answer me fast. Find velocity in Acceleration Time Graph.​

Answer:

How are physical and chemical changes similar and different? (compare and contrast) (Physical and chemical changes are similar because matter experiences a change in state, Physical changes are different because matter remains the same substance, just in a different state, whereas chemical changes change the matter

Answer:

B

Explanation:

The plasma membrane is a selectively premeable membrane that chooses what goes in and out of the cell. The cell wall is for support and the nuclear membrane decides what goes in and out of the nucleus

Answer:

Plasma membrane

Explanation:

The plasma membrane consists of a lipid bilayer that is semipermeable.The plasma membrane regulates the transport of materials entering and exiting the cell.So, it is selectively permeable membrane.

Answer:

no it is not safe to smoke

Answer:

well its not affecting you lungs or anything. the only way it will affect you is if you eat to much smarties or you choke on it. so yeah it is safe to smoke smarties

Explanation:

To solve this, we must be knowing each and everything related to atmosphere. Therefore, thermosphere is the layer of the atmosphere has no definite outer limit.

The atmosphere is more than simply the beautiful sky above. The atmosphere is made up of numerous levels of gases that surround the planet.

The word "atmo," which meaning vapor, smoke, or fog in Greek, is the source of the atmosphere's name. "Sphere" comes from the Greek word sphaira, which meaning ball. The term "atmosphere" refers to a vapor ball. Thermosphere is the layer of the atmosphere has no definite outer limit. The thermosphere is located between 53 miles (85 kilometers) and 375 mile (600 kilometers).

Therefore, thermosphere is the layer of the atmosphere has no definite outer limit.

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The exosphere is the layer of the atmosphere that has no clear outer limit. The exosphere is the Earth's atmosphere's outermost layer, extending from the top of the thermosphere to the edge of space.

The exosphere, unlike the other layers of the atmosphere, gradually transitions into the vacuum of outer space with no clearly defined border.

The density and spread out of gas molecules in the exosphere are exceedingly low.

This area is made up mostly of relatively light gases like hydrogen and helium, and it is where satellites and other spacecraft circle the Earth.

Thus, the progressive reduction in density as the atmosphere merges into space accounts for the lack of a well-defined outer boundary.

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The magnitude of the net force causing the 2300kg car to slow down is 6900N

HOW TO CALCULATE FORCE:

F = 2300kg × 3m/s²

F = 6900N

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The ball raised up the hill is given gravitational potential energy, which

causes it to roll spontaneously down the hill.

The statement that explains whether the ball rolling down the hill

experiment should be used is; The experiment shows the ball falls toward

the bottom of the hill, so it provides direct evidence that gravity pulls an

object downward. They should use it.

Reason:

The equation for the velocity of a ball falling down a hill is [tex]v = \sqrt{\dfrac{10}{7} \cdot g \cdot h}[/tex]

Therefore, by increasing the height from which the ball rolls down the hill,

the velocity of the ball increases, which indicates that the ball is

accelerating, and therefore, being acted on by a force, the force of gravity.

Therefore;

Given that the ball falls or moves with increasing speed towards

the bottom of the hill, which shows that the motion is due to Earth's pull

known as the gravitational force, the experiment should be used.

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Answer:

c. changes can occur to certain physical properties

Explanation:

got it right on test

Answer:200kg of water

Explanation:

Answer:

copy and paste

Explanation: As the power following up on an object increases, the speed of acceleration is increased. As the mass of the article is expanded, the speed increase of the item is diminished.

The initial velocity of the book before its hits the ground is 14.2 m/s.

The given parameters;

The initial velocity of the book is calculated as follows;

h = ut + ¹/₂gt²

where;

1.5 = 3u + (0.5 x 9.8 x 3²)

1.5 = 3u + 44.1

3u = 1.5 - 44.1

3u = -42.6

[tex]u = \frac{-42.6}{3} \\\\u = -14.2 \ m/s\\\\u = 14.2 \ m/s \ downwards[/tex]

Thus, the initial velocity of the book before its hits the ground is 14.2 m/s.

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Answer:

the answer is UV Radiation

Answer:

gravity

Explanation:

because it acts on a particular direction that is towards the ground

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Addition of vectors:

vector u

has a magnitude of 20 and a direction of 0º with respect to the horizontal, vector v has a magnitude of 40 and a direction of 60º with respect to the horizontal.

a) Find the magnitude and direction of the resultant to the nearest whole

number.

Vector Sum:

The resultant of two vectors is simply the vector sum of the vectors. There are a handful of ways to present the resultant factor; the notation that shows the vector magnitude and direction is called the polar vector notation. An example of a vector presented in polar vector notation is

a∠θ where a is the magnitude and θis the angle that the vector makes with the horizontal axis.

Answer and Explanation:

Let's first present the vectors in rectangular vector notation.

For the vector →u of magnitude 20 and direction 0∘ to the horizontal axis, the vector is →u=^i20.

For the vector →v

of magnitude 40 and direction 60∘ to the horizontal axis, the vector is →v=^i40cos60∘+^j40sin60∘.

The resultant vector →w is the vector sum of the vectors, i.e.

→w=→u+→v

=^i20+^i40cos60∘+^j40sin60∘

=^i(20+40cos60∘)+^j(40sin60∘)

=^i40+^j20√3

For a vector ^ix+^jy, the magnitude of the vector is √x2+y2 and the direction above the horizontal axis is θ=tan−1(yx).

Let's use the formulas:

|→w|∠θ=√(40)2+(20√3)2∠tan−1(20√340)≈52.9∠40.9∘

The magnitude of the vector is about 53 units in the direction 41-degrees above the horizontal axis.

The magnitude of the resultant vector would be 60 units, and its direction will be 0°.

To find the magnitude and direction of the resultant vector when adding vectors u and v, we can use vector addition formulas:

Magnitude of the Resultant Vector (R):

R = √(u^2 + v^2 + 2uv * cosθ)

where:

u = magnitude of vector u (20)

v = magnitude of vector v (40)

θ = angle between vectors u and v (60°)

Plugging in the values:

R = √(20^2 + 40^2 + 2 * 20 * 40 * cos(60°))

≈ √(400 + 1600 + 1600)

≈ √3600

= 60

Direction of the Resultant Vector (θR):

Use the Law of Cosines to find the angle θR between the resultant vector R and vector u:

cosθR = (v^2 + R^2 - u^2) / (2 * v * R)

Plugging in the values:

cosθR = (40^2 + 60^2 - 20^2) / (2 * 40 * 60)

= (1600 + 3600 - 400) / 4800

= 1

Since cos(0°) = 1, we have θR = 0°.

So, the magnitude of the resultant vector is 60 units, and its direction is 0°.

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Answer:

2)Electric charge is the physical property of matter that causes it to experience a force when placed in an electromagnetic field. Electric charge can be positive or negative (commonly carried by protons and electrons respectively)

Answer:

1.  F = M x A

2. Force  

3. 2nd Law: Force

4. a, b, c (in order)

5. 3rd Law: Action and Reaction

6. b, c, a (in order)

7. 1st Law: Inertia

1. F=ma

2. Force

3. Second law

4. a)first

b)second

C) third

5. Third

6. a) second

b) third

C) first

7. First

A car that experiences a deceleration of -41.62 m/s² and comes to a stop after 10.99 m has an initial velocity of 30.60 m/s.

A car experiences a deceleration (a) of -41.62 m/s² and comes to a stop (final velocity = v = 0 m/s) after 10.99 m (s).

We can calculate the initial velocity of the car (u) using the following kinematic equation.

[tex]v^{2} = u^{2} + 2as\\\\u = \sqrt[]{v^{2}-2as} = \sqrt[]{(0m/s)^{2}-2(-42.61m/s^{2} )(10.99m)} = 30.60m/s[/tex]

A car that experiences a deceleration of -41.62 m/s² and comes to a stop after 10.99 m has an initial velocity of 30.60 m/s.

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Answer:

the maximum height is 1.276 meters

Answer:se obesrva ca indicele de refractie NU are unitate de masura, este adimensional. Se exprima print-un raport, de exemplu 4/3, 1,5 etc.

Explanation:

Answer:

Displacement

Explanation:

The definition of speed and the graphical analysis allows to find the result for the question of the meaning of the area under the curve is:

Velocity is defined as the variation of position with respect to time.

      [tex]v = \frac{dx}{dt}[/tex]  

Where v is the velocity, x the displacement and t the time.

If we make a graph of speed versus time, see attached, where we have a diagram of the process.

The expression of the velocity for the case of zero acceleration is

      [tex]v = \frac{\Delta x}{\Delta t }[/tex]  

      Δx = v  Δt

They indicate that the shaded section is under the curve, therefore it is

        Area = Δv Δt

When comparing the two expressions they are equivalent, therefore the area is equal to the distance traveled.

In conclusion, using the definition of velocity and graphical analysis we can find the result for the question of the meaning of the area under the curve is:

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Answer:

360 m

Explanation:

Explanation is given in the attached image below.

Answer:

3 meters

Explanation:

add up dum boi

Answer:

The angular velocity is: (2π radians) ⁄ (4.3 sec) = 1.461 rad/sec

The angular displacement is: (1.461 rad/sec)(1 sec) = 1.461 radians

Explanation:

Explanation:

what is your language i don't no

Answer:

You can see how forces can stack on one another by comparing the normal force of the bottom most rock to the normal force of the upper most rock.

Explanation:

Say you have 3 rocks all with mass m=3kg

These 3 rocks will all have the gravitational force of -29.4N (multiply 3kg by -9.8m/s^2)

If none of the rocks are stacked, then they all have the same normal force as well (29.4N)

However, stack them, and see how their normal forces change.

m1 will continue to have a normal force of 29.4N

m2 will now have a normal force of 58.8

m3 will now have a normal force of 88.2

Though they all retain the same gravitational force, their normal force changes depending on the forces acting down on them.

Mass 1 have no forces acting downwards other than gravity.

Mass 2 has the force of mass 1 and gravity acting down on it.

Mass 3 has the force of mass 1, mass 2, and gravity acting down on it.

Answer:

Below

Explanation:

We can use this formula to find the final velocity of the object :

     vf = vi + at

Now, because no force is applied to the object, the acceleration of this object will be 0 according to Newton's 1st law!

     vf = 5m/s + (0)(5)

     vf = 5 m/s

Hope this helps!