You can finish the sentence like this: Consisting of both straight and curved lines, icons are images.
What is sentence?
A sentence is indeed a linguistic expression in linguistics as well as grammar, as in the English instance "The quick brown fox jumps so over lazy dog." It is typically described in traditional grammar as a group of words that conveys a complete thought or as a unit made up of a subject as well as predicate. It is typically described in non-functional linguistics as a maximal component of syntactic structure, such as a constituent. According to functional linguistics, it is a group of written texts that are separated by markers like periods, question marks, as well as exclamation points as well as graphological features like capital letters. Contrast this idea with a curve, which is defined by phonological characteristics like pitch and loudness as well as markers like pauses.
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Which of these parts converts the spinning motion of the driveshaft 90° to turn the wheels?
A. Transmission
B. Axle
C. Differential
D. Engine
Refrigerant 134a enters the evaporator of a refrigeration system operating at steady state at -16oC and a quality of 20% at a velocity of 5 m/s. At the exit, the refrigerant is a saturated vapor at -16oC. The evaporator flow channel has constant diameter of 1.7 cm. Determine the mass flow rate of the refrigerant, in kg/s, and the velocity at the exit, in m/s.
Answer:
mass flow rate = 0.0534 kg/sec
velocity at exit = 29.34 m/sec
Explanation:
From the information given:
Inlet:
Temperature [tex]T_1 = -16^0\ C[/tex]
Quality [tex]x_1 = 0.2[/tex]
Outlet:
Temperature [tex]T_2 = -16^0 C[/tex]
Quality [tex]x_2 = 1[/tex]
The following data were obtained at saturation properties of R134a at the temperature of -16° C
[tex]v_f= 0.7428 \times 10^{-3} \ m^3/kg \\ \\ v_g = 0.1247 \ m^3 /kg[/tex]
[tex]v_1 = v_f + x_1 ( vg - ( v_f)) \\ \\ v_1 = 0.7428 \times 10^{-3} + 0.2 (0.1247 -(0.7428 \times 10^{-3})) \\ \\ v_1 = 0.0255 \ m^3/kg \\ \\ \\ v_2 = v_g = 0.1247 \ m^3/kg[/tex]
[tex]m = \rho_1A_1v_1 = \rho_2A_2v_2 \\ \\ m = \dfrac{1}{0.0255} \times \dfrac{\pi}{4}\times (1.7 \times 10^{-2})^2\times 6 \\ \\ \mathbf{m = 0.0534 \ kg/sec}[/tex]
[tex]\rho_1A_1v_1 = \rho_2A_2v_2 \\ \\ A_1 =A_2 \\ \\ \rho_1v_1 = \rho_2v_2 \\ \\ \implies \dfrac{1}{0.0255} \times6 = \dfrac{1}{0.1247}\times (v_2)\\ \\ \\\mathbf{\\ v_2 = 29.34 \ m/sec}[/tex]
Fill in the blank to output the quotient of dividing 100 by 42. print (100______42)
Answer:
print(100/42)
Explanation:
This is the operand for division in python and some other languages.
which of the following code segments will move the robot from the center square along the same path as the code segment above?
count ← 0
REPEAT 4 TIMES
{
count count + 1
REPEAT count TIMES
{
MOVE_FOWARD ()
}
ROTATE_LEFT ()
}
Which of the following best describes the typical method by which messages are transmitted over the Internet?The message is broken into bundles that are communicated in a predefined request. Every bundle should be gotten in the request it was sent for the message to be accurately reassembled by the beneficiary's gadget.
Which of the following best shows how keylogging can be used to get into a computer system without permission?A user installs a program on their computer that records and transmits all user input unintentionally.
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Which of these parts reduces the amount of pollutants in the engine exhaust?
A. Transmission
B. Catalytic converter
C. Tailpipe
D. Muffler
Answer:
Option B
Explanation:
Catalytic convertor with in the exhaust pipes of any vehicle converts harmful gases (such as hydrocarbons (HC), carbon monoxide (CO) and nitrogen oxides (NOx)) produced by combustion of fossil fuels (petrol, diesel etc.) into less harmful/toxic pollutants by acting as a catalyst for redox reaction. A catalytic convertor releases some mild gases from the exhaust like less harmful CO2, nitrogen and water vapour (steam)
Hence, option B is correct
can someone please help me with this
I've an exams tomorrow
Answer:
I am in Eight Grade
Explanation:
For some metal alloy, a true stress of 345 MPa (50040 psi) produces a plastic true strain of 0.02. How much will a specimen of this material elongate when a true stress of 412 MPa (59760 psi) is applied if the original length is 480 mm (18.90 in.)? Assume a value of 0.22 for the strain-hardening exponent, n.
Answer:
the elongation of the metal alloy is 21.998 mm
Explanation:
Given the data in the question;
K = σT/ (εT)ⁿ
given that metal alloy true stress σT = 345 Mpa, plastic true strain εT = 0.02,
strain-hardening exponent n = 0.22
we substitute
K = 345 / [tex]0.02^{0.22[/tex]
K = 815.8165 Mpa
next, we determine the true strain
(εT) = (σT/ K)^1/n
given that σT = 412 MPa
we substitute
(εT) = (412 / 815.8165 )^(1/0.22)
(εT) = 0.04481 mm
Now, we calculate the instantaneous length
[tex]l_i[/tex] = [tex]l_0e^{ET[/tex]
given that [tex]l_0[/tex] = 480 mm
we substitute
[tex]l_i[/tex] =[tex]480mm[/tex] × [tex]e^{0.04481[/tex]
[tex]l_i[/tex] = 501.998 mm
Now we find the elongation;
Elongation = [tex]l_i - l_0[/tex]
we substitute
Elongation = 501.998 mm - 480 mm
Elongation = 21.998 mm
Therefore, the elongation of the metal alloy is 21.998 mm
In the production of soybean oil, dried and flaked soybeans are brought in contact with a solvent (often hexane) that extracts the oil and leaves behind the residual solids and a small amount of oil.
a. Draw flow diagram of the process, labeling the two feed streams (beans and solvent) and the leaving streams (solids and extract).
b. The soybeans contain 18.5 wt% oil and the remainder insoluble solids, and the hexane is fed at a rate corresponding to 2.0 kg hexane per kg beans. The residual solids leaving the extraction unit contain 35.0 wt% hexane, all of the non-oil solids that entered with beans, and 1.0% of the oil that entered the beans. For a feed rate of 1000 kg/h of dried flaked soybeans, calculate mass flow rates of extract and residual solids and the composition of extract.
Answer: its c
Explanation:
The distribution of SAT scores of all college-bound seniors taking the SAT in 2014 was approximately normal with mean μ=1497 and standard deviation σ=322. A certain test-retake preparation course is designed for students whose SAT scores are in the lower 25%, percent of those who take the test in a given year. What is the maximum SAT score in 2014 that meets the course requirements?
Answer:
1279
Explanation:
We have the mean u = 1497
Standard deviation sd = 322
We find the x distribution using 25%
P(Z<z) = 0.25
Z = -0.675
From here we use the formula for z score
X = z(sd) + u
X = -0.675*322 + 1497
X = -217.35 + 1497
X = 1279.6
Which is approximately 1279
So we conclude that the maximum sat scores in year 2014that meets with the requirements of this course is 1279
Answer:
1831
Explanation:
Barries of effective
communication?
Answer: barries
Explanation:
A cylindrical rod of brass originally 10 mm in diameter is to be cold worked by drawing. The circular cross section will be maintained during deformation. A cold-worked tensile strength in excess of 380 MPa and a ductility of at least 15 %EL are desired. Furthermore, the final diameter must be 7.5 mm. Explain how this may be accomplished. Use the graphs given in previous question.
Answer:
Explanation:
From the information given:
original diameter [tex]d_o[/tex] = 10 mm
final diameter [tex]d_f =[/tex] 7.5 mm
Cold work tensile strength of brass = 380 MPa
Recall that;
[tex]\text {The percentage CW }= \dfrac{\pi (\dfrac{d_o}{2})^2 - \pi(\dfrac{d_f}{2})^2 }{\pi(\dfrac{d_o}{2})^2} \times 100[/tex]
[tex]\implies \dfrac{\pi (\dfrac{10}{2})^2 - \pi(\dfrac{7.5}{2})^2 }{\pi(\dfrac{10}{2})^2} \times 100[/tex]
[tex]\implies43.87\% \ CW[/tex]
→ At 43.87% CW, Brass has a tensile strength of around 550 MPa, which is greater than 380 MPa.
→ At 43.87% CW, the ductility is less than 5% EL, As a result, the conditions aren't met.
To achieve 15% EL, 28% CW is allowed at most
i.e
The lower bound cold work = 15%
The upper cold work = 28%
The average = [tex]\dfrac{15+28}{2}[/tex] = 21.5 CW
Now, after the first drawing, let the final diameter be [tex]d_o^'[/tex]; Then:
[tex]4.5\% \ CW = \dfrac{\pi (\dfrac{d_o^'}{2})^2 - (\dfrac{7.5}{2})^2}{\pi (\dfrac{d_o^'}{2})^2}\times 100[/tex]
By solving:
[tex]d_o^'} = 8.46 mm[/tex]
To meet all of the criteria raised by the question, we must first draw a wire with a diameter of 8.46 mm and then 21.5 percent CW on it.
Explain what the engineering team should advise in the following scenario.
Situation: An engineering team is analyzing a problem with a dam near a large metropolitan area. The dam reservoir has a capacity of 300 billion cubic feet, and it produces hydroelectric power for local municipalities. The dam has developed a severe crack.
Answer: its c
Explanation:
Fig_Q5
6. A steel rod is stressed by a tension force of 250 N. It is found that the rod has length of 45
m and diameter of 1.5 mm. If the modulus of elasticity of the steel rod is assumed as 2 x 105
MPa, determine the strain of the steel rod due to the applied force.
Answer:
The strain of the steel rod due to the applied force is 41.93
Explanation:
Modulus of elasticity is equal to stress divided by strain.
And stress is equal to force divided by area
Surface area of cylindrical rod
[tex]2\pi r (r+h)[/tex]
Substituting the given values we get -
[tex]2 *3.14 * \frac{1.5}{1000} * 45 (45 + \frac{1.5}{1000}) = 19.07[/tex]
[tex]2 * 10 ^5 = \frac{250}{19.07 * S=(\frac{\Delta L}{L} )}[/tex]
Hence, strain is equal to
Strain = 41.93
Three spheres are subjected to a hydraulic stress. The pressure on spheres 1 and 2 is the same, and they are made of the same material. The fractional compression on the third sphere is equal to the fractional compression on the first sphere times the reciprocal of the fractional compression on the second. If the pressure on the third sphere is 150000 N/m2 , what is the Bulk Modulus for the third sphere
Answer:
"150000 N/m²" is the right approach.
Explanation:
According to the question, the pressure on the two spheres 1 and 2 is same.
Sphere 1 and 2:
Then,
⇒ [tex]P_1=P_2[/tex]
⇒ [tex]\frac{\Delta V_1}{V_1}=\frac{\Delta V_2}{V_2}[/tex]
and the bulk modulus be,
⇒ [tex]B_1=B_2[/tex]
Sphere 3:
⇒ [tex]\frac{\Delta V_3}{V_3} =\frac{\frac{\Delta V_1}{V_1} }{\frac{\Delta V_2}{V_2} } =1[/tex]
then,
⇒ [tex]P_3=B\times \frac{\Delta V_3}{V_3}[/tex]
⇒ [tex]=B\times 1[/tex]
⇒ [tex]=150000\times 1[/tex]
⇒ [tex]=150000 \ N/m^2[/tex]
Structural engineers use wireless sensor networks to monitor the condition of dams and bridges.
a. True
b. False
Answer: True
Explanation:
Structural engineering is simply referred to as a branch of civil engineering, and they help in the designing of structures like buildings, dams, tunnels, bridges, tunnels, etc. Structural engineers typically work as consultants.
Wireless sensor networks are used by structural engineers to monitor the condition of dams and bridges. Wireless sensor network refers are dedicated sensors that are used in monitoring the physical conditions of the bridges and to know if they're still in good conditions.
Define hermetic compressor
Answer:
Hermetic compressors are ideal for small refrigeration systems, where continuous maintenance cannot be ensured.
state the parallelogram law of forces
Answer:
The law of parallelogram of forces states that if two vectors acting on a particle at the same time be represented in magnitude and direction by the two adjacent sides of a parallelogram drawn from a point their resultant vector is represented in magnitude and direction by the diagonal of the parallelogram drawn from .
Knowing that the central portion of the link BD has a uniform cross-sectional area of 800 2, determine the magnitude of the load P for which the normal stress in that portion of BD is 50 .
Answer: 50
Explanation:
Electronic rack-and-pinion systems use an electric motor to pump the hydraulic fluid through the hoses.
a. true
b. false
Electronic rack-and-pinion systems use an electric motor to pump the hydraulic fluid through the hoses. This statement is true.
The rack and pinion gearset is housed inside a metal tube, with each end of the rack protruding out and being attached to an axial rod. This is how it operates. When the steering wheel is twisted, the rack is moved by the pinion gear, which is mounted to the steering shaft. Based on the torque being given to the steering wheel by the driver, the steering wheel position, and the vehicle's speed, the EPS electronic control unit (ECU) determines the amount of aiding power required. With an applied force, the EPS motor rotates a steering gear, lowering the driver's necessary torque.
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If it is struck by a rigid block having a weight of 550 lblb and traveling at 2 ft/sft/s , determine the maximum stress in the cylinder. Neglect the mass of the cylinder. Express your answer to three significant figures and include appropriate units.
This question is incomplete, The missing image is uploaded along this answer below;
Answer:
the maximum stress in the cylinder is 3.23 ksi
Explanation:
Given the data in the question and the diagram below;
First we determine the initial Kinetic Energy;
T = [tex]\frac{1}{2}[/tex]mv²
we substitute
⇒ T = [tex]\frac{1}{2}[/tex] × (550/32.2) × (2)²
T = 34.16149 lb.ft
T = ( 34.16149 × 12 ) lb.in
T = 409.93788 lb.in
Now, the volume will be;
V = [tex]\frac{\pi }{4}[/tex]d²L
from the diagram; d = 0.5 ft and L = 1.5 ft
so we substitute
V = [tex]\frac{\pi }{4}[/tex] × ( 0.5 × 12 in )² × ( 1.5 × 12 in )
V = 508.938 in³
So by conservation of energy;
Initial energy per unit volume = Strain energy per volume
⇒ T/V = σ²/2E
from the image; E = 6.48(10⁶) kip
so we substitute
⇒ 409.93788 / 508.938 = σ²/2[6.48(10⁶)]
508.938σ² = 5,312,794,924.8
σ² = 10,438,982.5967
σ = √10,438,982.5967
σ = 3230.9414
σ = 3.2309 ksi ≈ 3.23 ksi { three significant figures }
Therefore, the maximum stress in the cylinder is 3.23 ksi
Suppose a student table has two columns, names and marks. How to get name and marks of top three students
Answer:
SELECT Name, Marks FROM Student s1 where 3 <= (SELECT COUNT(*) FROM Students s2 WHERE s1.marks = s2.marks)
In a certain company the cost of software depends on the license type which could be Individual or Enterprise. Write a program that reads License Type wanted (just the first character of each type: I, i, E, e). Number of Users to use the software. Type Price/User Minimum number of users Individual 500$ 1 Enterprise 300$ 5 Your program should: Check if the number of users is greater than or equal than Minimum Number of Users allowed Compute the cost: (for example cost = Cost per user x Number of Users)
Solution :
import [tex]$\text{java}.$[/tex]util.*;
public [tex]$class$[/tex] currency{
public static [tex]$\text{void}$[/tex] main(String[tex]$[]$[/tex] args) {
Scanner input [tex]$=$[/tex] new Scanner(System[tex]$\text{.in}$[/tex]);
System[tex]$\text{.out.}$[/tex]print("Enter [tex]$\text{number of}$[/tex] quarters:");
int quarters = input.nextInt();
System.out.print("Enter number of dimes:");
int [tex]$\text{dimes =}$[/tex] input.nextInt();
System[tex]$\text{.out.}$[/tex]print("Enter number of nickels:");
int nickels = input.nextInt();
System[tex]$\text{.out.}$[/tex]print("Enter number of pennies:");
int [tex]$\text{pennies = }$[/tex] input.nextInt();
// computing dollors
double dollars = (double) ((quarters*0.25)+(dimes*0.10)+(nickels*0.05)+(pennies*0.01));
System[tex]$\text{.out.}$[/tex]format("You have : $%.2f",dollars);
}
}
In a parking garage, each level is 18 feet apart, Each ramp to a level is 120 feet long. Find the measurement of elevation for each ramp?
Answer:
Sin(angle)=0.1538
Angle=arcsine(0.1538)
Angle is 8.85 degrees
Explanation:
Firstly draw a diagram showing a triangle with the required angle, a hypotenuse of 130 ft and an opposite side of 20 ft.
The sine of the angle required uses the formula Opposite/Hypotenuse
(i am not sure sure)
Which of these is shown in the animation below?
A. Air spring
B. Coil spring
C. Shock absorber
D. Torsion bar
Define;
i) Voltage
ii) Current
iii) Electrical Power
iv) Electrical Energy
Answer:
I) Voltage - is the pressure from an electrical circuit's power source that pushes charged electrons (current) through a conducting loop, enabling them to do work such as illuminating a light. In brief, voltage = pressure, and it is measured in volts (V).
II) Current - is the movement of electrons through a wire. Electric current is measured in amperes (amps) and refers to the number of charges that move through the wire per second. If we want current to flow directly from one point to another, we should use a wire that has as little resistance as possible.
III) Electrical Power - is the rate, per unit time, at which electrical energy is transferred by an electric circuit. The SI unit of power is the watt, one joule per second. Electric power is usually produced by electric generators, but can also be supplied by sources such as electric batteries.
IV) Electrical Energy - is a form of energy resulting from the flow of electric charge. Energy is the ability to do work or apply force to move an object. In the case of electrical energy, the force is electrical attraction or repulsion between charged particles.
Explanation:
I hope ot helps to you a lot! Correct me if I'm wrong.
g Design of a spindle present in an existing design needs to be reviewed for use under new loading needs. It is currently designed to withstand combined torsional and compressive loading. The design team needs to determine what the maximum torque it can withstand before failing if a compressive, axial load of 15 kips is present. The ultimate compressive and tensile strengths of the material are 135 ksi and 40 ksi, respectively. Determine the torsional shear stress that will just cause failure using a non-conservative failure theory.
Answer: its c
Explanation:
Identify parts of the E-Cig that constitute voltage, current, and resistance. Discuss the role each plays in the E-Cig and typical values for each including units.
Discuss the electrical dangers of an E-Cig. Give specific examples.
There are many electrical safety rules. Pick one, and discuss its application on a small system, such as the E-Cig.
Answer: c
Explanation:
How may the desire for a perfect lawn be related to environmental pollution? A. Lawns have little to do with environmental pollution. B. Perfect lawns require excess use of manual labor. C. Manicured lawns are subject to increased runoff. D. Lawns absorb pesticides and fertilizers and these chemicals leach out of the lawn and run into creeks, streams and eventually, rivers, with rain or watering, eventually reaching the ocean.
Answer: is b
Explanation:
To read signs you need good focal vision
Answer:eyesight
Explanation:
Which of the following situations best describes the chemical weathering process of sedimentary rock?
answer choices
Sedimentary sandstone is carried away by water along the bedrock of a stream.
Sedimentary sandstone allows water to freeze and thaw inside its cracks.
Sedimentary limestone cliffs are battered by strong ocean waves.
Sedimentary limestone is exposed to acid rain at the top of a mountain.
A situation which best describes the chemical weathering process of sedimentary rock include the following: D. Sedimentary limestone is exposed to acid rain at the top of a mountain.
What is weathering?In Geology, weathering can be defined as a biogeochemical process that involves both the physical and chemical breakdown of rock into smaller pieces or fragments called sediments.
Additionally, weathering is broadly classified into two (2) categories and these include the following;
Physical weatheringChemical weatheringDuring the chemical weathering process of sedimentary rock, sedimentary limestone that are found at the top of a mountain become exposed to acid rain.
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