a uniform cube of mass m and edge a moves on a horizontal surface along the positive x-axis, with initial velocity v0: (a) during motion, n>mg (b) during motion, normal reaction acts on the centre of mass (c) during motion, the normal reaction shifts towards positive x-axis from the centre of mass (d) during motion, normal reaction shifts in the direction of the forces of friction

Answer:

6.3 m

Explanation:

Work = force   X    distance

 600 = 95   x   d

d = 600/95 = 6.3 m

The velocity of the cyclist when he grabs the branch is 36.1 m/s.

The final velocity of the cyclist is calculated as follows;

The final vertical velocity of the cyclist will be smaller than the initial vertical velocity due to opposing force of gravity.

Final vertical velocity of the cyclist, Vy = vi - vi sinθ

Vy = 32.25 - 32.25 sin(30)

Vy = 16.13 m/s

The final horizontal velocity will be constant.

Vx(final) = Vx(initial)

Vx = 32.25 m/s

Resultant final velocity = √Vx² + Vy²

Resultant final velocity = √(32.25² + 16.13²)

Resultant final velocity = 36.1 m/s

Thus, the final velocity of the cyclist will change when he grabs the overhanging tree branch.

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The time required by the truck moving with speed 25.0 m/s and covering the distance 48.0 m is 3.84 seconds.

What is speed?

The speed of an object, also known as v in kinematics, is the size of the change in that object's position over time or the size of the change in that object's position per unit of time, making it a scalar quantity.

As given in the question,

the initial speed of the truck when brakes are applied (u) = 25 m/s.

Final speed (v) = 0 m/s

The distance covered after brakes are applied (s) = 48 m.

By the Newton's equation of motion

[tex]v^2 = u^2 + 2as[/tex]

Putting values from the question from the question.

0 = (25)^2 + 2a(48)

a = -6.51 m/s^2

Now by the equation,

v = u + at

Putting value from question

0 = 25 - 6.51 t

t = 25/6.5

t = 3.84 seconds

Therefore, time taken is 3.84 seconds.

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Answer:

B. 2.45 Newtons

Explanation:

This is a tension force problem with only tension and the weight force acting on the object. Using Newton's second law F=ma, and there being no acceleration in the system, T-w=0. Using this, T=w. w=mg, therefore (.250kg)(9.8m/s^2) = 2.45 Newtons

Answer:

See image

Explanation:

Plato

When the extension of the spring becomes 5 cm, the applied force is 66.67 N.

The length produced by a force of 100 N is 7.5 cm.

The spring constant of a spring is also known as force constant, is the ratio of force to the extension of a spring.

The force constant of a spring describes how stiff a spring is or how tough a spring is.

The force constant of the given spring is calculated as follows;

k = F/x

where;

The extension of the spring = 3 cm = 0.03 m

The force is given as 40 N

K = 40 N / 0.03 m

K = 1,333.33 N/m

If the extension of the spring becomes 5 cm, the applied force is calculated as follows;

F = kx

F = 1,333.33 x 0.05

F = 66.67 N

The extension produced by a force of 100 N;

x = F/k

x = 100/1,333.33

x = 0.075 m = 7.5 cm

The assumption made is that the applied force is directly proportional to the extension of the spring.

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The final vertical velocity of the soccer ball is 20 m/s.

We need to know about the projectile motion to solve this problem. The projectile motion is known as parabolic motion and the velocity is divided by 2 axes.

vox = vo cosA

voy = vo sinA

where vox is initial velocity of x axis, voy is initial vertical velocity, vo is initial velocity and A is the angle.

From the question above, the given parameters are

vox = 15 m/s

h = 40 m

x = 60 m.

The time taken of horizontal motion will be

x = vox . t

60 = 15 . t

t = 4 s

By using the uniform motion, where vty = 0 m/s and time taken to reach the peak is half of total time. Hence

vty = voy - gt

0 = voy - 10.(1/2 . 4)

voy = 20 m/s

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Answer:

So as the mass of either object increases, the force of gravitational attraction between them also increases.

Explanation:

If the mass of one of the objects is doubled, then the force of gravity between them is doubled. If the mass of one of the objects is tripled, then the force of gravity between them is tripled.

Answer:

-28990N

Explanation:

F = mass * acceleration = 2899kg * 10m/s^2 = -28990N (because it is a normal force applying pressure upward).

There are four aspects of waves that only pertain to specific types of waves. Peaks and troughs are used to describe transverse waves. Compressions and rarefactions are used to describe longitudinal waves. Medium, wavelength, amplitude, and frequency are the four qualities that both types of waves have in common.

In addition to longitudinal waves, which also move in the direction of the medium, there is another type of wave that does so: the transverse wave. While longitudinal waves are made up of compressions and rarefactions, transverse waves are made up of crests and troughs.

In longitudinal waves, localized compression and rarefaction are observed. Compressions are regions of extremely high pressure because of the near proximity of the particles. Rarefactions are regions of low pressure because to the particles' enhanced dispersion.

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Answer:

9.8 seconds

Explanation:

Power = work / time

work = F * d     =   200kg ( 9.81 m/s^2 ) * 4 m = 7818 J

800 W = 7818 J / t       t = ~ 9.8 seconds

Answer:

.12 * .12 = .0144        counterclockwise torque

.06 * .18 + W * .03 = .0108 + .03 W        clockwise torque

W = (.0144 - .0108) / .03 = .12 N     as requested

(.12 + .06 + .12) N = .30 N       total weight supported by thread

C) Suppose now rod supported at middle

.12 * .15 = .018 N      counterclockwise torque

.06 * .15 = .009 N     clockwise torque

Obviously the thread must be moved closer (left) to .12 weight to increase the clockwise torque (other weights are in the middle of the rod

Answer:

44 ohms.

Explanation:

R for V (according to Ohm's law). This second formula is more frequently used in practice to calculate resistive heating, whereas the first formula has other, more general applications. As we might infer from the equation, the units of watts also correspond to amperes2 x ohms (A2 x Ω).

Answer:

Oxygen gas is two oxygen atoms bonded together, O2. Water, is one oxygen atom bonded to two different hydrogen atoms, H2O

Explanation:

The answer is true!!!!!!!!!!!

If a  0.6 kg squirrel falling at 14 m/s hits a pile of leaves and comes to rest in 2 s , the normal force of the leaves on the squirrel as it comes to rest would be 4.2 Newtons.

Newton's Second Law states that The resultant force acting on an object is proportional to the rate of change of momentum.

As given in the problem a 0.6 kg squirrel falling at 14 m/s hits in a pile of leaves and comes to rest in 2 s.

The change in the moment of the squirrel = 0.6 × 14

                                                                      =8.4  Kg - m/s

The normal force = rate of the change of the momentum

                             = 8.4 / 2

                             = 4.2 Newtons

Thus,  the normal force of the leaves on the squirrel as it comes to rest would be 4.2 Newtons.

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If there isn't any beginning vertical velocity, figure out how long it will take to get to the water, then divide that number by the horizontal distance to get the necessary minimum horizontal speed.and for t=6.18 sec, we obtain v =1.28 m/s.

Velocity is the rate of change in direction of an object in motion as measured by a specific standard of time and observed from a specific point of reference (for example, 60 km/h northbound).  A key idea in kinematics, the area of classical mechanics that studies how bodies move, is velocity.

The definition of velocity requires both its magnitude and its direction because it is a physical vector quantity. Speed is a coherently derived unit that is measured in the SI (metric system) as metres per second (m/s or m/s1). Speed is the scalar absolute value (magnitude) of velocity. A scalar is a number, such as "5 meters per second," whereas a vector is "5 meters per second east." the case

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Answer:

Headphones

Explanation:

There is some with wires and without

Answer:

headphones,phones,computers,robots,

Explanation:

some may have wires some may not but even if i did not answer correctly please give me a brainlyest

According to air masses classification, we can assume that to the west of the stationary front in northwestern Canada there is a maritime Polar (mP) air mass which is likely to be warmer than the air mass to the east. Option B) mP, warmer.

Air masses are horizontal extensions of moving air in which humidity, temperature, and physical properties are homogeneous.

Air masses can be classified according to their temperature (Cold or Warm), nature (continental -c- or maritime -m-), Origin region (Polar -P-, Artic -A-, Antarctic -AA-, Tropical -T-, Equatorial -E-)

Joining the previous classifications, we can identify different air masses

Maritime Polar air masses (mP)

Looking at the image, we will focus on the superior left area near the A. This is a red line with semicircles that represents a warmer front.

This red line comes from the west and moves forward to the northeast. Since this point is located near the coast, we can assume this is a maritime air mass.

These red lines, which represent worm fronts, suggest that to the west, the air is warmer than to the east.

The likely air mass to the west of the stationary front is a maritime Polar (mP) air mass which is likely to be warmer than the air mass to the east.

Option B) mP, warmer.

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Complete question

Find the stationary front located in northwesterm Canada.

The likely air mass to the west of the stationary front is ______ a air mass that is likely to be _____ than the air mass to the east.

A) cP: cooler

B) mP: warmer

C) cP: warmer

D) ml: warmer

Answer: Force required to 25 joule work when the force causes a displacement of 0.5m is 50N

Explanation: To calculate the work done we use the formula

W=F.s                               (1)

W= work done

F=  force applied               s= displacement

Given, work done W= 25 joules= 25 J

displacement s= 0.5m

∴From equation (1) we get the force required when work is done and displacement is given, that is

F[tex]=\frac{W}{s}[/tex]                                (2)

∴Force required [tex]F=\frac{W}{s}= \frac{25J}{0.5m}=50N[/tex]            

(1 J is the work done by a force of 1 N acting over a displacement of 1 m and so 1 J= 1 Nm⇒ 1 N = 1 J/m)

ANS: Force required to do 25 J work when a force causes displacement of 0.5m = 50 N

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An object has a mass of 10 kg and is pushed with a force of 2 N the object acceleration is  0.2m/s².

Given;

m = 10 kg

F = 2N

by using Newton's second law of motion that is the formula of force

F = ma

a =  F/m

a = 2/10

a = 0.2m/s²

An object is said to accelerate when its velocity changes. A change in the speed of an object can be an increase or decrease in speed or a change in  direction of motion. Some examples of acceleration are a falling  apple, the moon orbiting  the Earth, or  a car stopping at a traffic light. Using these examples, we can understand that when  a moving object changes direction or increases or decreases speed, acceleration occurs.

The  unit of acceleration is  meter per second per second (m/s2).

There are 2 types of acceleration

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The block has gravitational potential energy when it briefly comes to rest at the top of the ramp and starts with kinetic energy at the bottom. However, some of that energy is lost due to frictional effort. Use Newton's second law to determine the friction force on the block.

The work-kinetic energy theorem can be used to provide a solution to this issue. Start by calculating how far the block will travel up the ramp. The block has gravitational potential energy when it briefly comes to rest at the top of the ramp and starts with kinetic energy at the bottom. However, some of that energy is lost due to frictional effort.

You can use a free body diagram and Newton's second law to calculate the frictional force on the block. The frictional energy is calculated as the frictional force multiplied by the distance the block travels up the ramp.

The distance climbed up the ramp will also affect how much the gravitational potential energy changes. You can now generate kinetic energy.

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When we are comparing three different ways of having a ball move down through the same height, dropping the ball reaches the bottom with the highest speed.

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The efficiency of the engine is 60%.

The efficiency of a heat engine describes the amount of input energy converted into useful work.

It also entails the amount of useful work done by the engine. The greater the amount of useful work done by the engine, the greater the efficiency of the engine.

The efficiency of an engine ranges from 0 to 100%.

If there four stages in the energy conversion cycle, and 10% energy is wasted in each cycle, the total energy wasted in the four cycles is calculated as;

Total wasted energy = 4 x 10% = 40%

Efficiency of the engine = Useful energy = 100% - 40% = 60%

Thus, the efficiency of the engine is the useful work done by the engine.

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A missile is moving 1810 m/s at a 20.0 angle. it needs to hit a target 19,500 m away in a 32.0 direction in 9.20 s. The acceleration that the engine must deliver is 112 meters per second.

The term "acceleration" refers to the rate of change in the object's velocity in relation to time, and it is measured in meters per second (m/s). In most contexts, meters per second squared is the unit of measurement for acceleration.

Let us start by thinking about the component that is horizontal in the x direction.

The length of travel in a plane horizontal to the starting point.

x = 19,500 cos 32.0° m

Using the second equation of motion to determine acceleration along the horizontal axis in order to:

[tex]x = ut + 1/2at^2[/tex]

[tex]19,500 * (cos 32.0^0 = 0 + (1810* cos 20.0^o) *9.20+ 0.5*a *9.20^2[/tex]

a = 21.01 m/s²

The same may be said for the vertical direction.

The distance traveled in the upward and downward directions combined.

Y is the velocity in the vertical direction, and it is equal to 19,500 in 32.0° m.

u= 1810 sin 20.0° m/s

t = 9.20 s

For the purpose of determining acceleration along the vertical axis by using the second equation of motion, For the purpose of determining acceleration along the vertical axis by using the second equation of motion

[tex]y = ut +1/2at^2[/tex]

19,500 sin 32.0° = 0 + (1810 sin 20.0^o)* 9.20 + 0.5*a* 9.20^2

a = 109.6 m/s^2

The resultant acceleration

[tex]a^2 = (21.01)^2 + (109.6)^2[/tex]

a = 112 m/s²

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The radius of the cylinder is 0.43 cm while the uncertainty is 0.04. This can likely be expressed as 0.43 +/- 0.04 cm

Absolute uncertainty or error is the difference between measured value of a quantity and the actual value.

Given an expression for the volume of a cylinder to be

V = πr²h

Where

From the formula, make radius r the subject of the formula and calculate the radius

V = πr²h

r² = V/πh

r = √(V/πh)

r = √12/21π

r = √12/65.97

r = √0.18

r = 0.43 cm

The uncertainty Δr will be

Δr/r = (ΔV/V + Δh/h) × 2

Δr/0.43 = (0.5/12 + 0.1/21) × 2

Δr/0.43 = (0.0417 + 0.0048) × 2

Δr/0.43 = 0.093

Δr = 0.093 × 0.43

Δr = 0.0399

Δr = 0.04

Therefore, the radius of the cylinder is 0.43 +/- 0.04 cm

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The speed of the car when the load is dropped in it is 10.90 m/s.

Using the data given above:

Mass of the railroad car, m₁ =  12100kg

Mass of the load, m₂ =  4790kg

It can be assumed as the speed of the car, u₁ = 10 m/s

So, it is at rest, u₂ = 0

Here we assume the speed of the car be v

Using law of conservation of energy

Thus:

m1v1 + m2v2 = (m1v1)/ (m1 + m2)

= 12100*10 / 12100 + 4790

121000/16890

= 7.16 m/s

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The net force of the lawn mower is 32.5 N and acceleration is 1.62 m/s^2.

The student pushes the lawn mower with 15.5 force and the lawn mower's motor provides 20.0 N force. The grass has a resistance force 3.0 N which is in opposite direction to the student's and lawn mower's forces. So, the net force is given,

F = 15.5 N + 20.0 N - 3.0 N = 32.5 N

According to Newton's second law, we know the relation between acceleration and force applied. Force is equal to mass times acceleration. The mass of the lawn mower is 25.0 kg.

[tex]a=\frac{F}{m}[/tex]

a = 32.5/20 = 1.62 m/s^2

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Answer:

If the mass is doubled, then acceleration will be halved.

Explanation:

That situation is described by Newton's Second Law of Motion. F is force, m is mass and a is acceleration. The math behind this is quite simple. If you double the force, you double the acceleration, but if you double the mass, you cut the acceleration in half.

According to Newton's Second law of Motion, the acceleration of the mass spring system will be halved if the mass of the spring system is doubled.

Newton's second law of motion states that when an external net force is applied on an object, the acceleration of the object is proportional to the net force which is applied on the object, and it also occurs in the same direction as the direction of applied force. The acceleration of an object is inversely proportional to the net force applied and acceleration is inversely proportional to the mass of the object.

This situation can be best described by Newton's Second Law of Motion. The second law of motion can be expressed by the equation:

F = m × a

where, F is force,

m is mass, and

a is acceleration

Mass of an object is inversely proportional to the acceleration of the body. If the mass of the spring system is doubled then the acceleration of the object will be reduced to half.

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Answer:

Explanation:

(I) Electrical energy into sound energy. (ii) Heat energy into kinetic energy (or mechanical energy). (iii) Chemical energy into kinetic energy (or mechanical energy). (iv) Chemical energy into heat energy