After 8 years, how much will brandon have saved in interest by consolidating the two balances? a. $581.76 b. $194.40 c. $256.32 d. $325.44

[tex]~~4\sqrt{15} \left( 2\sqrt 2 + \sqrt 5 \right)\\\\=8\sqrt{15} \sqrt 2 + 4\sqrt{15} \sqrt 5\\\\=8\sqrt{15\times 2}+4 \sqrt{15 \times 5}\\\\=8\sqrt{30}+4\sqrt{3 \times 5 \times 5}\\\\=8\sqrt{30} + 4 \sqrt{3\times 5^2}\\\\=8\sqrt{30} + 4\cdot 5 \sqrt 3\\\\=8\sqrt{30} +20\sqrt{3}[/tex]

The reason for step 4 that is missing is: definition of linear pair.

A line pair are two angles on a straight line whose sum equals 180 degrees.

Angles ANV and ANR line on a straight line and are therefore linear pair. This implies that:

m∠ANV + m∠ANR = 180 degrees

Therefore, the missing reason is: definition of linear pair.

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The equation that models the scenario is 16p+32q = 1,280.

Addition is the mathematical operation that is used to determine the sum of two or more numbers.

The equation that would model the scenario can be determined by adding the total pints and total quarts Chin has :

Total pint + total quart = total ounces

16p+32q = 1,280.

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Answer:

Step-by-step explanation:

Let the length of shorter sides be x and longer sides be y.

Then we have the system:

Solve it by substitution:

Find the value of y:

Shorter one be x

longer one=x+8

So

Time required for longer side

The expression that is equivalent to (4mn/m^-2n^6)^-2 is [tex]\frac{n^{10}}{16m^{6}}[/tex]

The expression is given as:

(4mn/m^-2n^6)^-2

Apply the law of indices

[tex](4m^{1 + 2}n^{1-6})^{-2[/tex]

Evaluate the sum and the differences

[tex](4m^{3}n^{-5})^{-2[/tex]

Apply the negative exponent

[tex]\frac{1}{16m^{2*3}}}n^{5*2}[/tex]

Evaluate

[tex]\frac{1}{16m^{6}}n^{10}[/tex]

Rewrite as:

[tex]\frac{n^{10}}{16m^{6}}[/tex]

Hence, the expression that is equivalent to (4mn/m^-2n^6)^-2 is [tex]\frac{n^{10}}{16m^{6}}[/tex]

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Answer:

See below

Step-by-step explanation:

Given there are 56 M&M's:

Remember to use [tex]np[/tex] to calculate expected value! This will especially be helpful if you are conducting a chi-squared test of independence.

Answer:

6p + 3 < -15 or 6p + 3 > 15

P < - 3 or P > 2

Answer:

Step-by-step explanation:

It looks like the best option is 3.

Given the equation,

we can make a table. x as input and y as output to get our points to the graph.

I have used the desmos graph as a reference to confirm the equation by graphing also. The table is also there.

[tex]~~(6+9i)(6-9i)\\\\=6^2-(9i)^2~~~~~~~~~~~~~~~~~~~;[a^2-b^2 =(a+b)(a-b)]\\\\=36-81i^2\\\\=36-81(-1)~~~~~~~~~~~~~~~~;[i^2 = -1]\\\\=36+81\\\\=117[/tex]

An event that may occur in the game is you roll a  and get a tail.

The probability that he will roll a 5 and get a head is 1 / 12.

Probability determines the chances that an event would happen. The probability the event occurs is 1 and the probability that the event does not occur is 0.

The probability that he will roll a 5 and get a head = (Number of sides with a 5 / number of sides in a cube) x (number of sides with a head / number of sides in a coin)

1/6 x 1/2 =  1 / 12.

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Answer:

(x+1)(x-9)

Step-by-step explanation:

x^2+x-9x-9=0
x*(x+1)-9(x+1)=0
(x+1)(x-9)=0
x+1=0
x-9=0
x=-1 and x=9

Answer:

21.47034391

by using the formula of volume i found radius and after that i use the formula of circumference and found it

hope you will understand

volume=4/3πr^3 and circumference= 2πr

The slope of Anya’s line on the graph is 3

The equation is given as:

(y−2)=3(x−1)

Remove brackets

y − 2 = 3x − 3

Add 2 to both sides

y = 3x − 1

A linear equation is represented as:

y = mx + c

Where m represents the slope;

By comparison, m = 3

Hence, the slope of Anya’s line is 3

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Answer:

3

Step-by-step explanation:

its right

Power is often measured in joules of work per second

Answer:

110 is the correct answer...

Answer:

cos(x)+1 or cos x + 1

Step-by-step explanation:

The wave starts at y=2 this means it is a cosine function, then the first positive x-intercept is at about (pi, 0) which is about 3, this leads to cos x + 1 as the answer.

Answer:

Step-by-step explanation:

As it is a second order equation, it means that it has two possible answers and they are [tex]x_1[/tex] and [tex]x_2[/tex].

The famous quadratic formula for solving any second order equation is the following:

[tex]x_{1} = \frac{-b + \sqrt{b^2 - 4 ac}}{2a}\\x_{2}=\frac{-b - \sqrt{b^2 - 4 ac}}{2a}[/tex]

Where a is the coefficient of [tex]x^2[/tex], b is the coefficient of x, and c is the free term. In other words,

[tex]a = 3\\b=4\\c=-2[/tex]

as the equation should be in the following form:

[tex]a x^2 + bx+c = 0[/tex]

Therefore the possible answer should be the following,

[tex]\frac{-4 + \sqrt{4^2 - 4*3*(-2)}}{2*3}=\frac{-4 +\sqrt{16 + 24}}{6} =\frac{-4 + \sqrt{40}}{6}=\\ \frac{-4 + \sqrt{4*10}}{6} = \frac{-4 + 2\sqrt{10}}{6}[/tex][tex]\frac{2*(-2 + \sqrt{10})}{2*3} = \frac{-2 + \sqrt{10}}{3}[/tex]

by dividing the numerator and denominator by 2, we can deduce the following,

Answer:

68

Step-by-step explanation:

[tex]4+\left(11-3\right)^2\\(11-3)=8\\=4+8^2\\=4+64\\=68[/tex]

Expand the square. Remember that

(a - b)² = a² - 2ab + b²

With a = 5√3 and b = √27, we have

(5√3 - √27)² = (5√3)² - 2 (5√3) √27 + (√27)²

… = 25•3 - 10√81 + 27

… = 75 - 10√(9²) + 27

… = 102 - 10•9

… = 102 - 90

… = 12

The statement: "Kiley bought a platter for $ 19 and several matching bowls that were $ 8 each. What is the cost before tax?" shows discrete graph.

A discrete graph is one with scattered points. They may or may not show a direction or trend. They don't have data in between the points already given.

Here only first option shows a graph with scattered point.

Thus, the statement: "Kiley bought a platter for $ 19 and several matching bowls that were $ 8 each. What is the cost before tax?" shows discrete graph.

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Answer:

-2x²-3x+5=0

-2x²+2x-5x + 5 = 0

-2x(x+1)-5(x + 1) = 0

(x+1) (-2x-5) = 0

Answer:

162 metres

Step-by-step explanation:

Since h is proportional to the square of v, we know that their ratio must be constant, so [tex]v_1^2/h_1 = v_2^2/h_2[/tex] where v1 and v2 are velocities and h1 and h2 are their respective heights.

Since we are given that v = 10 and h = 8, we can set v1 = 10 and h1 = 8 and since we are trying to find the height for v = 45, we can set v2 = 45. Inputting these values into the equation and solving, we get

10^2/8 = 45^2/h2

h2 = 45^2/(10^2/8) = 162 metres

I hope this helps!

Answer:

C 13

Step-by-step explanation:

i think answer its c

Answer:

nah man it's 12without a doubt look over at d a that's 13 if you compare the to gc is smaller in length so it is 12

[1] 0.25, 0.25%, or [tex]\frac{1}{4}[/tex]

     We will divide the number of wanted outcomes by possible outcomes.

[tex]\displaystyle \frac{\text{wanted outcomes}}{\text{possible outcomes}} =\frac{5}{3+5+12} =\frac{5}{20} =\frac{1}{4}[/tex]

[2]

     We will follow the same steps as problem 1.

MTHMTCS = 7 consonants

AEAI = 4  vowels

MTHEMTICS = 9 letters that are not A's

MATHEMATICS = total of 11 letters

(a)

[tex]\displaystyle \frac{\text{wanted outcomes}}{\text{possible outcomes}} =\frac{7}{11}[/tex]

(b)

[tex]\displaystyle \frac{\text{wanted outcomes}}{\text{possible outcomes}} =\frac{4}{11}[/tex]

(c)

[tex]\displaystyle \frac{\text{wanted outcomes}}{\text{possible outcomes}} =\frac{9}{11}[/tex]

[3] 0.877

     If the probability that a television is defective is 0.123, then the probability that a television is not defective is:

1 - 0.123 = 0.877

Based on the calculations, an expression which is equivalent to [u/v](x) is: C. -x³ + x² - 1.

Given the following data:

An expression is a mathematical equation which is used to show the relationship that exist between two or more numerical quantities or variables.

In this exercise, we would evaluate the given expressions by factorizing the function u(x) as follows:

u(x) = x⁵ – x⁴ + x²

u(x) = x²(x³ – x² + 1)

Rewriting the expressions as a fraction, we have:

[tex]\frac{u(x)}{v(x)} = \frac{x^2(x^3 - x^2 + 1)}{-x^2}\\\\\frac{u(x)}{v(x)} = -(x^3 - x^2 + 1)\\\\\frac{u(x)}{v(x)} = -x^3 + x^2 - 1[/tex]

Therefore, u(x)/v(x) = -x³ + x² - 1.

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Answer:

c

Step-by-step explanation:trust