Answer:
11.025m
Explanation:
Using kinematics,
u = Initial velocity = 0.
t = Time taken = 1.5sec.
a = Acceleration from gravity = 9.8m/s^2
Distance = s
= ut + 1/2 * a * t^2
= 0 + 1/2 * 9.8 * (1.5)^2
= 11.025m
The egg fall from the nest of a tree is 11.025 m.
To find height from where the egg fall, the given values are:
Time taken t = 1.5 seconds.
What is the distance of the egg fall? The egg was falling from the nest of a tree.By knowing the concept of Kinematics,
For a particle moving with a constant acceleration, its displacement after a time period is given by
s = ut +1/2 at²
where, u - initial velocity,
t - Time,
a - acceleration.
As u is the Initial velocity = 0.
t = 1.5s
Acceleration from gravity = 9.8m/s²
Here, Distance = s
Substituting all the values in the formula,
s = ut + 1/2 ( a × t²)
= 0 + 1/2 × 9.8 × (1.5)²
Distance s = 11.025m
So, the distance the egg fall from a nest of a tree is s = 11.025 m.
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A jet starts at rest at the end of a runway and reaches a speed of 80 m/s in 20 s. What is its acceleration?
Answer:
80/2= 40 m/s^2.
Explanation:
A jet starts at rest at the end of a runway and reaches a speed of 80 m/s in 20 s. Its acceleration is 4 m/sec².
What is acceleration?The rate at which an item changes its velocity is known as acceleration, a vector quantity. If an object's velocity is changing, it is acceleration.
The net acceleration that objects get as a result of the combined action of gravity and centrifugal force is known as the Earth's gravity, or g. It is a vector quantity whose strength or magnitude is determined by the norm and whose direction correlates with a plumb bob.
acceleration = change in velocity / time
acceleration = 80 / 20
acceleration = 4 m/sec²
A jet starts at rest at the end of a runway and reaches a speed of 80 m/s in 20 s. Its acceleration is 4 m/sec².
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w
Trial
х
1
75.0 72.2
2
75.1
72.3
3
75.1 72.1
4
74.9
72.2
Which set of data is most likely the result of a systematic error?
Y
75.0
80.1
69.5
72.7
Z
86.2
86.7
71.5
70.8
w
Х
Z
Answer:
75
Explanation:
w
X
y
z.86.2,86.7,70.8
(100 POINTS AND BRAINLEIST) could you please help me with this ASAP!
The above are questions related to the formula of force F = m * a i.e. mass * accleration. It is defined by the Newton's second law of motion.
In the attachment, I can see that Question 1) and Question 2) are already done, So lemme start from Question 3[tex])[/tex]
3) Provided:-
Force applied = 7000 NOn a ball of mass = 0.5 kgTo FinD:-
Acceleration of the ball...?By using formula,
⇛ F = ma
⇛ 7000 N = 0.5 kg × a
⇛ a = 7000 / 0.5 m/s²
⇛ a = 14000 m/s²
So, the ball acclerates at the rate of 14000 m/s².
4) Provided:-
Accleration of the truck = 10 m/s²On a truck of mass = 31200 kgTo FinD:-
Force applied on the truck..?By using formula,
⇛ F = ma
⇛ F = 31200 kg × 10 m/s²
⇛ F = 312000 kg/m/s²
⇛ F = 312000 N
So, force on the truck = 312000 N
5) a) Force applied = 100 N
Mass applied = 5 kg
Then, Acceleration = 100 ÷ 5 = 20 m/s²
b) Force applied = 100 N
Mass applied = 10 kg
Then, Acceleration = 100 ÷ 10 = 10 m/s²
c) Force applied = 100 N
Mass applied = 20 kg
Then, Acceleration = 100 ÷ 20 = 5 m/s²
d) Force applied = 100 N
Mass applied = 50 kg
Then, Acceleration = 100 ÷ 5 = 2 m/s²
And we are done !!
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Answer: The answer are above :(
. Air moves up and down by convection. Molecules of air are spaced farther apart in rising warm air. What must the volume of cold air have more of than the same volume of warm air?
Answer:d
Explanation:tsssss
What year was volleyball invented?
10 p
1889
1874
1895
1918
How many players are on each volleyball team?
Please help
Please help with these physics problems 1. A soccer ball is dropped from the top of a building. It takes 5.8 seconds to fall to the ground. The height of the building is...? 2. The Falcon 9 launches to a height of 123 meters. What is its vertical initial velocity? 3. An apple falls from rest off a 10.m m tree. How long will it take before it hits the ground?
Answer:
1.) h = 164.8 m
2.) U = 49.1 m/s
3.) t = 1.43 seconds
Explanation:
1.) A soccer ball is dropped from the top of a building. It takes 5.8 seconds to fall to the ground. The height of the building is...?
Since the soccer ball is dropped from the building, the initial velocity U will be equal to zero
Using second equation of motion
h = Ut + 1/2gt^2
Substitutes the time into the formula
h = 1/2 × 9.8 × 5.8^2
h = 164.8 m
2. The Falcon 9 launches to a height of 123 meters. What is its vertical initial velocity?
At maximum height final velocity = 0
Using the third law of motion
V^2 = U^2 - 2gH
0 = U^2 - 2 × 9.8 × 123
U^2 = 2410.8
U = 49.1 m/s
3. An apple falls from rest off a 10.m m tree. How long will it take before it hits the ground?
Since the apple fall from rest, the initial velocity U will be equal to zero
Using the second equation of motion,
h = Ut + 1/2gt^2
substitute all the parameters into the formula
10 = 1/2 × 9.8 × t^2
10 = 4.9t^2
t^2 = 10/4.9
t^2 = 2.04
t = 1.43 seconds
Conduction occurs when thermal energy is transferred by the movement of
a. Waves
b. molecules
c. liquids
d. fluids
Answer: Molecules
Explanation:
Answer:
B. molecules
Explanation:
got 100% on the edge quiz
A plant is moved from direct sunlight and placed into complete darkness.
Which structure in the plant's cells would be most affected by this change?
Choose 1 answer:
(Choice A)
A
Mitochondria
(Choice B)
B
Chloroplast
(Choice C)
C
Vacuole
(Choice D)
D
Golgi body
a,
Explanation:
because when its moved thats the sugar of it
Answer:
b. Chloroplast
Explanation:
A speed skater moving to the left across frictionless ice at 8.0 m/s hits a 5.0-m-wide patch of rough ice. She slows steadily, then continues on at 6.0 m/s. What is her acceleration on the rough ice?
Answer:
Acceleration, [tex]a=-2.8\ m/s^2[/tex]
Explanation:
It is given that,
The initial speed of a speed skater, u = 8 m/s
The final speed of a speed skater, v = 6 m/s
Width of patch of rough ice, s = 5 m
We need to find the acceleration on the rough ice. Acceleration can be calculated using third equation of motion as :
[tex]v^2-u^2=2as\\\\a=\dfrac{v^2-u^2}{2s}\\\\a=\dfrac{(6)^2-(8)^2}{2\times 5}\\\\a=-2.8\ m/s^2[/tex]
So, the acceleration on the rough ice is [tex]2.8\ m/s^2[/tex]. Negative sign shows that its speed is decreased.
The car was initally traveling at 25 m/s. The car slows with a negative acceleration as shown. How long does it take the car to slow to a final velocity of 2.0 m/s?
Answer:
t = 2.35sExplanation:
Using one of the equation of motion expressed as v = u+at where;
v is the final velocity = 2.0m/s
u is the initial velocity = 25m/s
a is the acceleration = -a (since the acceleration is negative)
t is the time taken
Substituting the given parameters into the formula above;
2.0 = 25-9.81t
subtract 25 from both sides
2.0 - 25 = 25-9.81t - 25
-23 = -9.81t
Divide both sides by -9.81
-23/-9.81 = -9.81t/-9.81
t = 23.0/9.81
t = 2.35s
Hence it took the car 2.35s to slow to a final velocity of 2.0 m/s
what is the momentum in Kg m/s of a 10 kg truck travelling at A) 5 m/s B) 20 cm/s C) 36 km/h?
Answer:
A) 50 kg m/s
B) 2 kg m/s
C) 100 kg m/s
Explanation:
Recall that momentum is a physical quantity defined by the product of the object's mass times its velocity. Therefore, in our case the truck's momentum (p) is:
A) p = m * v = 10 kg * 5 m/s = 50 kg m/s
B) p = m * v = 10 kg * 0.20 m/s = 2 kg m/s (notice that the velocity in cm/s was converted into m/s before multiplying)
C) the conversion from km/h to m/s is a little more involved, so we taclke it first:
since 1 km = 1000 m and 1 hour = 3600 seconds, we convert 36 km/h by replacing each unit by its m and s expression as shown below:
[tex]36 \frac{km}{h} =36\,\frac{1000\,m}{3600\,\,s}=10\,\frac{m}{s}[/tex]
Then, the momentum is: p = m * v = 10 kg * 10 m/s = 100 kg m/s
A typical galaxy contains about 100 billion stars, and there are approximately 100 billion galaxies in the observable universe. About how many stars are in the observable universe
Answer = (100 billion stars/galaxy) x (100 billion galaxies/universe)
Answer = (100 billion x 100 billion) stars
Answer = 10,000 billion billion stars
Answer = 10,000,000,000,000,000,000,000 stars
Answer = 10²² stars/observable universe
The number of stars in the observable universe is; 10²² stars/observable universe.
How many stars are in the observable universe?Since there are about 100 billion stars in our galaxy; we can rewrite that to be;
100 billion stars/galaxy
However, there are about 100 billion galaxies in the observable universe.
Since our galaxy is one of the 10¹¹ observable galaxies in the universe; the number of stars in the observable universe is;
(100 billion stars/galaxy) x (100 billion galaxies/universe)
= (100 billion x 100 billion) stars
= 10,000 billion billion stars
= 10,000,000,000,000,000,000,000 stars
= 10²² stars/observable universe
Therefore, the number of stars in the observable universe is; 10²² stars/observable universe.
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A boy wishes to make
a catapults out of
a rubber band of width 9mm and thickness 1.55mm. Determine the length of the band
he must use so that when the stretches it by 0.25
of its natural length and releases it, the velocity of the pebble of mass 0.0006kg is
30ms - Take the youngs modulus of the rubber
to be 4x10000000nm-2
3. Daniel stands on a bridge over a river. He drops a coin and notes that the coin takes 3 s to reach the river below.
He must be standing
above the river.
A 10 m
B. 15 m
C. 30 m
D. 45 m
Answer:
45 m
Explanation:
Initial velocity of the coin = 0 m/s (since he dropped it from his hands)
time spent in falling - 3 sec
distance s = ?
using
s = ut + [tex]\frac{1}{2}[/tex]g[tex]t^{2}[/tex]
where
s is the distance the stone fell
u is the initial velocity
t is the time spent falling
g is acceleration due to gravity = 10 m/s^2 (positive downwards)
substituting values, we have
s = (0 x 3) + [tex]\frac{1}{2}[/tex](10 x [tex]3^{2}[/tex])
s = 45 m
The displacement d (m) of a block sliding along a straight line is given by the equation d = -0.65 t + 0.21 t2, where t is the time in seconds. What is the instantaneous velocity of the block when t = 2.0 s?
Answer:
0.19m/sExplanation:
velocity is the change in displacement of a body with respect to time. Given the displacement d (m) of a block sliding along a straight line is given by the equation d = -0.65 t + 0.21 t², where t is the time in seconds, instantaneous velocity is expressed by differentiating the displacement with respect to time
Velocity = dd/dt
Velocity = -0.65 + 2(0.21)t²⁻¹
Velocity = -0.65 + 0.42t
The instantaneous velocity of the block when t = 2.0 s can be gotten by substituting t = 2.0s into the expression above:
Velocity = -0.65 + 0.42(2)
Velocity = -0.65 + 0.84
Velocity = 0.19
Hence the instantaneous velocity of the block when t = 2.0 s is 0.19m/s
What happens to scientific laws if new, unexpected data is discovered? a They become scientific theories. b They are revised. c Nothing, the new data is ignored.
Answer:
revised
Explanation:
The _____ optical illusion contains a horizontal line terminating in inward- or outward-pointing arrowheads.
Answer:
Muller-Lyer optical illusion
What type of microscope bends light and uses multiple lenses to magnify a cell?
Choose 1 answer:
(Choice A) A Transmission electron microscope
(Choice B) B Simple light microscope
(Choice C) C Compound light microscope
(Choice D) D Scanning electron microscope
A car starting from rest accelerates at a rate of 8 0 m/s/s. What is its final speed at the end of 40 seconda?
i have no idea what is if you know the answer, can you please answer it?
Answer:
you have to organize the data. a= acceleration vi=inicial velocity vf=final velocity t=time.
a=80m/s
vi=0
vf=?
t=40 s
the formula you have to use is:
vf=vi+a*t (final velocity= inicial velocity plus acceleration times time)
Explanation:
I was the best one at my class, hope it helped
Answer: 320 m/s
Explanation: V initial = 0, V final= ? Acceleration = 8m/s/s t=40s
So at the end of V 40 sec= v intial + acceleration x Δt = 0 +8m/s² x 40s = 320m/swhat is one common electrostatic phenomenon
Answer:
There are many examples of electrostatic phenomena, from those as simple as the attraction of the plastic wrap to one's hand after it is removed from a package to the apparently spontaneous explosion of grain silos, the damage of electronic components during manufacturing, and photocopier & laser printer operation
PLZ HELP TIMES TEST
When a person strikes and lights a match, potential energy in the match is transformed into which types of energy?
electrical and thermal
thermal and radiant
radiant and nuclear
nuclear and kinetic
Answer:
Thermal and Radiant
Explanation:
Thermal = Heat
Radiant = Light
Answer: B
Explanation:
6. Amy spits watermelon seeds at 1.8 m/s. How far will the seed travel in 1.2 s?
Answer:
2.16 meters
Explanation:
We can find distance using the following formula.
[tex]d=s*t[/tex]
where [tex]s[/tex] is the speed and [tex]t[/tex] is the time.
The speed of the watermelon seed is 1.8 meters per second. The time is 1.2 seconds.
[tex]s= 1.8 m/s\\t=1.2 s[/tex]
Substitute the values into the formula.
[tex]d= 1.8 m/s * 1.2 s[/tex]
Multiply. When you multiply the 2 "s" that represent seconds will cancel out.
[tex]d= 1.8 m * 1.2[/tex]
[tex]d=2.16 m[/tex]
The watermelon seed with travel 2.16 meters in 1.2 seconds.
I will give brainliest if right
Prokaryotes are structurally simple organisms that have existed for over two billion years.
Which of the following are prokaryotes?
Choose 1 answer:
(Choice A) A Animals
(Choice B) B Bacteria
(Choice C) C Plants
(Choice D) D Fungi
I will give brainliest if right
Answer:
Prokaryotic Cells are cells that lack Cell Nucleus so the answer is bacteria
Answer:
B Bacteria
Explanation:
Choice B because the prokaryotes are single-celled organism with no nucleus.
how water is constructed and how the matter is built-up?
Answer:
How is water constructed ?A molecule of pure water is made of two hydrogen atoms bonded to an oxygen atomHow is matter built-up?The basic building blocks that make up matter are called atoms. (hope i could help :)Explanation:
If a dog moves 3 meters due East and then 4 meters due North, what will be the dispalcement of the dog?
Answer:
5 mExplanation:
Displacement is the diatnce moves in a specified direction. It is the shortest distance covered by the dog. The displacement of the dog can be gotten by using the pythagoras theorem as shown;
According to the theorem, a²+b² = d² where d is the displacement
Substituting the given value into the fofrmula;
3²+4² = d²
9+16 = d²
d² = 25
square root both sides
√d² = √25
d = √25
d = 5 metres
Hence the displacement of the dog is 5metres
If 2 different processes driven by heat transfer start at state 1 and end at state 2 BUT follow different paths, is the amount of energy transferred by heat the same for each path? Yes or no?
Car A of mass 1500 kg travelling at 25 m/s collides with another car B of mass 1000 kg travelling at 15 m/s in the same direction. After collision, the velocity of car A becomes 20 m/s. Calculate the velocity of car B after collision.
Answer:
Apparently this has been asked a few years ago, so I copied this answer from deepikakvvk06 - - all credit goes to them!
velocity of car 'B' after collision is 22.5m/s. //it's a conservation of momentum question
Explanation:
Let ,
mass = m
initial velocity = u
final velocity = v
here ,
m₁= 1500 kg
m₂=1000 kg
u₁ = 25 m/s
u₂ = 15 m/s
v₁ = 20 m/s
we have to find v₂ !!
v₂ is the velocity after collision
Here is a formula relating the values given ,
m₁u₁+m₂u₂ = m₁v₁ + m₂+v₂
m₁u₁+m₂u₂ = 1500 × 25 + 1000 ×15
= 37500 + 15000
= 52500
m₁v₁ + m₂+v₂ = 1500 × 20 + 1000 × v₂
= 30000 + 1000v₂
m₁u₁+m₂u₂ = m₁v₁ + m₂+v₂
52500 = 3000 + 1000v₂
1000v₂ = 52500 - 30000
1000 v₂ = 22500
v₂ = 22500/1000
= 22.5 m/s
Thus, velocity of car 'B' after collision is 22.5m/s.
. Explain how surface waves can have characteristics of both longitudinal waves and transverse waves.
Please use 3 content related sentences. (ref: p.388-393)
Answer:
This whole concept depends on the depends on the direction of propagation of the surface wave or displacement of wave such that if its in direction of wave velocity its said to features of longitudinal wave and if its in direction at 90° to wave velocity its said to have transverse features
6)
Calculate the area of a body which experiences a pressure of 60000 Pa by a force of 120N
Answer:
area = force by pressure
or, a = 120N by 60000 Pa
or, a= 0.002 m²
science numerical problem .Hari drag a load a of 60 kg along a distance of 12 m . what amount of work does he do? as 0 mention the type of work
We don't know, and we don't have enough information to calculate it.
The weight of the 60kg load is (m g) = 588 Newtons.
IF Hari wanted to lift the load 12m straight up, he would have to do
(Force x distance) = (588 N) x (12 m) = 7,056 Joules of work.
But to drag it, he has to provide enough force to balance out the force of friction, and we don't know how much that is. It depends on the weight of the load, the shape of the load, the smoothness of the part of the load that sits on the ground, and the smoothness of the ground. But the only thing we know is the weight of the load.