The weight percent of each element in the compound. is given below.
The mass percent of C = 24%
The mass percent of H = 4%
The mass percent of Cl = 50%
The mass percent of N = 9.8%
The Mass percent of oxygen = 12.2%
The weight percent of the element in the compound?The following formula is used to calculate the mass of each component element in a sample of the compound:
The weight of C:
In 1 mole of CO2, there is 1 mole of carbon.
In 0.138 g of CO2, there will be:
0.138 g / 44 g * 12 g = 0.0368 g
H's mass:
1 mole of H2O contains 2 moles of hydrogen.
0.0566 g of H2O will contain the following quantity of H:
0.0566 g / 18 * 2 * 1 = 0.00628 g
volume of Cl;
In 1 mole of AgCl, there is 1 mole of Cl.
In 0.251 g of AgCl, the mass of Cl will be:
0.251 g / 143.5 g * 35.5 g = 0.0621 g
N's mass:
In 1 mole of NH3, there is 1 mole of N.
In 0.251 g of NH3, the mass of N will be:
0.0238g / 17.0 g * 14 g = 0.0196 g
Each element's mass percentage will be:
Mass proportion of C:
mass percent is equal to 0.0368/0.15 * 100.
24% mass percent
Mass proportion of H:
mass percent is equal to 0.00628/0.15 * 100%.
4% mass percent
Cl mass percentage;
Mass proportion of Cl:
mass percent is equal to 0.0621/0.125 * 100%.
50% mass percentage
N mass percentage:
Mass percent is equal to 0.0196/0.2*100%.
9.8% mass percent
Oxygen mass percentage equals 100 minus (24 + 4 + 50 + 9.8)
oxygen mass percentage: 12.2%
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Consider the aldol condensation between dibenzyl ketone and benzil in strong base. Calculate the molar masses of the reactants and product. (Hydrogens in the structures have been omitted for clarity) Report molar masses to 1 decimal place. g/mol g/mol Molar mass of dibenzyl ketone Molar mass of benzil Molar mass of 2,3,4,5-tetraphenylcyclopentadienone g/mol
Answer:
a) 210.3 g/mol
b) 210.2 g/mol
c) 384.5 g/mol
Explanation:
First step we will calculate the molar masses of ; carbon atom, hydrogen atom and oxygen atom in each .
Molar mass of dibenzyl ketone
Molar mass of dibenzyl ketone = ∑ molar masses of atoms in dibenzyl ketone
= carbon( 15 ) = 15 ( 12.0107 ) + oxygen ( 14 ) = 1 ( 15.999 ) + hydrogen(14) =14(1.00784)
= 210.26926 ≈ 210.3 g/mol
Molar mass of benzil
Molar mass of Benzil = ∑ molar masses of atoms in Benzil
= carbon( 14) = 14(12.0107) + oxygen(2) = 2 ( 15.999) + hydrogen(10) =10(1.00784)
= 210.2262 ≈ 210.2 g/mol
Molar mass of 2,3,4,5-tetraphenylcyclopentadienone
Molar mass = ∑ molar masses of atoms
= carbon ( 29) = 29(12.0107) + oxygen (1) = 1( 15.999 ) + hydrogen(20) = 20(1.00784 )
≈ 384.5 g/mol
If the colour of a solution turns pink on adding few drops of phenolphthalein indicator, it means solution is acidic. Select one :
True
False
Answer:
False, it becomes colourless in acidic solutions and turns pink in basic solutions
There are approximately 4,600 species of cockroaches that have been discovered and named on the planet. Cockroaches first landed in the Americas in 1625, and about 65 species are currently found in the United States. Below is a table that compares egg production of three different cockroach species that are common pests in Texas.
Answer:
may you include the table and actual question? would love to help but I need clarity on what is being asked.
Explanation:
Please help me l don’t understand please !!!!!!
Answer: C
Explanation:
he never had evidence in the first place that was nearly enough.
At the same temperature and pressure, balloons of equal volume always contain
a.equal masses of gas.
b.equal numbers of molecules.
c.equal densities of gas.
d.equal numbers of atoms.
Answer:
B. equal numbers of molecules
Explanation:
how to make your Go ogle forms look impressive
Lots of fonts, you can also insert those images with the checkered background (they show up clear) and decorate it, also make sure that you have proper spacing a paragraph structure
What is another name for heat?
A
light energy
B.
infrared energy
C
Thermal energy
D
electromagnetic energy
Answer:
C
Explanation:
thermal energy is the another name for heat
Of the following waves, which kind of wave does NOT require a medium?
a. light
b. water
с. ultrasound
d. sound
Scientists classify organisms into three domains and six kingdoms. In which
kingdom are yeasts classified and why?
A Plantae, because they are eukaryotic.
B Protista, because they are prokaryotic.
Fungi, because they are heterotrophic.
Animalia, because they are autotrophic.
Answer:
c is correct option
according to the question.
Scientists classify organisms into three domains and six kingdoms. In Fungi kingdom are yeasts classified because they are heterotrophic. Therefore, option C is correct.
What do you mean by the term heterotrophic ?An organism is referred to be a heterotroph if it is unable to manufacture food on its own and must obtain it from other sources of organic carbon, primarily plant or animal materials.
All fungi are heterotrophic, which means they draw their energy from other living things.
Since they share some traits with fungi, such as the presence of chitin in their cell walls, extracellular digestion, saprophytic feeding, asexual reproduction by budding, and the ability to store food as glycogen, yeast cells are categorised as fungi.
Thus, option C is correct.
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What type of energy is being represented in the image
Answer:
Its Kinetic energy
Explanation:
You are giving the bow potential energy. "When you let the bow go, it returns to its original shape. The energy is transformed to kinetic energy and transferred to the arrow"
Answer:
potential
Explanation:
the energy is potential lol
how the proton H gradient is used to make ATP
Answer:
The proton gradient produced by proton pumping during the electron transport chain is used to synthesize ATP. Protons flow down their concentration gradient into the matrix through the membrane protein ATP synthase, causing it to spin (like a water wheel) and catalyze conversion of ADP to ATP.
A solution of nitric acid has a [H3O+] = 2.8 x 10-6 M. What is the pH?
Answer:
5.55
Explanation:
see explanation attached
hope it helps
How many moles are in 15.2 grams of Calcium (Ca)?
Answer:
There are 0.379 moles of Ca in the given sample.
Explanation:
Hey there!
We're given that we have 15.2 grams of Ca (Calcium). We need to convert grams to moles.
There are many different conversion types for moles. A few examples are:
grams to molesmoles to gramsgrams to particlesmoles to litersThere are really endless possibilities for conversion factors. Since we want to find the number of moles in a certain sample, we first need to define what a mole is.
Mole - a unit of measurement in chemistryA mole is one unit of a certain item. For instance, one cup would be equivalent to one mole. Moles are simply a hypothetical unit in chemistry that act as a placeholder.
Now, how do we find the number of moles?
We know that a mole of something is one of that substance. In this case, we're referring to one atom of Calcium.
Therefore, we need to reference a periodic table to understand what the mass of one atom of calcium is equivalent to. I'll be using the official AP Chemistry periodic table as issued by the College Board.
When we reference the periodic table, we see the mass of one atom of calcium is equivalent to 40.08 amu (atomic mass units).
We learn in chemistry that we can use the terms amu and grams interchangeably, so we have learned that one mole of calcium is equivalent to 40.08 grams.
How do we work this out?
Now, we need to find out how many moles are in 15.2 grams of calcium. We can use dimensional analysis to work this out.
Our starting unit will be 15.2 grams of Ca.
[tex]\text{15.2 grams Ca}[/tex]We want to convert this into moles, so we need to cancel out our grams value. Additionally, since we know that we have 40.08 grams of Ca in one mole, we can set these up as two ratios:
[tex]\displaystyle \frac{\text{40.08 grams Ca}}{\text{1 mole Ca}}[/tex][tex]\displaystyle \frac{\text{1 mole Ca}}{\text{40.08 grams Ca}}[/tex]These ratios can be used to express the relationship between the moles of calcium and the mass of one calcium atom. However, we need our value of grams to cancel out, so since we will be using cross multiplication in our dimensional analysis, we need to use the ratio with grams on the bottom.
Now that we have selected our ratio, we can set up a multiplication problem of our two ratios:
[tex]\displaystyle \text{15.2 grams Ca} \times \frac{\text{1 mole Ca}}{\text{40.08 grams Ca}}[/tex]
We assume that we have a denominator of 1 below 15.2 grams Ca.
Now, we perform our multiplication.
[tex]\displaystyle \frac{\text{15.2 grams Ca} \ \times \ \text{1 mole Ca}}{\text{40.08 grams Ca}}[/tex]
We see that our remaining unit is going to be mole(s) Ca, so we can go ahead and drop our grams Ca unit.
[tex]\displaystyle \frac{\text{15.2} \ \times \ \text{1 mole Ca}}{\text{40.08}}[/tex]
Now, we need to simplify a little bit.
[tex]\displaystyle \frac{\text{15.2}}{\text{40.08}} = \text{? moles Ca}[/tex]
Finally, let's divide our fraction and evaluate our equation to find the value of moles Ca.
[tex]\displaystyle \frac{15.2}{40.08} = \text{0.379241517 moles Ca}[/tex]
Are we done yet?
Not just yet! To complete our work, we need to find the number of significant figures we can use. We are given two values in which we can use to judge how many significant figures we are limited to.
15.2 -- Three significant figures40.08 -- Four significant figuresIn chemistry, we always use the least number of significant figures for precision calculations, so we need to round our answer to three significant figures.
[tex]0.379241517 \approx 0.379[/tex]
Therefore, there are approximately 0.379 moles of Ca in the given sample.
What is the coefficient for hydrogen in the balanced equation for the reaction of solid tungsten(VI) oxide with gaseous hydrogen to form solid tungsten and liquid water?
Answer:
2
Explanation:
WO2(s) + 2H2(g) -> W(s) + 2H2O(l)
Determine the mass of hydrogen contained in 9.06 x 1024 H2O molecules.
Answer:
15.2 g H2
Explanation:
2H2O -> 2H2 + O2
9.06 x 10^24 molecules x (1 mol/6.022 x 10^23 molecules) x (2 mol H2/2 mol H2O) x (1.008 g/1 mol) = 15.2 g H2
Scientists have developed a new way to extract natural gas, called hydraulic fracturing, or fracking. Which of these is a positive impact of this method?
A. Decreased habitat
B. Decreased earthquakes
C. Increased supply
D. Increased demand
Answer:
The answer is C if its wrong you can report my answer I'm 100% sure its C
One of the reactions used to inflate automobile air bags involves sodium azide (NaN₃).
2NaN₃ --> 2Na + 3N₂
Determine the mass of N₂ produced from 250.0 g NaN₃
Answer:
161.54 g of N₂
Explanation:
The balanced equation for the reaction is given below:
2NaN₃ —> 2Na + 3N₂
Next, we shall determine the mass of NaN₃ that decomposed and the mass of N₂ produced from the balanced equation. This is illustrated below:
Molar mass of NaN₃ = 23 + (3×14)
= 23 + 42 = 65 g/mol
Mass of NaN₃ from the balanced equation = 2 × 65 = 130 g
Molar mass of N₂ = 2 × 14 = 28 g/mol
Mass of N₂ from the balanced equation = 3 × 28 = 84 g
SUMMARY:
From the balanced equation above,
130 g of NaN₃ decomposed to produce 84 g of N₂.
Finally, we shall determine the mass of N₂ produced by the decomposition of 250 g of NaN₃. This can be obtained as follow:
From the balanced equation above,
130 g of NaN₃ decomposed to produce 84 g of N₂.
Therefore, 250 g of NaN₃ will decompose to produce
= (250 × 84)/130 = 161.54 g of N₂
Thus, 161.54 g of N₂ were obtained from the reaction.
Which statement describes a homogeneous catalyst?
do
It is in a gaseous phase only. It is in the same phase as the reactants.
It is completely consumed by reactants.
It forms different products than the uncatalyzed reaction forms.
The statement which is given below describe a homogeneous catalyst.
"It is in the same phase as the reactants"
What is homogeneous catalyst?The catalyst which have similar phase to the reactant of the reaction is called homogeneous catalyst.
Mostly in homogeneous catalyst, catalyst present in liquid form.
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48 g of magnesium sulfate are left after dehydration of magnesium sulfate heptahydrate . What was the original weight of the sample before dehydration?
Answer:
98.6g is the mass of the heptahydrate
Explanation:
The hydrated magnesium sulfate contains 7 moles of water per mole of magnesium sulfate. 1 mole of MgSO₄ dehydrated is 1 mole of MgSO₄.7H₂O
To solve this question we must find the moles of MgSO₄. These moles = Moles of MgSO₄.7H₂O. Then, we must convert the moles to mass:
Moles MgSO₄ -Molar mass: 120.366g/mol-:
48g * (1mol / 120.366g) = 0.40 moles MgSO₄ = moles MgSO₄.7H₂O
Mass MgSO₄.7H₂O -Molar mass: 246.47456 g/mol-:
0.40 moles MgSO₄.7H₂O * (246.47456 g / 1mol) =
98.6g is the mass of the heptahydrate
7th grade science lol help
Answer:
C) Organic Weathering
Explanation:
Heat and Cold
And if some people start reporting and making fun of me in this answer don't listen to them.
They are hunting me down.
Sulfur and fluorine react to form sulfur hexafluoride according to the reaction shown here. How many mol of F2 are required to react completely with 2.15 mol of S?
S(s)+3F2(g)→SF6(g)
A. 12.9 molF2
B. 6.45 molF2
C. 0.72 molF2
D. 2.15 molF2
6.45 mole of fluorine are required to completely react with 2.15 mole of sulfur according to the stoichiometry of the reaction .
What is stoichiometry?It is the determination of proportions of elements or compounds in a chemical reaction. The related relations are based on law of conservation of mass and law of combining weights and volumes.
Stoichiometry is used in quantitative analysis for measuring concentrations of substances present in the sample.
In the given example the balanced chemical reaction is as follows:
S +3 F₂ [tex]\rightarrow[/tex] SF₆
According to the reaction, 1 mole of sulfur reacts with 3 moles of fluorine to yield 1 mole of sulfur hexafluoride.
∴2.15 mole of sulfur requires 2.15×3=6.45 mole of fluorine.
Hence, 6.45 mole of fluorine are required to completely react with 2.15 mole of sulfur.
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The following information is to be used for the next 2 questions. In order to analyze for Mg and Ca, a 24-hour urine sample was diluted to 2.000 L. After the solution was buffered to pH 10, a 10.00 mL aliquot was titrated with 26.23 mL of 0.003474 M EDTA. The calcium in a second 10.00 mL aliquot was isolated as CaC2O4, redissolved in acid, and titrated with 20.49 mL of the EDTA solution. (Note: Normal levels for magnesium are 15 to 300 mg per day and for calcium are 50 to 400 mg per day.)
a. How many mg of Ca were in the original sample?
b. How many mg of Mg were in the original sample?
Answer:
Explanation:
From the given information:
The concentration of metal ions are:
[tex][Ca^{2+}]= \dfrac{0.003474 \ M \times 20.49 \ mL}{10.0 \ mL}[/tex]
[tex][Ca^{2+}]=0.007118 \ M[/tex]
[tex][Mg^2+] = \dfrac{0.003474 \ M\times (26.23 - 20.49 )mL}{10.0 \ mL}[/tex]
[tex]=0.001994 \ M[/tex]
Mass of Ca²⁺ in 2.00 L urine sample is:
[tex]= 2.00 L \times 0.001994 \dfrac{mol}{L} \times \dfrac{40.08 \ g}{1 \ mol}[/tex]
= 0.1598 g
Mass of Ca²⁺ = 159.0 mg
Mass of Mg²⁺ in 2.00 L urine sample is:
[tex]= 2.00 L \times 0.007118 \dfrac{mol}{L} \times \dfrac{24.31 \ g}{1 \ mol}[/tex]
= 0.3461 g
Mass of Mg²⁺ = 346.1 mg
A flask contains 1.45 moles of N2, 0.659 moles of He. If the total pressure is 775 torr, what is the partial pressure of O2 ?
Answer:
533.2 torr.
Explanation:
The following data were obtained from the question:
Mole of N₂ = 1.45 moles
Moles the He = 0.659 mole
Total pressure = 775 torr
Partial pressure of N₂ =?
Next, we shall determine the mole fraction of N₂. This can be obtained as follow:
Mole of N₂ = 1.45 moles
Moles the He = 0.659 mole
Total mole = 1.45 + 0.659 = 2.109 moles
Mole fraction of N₂ = Mole of N₂ / total mole
Mole fraction of N₂ = 1.45 / 2.109
Mole fraction of N₂ = 0.688
Gina, we shall determine the partial pressure of N₂. This can be obtained as follow:
Total pressure = 775 torr
Mole fraction of N₂ = 0.688
Partial pressure of N₂ =?
Partial pressure of N₂ = total pressure × mole fraction of N₂
Partial pressure of N₂ = 775 × 0.688
Partial pressure of N₂ = 533.2 torr.
Therefore, the partial pressure of N₂ is 533.2 torr.
Approximately 1 mL of two clear, colorless solutions, 0.1 M Ba(NO3)2 and 0.1 M Na2SO4, were combined. Upon mixing, a thick milky white precipitate formed. After centrifugation, the solution above the precipitate was found to be clear and colorless. Based on the these observations, determine if a reaction occurred. If so, what is the net ionic equation for the reaction.
Answer:
Ba²⁺(aq) + SO₄²⁻(aq) ⇒ BaSO₄(s)
Explanation:
Let's consider the molecular equation for the reaction between Ba(NO₃)₂ and Na₂SO₄. This is a double displacement reaction in which BaSO₄ forms a white precipitate.
Ba(NO₃)₂(aq) + Na₂SO₄(aq) ⇒ BaSO₄(s) + 2 NaNO₃(aq)
The complete ionic equation includes all the ions and insoluble species.
Ba²⁺(aq) + 2 NO₃⁻(aq) + 2 Na⁺(aq) + SO₄²⁻(aq) ⇒ BaSO₄(s) + 2 Na⁺(aq) + 2 NO₃⁻(aq)
The net ionic equation includes only the ions that participate in the reaction and insoluble species.
Ba²⁺(aq) + SO₄²⁻(aq) ⇒ BaSO₄(s)
How much energy is required to vaporize 1.5 kg of aluminum? (Refer to table
of latent heat values.)
A. 733 kJ
B. 1650 kJ
C. 7095 kJ
D. 600 kJ
Answer:
B 1650
Explanation:
What is chemical equilibrium?
Question 1 options:
The rearrangement of the constituent atoms to create different substances as products.
A reversible reaction.
The process by which the reactants form products and products form reactants at equal rates.
A process that involves rearrangement of the molecular or ionic structure of a substance, as opposed to a change in physical form or a nuclear reaction.
The solubility of magnesium phosphate at a given temperature is 0.173 g/L. Calculate the Ksp at this temperature. After you calculate the Kspvalue, take the negative log and enter the (pKsp) value with 2 decimal places.
Answer: [tex]K_{sp}=1.25\times 10^{-14}[/tex]
[tex]pK_{sp}=13.90[/tex]
Explanation:
Solubility product is defined as the equilibrium constant in which a solid ionic compound is dissolved to produce its ions in solution. It is represented as [tex]K_{sp}[/tex]
The equation for the ionization of magnesium phosphate is given as:
[tex]Mg_3(PO_4)_2\rightarrow 3Mg^{2+}+2PO_4^{3-}[/tex]
When the solubility of [tex]Mg_3(PO_4)_2[/tex] is S moles/liter, then the solubility of [tex]Mg^{2+}[/tex] will be 3S moles\liter and solubility of [tex]PO_4^{3-}[/tex] will be 2S moles/liter.
Thus S = 0.173 g/L or [tex]\frac{0.173g/L}{262.8g/mol}=0.00065mol/L[/tex]
[tex]K_{sp}=(3S)^3\times (2S)^2[/tex]
[tex]K_{sp}=108S^5[/tex]
[tex]K_{sp}=108\times (0.00065)^5=1.25\times 10^{-14}[/tex]
[tex]pK_{sp}=-log(K_{sp})=\log (1.25\times 10^{-14})=13.90[/tex]
The value of Ksp and pKsp for the given reaction is 1.25 × 10⁻¹⁴ and 13.90 respectively.
How we calculate the Ksp?Solubility product constant (Ksp) is define as the product of the solubilities of the products, present in any chemical reaction.
Given chemical reaction will be represented as:
Mg₃(PO₄)₂ → 3Mg²⁺ + 2PO₄³⁻
Solubility of Mg₃(PO₄)₂ = 0.173 g/L or 0.173g/L / 262.8g/mole = 0.00065mol/L
Now for the given reaction let we consider that solubility of Mg₃(PO₄)₂ be x, solubility of Mg²⁺ be 3x and solubility of PO₄³⁻ will be 2x and equation for Ksp will be written as:
Ksp = [Mg²⁺]³[PO₄³⁻]²
Ksp = [3x]³[2x]²
Ksp = 108[x]⁵
Now we pot the solubility value of x as the solubility of Mg₃(PO₄)₂ & we get,
Ksp = 108(0.00065)⁵
Ksp = 1.25 × 10⁻¹⁴
Now we calculate the value of pKsp as:
pKsp = -log(Ksp)
pKsp = -log(1.25 × 10⁻¹⁴)
pKsp = -(-13.90) = 13.90
Hence value of pKsp is 13.90.
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In the balanced equation-aPb(NO3)2(s)heatb PbO(s)+ c NO2(g)+ dO2(g); the values of a,b,c, d are respectively
Answer:
The balance reaction is
2Pb(NO3)2 ----》4NO2+2PbO+O2
hence the value of a,b,c,d are 2,4,2,1 respectively!
6. The random motion of the particle in a substance is greatest when the
substance is
Answer:
when the substance is decrease
Explanation:
Tam a highly reactive alkali metal in period 3 with only one valence electron
O Sodium (Na)
Beryllium (Be)
Magnesium (Mg)
Answer:
Sodium (Na)
Helium
Magnesium (Mg).
Explanation:
From the periodic table, we will understand that the group 1 metals are the alkali metal. However, the period runs from left to right on the periodic table while the group runs from up to down in the periodic table. In period 3, the alkali metal present there with one valence electron in its outermost shell is sodium (Na).
The only noble gas exists in the last group, group zero of the periodic table. However, the only noble gas with two electrons in its outermost shell is called Helium
The ALkaline earth metals are group 2 metals. They are usually shiny metals and the ability to lose 2 electrons in their outermost electron shell. The alkaline earth metal located in period 3 is Magnesium (Mg).