According to a candy​ company, packages of a certain candy contain ​% orange candies. Suppose we examine random candies. a. What value should we expect for our sample percentage of orange​ candies? b. What is the standard​ error? c. Use your answers to fill in the blanks below. We expect​ ____% orange​ candies, give or take​ _____%. Question content area bottom Part 1 a. We should expect 22​% of the candies in the sample to be orange. ​(Type an integer or a​ decimal.) Part 2 b. What is the standard​ error? SE 0.021 ​(Round to three decimal places as​ needed.) Part 3 c. Use your answers to fill in the blanks below. We expect enter your response here​% orange​ candies, give or take enter your response here​%. ​(Round to one decimal place as​ needed.)

Answers

Answer 1

The sample percentage of orange candies is 0.22, and the standard error is 0.0195 and the expected 22% orange candies, give or take 1.95%.

a) It is assumed that there are 450 random candies with a p=0.22 percentage of orange candies.

As a result, the orange candy sample percentage should be 0.22.

b) Substituting the above data into the standard error formula, compute the needed value as shown below:

SE= √(p × q) ÷ n = √(0.22 × 0.78) ÷ 450 = 0.0195.

Therefore, the answer is 0.0195.

c) Fill in the blanks with the calculated values to get the following:

Therefore, expected 22% orange candies, give or take 1.95%.

We know that if a population proportion, p is drawn from n Bernoulli trials, then the sample proportion, p vector follows an approximately normal distribution, given the sample size is large. The sample proportion's standard error is given by √(p × q) ÷ n.

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Related Questions

The carnival spinner shown below is divided into equal sections. On every spin, each outcome is equally likely.
If the spinner lands on a number less than 10 on its next spin, what is the probability that it is a multiple of 4?
a. 1/5
b. 2/9
c. 1/4
d. 1/3

Answers

Answer:

2/9

Step-by-step explanation:

The possibilities that satisfy the condition are 4 and 8.

This is 2 numbers out of the possible 9, so the probability is 2/9.

HELP PLEASE!!!!!!!!
To rent a certain meeting room, a college charges a reservation fee of $13 and an additional fee of $4 per hour. The chemistry club wants to spend at most $33 on renting the room. What are the possible numbers of hours the chemistry club could rent the meeting room?
Use t for the number of hours.
Write your answer as an inequality solved for t.

Answers

The inequality that represents the possible number of hours the chemistry club could rent the meeting room is 13 + 4t ≤ 33 or t ≤ 5.

The possible numbers of hours the chemistry club could rent the meeting room are  1, 2, 3, 4 and 5 hours.

Given that:-

Reservation fee charged to rent the meeting room by college = $ 13

Additional fee per hour charged by the college = $ 4

The maximum amount the chemistry club want to spend on meeting room = $ 33

Let t be the number of hours.

Hence,

13 + 4t ≤ 33

4t  ≤ 33 - 13

4t  ≤ 20

t  ≤ 5 hours.

Hence, the possible number of hours the meeting room can be booked by chemistry club are 1, 2, 3, 4 and 5 hours.

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Is 6c + 5 an odd integer?

Answers

Yes, because 6 c+5=2(3 c+2)+1 and 3 c+2 is an integer. Option A

This is further explained below.

What is Integer?

Generally, A natural number that is either positive or negative expressed as an integer, or the number zero itself are all examples of integers.

The additive inverses of the positive numbers that they relate to are represented by the negative numbers.

In conclusion, Because 6c+5=2(3c+2)+1 and 3c+2 is an integer, the answer to this question is yes.

is correct, Integer

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CQ

[tex](b) Is\ $6 c+5$ \an \odd \integer?\\\\Yes, because $6 c+5=2(3 c+2)+1$ and $3 c+2$ is \ an \ integer.\\\\Yes, because $6 c+5=2(3 c+2)$ and $3 c+2$ is \ an integer.\\\\No, because $6 c+5=2(3 c+2)+1$ and $3 c+2$ is an integer.\\\\No, because $6 c+5=2(3 c+2)$ and $3 c+2$ is an integer.[/tex]

Write an equation of the line through the points (2,1) and (1,4). Write the equation in slope-intercept form.
The equation of the line through the points (2,1) and (1.4) is
(Simplify your answer. Use integers or fractions for any numbers in the equation.)

Answers

The equation of line in slope-intercept form is found as y = -3x + 7.

What is meant by slope-intercept form?The slope-intercept part of a line is a method for writing a line's equation so that the slope and y-intercept are easily recognizable. The slope of the line is its steepness, as well as the y-intercept is where the line intersects the y-axis.

For the given question;

The two passing point of the line are;

(x1, y1) = (2,1)

(x2, y2) = (1,4)

Slope = m = (y2 - y1)/(x2 - x1)

Put the values.

m = (4 - 1)/(1 - 2)

m = -3

Then, the equation of the line in slope intercept form is found using two point equation.

y - y1 = m(x - x1)

y - 1 = -3(x - 2)

Simplifying,

y = -3x + 7

-3 is the slope and 7 is the y intercept.

Thus, the equation of line in slope-intercept form is found as y = -3x + 7.

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Find the area of the figure. 16cm 9cm
area: cm2

Answers

The area of the figure is 144 square centimeters

What are areas?

The area of a shape is the amount of space on the shape

For most regular quadrilaterals, you multiply the side lengths to determine the area

How to determine the area of the shape?

The given parameters are

Shape = parallelogram

Base = 9 cm

Height = 16 cm

The area of a parallelogram shape is

Area = Base * Height

So, we have

Area = 9 * 16

Evaluate the expression

Area = 144

Hence, the area  is 144 square centimeters

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Find the first 5 terms of the sequence given the nth term.

1. an=2n^2+5n-10

2. an=3n+4/n^2+5

Answers

Part 1: The first five terms of the sequence are -1, 16, 69, 266, 1039

Part 2: The first five terms of the sequence are 12, 12, 130/9, 69/4, 126

Part 1:

For finding the first five terms we will substitute values in n from 1,2,3,4 and 5

an = 2n^2 + 5n-10

a1 = 2(1)^2 + 5(1)-10

=4+5-10 = -1

So, the first term is -1

a2 = 2(2)^2+5(2)-10

= 16+10-10 =16

The second term is 16

a3 = 2(3)^2+5(3)-10

=64+15-10

=69

The third term is 69

a4 = 2(4)^2+5(4)-10

=256+20-10

=266

The fourth term is 266

a5 = 2(5)^2+5(5)-10

= 1024+25-10

= 1039

The fifth term is 1039

Part 2:

an = 3n+4/n^2+5

a1 = 3(1)+4/1^2+5

= 3+4+5

= 12

The first term is 12

a2 = 3(2)+4/2^2+5

= 6+1+5

= 12

The second term is 12

a3 = 3(3)+4/3^2+5

= 9+4/9+5

= 81+4+45/9

=130/9

The third term is 130/9

a4 = 3(4)+4/4^2+5

= 12+4/16+5

=17+1/4

=69/4

The fourth term is 69/4

a5 = 3(5)+4/5^2+5

= 15+4/25+5

=20+4/25

=504/4

= 126

The fifth term is 126

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If Rebekah can run 6 miles every 60 minutes, how
many miles can she run in 50 minutes?

Answers

Answer:

5 miles in 50 minutes

The rate is 1 mile per 10 minutes.
50 divided by 10 = 5.
So the answer is 5 miles

I need help i dont understand this

Answers

Answer:

oh god what da heck is this math :')

Step-by-step explanation:

How did the capture of the forts at Vincennes, Kaskaskia and Cahokia help end the war? A) It helped the Americans control the Ohio Valley. B) It helped the Americans control the Appalachian Mountains. C) It helped the Americans control the Mississippi Delta. D) It helped the Americans control Virginia.

Answers

The capture of the forts at Vincennes, Kaskaskia and Cahokia help end the war because it helped the Americans control the Appalachian Mountains.

What was the Siege of Fort Vincennes?

It was the War frontier battle that was fought in present-day Vincennes in which the Indiana won by the militia led by George Rogers Clark over a British garrison led by Henry Hamilton.

What was the Siege of Fort Kaskaskia?

The battle happened on 1778 where George Rogers Clark & his men reached Kaskaskia, seized it from the British men and bringing the colonies' battle for independence to the western edge of British territory in North America.

What was the Siege of Fort Cahokia?

It was one of the battle that happened in the West as the leader of the secret expeditionary forces captured Kaskaskia, Cahokia and Vincennes in 1778 to 1779.

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n(x) = -1 -1/3x + 1 2/3 given x = -2, 0, 5

Answers

The solution to the equations are n(-2) = 4/3, n(0) = 2/3 and n(5) = -1

How to solve the equation using the replacement sets?

The equation of the function is given as:

n(x) = -1 -1/3x + 1 2/3

The replacement set is given as

x = -2, 0, 5

So, we replace the variables using the elements in the replacement set

When x = -2, we have

n(-2) = -1 -1/3 x -2 + 1 2/3

Evaluate the equation

So, we have the following equation

n(-2) = 4/3

When x = 0, we have

n(0) = -1 -1/3 x 0 + 1 2/3

Evaluate the equation

So, we have the following equation

n(0) = 2/3

When x = 5, we have

n(5) = -1 -1/3 x 5 + 1 2/3

Evaluate the equation

So, we have the following equation

n(5) = -1

Hence, the values of the functions are 4/3, 2/3 and -1

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whats the explicit equation for r=3; f ( 1 ) = 1

Answers

The geometric sequence has an explicit equation of f(n) = 3^(n - 1)

How to determine the explicit equation of the function?

The given parameters are

r = 3

f(1) = 1

The above means that we have the following parameters:

Type of sequence: Geometric sequenceFirst term: f(1) = 1Common ratio: r = 3

The explicit equation of the geometric sequence is represented as

f(n) = f(1) * r^(n - 1)

Substitute the known values in the above equation

So, we have the following equation

f(n) = 1 * 3^(n - 1)

Evaluate the products

So, we have the following equation

f(n) = 3^(n - 1)

Hence, the explicit equation of the function is f(n) = 3^(n - 1)

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Solve the equation using the Quadratic Formula. 2x² + 5x = 3

Answers

Answer:

x = (1/2)

x = -3

Step-by-step explanation:

Quadratic:

2x² + 5x = 3

           -3     -3

----------------------

2x² + 5x - 3 = 0

-b ± √b² - 4(a)(c)

      -------------------

             2(a)

-5 ± √5² - 4(2)(-3)

---------------------------      

             2(2)

-5 ± √25 + 24

---------------------------

             4

-5 ± √49

----------------

      4

-5 ± 7

----------

    4

-5 + 7         2         1

---------- = ------- = ------

   4             4         2

-5 - 7        -12

---------- = --------- = -3

   4              4

----------------------------------------------------------------------------------------------------------

Factored (for fun):

(2x² + 6x) (-1x - 3) = 0

2x(x + 3) -1 (x + 3)

(2x - 1)(x + 3) = 0

2x - 1 = 0,    x + 3 = 0

     +1   +1         -3    -3

---------------    ------------------

  2x = 1             x = -3

 ÷2   ÷2

-------------

x = (1/2)

I hope this helps!

There are 16 boys and 12 girls in the running club. What is the ratio of girls to boys?
3:4
16:12
4:3
12:16

Answers

Answer:

4:3

Step-by-step explanation:

it will be 16:12 and when you divide both by 3 it will be 4:3

Write an augmented matrix for the following system of equations and give its size.- 8x + 3y = 1 4x - 7y = 4What is the augmented matrix?

Answers

SOLUTION:

The equation is;

[tex]\begin{gathered} -8x+3y=1 \\ \text{ }4x-7y=4 \end{gathered}[/tex]

Writing in matrix form, we have;

[tex]\begin{bmatrix}{-8} & {3} \\ {4} & {-7}\end{bmatrix}\begin{bmatrix}{x} & {} \\ {y} & {}\end{bmatrix}=\begin{bmatrix}{1} & {} \\ {4} & {}\end{bmatrix}[/tex]

The augmented matrix is thus;

[tex]\begin{bmatrix}{-8} & {3} & |{\text{ }1} \\ {4} & {-7} & |{\text{ }4} \\ {} & {} & \end{bmatrix}[/tex]

Umm.. Could someone answer this question pls...?
Find the value of v if 4(2v-1)=28​

Answers

Answer:

v = 4

Step-by-step explanation:

4(2v - 1) = 28

4(2v - 1)/4 = 28/4

2v - 1 = 7

2v - 1 + 1 = 7 + 1

2v = 8

2v/2 = 8/2

v = 4

Kelsey buys several pairs of uniform pants for $17.95 each, and a sweater for $24.
Jeana shops at a different store and buys several pairs of uniform pants for $18.95 each, plus a sweater for $18.
They set up the situation with the equation below, where x is the number of pairs of pants.
Is there a situation in which they pay the same amount for their purchases?
Which statements are true? Select all that apply.

17.95x + 24 = 18.95x + 18



There are no solutions to the equation.



There is one solution to the equation.



There are infinitely many solutions to the equation.



There is never a situation in which both girls will pay the same amount for their purchase.



The girls will both pay the same if they buy six pairs of pants and one sweater.



The girls will pay the same amount for any number of pants and one sweater.

Answers

Considering the definition of an equation and the way to solve it, the girls will both pay the same if they buy six pairs of pants and one sweater.

Definition of equation

An equation is the equality existing between two algebraic expressions connected through the equals sign in which one or more unknown values appear.

The solution of a equation means determining the value that satisfies it. In this way, by changing the unknown to the solution, the equality must be true.

To solve an equation, keep in mind:

When a value that is adding, when passing to the other member of the equation, it will subtract.If a value you are subtracting goes to the other side of the equation by adding.When a value you are dividing goes to another side of the equation, it will multiply whatever is on the other side.If a value is multiplying it passes to the other side of the equation, it will pass by dividing everything on the other side.

This case

Being "x" the number of pairs of pants, you know that:

Kelsey buys several pairs of uniform pants for $17.95 each, and a sweater for $24.Jeana shops at a different store and buys several pairs of uniform pants for $18.95 each, plus a sweater for $18.

The equation in this case is:

17.95x + 24 = 18.95x + 18

Solving:

24 -18= 18.95x - 17-95x

6= x

Finally, this means that Kelsey and Jeana pay the same if they buy six pairs of pants and one sweater.

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Is any real number exactly 2 more than its cube?

Answers

Answer: Yes  

Step-by-step explanation: The real number, which most exceeds its cube, is A 21

[tex] \rm \int_{0}^{1} \sqrt{ \frac{2 - {x}^{2} }{1 - {x}^{2} } } dx \\ [/tex]​

Answers

Substitute [tex]x=\sin(t)[/tex] and [tex]dx=\cos(t)\,dt[/tex], and recall the definition of the elliptic integral of the second kind,

[tex]\displaystyle E(k) = \int_0^{\pi/2} \sqrt{1 - k^2 \sin^2(\theta)} \, d\theta[/tex]

Then the integral has a value of

[tex]\displaystyle \int_0^1 \sqrt{\frac{2-x^2}{1-x^2}} \, dx = \int_0^{\pi/2} \sqrt{2-\sin^2(t)} \, dt \\\\ ~~~~~~~~~~~~~~~~~~~~~ = \sqrt2 \int_0^{\pi/2} \sqrt{1 - \frac12 \sin^2(t)} \, dt \\\\ ~~~~~~~~~~~~~~~~~~~~~= \boxed{\sqrt2 E\left(\frac1{\sqrt2}\right)}[/tex]

If a new truck is valued at $19,700, what will its value be in 1 year if it depreciates 14.4 % each year?

Answers

depreciated value of truck after 1year is $16863.2  

WHAT IS PERCENTAGE ?

% is a relative number that is used to represent hundredths of any quantity. Since one percent (1%) equals one tenth of something, 100 percent denotes the entire amount, and 200 percent denotes twice the amount mentioned.

CALCULATION

new truck valued depreciates 14.4% then

if old truck value be 100 % , depreciated value will  be 85.6 %

so depreciated value will be = 19700* 85.6 /100

                                                 = $16863.2

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A forest fire leaves behind an area of grass burned in an expanding circular
pattern. If the radius of the circle of burning grass is increasing with time
according to the formula r(t) = 2t + 1, express the area burned as a function of
time.

Answers

The function of the  area of the forest in terms of time is A(t) = π(2t + 1)²

How to determine the area function?

The given parameters are

Radius function,  r(t) = 2t + 1

From the question, we understand that:

The pattern is circular

The area of a circle is

A = πr²

Express as a function

A(r) = πr²

Substitute r(t) = 2t + 1

A(t) = π(2t + 1)²

Hence, the area function in terms of time is A(t) = π(2t + 1)²

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f(x) = -4/3 (-x+5)^3 +12

Answers

X   Y
3    1.333
4    10.667
5    12
6    13.333
8    48

Find the value of x.

Answers

x = 9


step by step


Hope this helps

Answer for this question

Answers

Answer:

Proofs provided below

Step-by-step explanation:

[tex]\bold {\text{Prove } (a + b)^2 = a^2 + 2ab + b^2}}[/tex]

[tex]\\\\\implies (a + b)^2 = (a+b) \times (a+b)\\\\\implies (a + b)^2 = a \times (a+b) +b \times (a+b)\\\\\implies (a + b)^2 = a \times a + a \times b + b \times a + b \times b\\\\\implies (a + b)^2 = a^2+ab+ba+b^2\\\\\implies (a + b)^2 = a^2+ab+ab+b^2 \;\;\;\;\text{ since ab = ba}\\\\\implies (a+b)^2 = a^2+2ab+b^2\\\\[/tex]

[tex]\bold{\text{Prove } a^2-b^2 \,=\, (a+b)(a-b)\\\\}[/tex]

1. Add and subtract ab to LHS
[tex]\implies a^2-b^2 = a^2-b^2-ab+ab\\\\\implies a^2-b^2 = a^2-ab+ab-b^2\\\\[/tex]

2. Factorize the above expression
[tex]\implies a^2-b^2 = a(a-b)+b(a-b)\\\\\implies a^2-b^2 = (a-b)(a+b) \;\;\;\; \text{since (a-b) is a common factor in RHS }[/tex]

∴  (a² - b²) = (a - b) (a + b)

[tex]\bold{\text{Prove $\dfrac{\sqrt{3}+1}{\sqrt{3}-1}$= $2+\sqrt{\ensuremath{3}}$}}\\[/tex]

[tex]\text{1. Multiply LHS by $\dfrac{\sqrt{\text{}3}-1}{\sqrt{3}-1}$}\\\\\implies $\dfrac{\sqrt{\text{}3}+1}{\sqrt{3}-1}$ \times $\dfrac{\sqrt{\text{}3}-1}{\sqrt{3}-1}$ \\\\[/tex]

[tex]\implies \dfrac{ (\sqrt{3} + 1)(\sqrt{3}-1) }{(\sqrt{3} - 1)(\sqrt{3}-1) }\\\\[/tex]

Numerator is
[tex](\sqrt{3} + 1)(\sqrt{3}-1) = (\sqrt{3})^2 - 1^2 = 3 - 1 = 2\\\\[/tex]

Denominator is
[tex](\sqrt{3}-1)^2 = (\sqrt{3})^2 - 2\cdot \sqrt{3} \;\cdot 1 + (-1)^2\\\\= 3 - 2 \sqrt{3} + 1\\\\= 4 - 2 \sqrt{3}\\\\[/tex]

So LHS becomes
[tex]\dfrac{2}{4 - 2\sqrt{3}} \\\\[/tex]

Dividing numerator and denominator by 2 yields

[tex]\dfrac{2}{4 - 2\sqrt{3}} = \dfrac {1}{2 - \sqrt{3}}[/tex]

Multiply numerator and denominator by [tex]{2-\sqrt {3}}[/tex]

[tex]$\dfrac{1\cdot(2+\sqrt{3})}{(2-\sqrt{3})(2+\sqrt{3)}}$[/tex]

[tex]=$\dfrac{\ensuremath{2}+\sqrt{3}}{2^{2}-(\sqrt{3)^{2}}}=$$\dfrac{\ensuremath{\ensuremath{2}+\sqrt{3}}}{4-3}=\ensuremath{2}+\sqrt{3}$[/tex]

Hence Proved

Divide 8 1/2 by the positive difference between 4 4/5 and 7 7/10

Answers

The division of  8 1/2 by the positive difference between 4 4/5 and 7 7/10 is 85/29.

How can we make the division?

We can find the difference between 4 4/5 and 7 7/10, but we will need to convert the mixed number into the improper fraction as

Then we have 24/5 and 77/10, then the difference between the values are:(77/10 - 24/5) = 29/10

Then we can proceed to find the division of this number that we got from the difference as ( 29/10)/  8 1/2

But we can make the  8 1/2 as improper fraction from the mixed fraction it was 17/2

Then the division of the values will be   ( 17/2)/ ( 29/10)  = 85/29

Therefore the division is 85/29.

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Maximize:
z= 6x +12y
subject to: 4x + 5y ≤20
8x + y ≤ 20
x≥0, y 20

Answers

Answer:

48

Step-by-step explanation:

Given:

[tex]\textsf{Maximize}: \quad z=6x+12y[/tex]

[tex]\begin{aligned}&\textsf{Subject to}: \quad &4x+5y & \leq 20\\&&8x+y &\leq 20\\&&x\geq 0, y&\geq 0\end{aligned}[/tex]

Graph the lines:

[tex]\textsf{Draw the line } \;\;4x+5y=20 \;\;\textsf{and shade under the line}.[/tex]

[tex]\textsf{Draw the line } \;\;8x+y=20 \;\;\textsf{and shade under the line}.[/tex]

[tex]\textsf{Draw the line } \;\;x=0\;\;\textsf{and shade above the line}.[/tex]

[tex]\textsf{Draw the line } \;\;y=0\;\;\textsf{and shade above (to the right of) the line}.[/tex]

Therefore, the feasible region is bounded by the corner points:

A = (0, 0)B = (0, 4)C = (⁵/₂, 0)D = (²⁰/₉, ²⁰/₉)

Determine the value of z at the corner points by substituting the x and y values of the points into the equation for z:

[tex]\textsf{Value of $z$ at $A(0,0)$}: \quad 6(0)+12(0)=0[/tex]

[tex]\textsf{Value of $z$ at $B(0,4)$}: \quad 6(0)+12(4)=48[/tex]

[tex]\textsf{Value of $z$ at $C\left(\dfrac{5}{2},0\right)$}: \quad 6\left(\dfrac{5}{2}\right)+12(0)=15[/tex]

[tex]\textsf{Value of $z$ at $D\left(\dfrac{20}{9},\dfrac{20}{9}\right)$}: \quad 6\left(\dfrac{20}{9}\right)+12\left(\dfrac{20}{9}\right)=40[/tex]

Hence, the maximum value of z is 48 at B(0, 4).

Maria has $5.05 in quarters and dimes. The number of quarters is exceeds twice the number of dimes by 1. Find the number she has of each kind.

Answers

The number of quarters and dimes with Maria are 17 and 8 respectively.

How are simultaneous linear equations solved?

Linear equations in mathematics are ones where the greatest power of the variable is one. A linear equation can only have one possible solution: a straight line. Thus, a simultaneous linear equation is a system of two linear equations in two or three variables that are solved concurrently to get a shared answer. Three methods are frequently used to solve simultaneous linear equations: substitution method, elimination method, and graphic method.

Let q be the number of quarters.

Let d be the number of dimes.

Given that the total amount is 5.05 in quarters and dimes

Therefore, 0.25 q + 0.10d = 5.05;

I once more, q = 2d + 1. — (ii) (ii)

Inferring from I and (ii), d = 4.80/0.60 = 8 and 0.25(2d + 1) + 0.10d = 5.05 and 0.60d = 4.80 respectively.

This is put into (ii), and the result is q = 2d + 1 = 2*8 + 1 = 17.

As a result, q = 17 and d = 8

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Which of the following expressions illustrates how you can use the
associative property of addition to solve 13+6.2+5.8 more simply?
a. 13+5.8+6.2
b. (13+6.2)+5.8
c. 13+(6.2+5.8)
d. (13+6.2)+(13+5.8)

Answers

Answer:

c.

Step-by-step explanation:

13+6.2+5.8

= 13+(6.2+5.8)

- the sum in the parentheses is easy to calculate (it = 12).

What type of linear equation is X +1 equals X +1?

Answers

The given equation is 1-degree linear equation in one variable.

What is linear equation?

A linear equation is one that may be written as a1x1+a2x2+......+anxn in mathematics, where a1, a2,...., an are the coefficients, which are frequently real integers. The coefficients, which may be any expressions as long as they don't contain any of the variables, can be thought of as the equation's parameters. The coefficients a1 to a must not all be 0 in order for the equation to have any sense. An alternative method for creating a linear equation is to equalize a linear polynomial over a field, from which the coefficients are drawn, to zero. The numbers that, when used to replace the unknowns in such an equation, result in the equality, are the solutions.

x+1 = x+1 is a 1-degree linear equation in one variable (x).

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A dolphin swims at a depth of 13.5 meters below sea level while a seagull flies 10 meters above sea level. How far apart are they? Write and evaluate an expression to answer this question.

Answers

ANSWER: 23.5 meters
10-(-13.5)= 23.5

Solve for .
5x - 4 ≥ 12 OR 12x + 5 < -4

Answers

Answer: That is the answer

Step-by-step explanation:

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