Answer correctly please?

Subtraction is a mathematical operation that reflects the removal of things from a collection. The least possible height of the mont blanc is 4800 meters.

Subtraction is a mathematical operation that reflects the removal of things from a collection. The negative symbol represents subtraction.

Given the height of mont blanc is 4810 m correct to the nearest 10 meters. Therefore, the least possible height of the mont blanc can be written as,

Least height = 4810m - 10m = 4,800 meters

Hence, the least possible height of the mont blanc is 4800 meters.

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Answer:

a = 25°

Step-by-step explanation:

60° and 3a - 15° are congruent because they are corresponding.

60 = 3a - 15

75 = 3a

a = 25°

-Chetan K

9 × 0 + (-80) + 8 = ?

= 0 - 80 + 8

= -80 + 8 <==> 8 - 80

= -72

~bilbul

9 × 0 + (-80) + 8

= 0 + (-80) + 8

= (-80) + 8

= -72 ✔️

:)

Answer:

$2.34

Step-by-step explanation:

30x0.078=2.34

Answer:

95%

Step-by-step explanation:

19/20=0.95

0.95x100=95%

Answer:

The Answer is 5,000,000

Hope this helps!!

Answer:

slop = 2/3

Step-by-step explanation:

slope = rise/run

Start at the lower left point (-2, -1).

We need to go to the upper right point (4, 3) by going only vertically (rise) and horizontally (run).

First we go up 4. The rise is 4.

Then we go right 6. The run is 6.

slope = m = rise/run = 4/6 = 2/3

slope = 2/3

Answer:

The answer is 60%

Step-by-step explanation:

To solve that, just divide 24 by 40

24 ÷ 40 = 0.6

Now turn 0.6 to fraction.

0.6 = 60%

To find the greatest common factor, line both numbers up and continue adding that specific number until you find two factors that correlate with both numbers.

With that being said, let's begin.

8: 8, 16, 24, 32, 40, 48, 56, 64, 72, 80, 88

Simply add 8.

11: 11, 22, 33, 44, 55, 66, 77, 88

Simply add 11.

The greatest common factor of 8 and 11 is 88.

It will take 2 seconds a jet to accelerate from 200 m/s to 300 m/s with a constant acceleration of 50 m/s.

One type of operation in mathematics is division. We divide the phrases or numbers into the same number of components during this operation.

Given:

A constant acceleration is of 50 meter per second.

A jet to accelerate from 200 m/s to 300 m/s.

Acceleration is 100 meters per 2 seconds.

That means,

it will take = (300 - 200)/ 50 m/s

                = 2 seconds.

Therefore, it will take 2 seconds.

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Answer:

it's 3 cause if u do 1 2 3 there are 3 hearts and they are broke up in half so 6

Answer:

y = −4x^2 + 4x − 3

Step-by-step explanation:

Answer:

$2.36

Step-by-step explanation:

0.44 x 8 = 3.52

5.88 - 3.52 = 2.36

$2.36

-Chetan K

Answer:

3a+ 16

Hope this helps!

[tex] \sf \: y = - \frac{1}{3} x + \frac{7}{3} [/tex]

hope it helps

Answer:

y = x + 8

Step-by-step explanation:

Let's build the equation:

There are 8 entries to start

y = 8

Adding 1 entry every day

y = x + 8

Answer:

A

Step-by-step explanation:

when dilating by a scale factor of 6, you are starting at the origin and just making it larger by a factor of 6, so you multiply the coordinates by 6 and get A

Answer:

Should be -69 1/3

Step-by-step explanation:

Let X equal the decimal number

Equation 1:

X=69.3333333333¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

With 10 digits in the repeating decimal group,

create a second equation by multiplying

both sides by 1010 = 10000000000

Equation 2:

10000000000X=693333333333.3333333333¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

Subtract equation (1) from equation (2)

10000000000XX9999999999X===693333333333.3333333333...69.3333333333...693333333264

We get

9999999999X=693333333264

Solve for X

X=6933333332649999999999

Find the Greatest Common Factor (GCF) of 693333333264 and 9999999999, if it exists, and reduce the fraction by dividing both numerator and denominator by GCF = 3333333333,

693333333264÷33333333339999999999÷3333333333=2083

Simplify the improper fraction,

=6913

In conclusion,

−69.3333333333¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯=−6913

Answer:

1. C,  2. A,  3. C,  4. B

Step-by-step explanation:

Parallel:  slopes are equal.  In problem 2, the slopes appear to be 2 ("rise over run") One line passes through points (2, 1) and (3, 3) -- y increases by 2 if x increases by 1.  The other line passes through points (0, 3) and (1, 5)  -- y increases by 2 if x increases by 1.  The lines have the same slope.

Perpendicular:  slopes are opposite reciprocals (they have opposite signs).  In problem 4, that happens:  2/3  and  -3/2.  That is not the relationship between slopes in problem 3.  1/3 and 3 are not opposite reciprocals.

Corrected!  #4 is B (perpendicular)

Answer:

It should be 38.1

Answer:

the answer is D pls brainliesttt

hope you like my answer its 17

If I built a toy model of my car for the given condition the scale distance between the toy model and the actual car will be 225 inches.

It is defined as the operation in which we do the addition of numbers, subtraction, multiplication, and division. It has basic four operators that are +, -, ×, and ÷.

The term PEMDAS describes the sequence in which arithmetic operations must be carried out in an equation.

It is given that the length of the toy model car is 15 inches and the actual car is 20 feet

As we know 1 foot consists of 12 inches as a result  20 feet has 240 inches.

The scale distance between the toy model and the actual car is the difference between the actual length and the model length.

Scale distance = 240 inches - 15 inches

Scale distance =225 inches

Thus, if I built a toy model of my car for the given condition the scale distance between the toy model and the actual car will be 225 inches.

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Answer:

Step-by-step explanation:

Answer:

2n-1

Step-by-step explanation:

-5 ---> -3 = 2

-3 -2= -1

Answer:

1.99c + 59 ≥ 75, where c ≥ 8.04

Step-by-step explanation:

Answer: $31.55

Step-by-step explanation:

$25.75 + 37.80 - 32.00 = $31.55

Answer:

0

Step-by-step explanation:

-6(2(1/3)+3(2/3(3))=

Starting with pedmas (parenthesis, exponents, division, mulitplication, addition, subtraction).

We look at 2*1/3 and 2/3*3

[tex]2*\frac{1}{3}=\frac{2}{3}[/tex] and [tex]\frac{2}{3}*3=2[/tex]

[tex]-6(\frac{2}{3})+3(2)[/tex]=-6+6=0

[tex]v = \dfrac 13 ,~ a = \dfrac 23\\\\-6(2v) +3a(3)\\\\=-12v + 9a\\\\=-12\left(\dfrac 13 \right) + 9 \left( \dfrac 23 \right)\\\\=-4+ 3 \cdot 2 = -4 +6 = 2[/tex]