Answer This Picture..

Answer:

hii

needed points

Answer:

40.7g

Explanation:

so mass = moles × mr( 6.94+16+1)

=1.7 × 23.94

= 40.698

so 3 S.F = 40.7 g

hope this helps :)

Answer:

1-chlorobutane

Explanation:

Given that :

-- The compound A is made to react with alcoholic KOH and produce compound B.

-- The compound B on Ozonolysis produces methanol as well as propanol

The compound A should be a haloalkanes as treatment of haloalkanes with the alcoholic KOH, it will give alkene.

[tex]$CH_3CH_2CH_2CH_2Cl+KOH( \text{alcohol}) \rightarrow CH_3CH_2CH=CH_2+KCl+H_2O$[/tex]

So, the compound B should be Butene

Now the ozonolysis of the compound B or butene will give methanol and propanal as shown :

[tex]$CH_3CH_2CH=CH_2 \rightarrow CH_2O+CH_3CH_2CHO$[/tex]

Therefore, the compound A is 1-chlorobutane.

Answer:

The answer is the first option 0.37 moles

Explanation:

the ideal gas law is PV = nRT, so in the terms of n,

n = PV/RT (divide both sides by RT to let n stand alone)

given: P = 700 kpa, V = 2L, T = 450 K , R = 8.31

n = (700 * 2) / (8.31 * 450)

= 1400/3739.5

= 0.34

Answer:

A

Explanation:

Saturated means all the carbon atoms has four single bonds around it. These bonds are strong and won't break easily therefore saturated hydrocarbons aren't very reactive

Unsaturated means in one instance the C has a double bond with another carbon. This double bond can be easily broken therefore making unsaturated compounds more reactive than saturated compounds

So saturation deals with the type of bonds the carbon has with other carbon atoms. (The C-C bonds)

Answer:

Hello There!!

Explanation:

I believe the answer is O Gas.

hope this helps,have a great day!!

~Pinky~

The given molecule is an aldehyde with the formula HCHO. It is the simplest and primary aldehyde . Hence, option c is correct.

Aldehydes are a class of organic compounds that contain a carbonyl group (a carbon double-bonded to an oxygen) at the end of a carbon chain. The general formula for an aldehyde is RCHO, where R is a substituent or side chain attached to the carbonyl group.

Aldehydes are often characterized by their distinctive odor, which can be described as pungent and irritating. Some common aldehydes include formaldehyde (used in building materials and as a disinfectant), acetaldehyde (found in alcoholic beverages), and benzaldehyde (used in food flavorings).

Aldehydes are important intermediates in many chemical reactions, and they are used in a variety of industrial and laboratory applications. They can be synthesized by the oxidation of primary alcohols or by the partial oxidation of hydrocarbons. The given compound is formaldehyde HCHO.

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Answer:

What are the answer choices????

Answer:

An increase in the number of gas molecules in the same volume container increases pressure. A decrease in container volume increases gas pressure. An increase in temperature of a gas in a rigid container increases the pressure.

Explanation:

Increasing the temperature would increase the pressure on the system

Answer:

7:4

Explanation:

O2 : NO2

7 : 4

hope this helps :)

B. They are vibrating slightly

Explanation:

This is because the particles are really close together and they vibrate on the spot.

Hope this is useful

There are several methods that can be employed to increase yield in the chemical synthesis of acetaminophen.

The term chemical synthesis has to do with the method of producing a chemical substance from other chemical substances.

It is usual in industrial chemistry to seek to optimize the yield of the target product. In the chemical synthesis of acetaminophen as shown in the image attached, the yield of the product can be increased by;

1) Removal of the ethanoic acid byproduct to drive the forward reaction

2) Increasing the concentration of each of the reactants to ensure that more product is obtained.

3) Operating the process at a higher temperature to ensure that reaction is more efficient.

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Answer: 581 Sn and 13 Sn

Explanation:

581 Sn and 13 Sn are both Sn which are the same element with different masses. Isotopes are same element with different masses and the elements can have different masses because of different number of neurons

Answer: False

Explanation: Took the test

Answer:

False

Explanation:

Answer:

≈ 2.74 mol [tex]AlCl_{3}[/tex]

(I rounded to 3 sig figs because the starting amount has 3 sig figs.)

Explanation:

[tex]\frac{365g AlCl_{3}}{1}*\frac{1 mol AlCl_{3}}{133.34g AlCl_{3}} =[/tex] 2.73736313184 mol [tex]AlCl_{3}[/tex] ≈ 2.74 mol [tex]AlCl_{3}[/tex]

Hope this helps!

Answer: A

Explanation:

i just took the quiz and it was right!

c) because rays contain electrons

For a given valye of l(l shell), values of m are from -l to 0 to l, so m could be; -3, -2, -1, 0, +1, +2, +3.

Easyy!

the value of m is equal to 2l+1 so there must beseven values for m.

m can have values from -l through zero to +l so the values are -3, -2, -1, 0, +1, +2 and +3.

Answer:

A. Sodium (Na)

Explanation:

The total number of electrons in the outermost principal energy level of an element is called the valence electrons of that element.

Na (11)---→1s2 2s2 2p6 3s1

There 1 electron in the outermost principal energy level of Sodium. So, the number of valence electron of Sodium is 11.

Answer:

Na

Explanation:

I was learning about it recently, that dude's right, it's Sodium

Answer:

Hello There!!

Explanation:

I believe the answer is how fast the molecules are vibrating.

hope this helps,have a great day!!

~Pinky~

Explanation:

in mathematics use Pascal triangle

Answer:

f-block

Explanation:

Answer:

someone already answered but i think it's 132.0 mol too

Answer:

[tex]M_b = \frac{0.10M * 9.50mL}{3.80mL}[/tex] ---- The setup

[tex]M_b = 0.25M[/tex] --- The molarity of KOH

Explanation:

Given

I will answer the question with the attached titration data

Required

The set and the value of the molarity of KOH

First, calculate the volume of acid (HCL) used:

[tex]V_a = Final\ Reading - Initial\ Reading[/tex]

[tex]V_a = 25.00mL - 15.50mL[/tex]

[tex]V_a = 9.50mL[/tex]

Calculate the final volume of base (KOH) used:

[tex]V_b = Final\ Reading - Initial\ Reading[/tex]

[tex]V_b = 8.80mL - 5.00mL[/tex]

[tex]V_b = 3.80mL[/tex]

The numerical setup is calculated using::

[tex]M_a * V_a = M_b * V_b[/tex]

Where

[tex]V_a = 9.50mL[/tex]

[tex]V_b = 3.80mL[/tex]

[tex]M_a = 0.10M[/tex] --- the given molarity of HCL

So, we have:

[tex]M_a * V_a = M_b * V_b[/tex]

[tex]0.10M * 9.50mL = M_b * 3.80mL[/tex]

Make Mb the subject

[tex]M_b = \frac{0.10M * 9.50mL}{3.80mL}[/tex] ---- The correct numerical setup

The solution is then calculated as:

[tex]M_b = \frac{0.10M * 9.50mL}{3.80mL}[/tex]

[tex]M_b = \frac{0.10 * 9.50}{3.80}M[/tex]

[tex]M_b = \frac{0.95}{3.80}M[/tex]

[tex]M_b = 0.25M[/tex]

Answer:

23, 51

Explanation:

Edmentum/plato

As per the balanced reaction, 2 moles of aluminum metal and 3 moles of copper nitrate gives 2 moles of aluminum nitrate and 3 moles of copper metal.  10 g  of Al and 25g of copper nitrate gives 0.08 moles of aluminum nitrate and 0.13 moles of copper.

A limiting reactant is the reacting species which is not sufficient in amount to complete the reaction. Hence, the limiting reactant determines the yield of the reaction.

The given reaction is written as:

[tex]\rm 3Cu(NO_{3})_{2} + 2Al \rightarrow 2 Al(NO_{3})_{3} + 3Cu[/tex]

2 moles of Al and 3 moles of copper nitrate gives 2 moles of aluminum nitrate and 3 moles of Cu.

Molar mass of copper nitrate = 187.5 g/mol

atomic mass of aluminum = 27 g/mol

then, number of moles in 10 g of Al = 10 g/27 g/mol = 0.37 moles.

number of moles in 25 g of copper nitrate = 25 g/187.5 g/mol = 0.13 moles.

0.37 moles of Al needs 0.5 moles of copper nitrate to react with. Hence, copper nitrate is the limiting reactant.

3 moles of copper nitrate gives 2 moles of aluminum nitrate. Then 0.13 moles will give 2/3rd of 0.13 i e., 0.08 moles of aluminum nitrate. Similarly 0.13 moles copper nitrate gives 0.13 moles of copper metal.

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Your question is incomplete. But your complete question probably was:

10 g of aluminum metal reacts with 25 g of copper nitrate. Use the periodic table to determine the amount of copper and aluminum nitrate formed in the reaction.

In the reaction,

moles of Cu and

moles of Al(NO3)3 are formed.

Answer:

acceleration

inversly

opposite

directly

mass