Answer:
Explanation:
PE = mgh
g = PE/mh
g = 15.0 / (0.200(0.500))
g = 150 m/s²
This is one strong astronaut if he can work in an environment where gravity is more than 15 times stronger than on earth.
Where is a divergent boundary most likely to be found?
Answer:
mid-ocean oceanic ridges
Explanation:
Answer:
mid-ocean oceanic ridges
Explanation:
Divergent boundaries are most likely to be found at mid-oceean oceanic ridges.
A 2.8 kg rectangular air mattress is 2.00 m long, 0.500 m wide, and
0.100 m thick. What mass can it support in water before sinking?
160 m long When a truck ulls
Mass the air mattress support before sinking will be M = 97.2 kg
What will be the mass mattress will support?Given that
mass of mattress m=2.8 kg
Length = 2.00 m
width =0.5 m
The mattress can support a total weight that is equal to the weight of water that the air mattress displaces.
The volume of the air mattress will be equal to
[tex]V= (2\times 0.5\times 0.1)[/tex]
[tex]V= 0.1 m^{3}[/tex]
This volume is equal to the maximum amount of water that the mattress can displace in the water before it begins sinking.
We know the density of water is 1000 kg / m²
We can calculate the weight of the maximum amount of water that mattress will displace
[tex]V\times density of water\times g=0.1\times 1000\times 9.81=981N[/tex]
Let M represent the mass that the mattress is supporting.
The total weight of the mattress and the supported mass is:
[tex](2.8+M)\times9.81[/tex]
Setting this weight equal to the weight of the water displaced gives:
[tex](2.8+M)\times9.81=981[/tex]
[tex]2.8+M=100[/tex]
m = 97.2 kg
Hence Mass the air mattress support before sinking will be M = 97.2 kg
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If you have a final velocity of 50 m/s and travelled for 120 seconds. What
is your acceleration?
Answer:
a=v-u/t
Explanation:
use this formula and initial velocity is 0
Answer:
Acceleration (a) is 0.416666667 m/ s^2
Explanation:
Acceleration (a) is the change in velocity (Δv) over the change in time (Δt), represented by the equation
a = Δv/Δt.
4. Trilobites are animals that lived during the Paleozoic era. They populated all parts of the
ocean showed consistent evolution over time and left behind fossils that are large
enough to be studied without a microscope. All of these characteristics make trilobites
the ideal
a. Trace fossil
b. Keystone species
c. Index fossil
d. Reference point
dnreserve the remains of dead
Answer:
c. index fossil
Explanation:
Trilobite fossils are found worldwide, with many thousands of known species. Because they evolved rapidly, and molted like other arthropods, trilobites serve as excellent index fossils. (Arthropods periodically shed their old exoskeletons, or molt.) An index fossil is one that is useful for dating and correlating the strata in which it is found.
What are the symmetry operations of molecule AB4, where the molecule b lies at the center of the square and A lies at the center of the square and is not coplaner with B atoms. How to find the multiplication table
The symmetry operations of molecule AB₄ is tetrahedral and they are :
E : Identity4C₃ : axis of rotation 3C₂ : axis of rotation3S₄ : Rotation-reflection axis 6бdTo find the multiplication table we have to apply the multiplication table for Td symmetry ( attached below )
Given that molecule B lies at the corners of the square and molecule A lie at the center and is not coplanar with molecule B the symmetry operations of the molecules AB₄ will belong to a tetrahedral symmetry group which contains :
E : Identity4C₃ : axis of rotation 3C₂ : axis of rotation3S₄ : Rotation-reflection axis 6бdLearn more about tetrahedral symmetry group : https://brainly.com/question/1968705
The magnetic field B at all points within the colored circle of the figure (Figure 1) has an initial magnitude of 0.780 T. (The circle could represent approximately the space inside a long, thin solenoid.) The magnetic field is directed into the plane of the diagram and is decreasing at the rate of 0.0300 T/s.
a) What is the magnitude of the induced electric field at any point on the circular conducting ring with radius r = 0.100 m ?
b) What is the direction of this field at any point on the circular conducting ring?
c) What is the current in the ring if its resistance is 4.00 Ω ?
d) What is the emf between points a and b on the ring?
e) If the ring is cut at some point and the ends are separated slightly, what will be the emf between the ends?
The magnitude of the induced electrical field is 0.0015V/m, the field is pointing towards the clockwise direction while the current in the ring will be 0.0002355A if the resistance is 4 ohms. The emf between point a and b is zero and the EMF across the point if they're slightly separated between the ends is 0.000942V
To solve this question, we would have to go about each one individually
Data:
[tex]r=10cm=0.1m\\[/tex]
a.
The magnitude of the induced electrical field at any point within the radius is
[tex]\int\limits^a_b {E} \, du=\frac{dU}{dt}=\pi \frac{dB}{dt}=\pi r^{2}\frac{dB}{dt}\\E*2\pi r=\pi r^{2}\frac{dB}{dt} \\E=\frac{r}{2}\frac{dB}{dt}=\frac{0.1}{2}*0.03=0.0015V/m[/tex]
b.
The field is pointing towards the clockwise direction.
c.
The current in the ring if we are given a resistance of 4ohms
[tex]I=\frac{emf}{R}=\frac{\pi r^{2}\frac{dB}{dt} }{R} =\frac{\pi (0.1)^2*0.03}{4} =0.0002355A[/tex]
d.
The emf between point a and b is zero
e.
The EMF across two points if they're separated by small distance across the ring is
we would use the formula to solve for the EMF
[tex]E=\pi r^{2}\frac{dB}{dt}=\pi (0.1)^2*0.03=0.000942V[/tex]
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Determine the rTo understand the concept of nodes of a standing wave.
The nodes of a standing wave are points where the displacement of the wave is zero at all times. Nodes are important for matching boundary conditions, for example that the point at which a string is tied to a support has zero displacement at all times (i.e., the point of attachment does not move).
Consider a standing wave, where y represents the transverse displacement of a string that extends along the x direction. Here is a common mathematical form for such a wave:
y(x,t)=Acos(kx)sin(ωt),
where A is the maximum transverse displacement of the string (the amplitude of the wave), which is assumed to be nonzero, k is the wavenumber, ω is the angular frequency of the wave, and t is time.
Part A
Which one of the following statements about wave y(x,t) is correct?
adius of the 236U nucleus.
Answer:
The nodes of a standing wave are points where the displacement of the wave is zero at all times nodes are important for matching boundary conditions for example that the point at which a string is tied to a support has zero displacement at all times ie the point of attachment does not move consider a standing
Which of the following is NOT a function of the lens in the eye?
W
It can perform minor adjustments for distance.
It flattens when light rays from distant objects are to be focused.
It is a light receptor that generates nerve signals that are sent to the brain
It maintains its spherical shape to view nearby objects.
Answer:
the last one
Explanation:
What is the significance of Isaac's name?
[tex] \large \bf{Answer:-}[/tex]
The name Isaac means “one who laughs” or “one who rejoices.” In the Old Testament of the Bible, Isaac is the firstborn son of Abraham. He is one of the three biblical patriarchs revered by Jews, Christians, and Muslims.
did the deadliest hurricanes happen recently or in the distant past
Answer:
Galveston hurricane of 1900
Explanation:
also called Great Galveston hurricane, hurricane (tropical cyclone) of September 1900, one of the deadliest natural disasters in U.S. history, claiming more than 8,000 lives.
Ginny is snowboarding down a ski slope. Her total mass (including the snowboard) is 68.5 kg. When she reaches the bottom of the slope, she is moving at 6.55 m/s. The coefficient of friction between the snowboard and the ground is 0.088 . How fast will Ginny be moving 2 seconds after reaching the bottom of the slope?
1) 5.71 m/s
2)5.91 m/s
3)4.82 m/s
4)4.08 m/s
Answer:
Explanation:
Assuming the run out at the bottom of the slope is horizontal
μ = Ff/N = Ff/mg
Ff = μmg
a = Ff/m = μmg/m = μg
v = u + at
v = u + μgt
v = 6.55 - 0.088(9.81)(2)
v = 4.82 m/s
After reaching the bottom of the slope, it will take a speed of 4.8m/s to reach. So, the correct option is (C).
What is Friction?Friction is the force which opposes the relative motion of solid surfaces, fluid layers, and material elements that are sliding against each other. There are many types of friction like
Dry frictionFluid frictionLubricated friction Skin friction Internal frictionFriction can be expressed as
Ff = μFN
where, Ff is the force of friction (N)
μ is the coefficient of friction.
FN is the normal force
As per the above equation, it is actually the normal force, not the weight, which is responsible for friction.
For given information,
Assuming the bottom of the slope is horizontal
So, μ = Ff/N = Ff/mg
Ff = μmg
a = Ff/m = μmg/m = μg
v = u + at (u- initial speed, v= final speed, a= acceleration and t= time)
v = u + μgt (g= acceleration due to gravity)
u = 6.55 - 0.088(9.81)(2)
u = 4.82 m/s
Thus, after reaching the bottom of the slope, it will take a speed of 4.8m/s to reach. So, the correct option is (C).
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i need some help getting started on an essay for physics. i decided on the topic of roller costers and dont know how to start it. see the image on my requirements.
Explanation:
force , motion , electric current
During a car accident on the NJ Turnpike, the airbags deploy. A 79 kg passenger traveling at 32 m/s makes impact with the airbag over a time of 0.25 seconds. What
was the impact force experienced by the passenger?
Hi there!
Recall that:
Impulse = Δ in momentum = mΔv
Impulse = Force · time
Begin by calculating the change in momentum, or impulse.
I = mΔv = m(vf - vi)
I = (79)(0 - 32) = -2528 Ns
Now, we can use the equation relating force and time to impulse.
I = Ft
Rearrange for time:
I/F = t
-2528/0.25 = -10112 N
**OR, if magnitude ⇒ |-10112| = 10112 N
Find the magnitude of the potential difference between two points located 1.2 m apart in a uniform 700 N/C electric field, if a line between the points is parallel to the field. Express your answer in volts.
The magnitude of the potential difference between the two points is 840 V
To solve the problem above, we need to use the formula of Potential difference as related to distance and electric field.
Potential difference: This can be defined as the work required to move a unit charge from a point to another in an electric field.
⇒ Formula:
V = E×d.................. Equation 1⇒ Where:
V = Potential differenceE = Electric Fieldd = DistanceFrom the question,
⇒ Given:
E = 700 N/Cd = 1.2 m⇒ Substitute these values into equation 1
V = 700(1.2)V = 840 VHence, The magnitude of the potential difference between the two points is 840 V
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Explain how the graphic organizer helped you formulate your decision and participate in the discussion.
Answer:
The graphic organizers help to keep track of the details. They are a visual representation of knowledge that rescue the important aspects of a concept using labels within a scheme. They also present information in a concise manner, highlighting the organization and the relationship of the concepts. Graphic organizers help students organize their thinking process and their writing.
Explanation:
Ram jumps onto a cement floor from a height of 1m and comes to rest in 0.1sec.
Then he jumps onto a sand floor from a height of 9m and comes to rest in 1sec.
Find the ratio of forces of cement floor and sand floor.
Answer:
3/10 F.
Explanation:
Height ( h ) = 1m
Time taken ( t ) = 0.1 second
Height² ( h² ) = 9m
Time taken² ( t² ) = 1 second
Solution,
F = ma
= m ( v - u ) / t
= m √2gh / t
now,
F/F² = √h/h² × t/t²
F¹ = 3/10 F.
answer !!
consider a throw ball to the air ,whre lagragian is given by ,L( m /2+Y^ '2 +Z^' 2 ]- msz, find the two concider momuntum when it is invariant under translation at x&x+E and y&yE(both x and y are cyclic cordinate)
Explanation:
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A block of mass m=10 kg at rest slides down a rough incline plane of θ=30° and length l=5 m. The coefficient of kinetic friction between the block and the incline is μ_k=0.1. At the bottom of the plane the block continues to slide on a frictionless surface and hits a spring with spring constant k=100 N/m.
The speed of the block at point B = 6.36 m/s
Given data :
Mass ( m ) = 10 kg
Angle of inclination ( θ ) = 30°
Length of incline = 5 m
Determine the speed of the block at a point B on the incline
First step : Calculate the work done by frictional force
given that there is no friction on the horizontal plane. Vinclined = Vhorizontal
∴ Work done by frictional force ( Wf ) = F * L cos 180
= - ( μ_k * N ) L
= - (0.1 * 84.86 ) * 5 = - 42.4 Joule
where N = mg cos 30°
= 10 * 9.8 * 0.866 = 84.86
Next step : Calculate the speed of the block at point B
applying work energy theorem
Wf = ΔK.E + ΔP.E
= ( 1/2 mv² - 0 ) + ( 0 - mgh )
∴ - 42.48 = 1/2 mv² - mgh
1/2 mv² = mgh - 42.48
= 10 * 9.8 * 5 sin 30° - 42.4
v² = 40.52
V ( speed of the block at point B ) = 6.36 m/s
Hence we can conclude that the speed of the block at point B = 6.36 m/s
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Attached below is the complete question related to your question
9. If the force acting on a mass of 4kg accelerates it at a rate of 2m/s2, what will be the acceleration of the body when the force is doubled?
Explanation:
Force= mass× acceleration
Force= 4×2
= 8N
Doubling the force, 8×2= 16N
16= 4 × a
a= 16/4
= 4m/s²
How do we become children of Abraham and sons of God?
Answer:
we already are.
Explanation:
God created us, and we are the descendants of Abraham. if you want to choose to live against it, you'll be doing something similar to fighting a current. gods love is unfathomable. he is the only true God, and is our father in heaven.
A thin stream of water flows smoothly from a faucet and falls straight down. At one point, the water is flowing at a speed of 1=1.31 m/s . At a lower point, the diameter of the stream has decreased by a factor of 0.805 . What is the vertical distance ℎ between these two points?
Answer:
Explanation:
as the mass cannot change, the volume per unit time is also constant so the area of the stream times the velocity is constant
If the diameter is 1 where velocity is 1.31 m/s
area is proportional to the square of the diameter A = (π/4)d²
1²(1.31) = 0.805²(v)
v = 1.31/0.805² = 2.02 m/s
v² = u² + 2as
2.02² = 1.31² + 2(9.81)h
h = 0.120819... m
h = 12.0 cm
Two forces act on a block as shown in the picture. What is the net force of the block?
30 N to the right
30 N to the left
10 N to the left 10
10 N to the right
Answer:
10 N to the left.
Explanation:
Since the forces are acting in opposite directions, you need to calculate the difference.
20 N - 10 N = 10 N
More force is being exerted to the left. Therefore, the net force is 10 N to the left.
How do you find the capacitance in this?
Answer:
Explanation:
parallel capacitances add directly
Series capacitances add by reciprocal of sum of reciprocals.
Ceq = [ C ] + [1 / (1/C + 1/C)] + [1 / (1/C + 1/C + 1/C)]
Ceq = [ C ] + [C / 2] + [C / 3]
Ceq = [ 6C/6 ] + [3C / 6] + [2C / 6]
Ceq = 11C/6
Which variable mentioned in Table 2-1 is kept constant? a. amount of time spent swimming b. type of swimming stroke c. number of calories used d. the person swimming
Answer:
a. amount of time spent swimming
You have a pendulum clock made from a uniform rod of mass M and length L pivoting around one end of the rod. Its frequency is 1 radian/sec. The pivot breaks. Though the mass change is negligible, you need to rehang the rod halfway between the old pivot point and the middle of the rod. The new oscillation frequency is:
A. 0.88 rad/sec
B. 1.13 rad/sec
C. 1.07 rad/sec
D. 0.92 rad/sec
The new oscillation frequency of the pendulum clock is 1.14 rad/s.
The given parameters;
Mass of the pendulum, = M Length of the pendulum, = LInitial angular speed, [tex]\omega _i[/tex] = 1 rad/sThe moment of inertia of the rod about the end is given as;
[tex]I_i = \frac{1}{3} ML^2[/tex]
The moment of inertia of the rod between the middle and the end is calculated as;
[tex]I_f = \int\limits^L_{L/2} {r^2\frac{M}{L} } \, dr = \frac{M}{3L} [r^3]^L_{L/2} = \frac{M}{3L} [L^3 - \frac{L^3}{8} ] = \frac{M}{3L} [\frac{7L^3}{8} ]= \frac{7ML^2}{24}[/tex]
Apply the principle of conservation of angular momentum as shown below;
[tex]I _i \omega _i = I _f \omega _f\\\\\frac{ML^2}{3} (1 \ rad/s)= \frac{7ML^2}{24} \times \omega _f\\\\\frac{24 \times ML^2}{3 \times 7 ML^2} (1 \ rad/s)= \omega _f\\\\1.14 \ rad/s = \omega _f[/tex]
Thus, the new oscillation frequency of the pendulum clock is 1.14 rad/s.
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Rust is a compound that occurs when the element iron and oxygen combine. Do they create a physical or a chemical change?
Answer:
I think it's a chemical change.
A converging-diverging nozzle has a throat area of 10 cm2 and an exit area of 28.96 cm2 . A normal shock stands in the exit when the back pressure is sea-level standard. If the upstream tank temperature is 400 K, estimate (a) the tank pressure and (b) the mass fl ow
The tank pressure is 5.08 kPa and the mass flow rate is 2.6 kg/s.
The given parameters:
Throat area of the nozzle, [tex]A^*[/tex] = 10 cm² = 0.001 m²The exit area of the nozzle, A = 28.96 cm² = 0.002896 m²Air pressure at sea level = 101.325 kPaThe ratio of the areas of the converging-diverging nozzle is calculated as follows;
[tex]= \frac{A}{A^*} \\\\= \frac{0.002896}{0.001} \\\\= 2.896[/tex]
From supersonic isentropic table, at [tex]\frac{A}{A^*} = 2.896[/tex], we can determine the following;
[tex]M_e = 2.6 \ kg/s\\\\\frac{P_o}{P_e} = 19.954[/tex]
The tank pressure is calculated as follows;
[tex]\frac{P_o}{P_e} = 19.954 \\\\P_e = \frac{P_o}{19.954} \\\\P_e = \frac{101.325 \ kPa}{19.954} \\\\P_e = 5.08 \ kPa[/tex]
Thus, the tank pressure is 5.08 kPa and the mass flow rate is 2.6 kg/s.
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how is the atomic mass determined?
Answer:
Atomic mass is defined as the number of protons and neutrons in an atom, where each proton and neutron has a mass of approximately 1 amu (1.0073 and 1.0087, respectively). The electrons within an atom are so miniscule compared to protons and neutrons that their mass is negligible.
Explanation:
An RLC circuit is used in a radio to tune into the radio lagos fm Station broadcasting at 93.5Hz. The resistance is 15ohms and the inductance is 1.6 H. Calculate the capacitance used
The characteristics of the RLC circuit allow to find the result for the capacitance at a resonance of 93.5 Hz is:
Capacitance is C = 1.8 10⁻⁶ F
A series RLC circuit reaches the maximum signal for a specific frequency, called the resonance frequency, this value depends on the impedance of the circuit.
[tex]Z^2 = R^2 + ( wL - \frac{1}{wC} )^2[/tex]
Where Z is the impedance of the circuit, R the resistance, L the inductance, C the capacitance and w the angular velocity. The negative sign is due to the fact that the current in the capacitor and the inductor are out of phase.
In the case of resonance, the impedance term completes the circuit as a resistive system.
[tex]wL - \frac{1}{wC} = 0 \\w^2 = \frac{1}{LC}[/tex]
Indicate that the inductance L = 1.6 H and the frequency f = 93.5 Hz.
Angular velocity and frequency are related.
w = 2π f
Let's substitute.
[tex]C = \frac{1}{L ( 2 \pi f)^2 }[/tex]
Let's calculate.
[tex]C = \frac{1}{1.6 \ ( 2\pi \ 93.5)^2}[/tex]
C = 1.8 10⁻⁶ F
In conclusion with the characteristics of the RLC circuits we can find the result for the capacitance at a 93.5 Hz resonance is:
Capacitance is C = 1.8 10⁻⁶ F
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You hang a light in front of your house using an
elaborate system to keep the 12-kg object in static
equilibrium (Figure 1). What are the magnitudes of the
forces that the ropes must exert on the knot connecting
the three ropes if 02 = 639 and 03 = 45° ?
The magnitudes of the forces that the ropes must exert on the knot connecting are :
F₁ = 118 N F₂ = 89.21 N F₃ = 57.28 NGiven data :
Mass ( M ) = 12 kg
∅₂ = 63°
∅₃ = 45°
Determine the magnitudes of the forces exerted by the ropes on the connecting knota) Force exerted by the first rope = weight of rope
∴ F₁ = mg
= 12 * 9.81 ≈ 118 kg
b) Force exerted by the second rope
applying equilibrium condition of force in the vertical direction
F₂ sin∅₂ + F₃ sin∅₃ - mg = 0 ---- ( 1 )
where: F₃ = ( F₂ cos∅₂ / cos∅₃ ) --- ( 2 ) applying equilibrium condition of force in the horizontal direction
Back to equation ( 1 )
F₂ = [ ( mg / cos∅₂ ) / tan∅₂ + tan∅₃ ]
= [ ( 118 / cos 63° ) / ( tan 63° + tan 45° ) ]
= 89.21 N
C ) Force exerted by the third rope
Applying equation ( 2 )
F₃ = ( F₂ cos∅₂ / cos∅₃ )
= ( 89.21 * cos 63 / cos 45 )
= 57.28 N
Hence we can conclude that The magnitudes of the forces that the ropes must exert on the knot connecting are :
F₁ = 118 N, F₂ = 89.21 N, F₃ = 57.28 N
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