All of the following statements are true except: group of answer choices installing the cross with the zerk fitting backwards will make it difficult, if not impossible, to lube the u-joint after the driveshaft is installed on the vehicle. universal joint lubricant is nlgi #5, with an extreme pressure (ep) additive. sometimes, universal joint cups are held in place with plastic material that is injected into a hole in the yoke. usually galling will be found on a trunnion 180 degrees to brinelling.

In order to clear the ground fault, the system bonding jumper offers a low-impedance fault-current path to the electrical supply source.

It refers to service entry equipment and its connected and interconnected parts; in other words, one system conductor is grounded to stabilize the voltage to grounding during normal operation and to reduce voltages caused by lights, line surges, or unintended contact with higher voltage lines. The primary function of this wire is to guarantee the provision of a low-impedance conduit for ground-fault current to return to the utility supply transformer or source and to permit overcurrent device operation during a ground-fault occurrence. When the Code refers to a "low impedance path," The key concept is low opposition or impedance; it refers to a conduit for current to travel on that gives less resistance to current flow, whether it be fault current or normal current.

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The diameter d of shaft is 0.319m

The actual maximum shear stress of the shaft is 44.95N/m^2

The angle of twist of the 3-m length shaft is 0.01409 rad

The question is incomplete, here is the complete question:

A solid steel shaft 3 m long is transmitting 12 MW at 400 rev/min. The working conditions

to be satisfied by the shaft are:

• The shaft must not twist more than 0.015 radian on a length of 10 times the diameter, i.e., 10D

• The maximum shear stress must not exceed 70 MN/m2.

If the modulus of rigidity of steel is 60 GN/m2 determine:

(a) The diameter of the shaft required

(b) The actual maximum shear stress and the angle of twist of the 3-m length shaft.

Part a

The diameter of the shaft

We use Torque equation to find diameter d:

[tex]\frac{T}{J} =\frac{G\theta }{L}[/tex]

[tex]\frac{12*10^{6}*60 }{25600d^{4} } =\frac{60*10^{9}*0.015 }{10d}[/tex]

[tex]d^{3} =0.032414[/tex]

d=0.319m

Hence, diameter of shaft d=0.319m

Part b

Actual maximum shear stress Y, and the angle of twist of the 3m length shaft

[tex]Y=\frac{16T}{\pi d^{3} }[/tex]

[tex]Y=\frac{16*286478.90}{\pi *0.319^{3} }[/tex]

[tex]Y=44.95N/m^{2}[/tex]

Angle of the twist

Let angle of twist =  [tex]\theta[/tex]

[tex]\theta=\frac{TL}{GJ}[/tex]

  [tex]=\frac{286478.90*3}{60*10^{9}(\frac{\pi }{32}(0.019)^{9} }[/tex]

 =0.01409rad

Angle of twist=0.01409 rad

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The reason that makes it is difficult to accurately quantify the quantum of carbon released from terrestrial ecosystems  are linked with Sensitivity analysis as well as bias made by gap filling of satellite data.

In its ground state, the six electrons of carbon (atomic number 6) in the second row of the periodic table occupy two of its primary energy levels, giving the highest-energy electron a principal quantum number n of 2.

Therefore, note that the act of  carrying out Sensitivity analysis  is a factor that has hindered the knowledge about the amount of release of carbon in the atmosphere.

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A steam nozzle is a channel or duct with a cross-sectional area that varies gradually and is used to transform the heat energy of steam into kinetic energy. The nozzle's shape is created to convert energy with the least amount of loss possible.

Steam loses both pressure and heat as it travels through the nozzle. The Rankine area is equal to the work completed, which is equal to the adiabatic heat decrease. Steam passing through nozzles can be thought of as expanding adiabatically. The gas's speed rises to supersonic (Mach number >1) as it travels through the diverging nozzle. If the flow is sonic at the throat, the flow rate is at its highest for the particular nozzle.

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What the question wants is to write a code that would find and display the average of two numbers given by a user.

The code or program has been written and has been given below in C + +

#include <iostream>

using namespace std;

int main() {

   int a, b, sum;

   double avg;

   cout << "Enter the first integer number: ";

   cin >> a;

   cout << "Enter the second integer number: ";

   cin >> b;

   sum = a + b;

   avg = (double)sum / 2;

   cout << "\nThe average of your numbers is: " << avg << "\n";

   return 0;

}

Enter the first integer number: 2

Enter the second integer number: 4

The average of your numbers is: 3

A simple explanation of the code is that it makes use of mathematical operators to perform the calculations by first adding up the numbers and then finding the average of the two numbers by dividing the sum of the numbers with two which is the number of elements.

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Answer:

(adjective)

produced by the internal heat of the earth.

{thermal means heat}

A performance (HC) curve for a given centrifugal pump shows that option B. Flow rate decreases as the head required to overcome system resistance increases.

The Centrifugal pump curves are helpful because they display metrics for the performance of the pump based on the head (pressure) the pump produces and the water flow through the pump. Impeller diameter, head, as well as the pump speed all affect flow rates.

Note that an instrument that predicts a pump's head and flow performance is a centrifugal pump performance curve. Pumps provide low volume flow rates when pumping against high-pressure heads and high volume flow rates if they are said to be pumping against low-pressure heads.

Therefore, one can say that every centrifugal pump has a curve that it follows in order to function, and every curve has a start point (the shut-off or zero flow) and an end point (the end-of-curve or the maximum flow that can be achieved without overtaxing the motor).

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The location at which a fuse should be installed in the 120 V, 20 A, residential circuit is in the live wire on the circuit, not in the neutral wire. The correct option is therefore;

A. A fuse should never be installed in the neutral.

The function of an electric fuse, which is a safety device, is to provide protection from an over flow of current in the circuit.

Generally, an electric fuse consists of a metal wire or filament that melts, due to its rise in temperature when excessive current or current at an unsafe level flows in the circuit, thereby opening the circuit, to protect the circuit and its components.

The effect of excessive or over current in a circuit is that it causes the circuit component to heat up and burn, such that the circuit and device stops functioning, and in some cases, may cause a fire.

The fuse, which is a circuit safety device, should be the first contact of the current.

Therefore;

The fuse should not be installed on the neutral wire, gives that the burning of the fuse in the neutral, in the event of an over current, leaves the high current in the circuit, which can cause unwanted damage to the circuit.

The correct option is therefore option A;

A. A fuse should never be installed in the neutral

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The option that  applies to using a hacksaw is option D. don't apply pressure on the forward stroke.

The hacksaw blade is one that  should be installed with the teeth facing forward. The blade of the saw will cut when it is pushed (the forward stroke) as opposed to when it is pulled.

Note that Certain blades feature an arrow that helps to show or indicates the proper placement.

Note that when using a Hacksaw, the cutting action is said to be one that occur on the forward stroke, so a person should not place pressure when they are pulling the saw towards them.

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A non-rotating solid round bar with diameter of 2-in has a groove cut to a diameter of 1.8-in, with a groove radius of 0.1-in. the bar is loaded with a repeated bending load that causes the bending moment at the groove to fluctuate between 0 and 25000 lbf-in. the bar is hot-rolled aisi 1095, but the groove has been machined. The factor of safety guarding against first-cycle yielding will be nf=1.11 and the factor of safety against fatigue failure will be ny=2.41.

From the table A-20 Deterministic ASTM minimum tensile and yield strengths for HR and CD steels, we have approximately:

D= 2.1, d (diameter) = 1.892, r= 0.117

Endurance limit for the material= Se'= 60 kpsi

According to the goodman relation= nf= 0.833

Yielding factor of safety: ny= Sy/σmax= 66/36.828

ny= 1.792

When the factor of safety is 1, the substance is practically at yield. Based on the greatest anticipated load situation, the majority of designers aim for a safety factor of between 2 and 4. Unless the maximum expected load is repeatedly applied, if some design elements experience yield, part failure is not necessarily the result.

The element of safety with regard to a fatigue failure at a specific design life is known as the fatigue safety factor. The Factor of Safety can go up to 15. Values less than one for the Fatigue Safety Factor imply failure before the design life is achieved.

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When refrigerant-134a is used, the refrigerant mass flow rate is 0.0952kg/s, and the compressor power requirement is 1.659kw

Part a

Refrigerant mass flow rate:

From the steam table refrigerant-134a, we have the following variables:

[tex]h_{1}[/tex] = 252kj/kg

[tex]h_{2}[/tex] = 270.43kj/kg

[tex]h_{3} = h_{4} = 95.47kj/kg[/tex]

Cooling load = 15kw

Now, refrigerator mass flow rate (m)= [tex]\frac{cooling load}{h_{1} -h_{4} }[/tex]

                                                       = [tex]\frac{15}{253-95.47}[/tex]

                                                       =0.0952kg/s

Part b

Compressor power requirement ([tex]W_{c}[/tex])

                                                  = [tex]m(h_{2} -h_{1} )[/tex] , where m is 0.0952kg/s

                                                  =0.0952(270.43-253)

                                                  =1.659kw

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The new dimensions of the titanium alloy pin will be that the width is 0.0775 mm and the length is 4.9225m.

The Poisson's ratio is the proportion of a material's change in width per unit width to its change in length per unit length due to strain. In order for a stable, isotropic, linear elastic material to have a positive Young's modulus, shear modulus, and bulk modulus, the Poisson's ratio must be between 1.0 and +0.5. Poisson's ratio values for the majority of materials fall between 0.0 and 0.5.

The formula for the longitudinal strain is:

= Change in length / Initial length

Based on the information, the longitudinal strain will be:

= 105 - 100 / 100

= 0.05

Poisson ratio will be illustrated as the change in the width divided by the longitudinal strain.

0.31 = ∆w/5 / 0.05

∆w = 0.0775 mm

New side length will be the difference in the changes in the dimensions. This will be:

= w - ∆w

= 5 - 0.0775

= 4.9225m

In conclusion, the length is 4.9225m.

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The pressure drop across the turbine if it delivers 60 kw is 75.4KPa.

The task of providing usable output shaft power to drive the propeller falls on the turbine section of the gas turbine engine. It must also deliver energy to run the compressor and other engine accessories. This is accomplished by expanding the gas at high pressure, temperature, and velocity and transforming the resulting gaseous energy into mechanical energy in the form of shaft power.

The turbine needs a significant volume of air to generate the required amount of electricity. The compressor provides this volume of air by pulling it into the engine and compressing it to provide high-pressure air for the turbine.

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According to the Hall-Petch connection, by lowering grain size, we could make materials stronger than their own theoretical strength.

In fact, their strength rises with decreasing grain size until it reaches a peak at about 20–30 nm. The yield strength is further decreased when the grain size grows by annealing at higher temperatures, but further advancement in tensile elongation is constrained. Be aware that ductility increases slightly when grains are refined from 2 to 1 micrometers in the micrometer-grained scale. strength, ductility, and hardness. Nanocrystalline materials exhibit a significant increase in hardness and strength compared to their coarser-grained counterparts as a result of Hall-Petch strengthening (increase in hardness associated with a reduction in average grain size).

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If Enzo’s balance sheet for the month of July is has both assets and liabilities. The expression that will finds Enzo’s net worth is: A. 127,100 dollars minus 88,500 dollars .

Net worth can be determine by deducting the assets of a company by its liabilities which in turn implies that a company or an organization will tend to known their net worth after deducting their financial obligation (debt) from their assets .

Using this formula to find the net worth

Net worth = Assets -Liabilities

Where :

Assets = $127,100

Liabilities = $88,500

Let plug in the formula

Net worth = $127,100 -$88,500

Net worth = $38,600

Hence,

127,100 dollars minus 88,500 dollars .

= $38,600

Therefore the company would have to record their net worth in the amount of $36,800 making option A  the correct option because assets minus the liabilities would give us $36,800.

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When technician a says that variable valve timing allows the engine’s piston displacement to be increased or decreased, and technician b says that in-block cams usually include variable valve timing, then both of them are correct.

In an engine, a variable valve timing allows the engine’s piston displacement to increased or decreased to provide better operating conditions to engine. The reason is if the engine piston displacement is increases or decreases it allows the air to the engine which can increase the RPM of the engine.

In an engine in which the block cam is used, the variable valve timing is present. The reason is the timing gap provided by the cam to the valves is variable.

Here, the technician A says variable valve timing allows the engine’s piston displacement to increased or decreased and technician B says that in block cams usually include variable valve timing. So, both technician A and B are correct.

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By torque, the allowable dimension d is 5.95 mm.

We need to know about torque to solve this problem. Torque is the rotational equivalent of linear force. It can be determined as

τ = F x r

where τ is torque, F is perpendicular force and r is radius.

From the question above, the parameter given are

F = 200 N

r = 250 mm

x = 24 mm

a = 20 mm

τallow = 35 MPa

The equation of torque will be

Fa . a = F . r

Fa . 0.02 = 200 . 0.25

Fa = 5000 N

τallow = F / A

τallow = F / x.d

35000 = 200 / 0.024.d

d = 5.95 mm

Hence, the dimension d is 5.95 mm

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Answer:

I could draw it but I cannot see the dimensions clearly. Also, be precise in question. In what projection are you drawing it.

The maximum capillary rise and tube diameter for this maximum-rise case will be d=0.414× 10⁻⁴ m.

What do you mean by tube?

A tube, also known as tubing, is a long hollow cylinder that is used to transport fluids (liquids or gases) or to protect electrical and optical cables and wires.

Given that, P = 4 KPa

Contact angle = 6°

Surface tension = 1 N/m

Lets assume that atmospheric pressure = 100 KPa

Lets take that density of water = 1000kg/m³

So the capillarity rise h

h=ΔP/ρg

h= (100×1000-4×1000)/(1000×10)

h= 9.61 m

We know that for capillarity rise h

h=2σcosθ/rρg

r = 2σcosθ/hρg

r = (2×1cos4°)/(9.61×1000×10)

r = 0.207×10⁻⁴m

d=0.414× 10⁻⁴ m

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Answer:

9 1/2

Explanation:

3 4/5 is 3.8

2/5 is 0.4

divide 3.8 by 0.4 you get 9.5 which is 9 1/2 in a fraction

Answer:

Strap wrench (I think)

Explanation:

The strap doesnt have any rough edges so it shouldn't mark the workpiece (assuming that is what you meant when you said 'marring'). I would recommend to wait for some other answers though since i haven't studied this yet :)

Advantage in using bearing installation or a removal tool to replace a seal in housing is that seal will have its inner edge taken all the insertion force. Hence, an option a is correct.

Sealed bearing are preferred due to basic aspects such as no accidental over lubrication, as they do not need lubrication thus save time in labor, On the inner track of bearing, it has no contact to the seal's bearing. Since, contaminants can cause wearing and tearing of the machine thus reduce lifespan since sealed bearing is more closed type it thus no contaminants enter since no lubricant is required.

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When technician a says it is important that a full battery test series be done before trying to test the starter system, and technician b says the internal condition of the engine has little effect on the operation of the starting system, then only technician a is correct.

Ideally, before testing the starter system, full battery test series is to be completed. The reason for this is that both the performance of starter and battery system is so closely related.

And it should also be replaced if it fails the load test. The operation of the starting system will be influenced by the internal condition of the engine.

Therefore, technician a is right.

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The given example in this question is a type of discretionary dependency. It states that the design of several deliverables must be completed before starting manufacturing. So option A is correct answer.

In project management, the dependencies show the relationship of the preceding task to the succeeding task. A task can have many preceding and succeeding tasks. Furthermore, there are three different types of dependencies that are mostly used in project management. These dependencies are discretionary, external, and mandatory.

Discretionary dependency is also known as soft logic. It shows how teams working on a project anticipate the work to be completed. It allows the teams working on the project to optimize the flow of work throughout the project life cycle.  It also utilizes the best practices and methodologies based on the team and project manager’s experience.

In the given scenario of the question, the design engineer based on her area of expertise properly defined on the project. She may decide based on her areas of expertise that all other deliverables must be completed before manufacturing can begin.

While the other options are incorrect because:

Mandatory dependency defined that a particular task or activity must be carried out at a specific time. While the external dependency takes input from an external source before proceeding a task.

The complete question is given below:

“ a design engineer is helping to ensure that the dependencies within her area of expertise are properly defined on the project. the design of several deliverables must be complete before manufacturing can begin. this is an example of what type of dependency?

A. Discretionary dependency

B. External dependency

C. Mandatory dependency

”

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The maximum positive moment at c is 135k/ft

the maximum positive vertical reaction at b is 27k

Part a

Maximum positive moment at c

For maximum positive moment at C and as per Muller's principle, ILD influence line will be on moment at с, this is calculated using the equation below:

Maximum positive moment at c = [tex](\frac{1}{2} *20*5*(0.4+0.5) )+(5*8)[/tex]

                                                    = 135k.ft

Part b

Maximum positive vertical reaction at b

To find this using Muller's principle, we keep dead load throughout the span and consequently keep point load at B

Maximum positive vertical reaction at b = [tex](\frac{1}{2} *20*1*(0.4+1.5))+(1*8)[/tex]

                                                                 = 27k

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As a hiring manager at GE, who is tasked with using the building blocks that managers can use in constructing an organization, the basic building block of structure I would use as I scale down on managerial positions and scale up on engineering positions is C. designing jobs

This refers to the process of taking charge of people or processes in order to achieve a set target or common goal, by maximizing or optimizing the available physical and human resources available.

Hence, we can see that based on the fact that I am a hiring manager for a company that has different facets and businesses and want to scale down on management positions and increase or scale up in the positions that require engineers, it would be important to make use of design jobs.

This would help the engineers to produce more things based on already available designs and option C is the correct answer.

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The complete question is:

as a hiring manager at GE, you are tasked with using the building blocks that managers can use in constructing an organization. which basic building block of structure would you use as you scale down on managerial positions and scale up on engineering positions

a. differentiating among positions

b. distributing authority among jobs

c. designing jobs

d. grouping jobs

The steps that should be taken to evaluate the team member's level of competence are:

The method that I will use to resolve this problem if you somehow didn't receive the desired expertise is to ask a person from my team to teach me how to do it as well as consult external people or the internet.

Long used as a framework, competencies help direct employees' behavior toward the issues that are most important to an organization and contribute to success.

Therefore, They can offer a standard method to coordinate, pick out, and nurture talent. For workers, as well as managers, and ultimately the organization, the advantages are obvious.

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The major advantage of using compound joint snips over a single joint tool is option A: flexibility.

Standard compound-action snips are known to be a form of a hand tool that is said to be made to cut steel or softer materials, yet it is not harmful to use them sometimes on stainless steel.

Note that the key or the  major merit or benefit of using compound joint snips than the use of a single joint tool is due to the fact that a person can be able use these pivot points to make their cut very easy through sheets of metal with the use of small effort.

Hence, option A is correct.

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