anyone know how to do this?

Answer:38°

Explanation:

Answer:

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

mass = Density × volume

From the question we have

mass = 3.66 × 270

We have the final answer as

Hope this helps you

Answer:

Chemical element, metallic, symbol Mg, situated in group IIa in the periodic table, atomic number: 12, atomic weight: 24,312. ... Magnesium is known for a long time as the lighter structural metal in the industry, due to it's low weight and to it's capability of forming mechanically resistant alloys.

Explanation:

byju's ig. Cause it gives a proper concept

Answer:

Ok:

Explanation:

4.

[tex]I_2_{(s)} + 3Cl_2_{(g)} => 2ICl_3{(s)}[/tex]

5.

[tex]NaHCO_3_{(s)} + HCl_{(aq)} => NaCl_{(aq)} + H_2O_{(l)} + CO_2_{(g)[/tex]

Answer:

20 mL

Given data:

Molarity of NaCl = 0.100 M

Volume of Pb(NO₃)₂ = 5.00 mL (5.0/1000 = 0.005 L)

Molarity of Pb(NO₃)₂ = 0.200 M

Volume of NaCl needed = ?

Solution:

Chemical equation:

2NaCl  + Pb(NO₃)₂    →      PbCl₂   +  2NaNO₃

Number of moles of Pb(NO₃)₂:

Molarity = number of moles / volume in L

0.200 M = number of moles / 0.005 L

Number of moles = 0.200 M  ×volume in L

Number of moles = 0.001 mol

now we will compare the moles of NaCl and Pb(NO₃)₂.

                         Pb(NO₃)₂       :            NaCl

                             1                 :              2

                        0.001              :         2/1×0.001 = 0.002 mol

Volume of NaCl:

Molarity = number of moles / volume in L

0.100 M = 0.002 mol / volume in L

Volume in L = 0.002 mol / 0.100 M

Volume in L = 0.02 L      

volume in mL:

0.02 L × 1000 mL/1 L

20 mL

121 mol CH₄

Math

Pre-Algebra

Order of Operations: BPEMDAS

Chemistry

Organic

Atomic Structure

Step 1: Define

7.31 × 10²⁵ molecules CH₄

Step 2: Identify Conversions

Avogadro's Number

Step 3: Convert

[tex]\displaystyle 7.31 \cdot 10^{25} \ molecules \ CH_4(\frac{1 \ mol \ CH_4}{6.022 \cdot 10^{23} \ molecules \ CH_4} ) = 121.388 \ mol \ CH_4[/tex]

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

121.388 mol CH₄ ≈ 121 mol CH₄

Answer:

metalloids

Explanation:

The kind of element most likely used to make semiconductors are the metalloids.

These elements have properties between those of metals and non-metals in that they are not truly metals and are partly non-metals.

Answer:

it reacts to limestone better and is a bit more firmer and mostly preferred over because of how fast it can react towards chemicals

Answer:

the answer should be A

Answer:

B. Electrons can exist in between energy levels .

Explanation:

The value of energy for each energy level in an atom is quantized. Thus, electrons are not allowed to be found in between the energy levels.

When an electron absorbs energy, it becomes excited. And it would jump to a higher energy level whose energy is equal to the new energy of the electron. If the value of its new energy is less than the energy of higher levels but greater than the energy of it current energy level, the electron remains in its initial level. This is because, electrons do not exist in between energy levels .

It makes the number simpler by putting it up to the next ten ex. 37 will be rounded up to 40

Answer:

a.The waves are absorbed or reflected to capture images

Explanation:

How Things Work: TSA scanners use electromagnetic waves for detection. ... These waves are bounced off the body of the person being scanned to create a three-dimensional image on the computer. The backscatter units instead bounce low-level electromagnetic X-rays off the body to create an image on the computer

Answer:

A. The waves are absorbed or reflected to capture images or

information

Explanation:

Answer:

Accuracy

Explanation:

It is important for scientists to review the work of other scientists, so they can be sure there are no mistakes or lack of judgement. They repeat to compare results to make hypotheses.

Answer:

Ok:

Explanation:

1a:  [tex](no number) NH_4NO_2_{(s)} => (no number) N_2_{(g)} + 2 H_2O_{(l)}[/tex]

1b: Decomposition reaction

2a. [tex](no number) Cl_2_{(g)} + 2 KBr_{(aq)} => 2 KCl_{(aq)} + (no number) Br_2_{(l)}[/tex]

2b Single replacement reaction

3a. [tex](no number)F_2S_{(s)} + 2HCl_{(aq)} =>(no number)H_2S{(g)} + (nonumber)FeCl_2_{(aq)}[/tex]

3b. Double replacement reaction

Answer:

I believe what your looking for is Nitrogen disulfide

Explanation:

Hope this helps (:

Answer:

amount of He = (7.91 × 10^22) ÷ (6.02 × 10^23) = 0.131mol (3sf)

Explanation:

you make use of the mole concept formula

amount(mol) = number of particles ÷ 6.02 × 10^23

(6.02 × 10^23 is the avogadro constant, which is an extremely important number in this formula for mole concept)

Explanation:

When an object undergoes a physical change (solid to liquid, decrease in temperature etc.), the mass of the object remains constant.

When water freezes, the water molecules vibrate closer to one another and there is less space between the molecules.

The same number of water molecules now occupy a smaller volume, therefore their density increases.

The correct answer is the 3rd option.

At the time when the water should be freezed so here the density should be decreased.

The density refers to the mass of the unit volume with respect to the material substance.

The formula for density should be d = M/v

So here d means the density

And, m means mass

V means the volume

So it should be expressed in units with respect to the units of grams per cubic centimeter.

Hence the last option is correct.

Learn more about water here: https://brainly.com/question/24720645

Answer:

:O Fr? Bet let me go get them lol

✧ Yes, since one of our senses are missing we won't really detect the taste.

Explanation: Think about it, we usually smell food and we can already tell if it's going to taste good or not. Looking or touching food doesn't always help to know if we will like the taste. ✧

Answer:

IM NOT COMPLETELY SURE BUT ITS ETHER A OR B IM SORRY ;//

Explanation:

Answer:

D

Explanation:

Answer: C: The inner core is densest due to gravitational compression

Explanation:  

Answer:

E

Explanation:

Answer:

Explanation:

Oxygen is prepared by catalytic decomposition of potassium chlorine (KClO3). Decomposition of potassium, chloride gives potassium chloride (KCl) and oxygen (O2). How many moles and how many grams of KClO3 are required to produce 2.4 mole O2?

Answer:

its D

Explanation:

Brooke should turn so that her back is to the Sun to her wall, and hold the Moon (ball representing Moon) in front of her. Therefore, option (D) is correct.

The eclipse of the moon occurs when the earth comes in between the sun and the moon. The earth blocks the light coming from the sun from reaching the surface of the moon and casts its shadow on the moon.

A lunar eclipse occurs on a full moon day and can be observed up to 3 lunar eclipses per year.  A lunar eclipse can be categorized depending on how the sun, the moon, and the earth line up.

A partial lunar eclipse is when only a part of the moon moves into the shadow's earth. A total lunar eclipse is when the earth crossed directly in front of the moon and casts its shadow.

If Brooke's head is earth then it will be in the center and her back will be towards to sun poster on the wall. So that the ball in her hand can play as a moon to show the lunar eclipse.

Learn more about the Lunar eclipse, here:

https://brainly.com/question/12075389

#SPJ6

Answer:

The nose consists of the visible external nose and the internal nasal cavity. The nasal septum divides the nasal cavity into right and left sides. Air enters two openings, the external nares (nostrils; singular, naris), and passes into the vestibule and through passages called meatuses. The bony walls of the meatuses, called concha, are formed by facial bones (the inferior nasal concha and the ethmoid bone). From the meatuses, air then funnels into two (left and right) internal nares. Hair, mucus, blood capillaries, and cilia that line the nasal cavity filter, moisten, warm, and eliminate debris from the passing air.

The pharynx (throat) consists of the following three regions, listed in order through which incoming air passes:

The nasopharynx receives the incoming air from the two internal nares. The two auditory tubes that equalize air pressure in the middle ear also enter here. The pharyngeal tonsil (adenoid) lies at the back of the nasopharynx.

The oropharyrnx receives air from the nasopharynx and food from the oral cavity. The palatine and lingual tonsils are located here.

The laryngopharynx passes food to the esophagus and air to the larynx.

The larynx receives air from the laryngopharynx. It consists of several pieces of cartilage that are joined by membranes and ligaments, shown in Figure 2:

The epiglottis, the first piece of cartilage of the larynx, is a flexible flap that covers the glottis, the upper region of the larynx, during swallowing to prevent the entrance of food.

The thyroid cartilage protects the front of the larynx. A forward projection of this cartilage appears as the Adam's apple (anatomically known as the laryngeal prominence).

The paired arytenoid cartilages in the rear are horizontally attached to the thyroid cartilage in the front by folds of mucous membranes. The upper vestibular folds (false vocal cords) contain muscle fibers that bring the folds together and allow the breath to be held during periods of muscular pressure on the thoracic cavity (straining while defecating or lifting a heavy object, for example). The lower vocal folds (true vocal cords) contain elastic ligaments that vibrate when skeletal muscles move them into the path of outgoing air. Various sounds, including speech, are produced in this manner.

The cricoid cartilage, the paired cuneiform cartilages, and the paired corniculate cartilages are the remaining cartilages supporting the larynx.

The trachea (windpipe) is a flexible tube, 10 to 12 cm (4 inches) long and 2.5 cm (1 inch) in diameter (Figure 2).

The mucosa is the inner layer of the trachea. It contains mucus‐producing goblet cells and pseudostratified ciliated epithelium. The movement of the cilia sweeps debris away from the lungs toward the pharynx.

The submucosa is a layer of areolar connective tissue that surrounds the mucosa.

Hyaline cartilage forms 16 to 20 C‐shaped rings that wrap around the submucosa. The rigid rings prevent the trachea from collapsing during inspiration.

The adventitia is the outermost layer of the trachea. It consists of areolar connective tissue.

The primary bronchi are two tubes that branch from the trachea to the left and right lungs.

Inside the lungs, each primary bronchus divides repeatedly into branches of smaller diameters, forming secondary (lobar) bronchi, tertiary (segmental) bronchi, and numerous orders of bronchioles (1 mm or less in diameter), including terminal bronchioles (0.5 mm in diameter) and microscopic respiratory bronchioles. The wall of the primary bronchi is constructed like the trachea, but as the branches of the tree get smaller, the cartilaginous rings and the mucosa are replaced by smooth muscle.

Alveolar ducts are the final branches of the bronchial tree. Each alveolar duct has enlarged, bubblelike swellings along its length. Each swelling is called an alveolus. Some adjacent alveoli are connected by alveolar pores.

The respiratory membrane consists of the alveolar and capillary walls. Gas exchange occurs across this membrane. Characteristics of this membrane follow:

Type I cells are thin, squamous epithelial cells that constitute the primary cell type of the alveolar wall. Oxygen diffusion occurs across these cells.

Type II cells are cuboidal epithelial cells that are interspersed among the type I cells. Type II cells secrete pulmonary surfactant (a phospholipid bound to a protein) that reduces the surface tension of the moisture that covers the alveolar walls. A reduction in surface tension permits oxygen to diffuse more easily into the moisture. A lower surface tension also prevents the moisture on opposite walls of an alveolus or alveolar duct from cohering and causing the minute airway to collapse.

Alveolar macrophage cells (dust cells) wander among the other cells of the alveolar wall, removing debris and microorganisms.

Answer:

htt ps://w ww.you  tube. com/watch?v =oyy377 Yoj4I

Explanation: