A woman does 236 J of work
dragging her trash can 24.4 m to
the curb, using a force of 18.9 N.
At what angle was her force
directed?

Answer:

the molecules will begin to move slowly and will turn to ice

Explanation:

hope this was good or not not sure if am right but yeah

Answer:

4

Explanation:

because people could lie about it

Answer:

Revolutions

Explanation:

Answer:

False

Explanation:

A single concave lens has the opposite effect of a magnifying glass.

Answer:

41.02m

Explanation:

Given parameters:

Initial velocity = 0m/s

Final velocity  = 96km/hr

Time taken  = 3.07s

Unknown:

Distance traveled by the time the final speed was achieved = ?

Solution:

To solve this problem, we first find the acceleration of the car;

     Acceleration  = [tex]\frac{v - u }{t}[/tex]

v is the final velocity

u is the initial velocity

t is the time taken

  Now convert the the final velocity to m/s;

          96km/hr to m/s;

               1 km/hr  = 0.278m/s

               96km/hr  = 96 x 0.278 = 26.7m/s

Now;

 Acceleration  = [tex]\frac{26.7 - 0}{3.07}[/tex]   = 8.69m/s²

So;

   v²  = u²  + 2as

v is the final velocity

u is the initial velocity

a is the acceleration

s is the distance

             26.7²  = 0²  + 2 x 8.69 x s

             712.89  = 17.38s

                  s  = 41.02m

Mass of book will be m = 4.495 kg  

The force of attraction between all masses in the universe; especially the attraction of the earth's mass for bodies near its surface is called gravitational force

Force = 2.68 x 10-8 N

mass of student(M)  = 55

mass of book=?

distance = 0.435m

gravitational constant (G)=6.67×10^-11

gravitational force (F)=2.68×10^-8

gravitational force (F) = (G*M*m) /[tex]d^{2}[/tex]

2.68 x 10-8  = ((6.67×10^-11) * ( 55 ) * m) / 0.435

m = 4.495 kg

Mass of book will be m = 4.495 kg  

learn more about gravitational force  

https://brainly.com/question/12528243?referrer=searchResults

#SPJ2

Answer:

acellus students

Explanation

1.382

Answer:189000J

Explanation:KE=1/2mv^2

1/2(420g)(30m/s)^2

=189000J

Answer:

The law of conservation of mass states that matter cannot be created or destroyed in a chemical reaction. For example, when wood burns, the mass of the soot, ashes, and gases, equals the original mass of the charcoal and the oxygen when it first reacted. So the mass of the product equals the mass of the reactant

Answer:

[tex]a=12.97\ m/s^2[/tex]

Explanation:

Given that,

The length of a string, l = 0.87 m

Speed of the ball, v = 3.36 m/s

We need to find the acceleration of the ball. The acceleration acting on the ball is centripetal acceleration. It is given by :

[tex]a=\dfrac{v^2}{r}\\\\a=\dfrac{(3.36)^2}{0.87}\\\\=12.97\ m/s^2[/tex]

So, the acceleration of the ball is [tex]12.97\ m/s^2[/tex].

Answer:

* far from one of the charges, the field of the other charge is small and can be neglected

* on the outside of the loads the fields are added territorially

* between the charges the two fields tend to vanish

Explanation:

The electric field around two objects with charge of the same sign, for simplicity suppose that the objects have positive point spherical charges,

          E = k q / r2

bold letters indicate vectors, therefore the total electric field is

           E_total = E1 + E2

the module of this field is

           E_total = E1- E2

therefore we can outline this field

* far from one of the charges, the field of the other charge is small and can be neglected

* on the outside of the loads the fields are added territorially

* between the charges the two fields tend to vanish

An outline of these shows in Attachment A

The equipotential surfaces are defined as being perpendicular to the electric field lines since the electric field and the power difference are related

              E = [tex]\frac{dV}{dx} i^ + \frac{dV}{dy} j^ + \frac{dV}{dz} k^ = \Delta V[/tex]

We can schematize some characteristics of these surfaces

* very close to each load are spherical surfaces

* very far from the load is an elliptical surface, which envelops the loads

* between them there is a point of zero potential point C

See attached part B

Answer:

Magnetic Field

Explanation:

Answer:

Magnetic field

Explanation:

Answer:

0.8%

Explanation:

We are given;

Number of oscillations; n = 20

Time taken; t = 25 s

Formula for period of oscillation;

T = t/n = 25/20 = 1.25 s

We are told that the least count is 0.2 s. Thus, error is; ΔT = 0.2 s

percentage error in the measurement of time is given by;

(0.2/(20 × 1.25)) × 100% = 0.8%

Answer:

12 N/cm²

Explanation:

From the question given above, the following data were obtained:

Weight (W) of block = 240 N

Area (A) = 20 cm²

Pressure (P) =?

Next, we shall determine the force exerted by the block. This can be obtained as follow:

Weight (W) of block = 240 N

Force (F) =.?

Weight and force has the same unit of measurement. Thus, we force applied is equivalent to the weight of the block. Thus,

Force (F) = Weight (W) of block = 240 N

Force (F) = 240 N

Finally, we shall determine the pressure on the floor as follow:

Force (F) = 240 N

Area (A) = 20 cm²

Pressure (P) =?

P = F/A

P = 240 / 20

P = 12 N/cm²

Therefore, the pressure on the floor is 12 N/cm².

Answer:

i think its 8.2

Explanation:

Answer: 432m

Explanation:

Convert 3 min to seconds

1 min = 60 sec

3 min = 180 sec

Multiply the speed times time to get distance.

2.4 x 180 = 432m

Answer:

the nuclear fusion process

Explanation:

:)

Answer:

nuclear fusion (not fission)

Explanation:

a p e x :))

Complete question is;

What is the electrical potential at the surface of gold nucleus? The radius of a gold atom is 6.6 × 10​^(-5) m and atomic number z = 79.

Answer:

172.36 × 10^(-5) V

Explanation:

We are given;

Radius; r = 6.6 × 10^(-5) m

Atomic number; Z = 79

Formula for Electric potential here is;

V = kZe/r

Where;

e is charge on proton = 1.6 × 10^(-19) C

k has a constant value of 9 × 10^(9) N⋅m²/C²,

​Thus;

V = (79 × 1.6 × 10^(-19) × 9 × 10^(9))/(6.6 × 10^(-5))

V = 172.36 × 10^(-5) V

Answer:

y = 14238 m.    the height of the rocket is much less than this distance therefore the plan will not work.

Explanation:

Let's analyze this exercise, so that the Martian's plan works, the vertical height of the body must be zero when it is more than half of the way to the planet Mars, this is so that Mars attracts it and can arrive.

Let's calculate the maximum height of the launch

          [tex]v_{y} ^2 = v_{oy}^2 - 2 g y[/tex]

at the highest point [tex]v_{y}[/tex] = 0

          y = v_{oy}² / 2g

          y = (v₀ sin θ)² / 2g

let's calculate

          y = (1250 sin 25)² /2 9.8

          y = 14238 m

In the exercise, indicate that the distance to Mars is h = 321770 m, half of this distance is

          h / 2 = 160885 m

therefore the height of the rocket is much less than this distance therefore the plan will not work.

The height reached is low, so it is not necessary to take into account the variation of g with height

Answer:

6.45×10¯²⁶ J

Explanation:

From the question given above, the following data were obtained:

Frequency (f) = 97.3 MHz

Energy (E) =?

Next, we shall convert 97.3 MHz to Hz. This can be obtained as follow:

1 MHz = 1×10⁶ Hz

Therefore,

97.3 MHz = 97.3 MHz × 1×10⁶ Hz / 1 MHz

97.3 MHz = 9.73×10⁷ Hz

Thus, 97.3 MHz is equivalent to 9.73×10⁷ Hz.

Finally, we shall determine the energy at which the frequency is broadcasting. This can be obtained as follow:

Frequency (f) = 9.73×10⁷ Hz

Planck's constant (h) = 6.63×10¯³⁴ Js

Energy (E) =?

E = hf

E = 6.63×10¯³⁴ × 9.73×10⁷

E = 6.45×10¯²⁶ J

Therefore, the energy at which the frequency is broadcasting is 6.45×10¯²⁶ J

Answer:

 F_A = 8 F_B

Explanation:

The force exerted by the planet on each moon is given by the law of universal gravitation

        F = [tex]G \frac{m M}{r^{2} }[/tex]

where M is the mass of the planet, m the mass of the moon and r the distance between its centers

let's apply this equation to our case

Moon A

the distance between the planet and the moon A is r and the mass of the moon is 2m

        F_A = G \frac{2m M}{r^{2} }

Moon B

        F_B = G \frac{m M}{(2r)^{2} }

         F_B = G \frac{m M}{4 r^{2} }

the relationship between these forces is

         F_B / F_A = [tex]\frac{1}{2 \ 4 }[/tex] = 1/8

         F_A = 8 F_B

Answer:

F_A = 8 F_B

Explanation:

The force exerted by the planet on each moon is given by the law of universal gravitation

       F =

where M is the mass of the planet, m the mass of the moon and r the distance between its centers

let's apply this equation to our case

Moon A

the distance between the planet and the moon A is r and the mass of the moon is 2m

       F_A = G \frac{2m M}{r^{2} }

Moon B

       F_B = G \frac{m M}{(2r)^{2} }

        F_B = G \frac{m M}{4 r^{2} }

the relationship between these forces is

        F_B / F_A =  = 1/8

        F_A = 8 F_B

Answer:

20g

Explanation:

Given parameters:

Quantity of heat  = 240calories

Initial temperature  = 80°C

Final temperature  = 68°C

Unknown:

Mass of water = ?

Solution;

To solve this problem, we use the expression:

         Q  = m c (t₂  - t₁)

Q is the quantity of heat

m is the mass

c is the specific heat = 1 cal/g°C

t₂ is the final temperature

t₁ is the initial temperature

  Insert the parameters and solve;

  Change in temperature is an absolute value

          240 = m x 1 x (68 - 80)

           m  = 20g

Explanation:

A molten steel is in a liquid phase of matter. It has no defined volume of shape at this state. The particles inside this materials in this form is randomized by they are still attached to each other.

Answer:

one could freeze and the second would thaw

Explanation:

sorry if its wrong

The two examples of how land can have a dramatic change in temperature

is during freezing and thawing.

Cold temperatures which is common during the winter period is

characterized by the formation of snow and freezing of smaller water

bodies.

There may be a short phase in which there is relative sunlight which melts

the frozen substances thereby forming liquids . This is usually as result of

the temperature being on the increase in the atmosphere.

Read more on https://brainly.com/question/25671319

Answer:

The time it will take the mega-ray blaster to hit the ground is 2.57 s.

Explanation:

Given;

initial velocity of Optimus Prime, u = 24 m/s

height of fall of the mega-ray blaster, h = 94 m

The time of fall of the mega-ray blaster is calculated using the following kinematic equation;

[tex]h = ut + \frac{1}{2}gt^2\\\\94 = 24t + \frac{1}{2}(9.8)t^2\\\\94 = 24t + 4.9t^2\\\\4.9t^2 +24t -94 = 0\\\\Use \ formula \ method \ to \ solve \ for \ "t"\\\\a = 4.9 , b = 24, c = -94\\\\t = \frac{-b \ +/- \ \sqrt{b^2 -4ac} }{2a} \\\\t = \frac{-24 \ +/- \ \sqrt{(24)^2 -4(-94 \times4.9)} }{2(4.9)} \\\\t = \frac{-24 \ +/- \ \sqrt{2418.4} }{9.8}\\\\t = \frac{-24 \ +/- \ 49.177 }{9.8}\\\\t = \frac{-24 \ +\ 49.177 }{9.8} \ \ or \ \ t = \frac{-24 \ -\ 49.177 }{9.8} \\\\[/tex]

[tex]t = 2.57 \ s \ \ or \ \ t = -7.47 \ s[/tex]

t = 2.57 s

Therefore, the time it will take the mega-ray blaster to hit the ground is 2.57 s.

Answer:

19.3 m/s

Take down to be positive.  Given:

Δy = 19 m

v₀ = 0 m/s

a = 9.8 m/s²

Find: v

v² = v₀² + 2aΔy

v² = (0 m/s)² + 2 (9.8 m/s²) (19 m)

v = 19.3 m/s

My camera quality is bad. Sorry..