsepower compressors is approximately 85% when operating normally1. The amount of air the device can pump out is known as the compressor capacity. Compressor capacity and pressure may be easily distinguished from one another since the former reveals "how much" and the latter measures "how strong." the proportion between the maximum compressor load and the average compressor load for a given time period.
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How many times will be body of the FOR loop execute. (note the semicolon at the end of FOR statement
for (int i=0; i<20;i++);
{
//body of for loop
}
O Syntax error
O 20
O 21
O Infinite Loop
will save this response
Answer:
Explanation:
code in the curly braces is treated as regular body and will be executed normally
superheated steam, with a state of 450 ∘c, 1.8 mpa , flows into an adiabatic mixing chamber at a rate of 0.31 kg/s . a second stream of dry, saturated water vapor, at 1.8 mpa , enters the chamber at a rate of 0.15 kg/s . there is no pressure loss in the system and the exit pressure is also 1.8 mpa .
Under normal relief conditions, where 10% accumulation is used, the permitted pressure drop in discharge pipe from the safety valve in vapor service is 10% of the set pressure, and under emergency fire conditions, where 20% accumulation is used, it is 20% of the set pressure
When calculating the size of the outlet piping, these influences must be considered since the pressure drop in the outlet piping affects the set pressure of a conventional safety relief valve and also affects the capacity of both a conventional and a bellows relief valve. If a pressure drop considerably impacts the set pressure or capacity of the relief valve, the discharge pipe from safety valves in liquid service must be raised. It cannot be smaller than the outlet connection on the safety valve.
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Hardened steel cutting edges honed with a/an
A. oilstone
B. Swiss cut file
C. emery block
D. riffler file
Hardened steel cutting edges honed with option A: An oilstone.
Check more about Honed edge below.
What is a honed edge on a cutting tool?
In order to significantly increase the flake and wear resistance of cutting tools constructed from brittle materials like carbide, edge honing, also known as edge rounding, that is its stabilizes the cutting edge.
Therefore, To hone a chisel, a person need to place a little amount of oil on an oilstone. Here, one need to place the back of the said chisel blade flat on top of the stone and then one can gently rub it very well.
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refrigerant 134a enters a water-jacketed compressor operating at steady state at -10°c, 1.4 bar, with a mass flow rate of 4.2 kg/s, and exits at 50°c, 12 bar. the compressor power required is 150 kw. neglecting kinetic and potential energy effects, determine the rate of heat transfer to the cooling water circulating through the water jacket
The load-carrying capacity of a system above and above what the system actually supports is a safety factor. Ultimate Load (Strength)/Allowable Load = Factor of Safety (Stress).
All structures, including bridges, buildings, safety gear, and fall protection, begin with a factor of safety. The safety factor, defined simply, is how much more robust a system is than necessary. In mechanical engineering, the ratio of material strength to allowed stress is known numerically as the factor of safety. For instance, let's say that a shaft needs to be able to support a 100 kg load. However, if our shaft is built to support a 200 kg load. The value of the Shaft safety factor is "two." When a structure or component has a FoS of 1, it signifies that it will fail exactly at the design load and cannot support any additional load.
The complete question is- The steel pipe is supported on the circular base plate and concrete pedestal. The applied force is 500 KN and the normal failure stresses for steel and concrete. The thickness of the pipe is t = 5 mm and the base plate has a radius of 150 mm. a) Determine the factor of safety against failure of the steel. b) Determine the factor of safety against failure of the concrete.
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the wood innovation design center was conceived as a showcase for the structural potential of timber, replacing steel and concrete as primary building materials.the meti handmade school was designed using mostly local materials, including bamboo, cob, clay, earth, sand, straw, and water.
This prompt is about Prince George's Wood Innovation Design Center. The building was erected as a model to highlight the possibilities of wood innovation and a departure from conventional concrete and steel architecture and building engineering models.
Why is the Wood Innovation Design Center Important?The Wood Innovation Design Centre (WIDC) is a meeting space for researchers, educators, and design professionals who are brainstorming new ways to use wood. The bottom floors of the building are dedicated to Integrated Wood Design instruction.
The Wood Innovation and Design Centre is located in Prince George, British Columbia. Michael Green Architecture ("Wood Innovation and Design Centre" n.p.) designed the 97-foot-tall, eight-story (six-story includes mezzanine and penthouse) structure.
The building's sleek, contemporary box shape is purposefully simple. Its simplicity serves as a canvas for the beauty of the numerous kinds of wood and their features, which include Douglas-fir, western red cedar, hemlock, pine, and spruce from British Columbia's sustainable forests.
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4 two balanced three-phase loads that are connected in parallel are fed by a three-phase line having a series impedance of (0.4 1 j2.7) ω per phase. one of the loads absorbs 560 kva at 0.707 power factor lagging, and the other 132 kw at unity power factor. the line-to-line voltage at the load end of the line is 2200 ï3 v. compute (a) the line-to-line voltage at the source end of the line, (b) the total real and reactive power losses in the three-phase line, and (c) the total three-phase real and reactive power supplied at the sending end of the line. check that the total three-phase complex power delivered by the source equals the total three-phase complex power absorbed by the line and loads
The line to line voltage is 4160. The real power loss is 12 Kva , the reactive power loss is 81 Kvar. The total real power supplies is 540 kVa. The total reactive power supplied at the end of line is (540 + 477j)
a. How to solve for the line to line voltageThe first calculation is the per phase line to node voltage.
= 2200√3 / √3
= 2200 V
Next is three-phase complex power absorbed by load 1
560 x 10³ ∠cos-1(0.707)
= 560 x 10³∠45
Then we would have
(396 + j396)kva
We have S2 = 132kva
next is the total complex load calculation
(396 + j396 + 132)kva
= 528 + j396 kva
= 660 ∠36.87 degrees kva
total current that is in the line
= 660 x 10³ ∠-36.87 / 3 x 2200
= 100 ∠ -36.87 degrees kva
Using the voltage law of Kirchoff
E1 = E2 + ZLI
= (2200 + 0.4 + j2.7)100 ∠ -36.87
= 2200 ∠0 + (2.73 ∠ 81.57)(100 ∠ -36.87)
=2401∠4.5 degrees
√3 x 2401
= 4160
b. Total real and reactive loss
= 3 x (.4 + 2.7j)(100 x100)
= 30x10^3)(.4 + 2.7j)
= 12 + 81 j
find the real power loss
p = 12 kw
total power loss is 12 kw
The reactive power loss is 81 Kvar
c. total 3 phase power
2401.7∠4.58 and 100∠36.87
= 3(2401.7∠4.58 x 100∠36.87)
= (540 + 477j)
the total real power is 540 kW
The total complex power of load and line
(396 + j396)kva + 132 + (12 + 81j)
= (540 + 477j)
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Give reasons why it is difficult to accurately determine the amount of carbon released from terrestrial ecosystems that are as a result of land-use change
Calculating the carbon footprint is difficult because of a lack of knowledge of all the factors of carbon emission on land.
Imagine drinking concentrated orange juice endlessly. because surely this is the best way to lose weight. Orange juice is recommended in moderation, but doctors are not the first to recommend it to people trying to lose weight.
Just as we don't want people to believe that more orange juice is the solution to the obesity pandemic, we don't want people to believe that the best way to fight climate change is to recycle more.
Recycling and blackouts are great steps towards a more sustainable society, but nothing is more important to the climate than reducing meat consumption, air travel, and driving.
People with good intentions often make the wrong decisions when it comes to reducing their carbon footprint.
For example, a test was conducted in which participants were selected and then the participants were then presented with 15 behaviors and asked to classify the behavior as low, medium, or high (with low representing less than 1% of a person's carbon footprint and high representing more than 5%).
Passenger car behavior is rightly regarded as critical in reducing greenhouse gas emissions.
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The reasons why it is hard to accurately determine the amount of carbon released from terrestrial ecosystems is that they are linked to sensitivity analysis and bias brought about by satellite data gap filling.
Additionally, the algorithms used for remote sensing do not effectively take into consideration environmental pressures such rooting depth, particularly in dry locations where plants depend on deep roots to access and maintain water availability.
What are the limitations about?The timing and size of terrestrial NPP are controlled by a variety of environmental factors on a global scale, such as climate, topography, as well as soils, plant and other forms of microbial characteristics, etc.
However, the relative contributions of these environmental factors to global NPP change over time and space. Globally, climatic change, including variations in temperature and precipitation, had a marginally favorable effect on NPP between 1982 - 1999.
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the steel pipe is supported on the circular base plate and concrete pedestal. the applied force is 500 kn, and the normal failure stresses for steel and concrete are (σfail)st
A safety factor is the amount of weight that a system can bear over and beyond what it can actually support. Factor of Safety = Ultimate Load (Strength)/Allowable Load (Stress).
Every structure, including buildings, bridges, safety equipment, and fall protection, starts with a safety factor. Simply put, the safety factor is how much more robust a system is than required. The safety factor is a numerical term used in mechanical engineering to describe the relationship between material strength and allowable stress. Let's take the example of a shaft that must be able to support a 100 kg load. Nevertheless, if our shaft is designed to hold a 200 kg load. The Shaft safety factor has a value of "two."
The complete question is- The steel pipe is supported on the circular base plate and concrete pedestal. The applied force is 500 KN and the normal failure stresses for steel and concrete. The thickness of the pipe is t = 5 mm and the base plate has a radius of 150 mm. a) Determine the factor of safety against failure of the steel. b) Determine the factor of safety against failure of the concrete.
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a designer requires a shunt regulator of approximately 20 v. two kinds of zener diodes are available: 6.8-v devices with r, of 100 and 5.1 -v devices with r, of 25 n. for the two major choices possible, find the load regulation. in this calculation neglect the effect of the regulator resistance r.
The load choices that are available in the question are:
three 6.8v zeners that would give 3 x 6.8-20 volts. This has the resistance of 30 ohms.The four 5.1 V zeners that would provide 4 x 5.1 20.4 volts. The resistance would be 100.How to determine the load choicesa. The 6.8 Zener diode
what is required would be 3 zener diodes. These would be able to provide 3 x 6.8 = 20. 4 output
The resistance would be 3 x 10 ohms = 30 Ohms.
b. For the 5.1 v zener diodeThe requirement here would be 4 zener diodes. This would have to provide 4 x 5.1 = 20.4 volts of output.
The resistance that it would have to give would be 4 x 25 = 100 ohms of resistance.
Therefore from the calculations that we have above we would have to conclude that the load regulation that is here without R would be
30 ohms for the case of a , while it would have to be 100 ohms for the case of b.
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6–15. the beam is subjected to a uniform dead load of 200 lb>ft and a single live load of 5 k. determine (a) the maximum moment created by these loads at c, and (b) the maximum positive shear at c. assume a is a pin, and b is a roller.
The greatest moment produced by these loads at c is 16.53 K.ft and the greatest positive shear by the load at c is 1.267 K.
A force's moment is a measurement of how likely it is to make a body rotate around a certain point or axis. This differs from a body's propensity to translate or move in the direction of the force. A body must experience the force in such a way that it starts to twist before a moment may emerge. This happens each time a force is applied so that it misses the body's centroid. When a force does not have an equal and opposing force acting immediately across its path of action, a moment results. Consider two individuals attempting to open a door at the doorknob from opposing sides. There is an equilibrium state if they are both pushing with the same amount of force. If one of them suddenly leaped back from the door, the other person's push would be met with no resistance, and the door would swing away. A pause was caused by the door-pusher who persisted in doing so.
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The cutting blade's bevel angle on a pair of snips typically measures A. 90 degrees B. 2 degrees C. 5 degrees D. 45 degrees
The cutting blade's bevel angle on a pair of snips typically measures is option A. 90 degrees.
What is the cutting angle of snip?These are said to be left- or right-cutting forged steel snips have 90-degree-angled jaws for that of convenient grasping while cutting sheet metal overhead or in a place that is said to be a constricted locations.
Therefore, note that a pair snips is said to be a little pair of shears that is known to be used for cutting sheet metal.
Hence, based on the above, option A is correct.
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