Anyone could help out with this

Answer:

x = 27.19

Step-by-step explanation:

Sin(54) =22/x

0.81=22/x

x0.81= 22

x = 27.19

Answer:

$2626.75

Step-by-step explanation:

First, let's set up the equation for this: [tex]4000 = P(1 + \frac{0.085}{4})^{4(5)}[/tex]

Now, we can simply divide [tex]\frac{4000}{(1+\frac{0.085}{4})^{20} }[/tex]

and we get P ≈ $2626.75

The expression for the amount of Meghan's newspaper for three months will be T = C - (9.95 x  3).

Expression in maths is defined as the collection of the numbers variables and functions by using signs like addition, subtraction, expansion and division.

The account balance total can be calculated with the following equation where the variable T represents the final balance while the variable C represents her current balance before the three months.

T = C - (9.95 * 3)

The monthly charge is multiplied by the three months that Megan will be charged and then discounted from her current balance in order to give the new Total Balance after paying the subscription for the three months.

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Answer:

29

Step-by-step explanation:

You do 119-3 because 3 students rode with their parents so then you do 116÷4=29

The statement about the graphs is true is:  Graph B is a valid density curve because the curve is above the horizontal axis, and the area under the curve is 1.

Graph curve is above the horizontal axis.

Let determine the area under the curve using this formula

Base of left and right triangle

Left  

Base = -3 - (-5)

Base= 2

Right

Base= 3 - (-3)

Base= 6

Right and left height

Height= 0.25

Hence:

Total area=(base× height)/2

Total area=[ (2×0.25)/2] + (6×0.25)/2

Total area=0.25+0.75

Total area=1

Therefore  Graph B is a valid density curve because the curve is above the horizontal axis, and the area under the curve is 1.

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Answer:

9

Step-by-step explanation:

because 3*4=12 then divide 108 by 12 giving you 9

Answer:

[tex]3x + y = -4[/tex]

Step-by-step explanation:

We were given to points on the line we are trying to find, hence we are able to determine the slope/gradient.

[tex]( - 1, \: 1) \: and \: (1, \: 7) \\ slope = \frac{ {y}^{2} - {y}^{1} }{ {x}^{2} - {x}^{1} } \\ \\ s = \frac{7 - 1}{1 - ( - 1)} \\ s = \frac{6}{2} [/tex]

Slope is equal to 3.

Since we have the value for the slope, we can now use one of the points on the line to determine the equation of the line.

note that the coefficient of x is the slope. In this case the A from the standard form (Ax + By= C) is the slope.

[tex] \\ let \: us \: use \: the \: point \: ( - 1, \: 1) \\ a = 3 \: \: \: \: y = 1 \: \: \: x = - 1\\ ax + by = c \\ 3( - 1) + 1 = c \\ - 3 + 1 = c [/tex]

[tex] - 2 = c \\ therefore \: the \: equation \: of \: the \\ \: line \: is \\ ax + by = c \\ 3x + y = - 4[/tex]

Answer:

b

Step-by-step explanation:

4 - 8 = -4 times 2 = -8

[tex]\qquad \textit{Amount for Exponential Decay} \\\\ A=P(1 - r)^t\qquad \begin{cases} A=\textit{current amount}\dotfill &\$14500\\ P=\textit{initial amount}\dotfill &\$22500\\ r=rate\to r\%\to \frac{r}{100}\\ t=years\dotfill &6\\ \end{cases}[/tex]

[tex]14500=22500(1 - \frac{r}{100})^{6}\implies \cfrac{14500}{22500}=\left( \cfrac{100-r}{100} \right)^6\implies \cfrac{29}{45}=\left( \cfrac{100-r}{100} \right)^6 \\\\\\ \sqrt[6]{\cfrac{29}{45}}=\cfrac{100-r}{100}\implies 100\sqrt[6]{\cfrac{29}{45}}=100-r \\\\\\ r=100-100\sqrt[6]{\cfrac{29}{45}}\implies r\approx \stackrel{\%}{7.06}[/tex]

Answer:

Yes, by ASA congruence.

Step-by-step explanation:

Solving :

Hence, as 2 angles and a side of the triangles are equal, we can say they are congruent by ASA congruence.

[tex]\huge\underline{{\sf Answer}}[/tex]

[tex] \textbf{Let's check if the two triangles are } [/tex][tex] \textbf{congruent} [/tex] ~

[tex] \large\textsf{Given information } [/tex]:

[tex] \textsf{Two angles of a triangle is equal to corresponding} [/tex] [tex] \textsf{two angles of another triangle, and they} [/tex][tex] \textsf{have one side in common (should be equal} [/tex][tex] \textsf{for both) } [/tex]

[tex] \textsf{So, after analyzing this information, we can } [/tex][tex] \textsf{conclude that the two triangles are congruent by} [/tex][tex] \textsf{AAS congruency criteria.} [/tex]

[tex] \texttt{[ since two angles are equal and one} [/tex][tex] \texttt{non included side is common/equal ]} [/tex]

Answer:

B. 11

Step-by-step explanation:

Hope this helps! ;-)

Answer:

11

Step-by-step explanation:

15-12/3

Parenthesis

Exponents

Multiplication

Division

Addition

Subtraction

15-4 = 11

Answer:

Step-by-step explanation:

The total cost of Tandoori Seasoning is incorrect.

Vijay made an error when multiplying 3.5 ounces by $3.60 .

Cost of both spice blends is actually $23.6.

it is defined as the deviation of an entitiy from its corrected value while calculating.

Now it is given that,

Tandoori Seasoning = 3.5 ounces for $3.60 an ounce

Garam Masala =  4 ounces for $2.75 an ounce

Hence, total cost of  Tandoori Seasoning =  3.5*$3.60

⇒ total cost of Tandoori Seasoning = $12.6

and total cost of Garam Masala =  4*$2.75

⇒ total cost of Garam Masala = $11

Therefore, total cost for the spices =cost of Tandoori Seasoning + cost of Garam Masala

⇒  total cost for the spices = $12.6 + $11

⇒  total cost for the spices =  $23.6

Hence, we conclude that,

The total cost of Tandoori Seasoning is incorrect.

Vijay made an error when multiplying 3.5 ounces by $3.60 .

Cost of both spice blends is actually $23.6.

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Answer:

The answer is the longest one <3

Step-by-step explanation:

I took the test:

If the coin is tossed and a card is chosen from 1 to 4, then the total sample will be 8. Then the correct option is D.

A sample is a collection of well-defined elements. A sample is represented by a capital letter symbol and the number of elements in the finite set is shown as a curly bracket {..}.

A student tosses a coin and then draws a card from a stack of 4 cards labeled 1 through 4.

Then the total number of the sample will be

Total sample = 2 × 4

Total sample = 8

Then the sample is given below.

[tex]\rm Sample = \begin{Bmatrix}(H,1) & (H,2) & (H,3) & (H,4) \\\\(T,1) & (T,2) & (T,3) & (T,4) \\\end{Bmatrix}[/tex]

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Answer:

Your kid will be 9 years old.

Step-by-step explanation:

It's not relevant, that you are 14 now.

Answer: 9

Step-by-step explanation: Regardless of if you are 14 or not, 30-21=9

The quadrants in which the tangent is positive are I and III.

Option B is the correct answer.

There are three commonly used trigonometric identities.

Sin x = Perpendicular / Hypotenuse

Cosec = Hypotenuse / Perpendicular

Cos x = Base / Hypotenuse

Sec x = Hypotenuse / Base

Tan x = Perpendicular / Base

Cot x = Base / Perpendicular

We have,

Tangent is defined as the ratio of the opposite side to the adjacent side of a right triangle.

It is positive when the opposite side and the adjacent side are both positive or both negative.

In the first quadrant (I), both the opposite and adjacent sides are positive, so the tangent is positive.

In the second quadrant (II), the opposite side is positive and the adjacent side is negative, so the tangent is negative.

In the third quadrant (III), both the opposite and adjacent sides are negative, so the tangent is positive.

In the fourth quadrant (IV), the opposite side is negative and the adjacent side is positive, so the tangent is negative.

Therefore,

The quadrants in which the tangent is positive are I and III.

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Answer:

x = 2

Step-by-step explanation:

We can find this by doing the short (and wildly incorrect way, according to teachers) way and input two in.  The way the teachers want you to do it is this way:

3x + 4 = 10

3x + 4 (-4) = 10 (-4)

3x = 6

3x = 6/3

x = 2

2 is your answer.

Answer:

haha kala mo ba maiinit

Step-by-step explanation:

[tex]\green{ \rule{500pt}{999999pt}}[/tex]

Answer:a function whose value decreases as the independent variable increases over a given range.

Step-by-step explanation:

Answer:

Step-by-step explanation:

In the question, it is given that a right cone has a radius of 15 units and volume of 3000π units³ and we have to find the height of the cone.

[tex] \: [/tex]

To Find the height of the cone, we must know this formula :

[tex]\\{\longrightarrow{ \qquad{\underline{\boxed {\pmb{\frak { \dfrac{1}{3} \: \pi {r}^{2}h ={ Volume_{(cone) }}}}}}}}} \\ \\[/tex]

Where,

Now, we will substitute the values in the formula :

[tex] \\ {\longrightarrow{ \qquad{{ {\pmb{\sf { \dfrac{1}{3} \times \pi \times {(15)}^{2} \times h = 3000 \pi}}}}}}} \\ \\[/tex]

Cancelling π from both sides we get :

[tex]\\ {\longrightarrow{ \qquad{{ {\pmb{\sf { \dfrac{1}{3} \times \cancel\pi \times {(15)}^{2} \times h = 3000 \cancel\pi}}}}}}} \\ \\[/tex]

[tex]\\ {\longrightarrow{ \qquad{{ {\pmb{\sf { \dfrac{1}{3} \times 225 \times h = 3000}}}}}}} \\ \\[/tex]

[tex]\\ {\longrightarrow{ \qquad{{ {\pmb{\sf { \dfrac{225}{3} \times h = 3000}}}}}}} \\ \\[/tex]

[tex] \\ {\longrightarrow{ \qquad{{ {\pmb{\sf 75 \times h = 3000}}}}}} \\ \\[/tex]

[tex]\\ {\longrightarrow{ \qquad{{ {\pmb{\sf h = \frac{3000}{75} }}}}}} \\ \\[/tex]

[tex]\\{\longrightarrow{ \qquad{\underline{\boxed {\pmb{\frak { h =40 }}}}}}} \\ \\[/tex]

Therefore,

Answer:

inscribed angle

Step-by-step explanation:

That is an inscribed angle in a circle ....

Answer:

inscribed angle

Step-by-step explanation:

The vertex (point, corner) of the angle is ON the circle, this is an inscribed angle.

Answer:

Step-by-step explanation:

Finding the hypotenuse of the triangular side :

Finding Surface Area :

Finding Volume :

Answer:y

=

6

(

x

+

5

4

)

2

−

147

8

Use the vertex form,

y

=

a

(

x

−

h

)

2

+

k

, to determine the values of

a

,

h

, and

k

.

a

=

6

h

=

−

5

4

k

=

−

147

8

Find the vertex

(

h

,

k

)

.

(

−

5

4

,

−

147

8

)

Step-by-step explanation:

Using the confidence interval, it is found that the correct option regarding the valid conclusion they can make is given by:

b. Because the confidence interval includes 0, we don't have convincing evidence that there is a difference in reaction time.

At the null hypothesis, it is tested if there is not a difference in reaction times, that is:

[tex]H_c - H_d = 0[/tex]

At the alternative hypothesis, it is tested if there is a difference, that is:

[tex]H_c - H_d \neq 0[/tex]

The interval contains 0, hence there is not enough evidence to reject the null hypothesis, which means that option B is correct.

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Answer:

∠[tex]DEC[/tex]

Step-by-step explanation:

vertical angles are opposite angles that are made by 2 intersecting lines

A diagram of parallelogram MNOP is attached below

We have side MN, || side OP, and side MP || NO

Using the rule of angles in parallel lines, ∠M and ∠P are supplementary as well as ∠M and ∠N.

Since ∠M+∠P = 180° and ∠M+∠N=180°, we can conclude that ∠P and ∠N are of equal size.

∠N and ∠O are supplementary by the rules of angles in parallel lines

∠O and ∠P are supplementary by the rules of angles in parallel lines

∠N+∠O=180° and ∠O+∠P=180°

∠N and ∠P are of equal size

we deduce further that ∠M and ∠O are of equal size

Hence, the correct statement to complete the proof is

∠M ≅ ∠O; ∠N ≅ ∠P

[tex]f(x) = 3^x + \ln x -108 x\\\\f'(x) = 3^x \ln 3 + \dfrac 1x - 108\\\\f''(x) = 3^x \cdot 0+ \ln 3\cdot 3^x\cdot \ln (3)-x^{-1-1}-0= 3^x \cdot \ln^2 3 -x^{-2}\\ \\f'''(x) = 3^x \cdot 0 + \ln^2 (3) \cdot 3^x \cdot \ln (3) +2x^{-2-1} = 3^x \ln^3 (3)+2x^{-3}\\\\f''''(x) = 3^x \cdot 0 + \ln^3 (3) \cdot 3^x \ln(3) -3\cdot 2 x^{-3-1} = 3^x\ln^4 (3)-6x^{-4} \\\\\text{Hence the fourth derivative of f(x) is}~~ 3^x\ln^4 (3)-6x^{-4}.\\\\[/tex]

[tex]\textbf{Note:}\\\\\dfrac{d}{dx}(uv) = u \dfrac{dv}{dx} + v\dfrac{du}{dx}\\\\\dfrac{d}{dx} \ln (x) = \dfrac 1x\\\\\dfrac{d}{dx} a^x = a^x \ln a\\\\\dfrac{d}{dx} x^n = nx^{n-1}\\\\\dfrac{d}{dx} (\text{Constant}) = 0[/tex]

Answer:

1.732

Step-by-step explanation:

If the equation is y = - 11sin(4x - 8). Then amplitude will be 11, the time period is 4, and the phase difference is 8.

It is a function that repeats itself in a particular time interval.

The sinusoidal function is given as

y= |A| sin(ωx - Φ) ...1

Where A is amplitude, ω is the time period, and Φ is the phase difference.

The equation is given below.

y =  -11 sin(4x - 8) ...2

Comparing the equations 1 and 2, then we have

Amplitude will be 11, the time period is 4, and the phase difference is 8.

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