A warehouse worker is stacking boxes. The height of each box is 20 centimeters. She cannot stack the boxes higher than 5 feet.
1 inch 2.54 centimeters, 1 foot = 12 inches
What is the maximum number of boxes the warehouse worker can stack? Enter the answer in the box.
boxes​

Answer:

$2576

Step-by-step explanation:

You need to get the areas of the squares, the little square the area is 8 yd since you multiply 4 times 2. The big rectangle we need our length times our width we get our width by subtracting 4 from 10 which means w=6, then we need our length, for that we add 12 and then 2 to account for the rest which means l=14, we multiply 14 times 6 which gives you 84 and add the area of the little square (8) so 84 plus 8= 92 multiply that times the cost per yard so (92)(28) and you get $2576

Answer:

A) 4 inches

Step-by-step explanation:

The length is 80 inches and the width is 76 inches. To find the difference subtract 80 minus 76 and you get 4... the amount that is exceeding the width!

Have a wonderful day!

Answer:

A. 4 inches

Step-by-step explanation:

In order to find by how much the length exceeds the width we have to subtract width from the length in order to get the difference between the two lengths, and so we get...

80 - 76 = 4

Therefore the answer is A. 4 inches

Answer:

I think it’s 11.8

Step-by-step explanation:

ahaha good one

Step-by-step explanation:

...........

Answer:

sidekick egocentric Jayco

Answer:

16

Step-by-step explanation:

Answer:

V=  480.7 m cubed

The volume of the cylinder nearest to tenths place is 480 m^3.

A cylinder is a three-dimensional shape consisting of two parallel circular bases, joined by a curved surface.

For the given situation,

The formula for volume of the cylinder is [tex]V=\pi r^{2} h[/tex]

Radius of the cylinder,r = 3 m

Height of the cylinder, h = 17 m

The value of π = 3.14

On substituting the above values,

[tex]V=(3.14) (3^{2})(17)[/tex]

⇒ [tex]V=480.42[/tex] ≈ 480

Hence we can conclude that the volume of the cylinder is 480 m^3.

Learn more about volume of cylinders here

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Answer:

2x+5x-6

Step-by-step explanation:

Step-by-step explanation:

18.706 → 19

18.706 → 18.71

18.706 = 19

18.706 = 18.71

The value that represents the Inter-Quartile Range of data is 26.

Option A is the correct answer.

An interquartile range is a measure of the difference between the upper and lower quartiles of a dataset.

W can find the values of the upper and lower quartile and median from a box plot.

The middle line is the median and the first line is the lower quartile and the last line is the upper quartile.

The formula used is Upper quartile - Lower quartile.

We have,

From the boxplot, we can see that,

Third quartile = 46

First quartile = 20

Now,

Interquartile range

= Third quartile - First quartile

= 46 - 20

= 26

Thus,

The value that represents the Inter-Quartile Range of data is 26.

Learn more about the interquartile range here:

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Answer:

Question 7: False, False, true

Question 8: B

Step-by-step explanation:

Answer:

x = 50

Step-by-step explanation:

Note that the 3 interior angles must sum up to 180 degrees:

50 + x + 80 =180, or

50 + x = 100, or

x  = 50

Answer:

Rosa is correct, it's the variable that determines if something has like terms, not the coefficients.

Step-by-step explanation:

Answer:

1. To Inspire Listeners

2. To Demand Action

5. To Rally Emotional Support

Step-by-step explanation:

I just took the test:)

Answer:

a

Step-by-step explanation:

They make a right angle. A right angle adds up to 90.

Answer:

Step-by-step explanation:

Answer: [tex]24\ ft[/tex]

Step-by-step explanation:

Given

The slant height of the square pyramid is [tex]l=25\ ft[/tex]

The length of the side of the base is [tex]a=14\ ft[/tex]

for the square pyramid, height is given by

[tex]\Rightarrow h=\sqrt{l^2-r^2}\quad \quad [\text{where r=}\frac{a}{2}]\\\Rightarrow h=\sqrt{25^2-7^2}\\\Rightarrow h=\sqrt{625-49}\\\Rightarrow h=\sqrt{576}\\\Rightarrow h=24\ ft[/tex]

Thus, the height of the prism is [tex]24\ ft[/tex]  

Answer:

Step-by-step explanation:

50.27 should be the area of a circle that has a radius of 4 in.

Answer:

6km² sounds like a reasonable answer

Answer:

Step-by-step explanation:

Answer:

Group A has greater variability

Step-by-step explanation:

Group A: 80, 100, 190, 110, 70, 90, 130

The variability of group A data :

Taking the range :

Maximum  = 190 ; Minimum = 70

Range = Maximum - Minimum ; 190 - 70 = 120

Group B : 50, 110, 100, 120, 107, 140, 150

The variability of group B data :

Taking the range :

Maximum  = 150 ; Minimum = 50

Range = Maximum - Minimum ; 150 - 50 = 100

Hence, Group A has greater variability

Answer:

It would be Angles GFC and EFH.

Think of it like I'm drawing a capital X. Would you consider the top and bottom parts of the X to be the same? Or would you consider the top and left parts to be the same?

The correct answer for this would be that the top and bottom parts of X are the same size. Now, remember that whenever two lines are making an X. this is because the two angles only touch each other in the center point and don't share a side.

Answer:

3.5

Step-by-step explanation:

The interquartile range is the difference between the third and first quartile

IQR = Q3 - Q1

From the dot plot given :

The data, X could be culled :

X = 43, 44, 44, 44, 45, 45, 47, 48, 48

n = 9

Q3 = 3/4(n + 1)th term

Q3 = 3/4(10) = 7.5th term = (47 + 48) / 2 = 47.5

Q1 = 1/4(n + 1)th term

Q1 = 1/4(10) = 2.5th term = (44 + 44) / 2 = 44

Q3 - Q1 = 47.5 - 44 = 3.5

Answer:

3.5

Step-by-step explanation:

smart

Answer:

[tex]Sec~ 0=\frac{\sqrt{66} }{8}[/tex]

Step-by-step explanation:

[tex]Cot~0=-4\sqrt{2}[/tex]

[tex]Sec~0=\sqrt{33}/4\sqrt{2}[/tex]

[tex]=\sqrt{33}/4\sqrt{2} *4\sqrt{2} /4\sqrt{2}[/tex]

[tex]=4\sqrt{66} /32[/tex]

[tex]= \sqrt{66}/8[/tex]

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hope it helps...

have a great day!!!

Answer:

49 - 9π

Step-by-step explanation:

Area of white portion = area of triangle - area of circle

To find the area of the triangle:

The area of a triangle can be calculated using this formula

[tex]A=\frac{bh}{2}[/tex] where b = base length and h = height

The height given is 7m and the base length given is 14m

That being said we plug in the given values into the formula

[tex]\frac{14*7}{2} \\14*7=98\\\frac{98}{2} =49[/tex]

Hence, the area of the triangle is 49 sq meters.

To find the area of circle

( note that the area is in terms of pi; shown by the answer choices. )

Formula for area of a circle = [tex]A=\pi r^2[/tex]

We are given the diameter  ( 6m )

However, we need the radius

To convert diameter to radius we divide by 2

6/2 = 3 so the radius = 3m

Now we plug in 3 into the formula

[tex]A=\pi 3^2\\3^2=9\\A=9\pi[/tex]

Remember we do not apply pi because the answer should be in terms of pi.

Now we subtract the two

Area of white portion = 49 - 9π

Hence, the answer is A

Answer:

49 - 9π

Step-by-step explanation:

Hope this helps

Answer:

-5/3

Step-by-step explanation:

Any line parallel to the given line will have the same slope as the given equation;

Given the equation 15x+9y=-162

Rewrite in standard from y = mx+b

15x+9y=-162

9y = -15x - 162

y = -15/9 x - 162/9

y = -5/3 x - 18

This gives the required equation;

Since mx = -5/3 x

m = -5/3

Hence the slope of the line parallel to the given line is -5/3

Answer:

Arithmetic Sequence

[tex]T_n = 240-60n[/tex] ---- Explicit

[tex]T_n = T_{n-1} - 60[/tex] --- Recursive

Geometric Sequence

[tex]T_n = 270* (\frac{2}{3})^n[/tex] ---- Explicit

[tex]T_n = T_{n-1} * \frac{2}{3}[/tex] ---- Recursive

Step-by-step explanation:

Given

[tex]180, 120,....[/tex]

(a) Assume it is an arithmetic sequence

The explicit formula is calculated using:

[tex]T_n = a + (n - 1)d[/tex]

Where

[tex]a = 180[/tex]

[tex]d = 120 - 180[/tex]

[tex]d = -60[/tex]

So, we have:

[tex]T_n = 180 + (n - 1)*-60[/tex]

[tex]T_n = 180 -60n + 60[/tex]

Rewrite

[tex]T_n = 180 + 60-60n[/tex]

[tex]T_n = 240-60n[/tex]

The recursive function is calculated using:

[tex]T_1 = 180[/tex]

[tex]T_2 = 120 = 180 - 60 = T_1 - 60[/tex]

[tex]T_3 = 60 = 120 - 60 = T_2 -60[/tex]

-

[tex]T_n = T_{n-1} - 60[/tex]

(b) Assume it is a geometric sequence

The explicit formula is calculated using:

[tex]T_n = ar^{n-1}[/tex]

Where

[tex]a = 180[/tex]

[tex]r = \frac{120}{180}[/tex]

[tex]r = \frac{2}{3}[/tex]

So, we have:

[tex]T_n = 180 * (\frac{2}{3})^{n-1}[/tex]

Split

[tex]T_n = 180 * (\frac{2}{3})^n \div (\frac{2}{3})^1[/tex]

[tex]T_n = 180 * (\frac{2}{3})^n \div (\frac{2}{3})[/tex]

Rewrite as:

[tex]T_n = 180 * (\frac{2}{3})^n * (\frac{3}{2})[/tex]

[tex]T_n = 180 * (\frac{3}{2})* (\frac{2}{3})^n[/tex]

[tex]T_n = 180 * \frac{3}{2}* (\frac{2}{3})^n[/tex]

[tex]T_n = 90 * 3* (\frac{2}{3})^n[/tex]

[tex]T_n = 270* (\frac{2}{3})^n[/tex]

The recursive function is calculated using:

[tex]T_1 = 180[/tex]

[tex]T_2 = 120 = 180 * \frac{2}{3} = T_1 * \frac{2}{3}[/tex]

[tex]T_3 = 80 = 120 * \frac{2}{3} = T_2 * \frac{2}{3}[/tex]

-

[tex]T_n = T_{n-1} * \frac{2}{3}[/tex]